How can I maintain a variable via closure with define_method? - ruby

I am trying to create a macro "has_accessor_for", that accepts a symbol which is used as a parameter for an internal object that it uses (the Accessorizer object). The problem I am having is, when multiple modules do the has_accessors_for, the parameter (scope) ends up being stuck on the last value it was assigned to.
I added a puts prior to the define_method, which shows that it's scope1, and then scope2... But inside the define_method, it's scope2 always. I am looking for a way to basically encapsulate that variable, so that when it the first module calls has_accessor_for, anytime my_wut is called, it will be bound to scope1... and anytime my_bleah is called, it will be bound to scope2. But as I said, right now, both my_bleah and my_wut are bound to scope2-- If I change the order of the includes in MyModel, then they will both be bound to scope1.
class Accessorizer
def initialize(record, scope)
#record = record
#scope = scope
end
def value_for(key)
#record.send key
end
end
module Magic
def has_accessors_for(scope)
accessors = {}
puts "initial: #{scope}"
define_method :get_value_for do |key|
puts "inside method #{scope}"
accessor.value_for key
end
define_method :accessor do
accessors[:scope] ||= Accessorizer.new(self, scope)
end
end
end
module SomeAccessor
extend Magic
has_accessors_for :scope1
def my_wut
get_value_for :wut
end
end
module SomeOtherAccessor
extend Magic
has_accessors_for :scope2
def my_bleah
get_value_for :bleah
end
end
class MyModel
include SomeAccessor
include SomeOtherAccessor
attr_accessor :wut, :bleah
end
m = MyModel.new
m.wut = 'wut'
m.bleah = 'bleah'
m.my_bleah
m.my_wut
output:
initial: scope1
initial: scope2
inside method scope2
inside method scope2

Short answer: the problem is not with the closures.
Long answer:
define_method :get_value_for do |key|
puts "inside method #{scope}"
accessor.value_for key
end
On a given class there can only be one method called get_value_for - the second definition will overwrite the first.
It doesn't matter so much because you're call accessor in both cases, however that method suffers from the same problem - you define it twice and so the second definition overwrites the first and you end up with only one Accessorizer object.
I think you'll need to rethink your design here.

Related

Why can't a class method have the same name as a non-class method?

I'm learning ruby, and noticed that I cannot create a class method called puts:
class Printer
def initialize(text="")
#text = text
end
def puts
puts #text
end
end
The error is:
`puts': wrong number of arguments (given 1, expected 0)
My expectation was that I could use the code like this:
p = Printer.new("hello")
p.puts
It's not just because puts is a built-in method, though. For instance, this code also gives a syntax error:
def my_puts(text)
puts text
end
class Printer
def initialize(text="")
#text = text
end
def my_puts
my_puts #name
end
end
tldr; within the scope of the instance, the puts resolves to self.puts (which then resolves to the locally defined method, and not Kernel#puts). This method overriding is a form of shadowing.
Ruby has an 'implicit self' which is the basis for this behavior and is also how the bare puts is resolved - it comes from Kernel, which is mixed into every object.
The Kernel module is included by class Object, so its methods [like Kernel#puts] are available in every Ruby object. These methods are called without a receiver and thus can be called in functional form [such as puts, except when they are overridden].
To call the original same-named method here, the super keyword can be used. However, this doesn't work in the case where X#another_method calls X#puts with arguments when it expects to be calling Kernel#puts. To address that case, see Calling method in parent class from subclass methods in Ruby (either use an alias or instance_method on the appropriate type).
class X
def puts
super "hello!"
end
end
X.new.puts
P.S. The second example should trivially fail, as my_puts clearly does not take any parameters, without any confusion of there being another "puts". Also, it's not a syntax error as it occurs at run-time after any language parsing.
To add to the previous answer (https://stackoverflow.com/a/62268877/13708583), one way to solve this is to create an alias of the original puts which you use in your new puts method.
class Printer
alias_method :original_puts, :puts
attr_reader :text
def initialize(text="")
#text = text
end
def puts
original_puts text
end
end
Printer.new("Hello World").puts
You might be confused from other (static) programming languages in which you can overwrite a method by creating different signatures.
For instance, this will only create one puts method in Ruby (in Java you would have two puts methods (disclaimer: not a Java expert).
def puts(value)
end
def puts
end
If you want to have another method with the same name but accepting different parameters, you need to use optional method parameters like this:
def value(value = "default value")
end

Difference between #foo, self.foo, and foo?

