I am having one spring project which is running with '*.htm' extension , we have bind it in web.xml file.
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
Now I want to integrate the Spring WebSocket and stomp js for the chat application, but the problem here is stomp.js is sending the request to the server without '.htm' extenstion.
due to which I am getting 404 error in each request (info or other xhr).
Is there any way to enable the Spring WebSocket and stomp js with '.htm' extension ?
I can't remove this extension it will hault my current application.
add prefix in the websocket url,it works well.
js:
var socket = new SockJS("/websocket_demo/myapp/ws");
web.xml DispatchServlet mapping:
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/myapp/*</url-pattern>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
You can add multiple servlet-mapping like this and keep the .htm working with "/url" serving for new functionality
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/url</url-pattern>
</servlet-mapping>
if you are using Servlet 2.5 you can directly use
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.htm</url-pattern>
<url-pattern>/url</url-pattern>
</servlet-mapping>
Related
Please why I am getting the requested resource is not found on project start up even though everything seems alright
<context-param>
<param-name>log4jConfigLocation</param-name>
<param-value>classpath:log4j.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.util.Log4jConfigListener</listener-class>
</listener>
<servlet>
<servlet-name>spring</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
Please assist me!!!
You need to load the Spring context with org.springframework.web.context.ContextLoaderListener, not Log4jConfigListener (or try out Spring Boot)
See Loading context in Spring using web.xml
I'm building a web project and have the following code in my web.xml:
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>-1</load-on-startup>
<enabled>true</enabled>
<async-supported>false</async-supported>
</servlet>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.faces</url-pattern>
<url-pattern>*.xhtml</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>/faces/*</url-pattern>
</servlet-mapping>
In eclipse markers window I see following error twice: The servlet mapping "Faces Servlet" refers to a servlet that is not defined. Well, in my opinion it is defined right there. When I delete servlet-mapping nodes, error disappears, but the project is useless. I've tried to re-validate project and web.xml file, refresh dependencies from maven. I haven't succeeded in finding anything relevant in google search. Also, I used very similar web.xml file in another project(not maven) and there it worked fine.
How can I fix this error?
I have come accross some existing code where in web.xml a single servlet is mapped multiple times. I dont understand the need of doing so.
e.g.
<servlet>
<servlet-name>test1</servlet-name>
<servlet-class>
com.test.spring.MyDispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet>
<servlet-name>test2</servlet-name>
<servlet-class>
com.test.spring.MyDispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet>
<servlet-name>test3</servlet-name>
<servlet-class>
com.test.spring.MyDispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
Assume if you have different url-pattern for each servlet, you can combine that into a single url-pattern.
If the url-patterns are same, then you can remove the redundant mappings.
As far I know, adding the same servlet mapping multiple times is not useful or not needed.
This post discussed in detail about servlet mapping. Hope this helps.
Thanks for the reply.
The url pattern are different.
e.g.
<servlet-mapping>
<servlet-name>test1</servlet-name>
<url-pattern>/test1/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>test2</servlet-name>
<url-pattern>/test2/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>test3</servlet-name>
<url-pattern>/test3/*</url-pattern>
</servlet-mapping>
Am try to integrate cometd(spring-jquery-jetty7) with the appfuse spring MVC project.
my web.xml is
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/app/*</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>cometd</servlet-name>
<servlet-class>org.cometd.server.CometdServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>cometd</servlet-name>
<url-pattern>/cometd/*</url-pattern>
</servlet-mapping>
and did all other configuration like spring-jquery-jetty7 example, When i try cometd.handshake() from the script, it's failed and got error from the log like follows
WARN [http-8080-6] PageNotFound.handleHttpRequestMethodNotSupported(183) | Request method 'POST' not supported
115117 [http-8080-6] WARN org.springframework.web.servlet.PageNotFound - Request method POST' not supported
Anybody experience this? hope the dispatcher servlet process the request instead of cometd servlet, i dont know whats wrong in this, suggestion regarding this are welcome.
thank you
I resolve the issue by changing the servlet orders like cometd servlet first and dispatcher servlet second. The dispatcher servlet handle the cometd request first and throw the error always so i change the order like follows
<servlet>
<servlet-name>cometd</servlet-name>
<servlet-class>org.cometd.server.CometdServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>cometd</servlet-name>
<url-pattern>/cometd/*</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/app/*</url-pattern>
</servlet-mapping>
and also add load-on-startup for initialize the comet servlet when application start. thank you
Say I have a Spring MVC application with JPA as backend. Now here we want to provide simple UI to user to perform simple configuration to some properties file. It would make sense to make it separate from the main Spring application because some configuration is related to Spring MVC so it will fail when start the main application by the main UI through Spring MVC.
But how to register both servlet(Spring and plain JSP)in the same web application?
<!-- Handles Spring requests -->
<servlet>
<servlet-name>SpringApplication</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/mvc-config.xml</param-value>
</init-param>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>SpringApplication</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>PlainJSPApplication</servlet-name> <!--Is it ok to separate request to different servlet like this?-->
<servlet-class>com.app.plainJSP</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>PlainJSPApplication</servlet-name>
<url-pattern>/config</url-pattern> <!--How to handle mapping so not conflict to Spring main application-->
</servlet-mapping>
I think it is common to register another servlet class to in the SAME web.xml, is it OK? and also how to handle that request URL pattern, as "/" has been assign to Spring servlet?
Any advice would be appreciated.
You can separate Spring managed controllers and your own servlet by mapping both with different url patterns.
The requests for Spring controllers are managed by DispatcherServlet. Basically, it is just a Servlet that, when you map urls to it, it will automatically be seen by Spring, thus mapping it to the right controller, views etc.
web.xml
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>PlainJSPApplication</servlet-name> <!--Is it ok to separate request to different servlet like this?-->
<servlet-class>com.app.plainJSP</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>PlainJSPApplication</servlet-name>
<url-pattern>*.htm</url-pattern>
<url-pattern>*.html</url-pattern>
<url-pattern>*.bmk</url-pattern>
<!-- other url pattern ... -->
<!-- other url pattern ... -->
<!-- other url pattern ... -->
</servlet-mapping>
Here, all the requests end with .do will be seen by Spring. Others will then be seen by your servlets.
So, as long as you don't harm this mapping, Spring MVC & your normal servlets will integrate gracefully.