concatenate variables in a bash script - bash

Hi I would like to set a variable by concatenating two other variables.
Example
A=1
B=2
12=C
echo $A$B
desired result being C
however the answer I get is always 12
Is it possible?
UPDATED
Example
A=X
B=Y
D=$A$B
xy=test
echo $D
desired result being "test"

It looks like you want indirect variable references.
BASH allows you to expand a parameter indirectly -- that is, one variable may contain the name of another variable:
# Bash
realvariable=contents
ref=realvariable
echo "${!ref}" # prints the contents of the real variable
But as Pieter21 indicates in his comment 12 is not a valid variable name.

Since 12 is not a valid variable name, here's an example with string variables:
> a='hello'
> b='world'
> declare my_$a_$b='my string'
> echo $my_hello_world
my string

What you are trying to do is (almost) called indirection: http://wiki.bash-hackers.org/syntax/pe#indirection
...I did some quick tests, but it does not seem logical to do this without a third variable - you cannot do concatenated indirection directly as the variables/parts being concatenated do not evaluate to the result on their own - you would have to do another evaluation. I think concatenating them first might be the easiest. That said, there is a chance you could rethink what you're doing.
Oh, and you cannot use numbers (alone or as the starting character) for variable names.
Here we go:
cake="cheese"
var1="ca"
var2="ke"
# this does not work as the indirection sees "ca" and "ke", not "cake". No output.
echo ${!var1}${!var2}
# there might be some other ways of tricking it to do this, but they don't look to sensible as indirection probably needs to work on a real variable.
# ...this works, though:
var3=${var1}${var2}
echo ${!var3}

Related

bash loop with the variable name inside file name [duplicate]

In shell scripts, when do we use {} when expanding variables?
For example, I have seen the following:
var=10 # Declare variable
echo "${var}" # One use of the variable
echo "$var" # Another use of the variable
Is there a significant difference, or is it just style? Is one preferred over the other?
In this particular example, it makes no difference. However, the {} in ${} are useful if you want to expand the variable foo in the string
"${foo}bar"
since "$foobar" would instead expand the variable identified by foobar.
Curly braces are also unconditionally required when:
expanding array elements, as in ${array[42]}
using parameter expansion operations, as in ${filename%.*} (remove extension)
expanding positional parameters beyond 9: "$8 $9 ${10} ${11}"
Doing this everywhere, instead of just in potentially ambiguous cases, can be considered good programming practice. This is both for consistency and to avoid surprises like $foo_$bar.jpg, where it's not visually obvious that the underscore becomes part of the variable name.
Variables are declared and assigned without $ and without {}. You have to use
var=10
to assign. In order to read from the variable (in other words, 'expand' the variable), you must use $.
$var # use the variable
${var} # same as above
${var}bar # expand var, and append "bar" too
$varbar # same as ${varbar}, i.e expand a variable called varbar, if it exists.
This has confused me sometimes - in other languages we refer to the variable in the same way, regardless of whether it's on the left or right of an assignment. But shell-scripting is different, $var=10 doesn't do what you might think it does!
