Laravel - Get an user who has specific relationships - laravel

Question

I have a user with countries relationship. (hasMany)
user_id 1
country_id 1
user_id 1
country_id 2
...
What I want is to get those users who have both countries (country 1 and country 2) How can I do this? I'm reading http://laravel.com/docs/eloquent#querying-relations but I'm not very sure what to do.
edit: almost the solution
$users = \User::whereHas('countries', function($query) {
$countries_ids = [1, 2, 4];
$query->whereIn('users_countries.country_id', $countries);
})->get();

Answer 1

This will work as long as there are no duplicates in the pivot table (unique index for pair of fk keys for example):
$countries = [1,5,9];
User::whereHas('countries', function ($q) use ($countries) {
$q->whereIn('users_countries.country_id', $countries);
}, '=', count($countries) )->get();
In case there are duplicates, like:
user_id | country_id
1 | 1
1 | 2
1 | 1
Then you would need raw count(distinct ...) so you couldn't use whereHas, so I suggest this, which will be much faster:
$countries = [1,5,9];
User::join('users_countries as uc','uc.user_id', '=', 'users.id')
->whereIn('uc.country_id', $countries)
->having(DB::raw('count(distinct uc.country_id)'), '=', count($countries))
->groupBy('users.id')
->get(['users.*']);

Answer 2

You can do it the other way. Make the query on the country model. Add a function in the country model
public function user(){
return $this->belongsTo('user');//or if there is no user_id column in the countries table, use the ('model','local_key','foreign_key') pattern.
}
Then create an array with the country_ids, and que the country model.
$country_ids=array(4,67);
$countries=Country::where('id',$country_ids[0])->where('id',$country_ids[1])->get();
In order to get the users you should loop through like this
foreach($countries->user as $user)