I followed the suggestions from user ehp in order to build a lightweight messaging-system:
https://stackoverflow.com/a/18717864/1084315
Users: id | username
Messages: id | from | content
user_messages: user_id | message_id
class User extends Eloquent {
public function messages()
{
return $this->belongsToMany('Message');
}
public function sent_messages()
{
return $this->hasMany('Messages', 'from');
}
}
class Message extends Eloquent {
public function from()
{
return $this->belongsTo('User', 'from');
}
public function to()
{
return $this->belongsToMany('User');
}
}
I create a message like this:
User::find(2)->messages()->create(array('text'=>'this is a message from admin to someone', 'from'=>'1');
Now I need to find / get every Message from a specific user to a specific user.
But in this example only the 'from' IDs are stored in the 'messages' table directly.
I can not even access the pivot of any Message by using
User::find(1)->sent_messages()->get();
What are best practices for collecting messages between one and another user?
Any help highly appreciated
First of all, I think there's a small typo:
public function sent_messages() {
return $this->hasMany('Messages', 'from');
}
This should probably be:
public function sent_messages() {
return $this->hasMany('Message', 'from');
}
Now, if you're looking to get all the messages sent from one user to another, what about this? Untested, but placing a constraint on the to relationship should do the trick.
$messages_from_A_to_B = Message::where('from', $UserA->id)->whereHas('to', function($q) use ($UserB) {
$q->where('user_id', $UserB->id);
})->get();
On a side note, I'm assuming that you specifically require that a user can send a message to more than one user? Else the following table structure seems like it would be easier:
users: id
messages: from | to
And then you just need:
class User extends Eloquent {
public function messages() {
return $this->hasMany('Message', 'to');
}
public function sent_messages() {
return $this->hasMany('Message', 'from');
}
}
class Message extends Eloquent {
public function from() {
return $this->belongsTo('User', 'from');
}
public function to() {
return $this->belongsTo('User', 'to');
}
}
$messages_from_A_to_B = Message::where('from', $UserA->id)->where('to', $UserB->id)->get();
Related
I have order and return tables which have a created_by and accepted_by field where the corresponding user id is stored.
But now I would like to have multiple types for created_by and accepted_by instead of only user type. Assume a company could also create or accept the order/return.
I was thinking of a polymorphic one to many relationship.
Let’s name this table participants.
Something like:
ID
created
participantable_id
participantable_type
1
1
1
user
2
0
11
company
This works either for order or return but not both.
Is it practically to add extra colums to participants like trx_id and trx_type (order/return)?
How would the realtionships looks like to perform queries like:
$order->createdBy // should give me either user or company model
$order->acceptedBy
$return->createdBy
$return->acceptedBy
Or is there even a cleaner solution I am overlooking?
Thanks!
It would be 1:N polymorphic relationships so no need for an extra table. The structure can be found in the documentation
Your Order and Return model need to have the columns created_by_id, created_by_type, accepted_by_id, accepted_by_type.
______ (1) Company
/
Order (N) ----<
\______ (1) User
_____ (1) Company
/
Return (N) ----<
\_____ (1) User
class Order extends Model
{
public function created_by()
{
return $this->morphTo(__FUNCTION__, 'created_by_type', 'created_by_id');
}
public function accepted_by()
{
return $this->morphTo(__FUNCTION__, 'accepted_by_type', 'accepted_by_id');
}
}
class Return extends Model
{
public function created_by()
{
return $this->morphTo(__FUNCTION__, 'created_by_type', 'created_by_id');
}
public function accepted_by()
{
return $this->morphTo(__FUNCTION__, 'accepted_by_type', 'accepted_by_id');
}
}
class User extends Authenticatable
{
public function created_orders()
{
return $this->morphMany(Order::class, 'created_by');
}
public function accepted_orders()
{
return $this->morphMany(Order::class, 'accepted_by');
}
public function created_returns()
{
return $this->morphMany(Return::class, 'created_by');
}
public function accepted_returns()
{
return $this->morphMany(Return::class, 'accepted_by');
}
}
class Company extends Model
{
public function created_orders()
{
return $this->morphMany(Order::class, 'created_by');
}
public function accepted_orders()
{
return $this->morphMany(Order::class, 'accepted_by');
}
public function created_returns()
{
return $this->morphMany(Return::class, 'created_by');
}
public function accepted_returns()
{
return $this->morphMany(Return::class, 'accepted_by');
}
}
I've 2 tables
Users table
id
name
...
Chats table
id
from_id // fk - id on users, the user sent the message
to_id // fk - id on users, intended user
message_body
Now, I'm trying to set up One to Many relation where user has many chat messages but a chat message has two user. from and to user
How can I define this relationship?. I have to user eager loading.
I tried to use Compoships but it didn't work.
My code
User Model
public function chats() {
return $this->hasMany(Chat::class, ['from_id', 'to_id'], 'id');
}
Chat Model
public function user() {
return $this->belongsTo(User::class, ['from_id', 'to_id'], 'id');
}
public function chats() {
return $this->hasMany(Chat::class, 'from_id', 'id') + $this->hasMany(Chat::class,'to_id','id');
}
public function userFrom() {
return $this->belongsTo(User::class, 'from_id', 'id');
}
public function userTo() {
return $this->belongsTo(User::class, 'to_id', 'id');
}
Why don't you do something like that?