class Artist
##song_count = []
attr_accessor :name, :songs
def initialize(name)
#name = name
#songs = []
end
def add_song(song)
#songs << song
end
def print_songs
songs.each {|song| puts song.name}
end
end
So in this example, it uses all two types, #songs and songs.
I'm having a hard time understanding why these are used, instead of using #songs for everything.
And then in this example,
def add_song(song)
self.songs << song
song.artist = self
##song_count +=1
end
Why is self.songs used instead of #songs?
Ok, so I forgot to say one more thing. In the first code snippet above,for method print_songs, why am I able to use songs.each instead of #songs.each? I was expected it to generate an error undefined songs.
Why is self.songs used instead of #songs
Using the method is more flexible. You're abstracting yourself from knowing how exactly it gets/stores data. The less you rely on implementation details, the easier it will be for you to change code later.
One small example, consider this implementation of songs
def songs
#songs ||= []
#songs
end
#songs may or may not have been assigned value prior to invocation of this method. But it doesn't care. It makes sure that #songs does have a sane default value. The concept is called "lazy initialization" and it's very tedious and error-prone to do if you use instance variables directly.
So, when in doubt, always use methods.
Difference between foo and #foo
Instance variables
Instance variables are defined within instance methods, and their names begin with #. Their value is only accessible within the specific object on which it was set. In other words, when we modify the value of an instance variable, the change only applies to that particular instance. Unlike local variables which are only available within the method where they were defined, instance variables are accessible by all methods within the object (instance methods of the class). Instance variables are the most commonly used type of variable in Ruby classes.
class Car
attr_reader :color
def set_color(color_receiverd_as_argument)
#color = color_receiverd_as_argument
end
end
car1 = Car.new
car1.color # Output: => nil
car1.set_color "black"
car1.color # Output: => "black"
car2 = Car.new
car2.set_color "silver"
car2.color # Output: => "silver"
In the example above, notice that:
Trying to access an instance variable before it's initialized will not raise an exception. Its default value is nil.
Changing the value of the color variable in one instance of the Car class does not affect the value of the same variable in the other instances.
Local variables
A local variable within a class is like any other local variable in Ruby. It is only accessible within the exact scope on which it's created. If defined within a method, it is only available inside that method.
class Car
def initialize
wheels = 4
end
def print_wheels
print wheels
end
end
c = Car.new
c.print_wheels # Output: NameError: undefined local variable or method `wheels'…
The self keyword
The self keyword is always available, and it points to the current object. In Ruby, all method calls consist of a message sent to a receiver. In other words, all methods are invoked on an object. The object on which the method is called is the receiver, and the method is the message. If we call "foo".upcase, the "foo" object is the receiver and upcase is the message. If we don't specify an object (a receiver) when calling a method, it is implicitly called on the self object.
Self keyword at class level
When used within a class but outside any instance methods, self refers to the class itself.
class Foo
##self_at_class_level = self
def initialize
puts "self at class level is #{##self_at_class_level}"
end
end
f = Foo.new # Output: self at class level is Foo
Self keyword at instance methods
When inside an instance method, the self keyword refers to that specific instance. In other words, it refers to the object where it was called.
class Meditation
def initialize
puts "self within an instance method is #{self}"
end
end
zazen = Meditation.new # Output: self within an instance method is #<Meditation:0x00000000ab2b38>
Notice that #<Meditation:0x00000000ab2b38> is a string representation of the zazen object, which is an instance of the Meditation class.

Lazy object in ruby

How can I create an opbjet that's totally lazy by itself? I have a block, and I want to pass around (as a dependency) the "current value" (at call time) of the block instead of the value at dependency injection time.
I can't actually pass around a lambda because all the services expect an actual object, so they won't send :call to them, just access them.
This (oversimplified) example might clarify the situation:
class Timer
def initialize(current_time)
#current_time = current_time
end
def print_current_time
print #current_time
end
end
class Injector
def current_time
# a lazy object that when accessed actually calls the lambda below
# every single time.
end
def current_time_lazy
-> { Time.now }
end
def instantiate(class_name)
# search for the class, look at the constructor and
# create an instance with the dependencies injected by
# name
# but to be simple
if class_name == "Timer"
Timer.new(current_time)
end
end
end
timer = Injector.new.instantiate("Timer")
timer.print_current_time # => some time
sleep 2
timer.print_current_time # => some *different* time
The actual situation implies passing around the current_user but depending on the situation the current user might change after those values are injected.
I would really appreciate any suggestion (even if for now I will carefully sort the dependency injection code so this doesn't happen, but I think it's pretty fragile)
This should help :
class Timer
def initialize(current_time)
#current_time = current_time
end
def print_current_time
puts #current_time
end
end
class LazyMaker < BasicObject
def self.instantiate(class_name, lambada)
if class_name == 'Timer'
::Timer.new(new(class_name, lambada))
end
end
def initialize(class_name, lambada)
#lambada = lambada
end
def method_missing(method, *args)
#lambada.call.send(method, *args)
end
end
timer = LazyMaker.instantiate('Timer', -> { Time.now })
timer.print_current_time # some time
sleep 2
timer.print_current_time # some other time
I'm trying to use delegation to implement it, so that I can call the block first, get a new object and redirect the method call to it. Why this way ? Because basically, accessing an object to do something means to call a method on it. For instance, in print #current_time, it sends #current_time.to_s.
But since almost all objects will have a few methods inherited from standard base classes in Ruby like Object, LazyMaker also has methods like to_s. So I thought of making just the LazyMaker inherit from BasicObject, which is a blank class. So almost all of the methods get delegated.
But yeah, there might be another way to do this.

