How to show all rows in jqGrid? - jqgrid

I'm trying to show all rows in a jqGrid table. I know I can use rowList to let the user choose how many rows wants to see, but how can I put an option to see all rows? If a put a number like 999999999, it will show all rows because there are less rows, but the user will see that big number as an option and is not too logic.

You can use words instead of numbers in rowList as follows:
rowList:['All','100','500','1000']
Then you have to use your server controller to "convert" that information to a number of rows to show.
I did it like this:
Integer intRows = 0;
if (rows.getClass().equals(String.class) && ((String)rows).equalsIgnoreCase("all")) {
intRows = Integer.MAX_VALUE;
} else {
intRows = Integer.valueOf(rows);
}
So your server will show Integer.MAX_VALUE if user selects "All", or a number of rows it other case.
I think you won't have more than Integer.MAX_VALUE rows in your table, it's such a big number!

Related

Google Apps Script: Activate and sort rows when cells in given column are not blank

I'm extremely new to Apps Script and trying to make my first thing. It's a shopping list.
I want to create a function that will activate and then sort (by Column 1, 'Aisle #') all rows where there are values in a given other column (Column 3, 'Qty'). The idea is to sort the items on the list for that week (i.e., with a value filled in for Qty) by aisle to give me the order I should be looking for things. I do not want to sort items which are in the spreadsheet but without
a value for Qty.
Here is what I've got so far:
var sheet = ss.getActiveSheet()
var range = sheet.getDataRange();
var rangeVals = range.getValues()
function orderList2(){
if(rangeVals[3] != ""){
sheet.activate().sort(1, ascending=true);
};
};
I'm trying to use "if" to define which rows to activate before doing the sort (as I don't want to sort the entire sheet—I only want to sort the items I will be buying that week, i.e., the items with a value in Column 3). The script runs but ends up sorting the entire sheet.
The closest thing I could find was an iteration, but when I did it, it ended up only activating the top-left cell.
Any help you can provide would be greatly appreciated!
Cheers,
Nick
Answer:
Use Range.sort() instead of Sheet.sort() if you don't want to sort the entire sheet.
Explanation:
You want to sort the data according to the value in column A (Aisle #), if the corresponding value in C (Qty) is not empty.
If my assumption is correct, the rows where Qty is empty should go below the rest of data, and they should not be sorted according to their Aisle #.
In this case, I'd suggest the following:
Sort the full range of data (headers excluded) according to Qty, so that the rows without a Qty are placed at the bottom, using Range.sort() (if you don't need to exclude the headers, you can use Sheet.sort() instead).
Use SpreadsheetApp.flush() to apply the sort to the spreadsheet.
Use getValues(), filter() and length to know how many rows in the initial range have their column C populated (variable QtyElements in the sample below).
Using QtyElements, retrieve the range of rows with a non-empty column C, and sort it according to column 1, using Range.sort().
Code sample:
function orderList2() {
var sheet = SpreadsheetApp.getActiveSheet();
var firstRow = 2; // Range starts at row 2, header row excluded
var fullRange = sheet.getRange(firstRow, 1, sheet.getLastRow() - firstRow + 1, sheet.getLastColumn());
fullRange.sort(3); // Sort full range according to Qty
SpreadsheetApp.flush(); // Refresh spreadsheet
var QtyElements = fullRange.getValues().filter(row => row[2] !== "").length;
sheet.getRange(firstRow, 1, QtyElements, sheet.getLastColumn())
.sort(1); // If not specified, default ascending: true
//.sort({column: 1, ascending: false}); // Uncomment if you want descending sort
}
Reference:
Range.sort(sortSpecObj)

How to get the total number of Rows in a table | Cypress

I have a table with N rows. How can I get the total number of rows present in the table?
I search for a name, and that particular name is in row number X, how can I get the value of that particular row.
You can use .find to solve both of your cases.
To get the table row count:
cy.get("#tableID")
.find("tr")
.then((row) => {
//row.length will give you the row count
cy.log(row.length);
});
To get the value ( index ) of the particular row, you can do something like this.
cy.get("#Table Id")
.find("tr")
.then((rows) => {
rows.toArray().forEach((element) => {
if (element.innerHTML.includes("Your Value")) {
//rows.index(element) will give you the row index
cy.log(rows.index(element));
}
});
});
Additional tip: If you want to select a specific table cell containing a value, you can do this:
cy.get("#customers").find("tr").find("td").contains("Germany");
Note: to get the table row index there can be many other alternative ways. Hope you will figure them out on the go.

