Yo all,
I have a users relationship pivot db table as follows:
id | user_id | relation_id | relationship
1 4 2 tutor
1 4 3 parent
The table relates user with one-and-other for various reasons.
I am trying to get the relationship column within the $user. I have managed to pull the related users
details no problem - $user->relations.
However, I just need to get the relationship - eg. Tutor or parent.
I am getting no dice with $relative->pivot->relationship
Any ideas? Thanks for taking the time to help.
#foreach($user->relations as $index=>$relative)
{{ $relative->first_name . ' ' . $relative->last_name}}
{{ $relative->pivot->relationship }}
#endforeach
To access ->pivot->whatever you need to add withPivot('whatever') to the relation definition:
public function relations()
{
return $this->belongsToMany('Relation')->withPivot('relationship');
}
Note: I wouldn't use relations and Relation names here, since it's misleading AND it may collide with Eloquent\Model stuff.
Related
I have many to many relationship between an actor and a theater_play.
How to add his stage name when making the connection? I have a table for the actor, a table for theater_play and a table for the connection of many to many call actor_theater_play where I connect the IDs.
My goal is to display John Doe is know for his roles: and then to list Name of Play - Character Name.
In your theatre play relation on your Actor model, make sure you use the ->withPivot() method to specify which pivot fields you want attached with the relation:
public function theaterPlays() {
return hasMany(\App\TheaterPlay::class)->withPivot('stage_name');
}
You will then able able to access in your list (Laravel blade example):
#foreach($actor->theater_plays as $theater_play)
{{ $theater_play->name . ' - ' . $theater_play->stage_name }}
#endforeach
I currently have two tables in the DB and a pivot table to join them when I need to do a belongsToMany lookup. The basic example is one DB table is 'teams' and the other is 'members'. I can utilize the belongsToMany method on both the team and members model to pull their relationship with each other. A team can have many members, and a member can belong to many teams.
public function teams()
{
return $this->belongsToMany(Team::class);
}
public function members()
{
return $this->belongsToMany(Member::class);
}
Pivot: team_member
team_id | member_id
---------------------
1 | 1
2 | 1
3 | 2
1 | 2
How can I expand on that pivot table to include a type of member for each team? For example, member1 is a leader on team1. member1 is an assistant on team2. member1 is a generic member on team3... and so on. Can I just add a column to that same pivot table? Would it be the membertype_id? How can I relate that to another model/table?
This is pretty common, and Laravel handles it already. Add extra columns to the pivot table and expand your relationships to use withPivot():
public function teams(){
return $this->belongsToMany(Team::class)->withPivot(["teamRole", ...]);
}
Then accessing is as simple as:
$user = \App\User::with(["teams"])->first();
$team = $user->teams->first();
$teamRole = $team->pivot->teamRole;
See the Documentation for more information:
https://laravel.com/docs/5.6/eloquent-relationships
To answer the second part, which is essentially a "Triple Pivot", that requires extra functionality. See
Laravel - Pivot table for three models - how to insert related models?
for more information, and an associated Package (by the answerer on that question, not maintained, but good for an example)
https://github.com/jarektkaczyk/Eloquent-triple-pivot
I'm trying to achieve something that is similar to Laravel's hasManyThrough, but I'm not sure my DB is set up appropriately or I'm just missing something.
I am trying to display a page for admins to show all of the sites we support. I would like to have a simple column that shows a distinct count of how many customers are attached to each site. To do this, I was going to go through the orders table and retrieve a distinct list of users, then simply use the ->count() method inside my view.
Here is my DB setup (simplified):
sites table (primary key: 'id'):
id | ...
users table (primary key: 'id'):
id | first_name | last_name | ...
orders table (primary key: 'order'):
id | order | user_id | site_id | ....
Site model:
public function customers()
{
return $this->hasManyThrough('App\User', 'App\Order', 'site_id', ' id')->distinct();
}
I realize right away that the key difference between my DB setup and the documentation is I do not have an order_id in my users table, but it doesn't make sense that I do since a user can have many orders.
It is worth noting: I also have a table user_orders. I'm not sure if I should be using that instead. user_orders has the following set up:
id | user_id | order
You can see that it is simply an intermediate table to hold connections between users and orders (remember order is the PK in orders, not id).
So, can anyone help me understand what I am doing wrong?
You could get away with a Join. I give you this sample code to guide you
public function customers()
{
return $this->hasMany('App\Order')
->leftjoin('users', 'users.id', 'orders.user_id')
->groupBy('users.id'); //Is this needed?
//Above code will return you a collection of Order though, but with the user data.
//Let's try using the User model
return App\User::whereHas('orders', function($query) use ($this->id) {
$query->where('site_id', $this->id);
})->get();
}
I have a database composed by users, users_child, child.
I create a ONE to MANY relationship between Users and users_child, then i create a relationship between users_child and child. Now the below code work:
$test = users::find(1)->users_child
$test1= users_child::find(1)->child
Now i want to know if is possible to create a single row that link the three table like this:
$test = users::find(1)->users_child->child
I create the relationship in the model but in the db i don't create Foreign Key, it's a problem? on the model i specify the field for link table.
http://laravel.com/docs/5.1/eloquent-relationships#querying-relations
You can chain relationships like this:
$user = Users::with("users_child.child")->where("id",1)->first();
Each point will mean a relation stored in the first.
Out of users users_child will be taken and out of users_child child will be taken. (Relations)
foreach($user->users_child as $user_child) {
$user_child->child;
}
will get you the data you need.
This question is best illustrated by an example:
users
id
name
roles
id
name
role_user
user_id
role_id
rank_id
group_id
...
ranks
id
name
groups
id
name
I can easily eager load a users table by specifying the following relationship in my User.php model:
public function roles() {
return $this->belongsToMany('Role');
}
Which will output the table below when calling User::with('roles'):
User | Role
-------------
Jon | Admin
Jan | Mod
However I have no idea how to extend this to include:
User | Role | Rank | Group
-----------------------------
Jon | Admin | Boss | Blue
Jan | Mod | Minion | Red
What I've tried doing User::with('roles', 'ranks', 'groups') but that is certainly wrong since I'm telling Laravel there are rank_user and group_user intermediate tables too but there aren't. What is the correct way?
PS: I know it's better to separate the ranks and groups into their own relationship/pivot tables, this is simply an example.
EDIT: Closest example I can find for this: https://github.com/laravel/framework/issues/2619#issuecomment-38015154
You can just treat your model's relations methods as ordinary queries and build upon them:
public function roles() {
return $this->belongsToMany('Role')
->join('role_user', 'role_user.role_id', '=', 'roles.id')
->join('ranks', 'ranks.id', '=', 'role_user.rank_id')
->join('groups', 'groups.id', '=', 'role_user.group_id');
}
Relations queries like the above are not so intuitive to understand when they get too complex, so it may be better to rethink database design, but in theory it's possible to manipulate them.