Write and read from a fifo from two different script - bash

Question

I have two bash script.
One script write in a fifo. The second one read from the fifo, but AFTER the first one end to write.
But something does not work. I do not understand where the problem is. Here the code.
The first script is (the writer):
#!/bin/bash
fifo_name="myfifo";
# Se non esiste, crea la fifo;
[ -p $fifo_name ] || mkfifo $fifo_name;
exec 3<> $fifo_name;
echo "foo" > $fifo_name;
echo "bar" > $fifo_name;
The second script is (the reader):
#!/bin/bash
fifo_name="myfifo";
while true
do
if read line <$fifo_name; then
# if [[ "$line" == 'ar' ]]; then
# break
#fi
echo $line
fi
done
Can anyone help me please?
Thank you

Answer 1

Replace the second script with:
#!/bin/bash
fifo_name="myfifo"
while true
do
if read line; then
echo $line
fi
done <"$fifo_name"
This opens the fifo only once and reads every line from it.

Answer 2

The problem with your setup is that you have fifo creation in the wrong script if you wish to control fifo access to time when the reader is actually running. In order to correct the problem you will need to do something like this:
reader: fifo_read.sh
#!/bin/bash
fifo_name="/tmp/myfifo" # fifo name
trap "rm -f $fifo_name" EXIT # set trap to rm fifo_name at exit
[ -p "$fifo_name" ] || mkfifo "$fifo_name" # if fifo not found, create
exec 3< $fifo_name # redirect fifo_name to fd 3
# (not required, but makes read clearer)
while :; do
if read -r -u 3 line; then # read line from fifo_name
if [ "$line" = 'quit' ]; then # if line is quit, quit
printf "%s: 'quit' command received\n" "$fifo_name"
break
fi
printf "%s: %s\n" "$fifo_name" "$line" # print line read
fi
done
exec 3<&- # reset fd 3 redirection
exit 0
writer: fifo_write.sh
#!/bin/bash
fifo_name="/tmp/myfifo"
# Se non esiste, exit :);
[ -p "$fifo_name" ] || {
printf "\n Error fifo '%s' not found.\n\n" "$fifo_name"
exit 1
}
[ -n "$1" ] &&
printf "%s\n" "$1" > "$fifo_name" ||
printf "pid: '%s' writing to fifo\n" "$$" > "$fifo_name"
exit 0
operation: (start reader in 1st terminal)
$ ./fifo_read.sh # you can background with & at end
(launch writer in second terminal)
$ ./fifo_write.sh "message from writer" # second terminal
$ ./fifo_write.sh
$ ./fifo_write.sh quit
output in 1st terminal:
$ ./fifo_read.sh
/tmp/myfifo: message from writer
/tmp/myfifo: pid: '28698' writing to fifo
/tmp/myfifo: 'quit' command received

Answer 3

The following script should do the job:
#!/bin/bash
FIFO="/tmp/fifo"
if [ ! -e "$FIFO" ]; then
mkfifo "$FIFO"
fi
for script in "$#"; do
echo $script > $FIFO &
done
while read script; do
/bin/bash -c $script
done < $FIFO
Given two script a.sh and b.sh where both scripts pass "a" and "b" to stdout, respectively, one will get the following result (given that the script above is called test.sh):
./test.sh /tmp/a.sh /tmp/b.sh
a
b
Best,
Julian