How can I more efficiently find the height of a table using Python

I am using openpyxl to copy data from an Excel spreadsheet. The data is a table for an inventory database, where each row is an entry in the database. I read the table one row at a time using a for loop. In order to determine the range of the for loop, I wrote a function that examines each cell in the table to find the height of the table.
Code:
def find_max(self, sheet, row, column):
max_row = 0
cell_top = sheet.cell(row = row - 1, column = column)
while cell_top.value != None:
cell = sheet.cell(row = row, column = column)
max = 0
while cell.value != None or sheet.cell(row = row + 1, column = column).value != None:
row += 1
max = max + 1
cell = sheet.cell(row = row, column = column)
if max > max_row:
max_row = max
cell_top = sheet.cell(row = row, column = column + 1)
return max_row
To summarize the function, I move to the next column in the worksheet and then iterate through every cell in that sheet, keeping track of its height until there are no more columns. The catch about this function is that it has to find two empty cells in a row in order to fail the condition. In a previous version I used a similar approach, but only used one column and stopped as soon as I found a blank cell. I had to change it so the program would still run if the user forgot to fill out a column. This function works okay for a small table, but on a table with several hundred entries this makes the program run much slower.
My question is this: What can I do to make this more efficient? I know nesting a while loop like that makes a program take longer but I do not see how to get around it. I have to make the program as foolproof as possible, so I need to check more than one column to stop user errors from failing the program
This is untested, but every time I've used openpyxl, I iterate over all rows like so:
for row in active_worksheet:
do_something_to(row)
so you could count like:
count = 0
for row in active_worksheet:
count += 1
EDIT: This is a better solution: Is it possible to get an Excel document's row count without loading the entire document into memory?
Read-only mode works row-by-row on the source so you probably want to hook it into it. Alternatively, you could pass the cells of the of a worksheet into something like a Pandas matrix which has indices for empty cells.

jqgrid column chooser returns column order based on current order not original order

I want to persist the column order via localStorage which is working. However, the column chooser gives the order of the columns based on the current order not the original order.
Example:
3 column table where 0 is first, 1 == second, 2 is last column
0,1,2
choose column order to put last column in first, order becomes
2,0,1
choose column order again and put (original last column) back into last and order becomes:
1,2,0
because it resets the column numbers based on current order rather than ORIGINAL order. How to fix this?
onClickButton: function () {
$(this).jqGrid('columnChooser', {
done : function (perm) {
if (perm) {
localStorage["OD_Table_Col_Order"] = perm;
$(this).jqGrid("remapColumns", perm, true);
}
}
});
}
I think that you can find the solution if you would use remapColumns parameter of jqGrid as additional information.
One more way would be to save in localStorage the array of name properties of colModel items instead of the indexes perm.

Dojo DataGrid (EnhancedGrid) sorting issue

I have a DataGrid, created programmatically and loaded from ItemFileReadStore.
I want the first column of DataGrid always be sorted in descending order and disabled for user for sorting. Any other column should be available for sorting as a secondary sortable.
I don't want to give users such a powerful(complex and confusing) feature, as sorting by multiple columns, because there are too many columns in my grid.
So, it should be one sortable column for user and another one "already sorted unsortable" column in fact.
Does anyone know how can this be achieved?
Thanks.
To sort the first column add "sortInfo:-1" when you created your object.
To allow sorting the grid from any other columns but not the first you need to overwrite the function canSort.
To create you grid should now look like this .
dijit.grid.DataGrid({
canSort: function (sortInfo) {
if (Math.abs(sortInfo) == 1){
return false;
} else {
return this.inherited("canSort", arguments);
}
},
sortInfo: -1, .....
If you need to sort on more as one column you need dojox.grid.enhanced.plugins.NestedSorting.
http://dojotoolkit.org/reference-guide/1.7/dojox/grid/EnhancedGrid/plugins/NestedSorting.html

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