You use {} for grouping. The braces are required to dereference array elements. Example:
dir=(*) # store the contents of the directory into an array
echo "${dir[0]}" # get the first entry.
echo "$dir[0]" # incorrect
You are also able to do some text manipulation inside the braces:
STRING="./folder/subfolder/file.txt"
echo ${STRING} ${STRING%/*/*}
Result:
./folder/subfolder/file.txt ./folder
or
STRING="This is a string"
echo ${STRING// /_}
Result:
This_is_a_string
You are right in "regular variables" are not needed... But it is more helpful for the debugging and to read a script.
Curly braces are always needed for accessing array elements and carrying out brace expansion.
It's good to be not over-cautious and use {} for shell variable expansion even when there is no scope for ambiguity.
For example:
dir=log
prog=foo
path=/var/${dir}/${prog} # excessive use of {}, not needed since / can't be a part of a shell variable name
logfile=${path}/${prog}.log # same as above, . can't be a part of a shell variable name
path_copy=${path} # {} is totally unnecessary
archive=${logfile}_arch # {} is needed since _ can be a part of shell variable name
So, it is better to write the three lines as:
path=/var/$dir/$prog
logfile=$path/$prog.log
path_copy=$path
which is definitely more readable.
Since a variable name can't start with a digit, shell doesn't need {} around numbered variables (like $1, $2 etc.) unless such expansion is followed by a digit. That's too subtle and it does make to explicitly use {} in such contexts:
set app # set $1 to app
fruit=$1le # sets fruit to apple, but confusing
fruit=${1}le # sets fruit to apple, makes the intention clear
See:
Allowed characters in Linux environment variable names
The end of the variable name is usually signified by a space or newline. But what if we don't want a space or newline after printing the variable value? The curly braces tell the shell interpreter where the end of the variable name is.
Classic Example 1) - shell variable without trailing whitespace
TIME=10
# WRONG: no such variable called 'TIMEsecs'
echo "Time taken = $TIMEsecs"
# What we want is $TIME followed by "secs" with no whitespace between the two.
echo "Time taken = ${TIME}secs"
Example 2) Java classpath with versioned jars
# WRONG - no such variable LATESTVERSION_src
CLASSPATH=hibernate-$LATESTVERSION_src.zip:hibernate_$LATEST_VERSION.jar
# RIGHT
CLASSPATH=hibernate-${LATESTVERSION}_src.zip:hibernate_$LATEST_VERSION.jar
(Fred's answer already states this but his example is a bit too abstract)
Following SierraX and Peter's suggestion about text manipulation, curly brackets {} are used to pass a variable to a command, for instance:
Let's say you have a sposi.txt file containing the first line of a well-known Italian novel:
> sposi="somewhere/myfolder/sposi.txt"
> cat $sposi
Ouput: quel ramo del lago di como che volge a mezzogiorno
Now create two variables:
# Search the 2nd word found in the file that "sposi" variable points to
> word=$(cat $sposi | cut -d " " -f 2)
# This variable will replace the word
> new_word="filone"
Now substitute the word variable content with the one of new_word, inside sposi.txt file
> sed -i "s/${word}/${new_word}/g" $sposi
> cat $sposi
Ouput: quel filone del lago di como che volge a mezzogiorno
The word "ramo" has been replaced.

