Redirection problems - bash

I've noticed something I don't understand while attempting to keep a progress log in a bash script. The issue can be reproduced using the following line:
var1=$(var2=$(echo "Hi!"))
After executing this line, var2 remains empty. I don't understand what causes this behavior (if the output generated by echo is redirected somewhere, it doesn't go into var1), and more importantly, what I might do to avoid having this problem.
Any sort of help (explanation/pointers) would be much appreciated.

The reason why original string remains unchanged because of your use of:
$(var2=$(echo "Hi!"))
Which basically changes value of var2 in a sub shell and any changes made there remain in sub shell only. Once sub shell exits you don't get changed value in the parent shell.

Related

Protecting scripts from errant clobbering

I spent some time building this handy bash script that accepts input via stdin. I got the idea from the top answer to this question: Pipe input into a script
However, I did something really dumb. I typed the following into the terminal:
echo '{"test": 1}' > ./myscript.sh
I meant to pipe it | to my script instead of redirecting > the output of echo.
Up until this point in my life, I never accidentally clobbered any file in this manner. I'm honestly surprised that it took me until today to make this mistake. :D
At any rate, now I've made myself paranoid that I'll do this again. Aside from marking the script as read-only or making backup copies of it, is there anything else I can do to protect myself? Is it a bad practice in the first place to write a script that accepts input from stdin?
Yes, there is one thing you can do -- check your scripts into a source-code-control repository (git, svn, etc).
bash scripts are code, and any non-trivial code you write should be checked in to source-code-control (and changes committed regularly) so that when something like this happens, you can just restore the most-recently-committed version of the file and continue onwards.
This is a very open-ended question, but I usually put scripts in a global bin folder (~/.bin or so). This lets me invoke them as myscript rather than path/to/myscript.sh, so if I accidentally used > instead of |, it'd just create a file by that name in the current directory - which is virtually never ~/.bin.

missed $ while using variableName in bash script - how to catch such issues?

I have a bash script which does the following:
#!/bin/bash
moduleName=$1
someInfo=`ls | grep -w moduleName`
echo $someInfo
In the line #3, I was supposed to use $moduleName, but I missed it.
Is there any way to find such issues in Bash scripts?
I used shell Check, but it didn't report this issue.
For me, the script looks fine; it lists the files whose name contain the string moduleName.
The script is syntactically correct.
The error in line #3 is a semantic error; it changes the meaning of the script. Only a person that knows the intention of the script can detect it.
There is no way to automatically detect such errors, unless you write a software that reads your mind and knows that you intended to write $moduleName and you mistakenly wrote moduleName instead.

Using variables between files in shell / bash scripting

This question has been posted here many times, but it never seems to answer my question.
I have two scripts. The first one contains one or multiple variables, the second script needs those variables. The second script also needs to be able to change the variables in the first script.
I'm not interested in sourcing (where the first script containing the variables runs the second script) or exporting (using environment variables). I just simply want to make sure that the second script can read and change (get and set) the variables available in the first script.
(PS. If I misunderstood how sourcing or exporting works, and it applies to my scenario, please let me know. I'm not completely closed to those methods, after what I've read, I just don't think those things will do what I want)
Environment variables are per process. One process can not modify the variables in another. What you're asking for is not possible.
The usual workaround for scripts is sourcing, which works by running both scripts in the same shell process, but you say you don't want to do that.
I've also given this some thought. I would use files as variables. For example in script 1 you use for writing variable values to files:
echo $varnum1 > /home/username/scriptdir/vars/varnum1
echo $varnum2 > /home/username/scriptdir/vars/varnum2
And in script 2 you use for reading values from files back into variables:
$varnum1=$(cat /home/username/scriptdir/vars/varnum1)
$varnum2=$(cat /home/username/scriptdir/vars/varnum2)
Both scripts can read or write to the variables at any given time. Theoretically two scripts can try to access the same file at the same time, I'm not sure what exactly would happen but since each file only contains one value, the time to read or write should be extremely short.
In order to even reduce those times you can use a ramdisk.
I think this is much better than scripts editing each other (yuk!). Live editing of scripts can mess up scripts and only works when you initiate the script again after the edit was made.
Good luck!
So after a long search on the web and a lot of trying, I finally found some kind of a solution. Actually, it's quite simple.
There are some prerequisites though.
The variable you want to set already has to exist in the file you're trying to set it in (I'm guessing the variable can be created as well when it doesn't exist yet, but that's not what I'm going for here).
The file you're trying to set the variable in has to exist (obviously. I'm guessing again this can be done as well, but again, not what I'm going for).
Write
sudo sed -i 's/^\(VARNAME=\).*/\1VALUE/' FILENAME
So i.e. setting the variable called Var1 to the value 5, in the file
test.ini:
sudo sed -i 's/^\(Var1=\).*/\15/' test.ini
Read
sudo grep -Po '(?<=VARNAME=).*' FILENAME
So i.e. reading the variable called Var1 from the file test.ini
sudo grep -Po '(?<=Var1=).*' test.ini
Just to be sure
I've noticed some issues when running the script that sets variables from a different folder than the one where your script is located.
To make sure this always go right, you can do one of two things:
sudo sed -i 's/^\(VARNAME=\).*/\1VALUE/' `dirname $0`/FILENAME
So basically, just put `dirname $0`/ (including the backticks) in front of the filename.
The other option is to make `dirname $0`/ a variable (again including the backticks), which would look like this.
my_dir=`dirname $0`
sudo sed -i 's/^\(VARNAME=\).*/\1VALUE/' $my_dir/FILENAME
So basically, if you've got a file named test.ini, which contains this line: Var1= (In my tests, the variable can start empty, and you will still be able to set it. Mileage may vary.), you will be able to set and get the value for Var1
I can confirm that this works (for me), but since you all, with way more experience in scripting then me, didn't come up with this, I'm guessing this is not a great way to do it.
Also, I couldn't tell you the first thing about what's happening in those commands above, I only know they work.
So if I'm doing something stupid, or if you can explain to me what's happening in the commands above, please let me know. I'm very curious to find out what you guys think if this solution.