Binding method to instance

Is there a way to bind an existing method to an existing instance of an object if both the method and the instance are passed as symbols into a method that does that if the instance is not a symbol?
For example:
def some_method
#do something
end
some_instance = Klass.new(something)
def method_that_binds(:some_method, to: :some_instance)
#how do I do that?
end
Your requirements are a little unusual, but it is possible to do this mostly as you say:
class Person; end
harry = Person.new
barry = Person.new
def test
puts 'It works!'
end
define_method :method_that_binds do |a_method, to|
eval(to[:to].to_s).singleton_class.send(:define_method, a_method, &Object.new.method(a_method))
end
method_that_binds :test, to: :harry
harry.test
# It works! will be sent to STDOUT
barry.test
# undefined method 'test'
This doesn't actually use a named parameter, but accepts a hash with a to key, but you can see you can call it in the way you want. It also assumes that the methods you are defining are defined globally on Object.
The API you want doesn't easily work, because you have to know from which scope you want to access the local variable. It's not quite clear to me why you want to pass the name of the local variable instead of passing the content of the local variable … after all, the local variable is present at the call site.
Anyway, if you pass in the scope in addition to the name, this can be accomplished rather easily:
def some_method(*args)
puts args
puts "I can access some_instance's ivar: ##private_instance_var"
end
class Foo; def initialize; #private_instance_var = :foo end end
some_instance = Foo.new
def method_that_binds(meth, to:, within:, with: [])
self.class.instance_method(meth).bind(within.local_variable_get(to)).(*with)
end
method_that_binds(:some_method, to: :some_instance, within: binding, with: ['arg1', 'arg2'])
# arg1
# arg2
# I can access some_instance's ivar: foo
As you can see, I also added a way to pass arguments to the method. Without that extension, it becomes even simpler:
def method_that_binds(meth, to:, within:)
self.class.instance_method(meth).bind(within.local_variable_get(to)).()
end
But you have to pass the scope (Binding) into the method.
If you'd like to add a method just to some_instance i.e. it's not available on other instances of Klass then this can be done using define_singleton_method (documentation here.)
some_instance.define_singleton_method(:some_method, method(:some_method))
Here the first use of the symbol :some_method is the name you'd like the method to have on some_instance and the second use as a parameter to method is creating a Method object from your existing method.
If you'd like to use the same name as the existing method you could wrap this in your own method like:
def add_method(obj, name)
obj.define_singleton_method(name, method(name))
end
Let's say we have a class A with a method a and a local variable c.
class A
def a; 10 end
end
c = '5'
And we want to add the method A#a to c.
This is how it can be done
c.singleton_class.send :define_method, :b, &A.new.method(:a)
p c.b # => 10
Explanations.
One way to add a method to an object instance and not to its class is to define it in its singleton class (which every ruby object has).
We can get the c's singleton class by calling the corresponding method c.signleton_class.
Next we need to dynamically define a method in its class and this can usually be accomplished by using the define_method which takes a method name as its first argument (in our case :b) and a block. Now, converting the method into a block might look a bit tricky but the idea is relatively simple: we first transform the method into a Method instance by calling the Object#method and then by putting the & before A.new.method(:a) we tell the interpreter to call the to_proc method on our object (as our returned object is an instance of the Method, the Method#to_proc will be called) and after that the returned proc will be translated into a block that the define_method expects as its second argument.

How do I make a Ruby method that lasts for the lifetime of a block?

Inside the body of a class, I'd like to pass a block to a method called with. For the lifetime of the block, I would like a with_value method to be available.
Otherwise, everything inside the block should behave as if it were outside the block.
Here's an example:
class C
extend M
with "some value" do
do_something_complicated
do_something_complicated
do_something_complicated
end
end
We can almost get this with:
module M
def with(str, &block)
Object.new.tap do |wrapper|
wrapper.define_singleton_method :with_value do # Here's our with_value
str # method.
end
end.instance_eval &block
end
def do_something_complicated # Push a value onto an
(#foo ||= []).push with_value # array.
end
end
but there's a problem: since we're evaluating the block passed to with inside the context of a different object, do_something_complicated isn't available.
What's the right way to pull this off?
This will make with_value available only within the block. However, _with_value will be defined within or outside of the block.
module M
def _with_value
...
end
def with(str, &block)
alias with_value _with_value
block.call
undef with_value
end
...
end
I cannot tell from the question whether this is a problem. If it is a problem, you need to further describe what you are trying to do.
Basically, the idea is to use method_missing to forward method calls from the dummy class to the calling class. If you also need to access instance variables, you can copy them from the calling class to your dummy class, and then back again after the block returns.
The Ruby gem docile is a very simple implementation of such a system. I suggest you read the source code in that repository (don't worry, it's a very small codebase) for a good example of how DSL methods like the one in your example work.
Here is a way that is closer to your attempt:
module M
def with(str, &block)
dup.tap do |wrapper|
wrapper.define_singleton_method :with_value do
...
end
end.instance_eval &block
end
...
end
dup will duplicate the class from where with is called as a class method.

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