I am trying to create posts with comments with CodeIgniter and I am trying to add voting for the comments with + and -.
But my problem is not actually this functionallity but more exactly creating the link and the method in controller/model for this.
I understand that there is some kind of link to methods.
If I have something like this:
public function like() {
echo 'Test Function';
}
and when I create link like this one sitename.com/posts/first-post/like theoritecally I will see blank page with "Test Function" text (and of course if I write proper routing rule but I cannor for now).
I can see a blank page with this working echo 'Test Function', but does this mean I have to load every methods and views for the entire page if I want to display the entire webpage with all the elements? I think that I mistake something very serious here but I don't know what.
The example with the "Create news" tutorial in ellislab.com didnt help me. They show something similar I think with /create/ section in the URL and create() methods.
If I have many links with functionallities do I have to add new routing rules for all of them? I really tried to search in Google and everywhere but I didnt find anything related.
Sorry for this lame question.
You need to use Ajax call and on callback you have to increase or decrease the count. For creating a link , once page is loading render the data and provided the default link like
for + http://<site.com>/<controller>/like?totalLike=<36>
for - http://<site.com>/<controller>/unlike?totalunLike=<3>
Once user will click + link then by using Ajax, call the controller method link/unlike and increase or decrease the count and repopulate the link again with fresh counter.
Hope it will resolve your problem.
Related
I'm programming in wxpython and I'm trying to use the mvc model. But I'm stuck with a lost controller :) I'll explain.
A have a panel which calls a controller. I do some things. then I destroy my controller and my panel. Well I try.
del self.tempMApanel.controller
self.tempMApanel.Destroy()
What I know for sure is that the controller isn't linked anymore with the panel because if I 'print' the controller I get an error that says main object has no attribute controller:
print "self.tempMApanel.controller: ",self.tempMApanel.controller #'Main' object has no attribute 'controller'
At a certain moment I recreate the panel with a new controller. But when I send a message (with pub.Sendmessage) to do something in the controller, the message is picked up by the old controller which isn't connected to a panel and the program complains (ofcourse :) )
SO my specific question is, can you 'kill' a controller and is it possible to have a 'lost', 'single', 'flying' controller?
The past 2 days programming was lifted to another dimension of difficult. All the virtual connections ... sometimes it is difficult to keep track and it is difficult to explain and ask for help. So I hope it is clear what I'm trying to say.
tx in advance and I hope there are some geniuses who can help me!
My day is so good!! I was talking about my 'lost' controller problem with our IT-guy and he said you use a subscriber, maybe your reference to your controller is still in there somewhere. And indeed, the controller was added to a list, so I had to remove the controller from this list and then I could remove my view.
I'm so relieved! The last 3 days there were so many problems in my program and I solved them all but this one. But now I can move on the next part.
So my advice is, always look for references if you see this kind of problem.
I put a Ajax link using the following code:
echo chtml::ajaxLink('GO', 'http://localhost/index.php?r=user/delete', array('method'=>'POST'));
But, regardless of giving the second parameter as URL i,e 'http://localhost/index.php?r=user/delete'. It generates link with the current URL in the browser not the URL I just specified.
What is the issue? How could I create AJAX link? Google several hours but can't solve the issue.
Any kind of help is highly appreciated.
First of all, you should always try and create normalized urls.
But i think your doubt lies in the # that is generated/appended. If you go and check the source of yii ajaxLink you'll see this:
public static function ajaxLink($text,$url,$ajaxOptions=array(),$htmlOptions=array())
{
if(!isset($htmlOptions['href']))
$htmlOptions['href']='#';
$ajaxOptions['url']=$url;
$htmlOptions['ajax']=$ajaxOptions;
self::clientChange('click',$htmlOptions);
return self::tag('a',$htmlOptions,$text);
}
so if you don't set the href property of the a tag in the htmloptions array, the # will be appended.
You should also understand that yii uses jquery, so if you check out the source of the page, you'll see at the bottom, how jquery is used to carry out an ajax request, your actual url that is called will also be seen in that script. So the third option/parameter in ajaxLink is for options for jquery's ajax function. You can create better ajax links using this option.
Regardless of where(which controller) your url points to in your project, the action associated with that url will be called.
So anyway, you can modify your code like this if you want the url to be shown and not a # :
echo CHtml::ajaxLink('GO', 'http://localhost/index.php?r=user/delete',
array('type'=>POST), //there are various other options for jquery ajax
array('href'=>'http://localhost/index.php?r=user/delete'));
To make better ajax links i would suggest going through jquery's ajax documentation. There is an option for a success function, that you can use to let the user know that the operation was completed.
Hope this helps, don't hesitate to leave comments if i haven't answered your question completely.
Have you tried:
echo CHtml::ajaxLink('GO', array('/user/delete'), array('method'=>'POST'));
as the ajaxLink documentation suggests...? Look also at the normalizeUrl method.
Using these methods, which in turn are using createUrl, is usually better since it will take care to create a valid url for your site.
I had the same issue(or maybe similar).
I've used renderPartial to load view and later in that view i was using ajaxLink and it was not working.
What i have found, that when using renderPartial, there was no jquery script for ajax action.
What you have to do is to add 4th argument(true) in renderPartial function to generate jquery script.
See the documentation: http://www.yiiframework.com/doc/api/1.1/CController/#renderPartial-detail
Hope it helps and saves time to figure it out.
I am trying to use CodeIgniter and jQuery-ui dialog to create a modal window with form to update user information.
The process should be like:
1. Press a button on a view page.
2. A modal window pops up.
3. Inside the window is a form that a user can fill.
4. If the user filled something before, the information should be shown in corresponding field
5. Click the update button on the modal window to save the changes to database.
Can anyone provide a good sample of this process?