Get last bash command including pipes

I wrote a script that's retrieving the currently run command using $BASH_COMMAND. The script is basically doing some logic to figure out current command and file being opened for each tmux session. Everything works great, except when user runs a piped command (i.e. cat file | less), in which case $BASH_COMMAND only seems to store the first command before the pipe. As a result, instead of showing the command as less[file] (which is the actual program that has the file open), the script outputs it as cat[file].
One alternative I tried using is relying on history 1 instead of $BASH_COMMAND. There are a couple issues with this alternative as well. First, it does not auto-expand aliases, like $BASH_COMMAND does, which in some cases could cause the script to get confused (for example, if I tell it to ignore ls, but use ll instead (mapped to ls -l), the script will not ignore the command, processing it anyway), and including extra conditionals for each alias doesn't seem like a clean solution. The second problem is that I'm using HISTIGNORE to filter out some common commands, which I still want the script to be aware of, using history will just make the script ignore the last command unless it's tracked by history.
I also tried using ${#PIPESTATUS[#]} to see if the array length is 1 (no pipes) or higher (pipes used, in which case I would retrieve the history instead), but it seems to always only be aware of 1 command as well.
Is anyone aware of other alternatives that could work for me (such as another variable that would store $BASH_COMMAND for the other subcalls that are to be executed after the current subcall is complete, or some way to be aware if the pipe was used in the last command)?
i think that you will need to change a bit your implementation and use "history" command to get it to work. Also, use the command "alias" to check all of the configured alias.. the command "which" to check if the command is actually stored in any PATH dir. good luck

Result of shell script as build setting

Is it possible to run a shell script and use its result as a user defined macro in Xcode?
Basically I just want the result of a shell script to be put in a variable so it gets set in Info.plist (just like ${EXECUTABLE_NAME} etc.)
For example:
If I add $(/usr/bin/whoami) as a build setting condition (at the bottom of settings of the build configuration) it just sets an empty string.
See this question for a couple of different approaches. All of them require add a "Run Script" build phase.
Assuming a bash like shell, and given an almost complete lack of context for your problem, try
EXECUTABLE_NAME=$( scriptToGetEXEC_NAME )
PRODUCT_NAME=$( scriptToGetPROD_NAME)
The $( ... cmd ... ) construct is called command substitution. What this means is the when the shell processor scans each line of code, if first looks to see if there are any $(...) embedded (and other things to). If there are, it spawns a new shell, executes the code inside, and if any text is returned, it is embedded in the command line and THEN the shell scans the line again, and eventually executes everything from left to right, assuming that the first word will turn into a built-in command or a command in the PATH.
I hope this helps.
P.S. as you appear to be a new user, if you get an answer that helps you please remember to mark it as accepted, and/or give it a + (or -) as a useful answer.

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