Windows Forms - Randomize BackColor - Powershell - windows

Question

I'm making a GUI using Windows Forms and I'd like to add a feature where you can randomize the background color of the form. Please be noted that I intend to keep the code fully written in Powershell.
Here's a snippet of the code:
[void] [System.Reflection.Assembly]::LoadWithPartialName("System.Drawing")
[void] [System.Reflection.Assembly]::LoadWithPartialName("System.Windows.Forms")
$objForm = New-Object System.Windows.Forms.Form
$choochoo = New-Object System.Windows.Forms.Button
And here is the code that I need help with:
$choochoo.Add_Click({$objForm.BackColor = Random})
Obviously 'Random' does not work in this example and is only being used as a placeholder.
I suppose I need to generate random values using the time but would appreciate a more concrete code. Thanks in advance.

Answer 1

Been learning Powershell recently. Playing around came up with a solution for this today if anyone wants to do all possible random colors (I know this thread is old).
Add-Type -AssemblyName System.Windows.Forms
$Form = New-Object system.Windows.Forms.Form
$Form.Text = "Sample Form"
$Label = New-Object System.Windows.Forms.Label
$Label.Text = "This is a Form."
$Form.Controls.Add($Label)
function colorful{
$c1 = '';
$c2 = '';
foreach( $digit in (1..6 | foreach{ '{0:X}' -f (Get-Random -Max 16) })){
$c1 = "$c1"+"$digit";}
foreach( $digit in (1..6 | foreach{ '{0:X}' -f (Get-Random -Max 16) })){
$c2 = "$c2"+"$digit";}
$Form.BackColor = "#FF"+$c1;
$Form.ForeColor = "#FF"+$c2;
};
colorful;
$Form.ShowDialog();

Answer 2

You'll want to be using an instance of System.Random to select from the possible static properties of System.Drawing.Color.

Answer 3

Got it to work with this if someone needs this too:
function RandomBacklight {`
$random = New-Object System.Random
switch ($random.Next(9)) {
0 {$objForm.BackColor = "LightBlue"}
1 {$objForm.BackColor = "LightGreen"}
2 {$objForm.BackColor = "LightPink"}
3 {$objForm.BackColor = "Yellow"}
4 {$objForm.BackColor = "Orange"}
5 {$objForm.BackColor = "Brown"}
6 {$objForm.BackColor = "Magenta"}
7 {$objForm.BackColor = "White"}
8 {$objForm.BackColor = "Gray"}
}
}
$choochoo.Add_Click({RandomBacklight})