I used ajax to pass the data but it didn't work when I was trying to update the data to the database. It would be nice if an example of how to pass data from ajax to php and how php handle that.
Thanks,
Milo
well the jquery bit for post(), get(), ajax() works the same in any measure you would normally use it.. key difference here is with CI you can't post directly to a file-name file-location due to how it handles the URI requests. That said your post URL would be the similar to how you would access a view file normally otherwise
ie: /viewName/functionName (how you've done it with controllers to view all along. post, get, ajax doesnt have to end in a extension. I wish I had a better example then this but I can't seem to find one at the moment..
url = '/home/specialFunction';
jQuery.get(url, function(data) {
jQuery("#div2display").html(data);
});
in the case of the above you notice despite it not being a great example that. you have the url with 2 parameters home and specialFunction
home in this case is the controller file for home in the control folder for the home file in views the specialFunction is a "public function" within the class that makes the home controller file. similar to that of index() but a separate function all together. Best way I have found to handle it is through .post() and a callback output expected in JSON cause you can form an array of data on the php side json_encode it and echo out that json_encode and then work with that like you would any JSON output. or if your just expecting a sinlge output and not multiples echoing it out is fine but enough of the end run output thats for you to decide with what your comfortable doing currently. Hopefully all around though this gives you some clairity and hopefully it works out for you.
I'm trying to add a URL parameter within a Spring MVC application. It's a basic search page that shows results.
In the search page, there is a form that is set to POST. There are many hidden fields and other fields I don't want in the URL. So, I don't want to do a GET.
I do want the search query in the URL. So after clicking the search button, the resulting search results page needs to have a URL like /search?query=hello
To get it to work, I'm creating a RequestMapping method in the Spring MVC Controller and doing a redirect: tacking on the query parameter. However, I'm not sure using a redirect is the best answer, seems there could be performance concerns redirecting as well.
I looked around and noticed folks using javascript and the location object, but setting the location object obviously relaunches the URL you set it to. I also looked at the HTTPServletResponse & HTTPServletRequest objects, but couldn't find much.
Any thoughts on how I can force the search parameter to be added to the URL?
Your form will have an 'action' specified telling it where to POST to. I'd have thought you could attach an onclick event to your submit button (or an onsubmit event to your form) that updates the action url by appending "?query=" to it.
document.<form name>.action += "?query=...";
Then you just have to worry about someone posting your form without JavaScript enabled - in this case you could fall back to your redirect.
I don't know how the server technology so I can't say if it will be happy giving you both GET and POST parameters, if not you'll have to manually strip the GETs out of the URL.
But anyway, this seems like a rather odd situation to be in - is it really that big a deal to show the parameters in the URL? Anything that gets posted by an HTML form can still be inspected with the right tools, it's just ever so slightly more difficult.
I wanted to provide a more complete answer to my question with code. The previous user helped me down this path, so I'll keep it as the accepted answer. However, there is one item to note:
If you add on to the action, and you have an input text box with the same name, the page posts a duplicate value like: query=hello,hello.
So, I needed to remove the name on the input box, and use the following javascript. Note, I am using the prototype.js framework:
Event.observe(window, 'load', function(event) {
Event.observe('searchForm', 'submit', function(event) {
$('searchForm').action += "?query="+$('searchBox').value;
});
Sorry about the question title, but I couldn't find a more appropriate way to phrase this.
I am currently building a CakePHP powered website and I'm not quite sure how to approach the following issue. The website looks something like the follwing mockup:
.
The greyed out areas are part of the layout, because their content does not change between views. In the sidebar, I have a collection of ads who are linked to several models. I need controller logic to determine the picture associated with an ad. Also, the ad list needs to be dynamic. Where should I put the logic for building the sidebar?
I've thought about:
putting the logic into the AppController (beforeFilter / afterFilter) - the problem is I can't use the controller logic I need (the other controllers inherit from AppController, I'm not sure how to use them there).
making a component - is it okay to build components that rely on controllers?
replicating the sidebar code in all controllers that render views - this seems kind of stupid to me.
What is the Cake way for this?
Update
After some reading and experimenting, I've gotten to refactoring most of it.
I obtained the best performance by moving the logic for building my ads in the model (eliminating the component that retrieved the pictures) and not using requestAction. It's almost three times faster and the code looks much better.
I've done something similar for data-driven navigation. I put my logic in AppController::beforeRender and haven't had any problems. I'm not sure I understand your concern related to controller inheritance. I retrieve my menus via:
$menus = $this->NavMenuItem->groupByMenu();
$this->set( compact( 'menus' ) );
I then created an element that renders the menu. It's executed by the layout via:
<?php echo $this->element( 'navigation', array( 'id' => 'secondary', 'menu' => $menus['SECONDARY'] ) ) ?>
If that doesn't help, maybe you can further explain your issue with controller inheritance in a comment.
I guess the answer is requestAction in case the results are cachable:
http://book.cakephp.org/view/434/requestAction
It can be done in this way:
Create an element that will help in layout of the Ad Block
Create one or more controller that will generate the data required for rendering of the block
Use requestAction for getting the data out of the models and into the element.
Check the cake book, there is an example of an element where data from Post Model is used to display top/latest 5 posts. Your requirement, I feel, is very similar to it.
Alex,
you're getting a SQL error because the build() function has to be in the Sidebar model, not controller. Also, you don't necessarily need to use $user = array('Sidebar'); you could calling Sidebar in all of your models with this:
$Sidebar = ClassRegistry::init('Sidebar'); and then $Sidebar->find();, $Sidebar->build(); etc.
Or, if you only need to call the build() function from the Sidebar model, you could do this:
$sidebar = ClassRegistry::init('Sidebar')->build();
$this->set('sidebar', $sidebar);
Cheers.