I want to display the select columns options outside of the grid table, by using clone method, so please help me on this one. Thank you.
Related
and thanks, I am creating a Suitelet in SS2, I need to filter across three selects on the client side. I was able to load the initial drop-down using 'insertSelectOption' but I cannot select any item. When I choose one it goes back to the blank option. I can't figure out what I am doing wrong. The entire list is loading in the select fine. Any help would be greatly appreciated.
thanks
You can only change the dependent dropdown lists via custom code-added form fields. I'm sure it would help if you were to post your code that you're trying to implement.
Hope you are doing well. Kindly help me out here. I am using Yajra data tables in laravel 5.3. I need to implement UI sorting ( drag and drop ), like when showing some records in datatable, i want to change the order of records and then save it back to data base through drag and drop. If there is any package or some useful links, kindly let me know. Thank you.
I don't know much about Yajra, but it looks like it makes Jquery datatables (https://datatables.net/) that seem quite sortable already.
For the drag and drop you might want to have a look at jquery sortable (https://johnny.github.io/jquery-sortable/)
Hope that helps you find the way!
Please check with below link,
http://web1.cs-computing.com/apps/demo/bootstrap/bootstrap_demo.nsf/dnd.xsp
I had tried this and it is working with me. Multiple options are there with drag, drop and sort.
I am working on columns drag nad drop its working fine and the new order is also saved in the database but when i again opens the page it shows the pervious order so, how cani achive this.
Thanks in advance
You can save remapColumns parameter of jqGrid and use the remapColumns method to restore the order of the columns. I recommend you to read the ansewer with the demo which show how to do this by saving the information in the localStorage. You can do the same, but save the information in the database.
I have a jqgrid that has several columns including a checkbox column that indicates if an item is selected.
Underneath that I have a dropdown menu and a text box. The idea is that each item in the dropdown menu is a column in the jqgrid. Then all I need to do is modified all of the checked rows with the contents of the text box for that column. So a quick mass update mechanism if you will.
The problem is, is that I can't figure out how to update a specific cell. Any tips or documentation that can help me? Thanks!
You can use for example setRowData (see jqGrid documentation) or setCell to update the data in the grid. The functions getCol, getCell or getRowData could help you the examine the row data. Another old answers: this and this could be helpful if you decide to search data in the grid with respect of jQuery.
Here's the "answer" I came up with to my problem. I wanted to edit only rows that were editable. Using setCell would overwrite my editable field with a non-editable one. So I looked at the HTML for a given row while it is in the edit state and passed that into the 'setCell' method. It feels 'hackish' though and if someone knows a better way, I'm all ears.
I have looked around and have yet to find a decent answer.
I wish to add a new row into my grid from my own custom button, without using their add buttom or edit forms.
Something like:
$("#grid").jqGrid('insert',{"id","col1","col2"});
I want to be able to programatically insert new rows and not have to use their form.
Any help would be greatly appreciated.
Regards,
Byron
Why do you not use addRowData method (see http://www.trirand.com/jqgridwiki/doku.php?id=wiki:methods)? Do you want do something more as to add the data?