On your User model, set up two relationships like this:
public function chatsFrom() {
return $this->hasMany('App\Chat', 'from_id');
}
public function chatsTo() {
return $this->hasMany('App\Chat', 'to_id');
}
Then, on your Chat model, also set up two relationships, one to from and another to to, both referencing a User model. Like this:
public function fromUser() {
return $this->belongsTo('App\User', 'from_id');
}
public function toUser() {
return $this->belongsTo('App\User', 'to_id');
}
This way, you can access the relationships using something like this:
$user->chatsFrom();
$user->chatsTo();
$chat->fromUser();
$chat->toUser();
I'm having a problem while creating a Forum with Laravel 5.7
I want to have these three models: User, Category, Thread and Post. The problem is that i don't how to define one of my Thread model relationships.
This model has a creator:
public function creator()
{
return $this->belongsTo('App\User');
}
...it has a series of replies:
public function replies()
{
return $this->hasMany('App\Post');
}
...and, finally, participants:
public function participants()
{
return $this->hasManyThrough('App\User', '???')
}
I should get the thread participants through its replies but it don't know if i should put the post class like this:
public function participants()
{
return $this->hasManyThrough('App\User', 'App\Post')
}
...or if this is an special case with some considerations. Any help?
Since posts acts as a pivot table, a BelongsToMany relationship is the better choice here:
public function participants()
{
return $this->belongsToMany('App\User', 'posts');
}
I have a chat app, and I need to filter those user conversations that have attachment[s] in the groups last message, by using eloquent ORM. I have following DB tables/models:
Groups & Users. Relation is N-N between them, so there's a pivot table between groups and users, named group_user. Although this table has been expanded with some extra fields, as a result group_user have it's own model now.
Messages. Relations are 1-N from both groups and users.
Attachments. Relation is 1-N from messages.
The algorithm of this filtering isn't the problem - take user (because I need specific users groups) and his groups, find all group messages, sort them by date of creation in descending order and take the top one. And then check whether this message have any records in 'attachments' table. Obivously I do have all the relations defined in the respective Models. Right now I have this code, but it returns all groups that have attachments in any of the messages.
Also, I need to sort the query by the last message 'created_at' date.
return $user->user_groups()->whereHas('group', function($query) {
$query->whereHas('messages', function ($query) {
$query->whereHas('attachments');
});
})->with('group')->latest()->paginate($this->group->getPerPage());
Edit.
class User
{
public function messages()
{
return $this->hasMany('App\Models\Message');
}
public function user_groups()
{
return $this->hasMany('App\Models\GroupUser');
}
}
class Message
{
public function attachments()
{
return $this->hasMany('App\Models\Attachment');
}
public function author()
{
return $this->belongsTo('App\Models\User');
}
public function group()
{
return $this->belongsTo('App\Models\Group');
}
}
class Attachment
{
public function message()
{
return $this->belongsTo('App\Models\Message');
}
}
class GroupUser
{
public function user()
{
return $this->belongsTo('App\Models\User');
}
public function group()
{
return $this->belongsTo('App\Models\Group');
}
}
class Group()
{
public function messages()
{
return $this->hasMany('App\Models\Message');
}
public function group_users()
{
return $this->hasMany('App\Models\GroupUser');
}
}
Add a groups relationship to your User model:
public function groups() {
return $this->belongsToMany('App\Models\Group');
}
Then try this:
$user->groups()
->select('groups.*')
->join('messages', function($join) {
$join->on('groups.id', 'messages.group_id')
->where('created_at', function($query) {
$query->selectRaw('max(created_at)')
->from('messages')
->where('group_id', DB::raw('groups.id'));
});
})
->whereExists(function($query) {
$query->from('attachments')
->where('attachments.message_id', DB::raw('messages.id'));
})
->orderByDesc('messages.created_at')
->paginate($this->group->getPerPage());
I'm trying to setup some simple favoriting for my app using Laravel/Jenssegers MongoDB
I have two models:
class Item {
public function favorites()
{
return $this->hasMany('App\Models\User', 'favorites');
}
}
class User {
public function favorites()
{
return $this->hasMany('App\Models\Item', 'favorites');
}
}
So an item can have many users and a user can have many items or "favorites".
When I try to run a simple query like:
Item::with('favorites')->get();
The relationship for favorites is there but an empty array.
The favorites table is simple and just has three columns:
_id, item_id, user_id
I've also tried using embedsMany with no luck:
return $this->embedsMany('App\Models\User', 'favorites');
I've also tried every combination of parameters.
return $this->embedsMany('App\Models\User', 'favorites', 'building_id', 'user_id');
return $this->embedsMany('App\Models\User', 'favorites', 'user_id', 'building_id');
return $this->hasMany('App\Models\User', 'favorites', 'building_id', 'user_id');
return $this->hasMany('App\Models\User', 'favorites', 'user_id', 'building_id');
Strange results when using:
return $this->hasMany('App\Models\User', 'favorites', 'building_id', 'user_id');
Only in this situation it returns ALL users, even though favorites has only one record.
Also trying to debug using getQueryLog just gives me an empty array at all times.
print_r(\DB::connection('mongodb')->getQueryLog());
I've done this using mysql and have never had issues. So not really sure where the issues are coming from.
Can you try these instead, I know its the same thing but might do the trick :
use App\User;
use App\Item;
class Item {
public function favorites()
{
return $this->hasMany('User');
}
}
class User {
public function favorites()
{
return $this->hasMany('Item');
}
}
class Favourite {
public function users()
{
return $this->belongsTo('User');
}
public function items()
{
return $this->belongsTo('Item');
}
}
Also add inverse of the above relations like: belongsTo.
and try this query then :
//Just for testing purpose, if raw query returns right result
$items = DB::table('items')
->join('favorites','items.id','=','favorites.id')
->get();