How to achive this route :
/test
/test/page-2
I want to pass "2" as parameter and if we are in page 1 just show /test not /test/page
I agree with the above comment, why not just use the page number alone as a parameter?
Routes:
Route::get('test', ['uses' => 'TestController#index']);
Route::get('test/page/{pageNumber?}', ['uses' => 'TestController#index']);
TestController method:
Assuming your views are in a directory tests and are named testPage-1, testPage-2, testPage-3, etc...
public function index($pageNumber = 1){
return View::make('tests.testPage-'.$pageNumber);
}
Related
I am new in Laravel using version 5.8
I do not want to set route manually for every controller.
What i want is that if i give any url for example -
www.example.com/product/product/add/1/2/3
www.example.com/customer/customer/edit/1/2
www.example.com/category/category/view/1
for the above example url i want that url should be treated like
www.example.com/directoryname/controllername/methodname/can have any number of parameter
I have lots of controller in my project so i want this pattern should be automatically identified by route and i do not need to specify manually again and again Directory Name, Controller , method and number of arguments(parameter) in route.
try this:
Route::get('/product/edit/{id}',[
'uses' => 'productController#edit',
'as'=>'product.edit'
]);
Route::get('/products',[
'uses' => 'productController#index',
'as'=>'products'
]);
in the controller:
public function edit($id)
{
$product=Product::find($id);
return view('edit')->with('product',$product);
}
public function index()
{
$products=Product::all();
return view('index')->with('products',$products);
}
in the index view
#foreach($products as $product)
Edit
#endforeach
in the edit view
<p>$product->name</p>
<p>$product->price</p>
I am new in laravel framework now I'm working fully developed website using Laravel. I have changed blog url form {id} to {id}/{name} like www.example.com/news/203 to www.example.com/news/203/title. It's working fine. but i need to redirect if old url enter into current url opened from cache or something else.
Route::get('{id}/{name}', 'EventController#show')
->name('events-detail')
->where([
"id" => "[0-9]+"
]);
You can define another route in which you will find the model by id and use its title to redirect the user to the new route:
Route::get('{id}', function ($id) {
$model = Model::findOrFail($id);
return redirect()->route('events-detail', ['id' => $id, 'name' => $model->name]);
});
Note that you have to change Model with the class you use for this route.
Create 2 routes and add below code.
Route::get('{id}/{name}', function () {
//new URL as you want
return redirect()->route({id}/{name});
});
Route::get('{id}', function () {
//as you want for simple URL
});
I'm assuming the name portion is not really used at all, except for SEO/friendlier urls. If this is the case, just make the name parameter optional, and there will be no need for a redirect:
Route::get('{id}/{name?}', 'EventController#show')
->name('events-detail')
->where([
"id" => "[0-9]+"
]);
This route will match /203 and /203/news-title.
My ultimate objective is to limit accesses to the group of routes by validating permissions provided to the user.
These target 'group of routes' have ONE COMMON PARENT GROUP and may have zero or more sub-groups, such that, if access to these target 'group of routes' is permitted/accessible to the user then, all its sub-route groups are also accessible to the user.
To achieve this, I believe I need to differentiate these target group of routes by any uniqueString/parameter in middleware, which is indeed answered here.
But, I want to generalize this further, by applying middleware to common SINGLE PARENT GROUP of all these target group of routes and identify these target group of routes by any means in the middleware.
So, my question is how do I identify/differentiate these target group of routes in the middleware? Is there any way to do so?
Sample Code of what I am trying to describe:
Route::group(['prefix' => 'singleParent','middleware' => 'permissionMiddleware'], function (){
Route::group(['prefix' => 'target-group-1', 'groupUniqueString' => 'tsg1'], function (){
Route::group(['prefix' => 'sub-group-1.1'], function (){
});
Route::group(['prefix' => 'sub-group-1.2'], function (){
});
});
Route::group(['prefix' => 'target-group-2', 'groupUniqueString' => 'tsg2'], function (){
Route::get('route-1','Controller#method-of-Route1');
});
});
So, to specify a route group in your middleware to handle some actions, you can do it in this way :
Route::group(['prefix' => 'singleParent','middleware' => 'permissionMiddleware'], function (){
Route::group(['prefix' => 'target-group-1', 'as' => 'tsg1.'], function (){
//...
});
});
This will generate route names with the prefix : tsg1
Now in your middleware you can do like this to get the route group :
function getCurrentRouteGroup() {
$routeName = Illuminate\Support\Facades\Route::current()->getName();
return explode('.',$routeName)[0];
}
Updated
and to check :
if ($request->route()->named('name')) {
//
}
return $next($request);
Or in another approach you can achieve :
To get the prefix of a route group you can do something like this :
$uri = $request->path();
// this will give you the url path like -> if this is the url :
// http://localhost:8000/foo/bar you will get foo/bar
And then :
$prefix = explode('/',$uri)[0];
// and you will get 'foo'
Let me know if this works for you.
Let's say I have a function in my controller which retrieves users looking something like this:
public function index($category) {
// retrieve users depending on category or all
}
Now is there a way to make named routes to include the function parameter like so:
Route::get('passengers', 'Controller#index(1)')->name('passengers');
Route::get('attendees', 'Controller#index(2)')->name('attendees');
This way they can all use the same function
No you can not pass a parameter the action name, and there is a problem in you routing logic :
Route::get('/{categoryName}', 'Controller#index')->name('index');
And in the controller you will for example get the category by name like this :
public function index($categoryName) {
$category = Category::where('name', $categoryName)->first();
// use $ category as you please ;)
}
In the blade :
route('index', ['categoryName' => $category->name])
If the named route defines parameters, you may pass the parameters as the second argument to the route function. The given parameters will automatically be inserted into the URL in their correct positions
https://laravel.com/docs/5.5/routing#named-routes
So, use route() helper like this:
route('passengers', ['category' => 1])
Then you need to add {category} to the route. Also, it's really better to use show() instead of index() here. So, your route will look like this:
Route::get('passengers/{category}', ['as' => 'passengers', 'uses' => 'Controller#show']);
Yes, you can define the param in the url like so:
Route::get('passengers/{yourParam}', 'Controller#index')->name('passengers');
View in docs
Route::get( '{category}', [ 'as' => 'users', 'uses' => 'Controller#index' ]);
Remember to add this route at the end of your routes file in order to not to collide with any other route.
Now in your controller
use Illuminate\Http\Request;
public function index(Request $request)
{
$category = $request->query('category');
// $category will be passengers, attendees, etc
}
Your routes will be
/passengers can be accessed as route('users', ['category' => 'passengers'])
/attendees can be accessed as `route('users', ['category' => 'attendees'])
I have a multilingue website created using Laravel 4, and I have lot of pages such as : "policy, "terms", "how it works" in database, so to access thoses pages I use this route:
// Group by locale
Route::group(
array( 'prefix' => $locale ), function () {
Route::get('{slug}', array('uses' => 'PageController#show','as' => 'pages.show');
// Website routes
});
And then I search for the given slug and the current locale.
My is problem is that I can't add for example a page link in the footer because the slug is dynamic. so is there any solution to resolve that.
It's make a sense ?
Thanks
You are already catching the slug in
Route::get('{slug}', array('uses' => 'PageController#show','as' => 'pages.show');
part. all you need is to inject this slug into controller like this:
class PageController extends BaseController {
public function show($slug)
{
return 'showing slug ' . $slug;
}
}
and whatever value the route receive for {slug} part in route laravel will automatically inject that value into the controller.