Loop over a list separated by '\r\n' and concat item in bash [duplicate]

In shell scripts, when do we use {} when expanding variables?
For example, I have seen the following:
var=10 # Declare variable
echo "${var}" # One use of the variable
echo "$var" # Another use of the variable
Is there a significant difference, or is it just style? Is one preferred over the other?
In this particular example, it makes no difference. However, the {} in ${} are useful if you want to expand the variable foo in the string
"${foo}bar"
since "$foobar" would instead expand the variable identified by foobar.
Curly braces are also unconditionally required when:
expanding array elements, as in ${array[42]}
using parameter expansion operations, as in ${filename%.*} (remove extension)
expanding positional parameters beyond 9: "$8 $9 ${10} ${11}"
Doing this everywhere, instead of just in potentially ambiguous cases, can be considered good programming practice. This is both for consistency and to avoid surprises like $foo_$bar.jpg, where it's not visually obvious that the underscore becomes part of the variable name.
Variables are declared and assigned without $ and without {}. You have to use
var=10
to assign. In order to read from the variable (in other words, 'expand' the variable), you must use $.
$var # use the variable
${var} # same as above
${var}bar # expand var, and append "bar" too
$varbar # same as ${varbar}, i.e expand a variable called varbar, if it exists.
This has confused me sometimes - in other languages we refer to the variable in the same way, regardless of whether it's on the left or right of an assignment. But shell-scripting is different, $var=10 doesn't do what you might think it does!
You use {} for grouping. The braces are required to dereference array elements. Example:
dir=(*) # store the contents of the directory into an array
echo "${dir[0]}" # get the first entry.
echo "$dir[0]" # incorrect
You are also able to do some text manipulation inside the braces:
STRING="./folder/subfolder/file.txt"
echo ${STRING} ${STRING%/*/*}
Result:
./folder/subfolder/file.txt ./folder
or
STRING="This is a string"
echo ${STRING// /_}
Result:
This_is_a_string
You are right in "regular variables" are not needed... But it is more helpful for the debugging and to read a script.
Curly braces are always needed for accessing array elements and carrying out brace expansion.
It's good to be not over-cautious and use {} for shell variable expansion even when there is no scope for ambiguity.
For example:
dir=log
prog=foo
path=/var/${dir}/${prog} # excessive use of {}, not needed since / can't be a part of a shell variable name
logfile=${path}/${prog}.log # same as above, . can't be a part of a shell variable name
path_copy=${path} # {} is totally unnecessary
archive=${logfile}_arch # {} is needed since _ can be a part of shell variable name
So, it is better to write the three lines as:
path=/var/$dir/$prog
logfile=$path/$prog.log
path_copy=$path
which is definitely more readable.
Since a variable name can't start with a digit, shell doesn't need {} around numbered variables (like $1, $2 etc.) unless such expansion is followed by a digit. That's too subtle and it does make to explicitly use {} in such contexts:
set app # set $1 to app
fruit=$1le # sets fruit to apple, but confusing
fruit=${1}le # sets fruit to apple, makes the intention clear
See:
Allowed characters in Linux environment variable names
The end of the variable name is usually signified by a space or newline. But what if we don't want a space or newline after printing the variable value? The curly braces tell the shell interpreter where the end of the variable name is.
Classic Example 1) - shell variable without trailing whitespace
TIME=10
# WRONG: no such variable called 'TIMEsecs'
echo "Time taken = $TIMEsecs"
# What we want is $TIME followed by "secs" with no whitespace between the two.
echo "Time taken = ${TIME}secs"
Example 2) Java classpath with versioned jars
# WRONG - no such variable LATESTVERSION_src
CLASSPATH=hibernate-$LATESTVERSION_src.zip:hibernate_$LATEST_VERSION.jar
# RIGHT
CLASSPATH=hibernate-${LATESTVERSION}_src.zip:hibernate_$LATEST_VERSION.jar
(Fred's answer already states this but his example is a bit too abstract)
Following SierraX and Peter's suggestion about text manipulation, curly brackets {} are used to pass a variable to a command, for instance:
Let's say you have a sposi.txt file containing the first line of a well-known Italian novel:
> sposi="somewhere/myfolder/sposi.txt"
> cat $sposi
Ouput: quel ramo del lago di como che volge a mezzogiorno
Now create two variables:
# Search the 2nd word found in the file that "sposi" variable points to
> word=$(cat $sposi | cut -d " " -f 2)
# This variable will replace the word
> new_word="filone"
Now substitute the word variable content with the one of new_word, inside sposi.txt file
> sed -i "s/${word}/${new_word}/g" $sposi
> cat $sposi
Ouput: quel filone del lago di como che volge a mezzogiorno
The word "ramo" has been replaced.

bash variable substitution right next to another string [duplicate]

In shell scripts, when do we use {} when expanding variables?
For example, I have seen the following:
var=10 # Declare variable
echo "${var}" # One use of the variable
echo "$var" # Another use of the variable
Is there a significant difference, or is it just style? Is one preferred over the other?
In this particular example, it makes no difference. However, the {} in ${} are useful if you want to expand the variable foo in the string
"${foo}bar"
since "$foobar" would instead expand the variable identified by foobar.
Curly braces are also unconditionally required when:
expanding array elements, as in ${array[42]}
using parameter expansion operations, as in ${filename%.*} (remove extension)
expanding positional parameters beyond 9: "$8 $9 ${10} ${11}"
Doing this everywhere, instead of just in potentially ambiguous cases, can be considered good programming practice. This is both for consistency and to avoid surprises like $foo_$bar.jpg, where it's not visually obvious that the underscore becomes part of the variable name.
Variables are declared and assigned without $ and without {}. You have to use
var=10
to assign. In order to read from the variable (in other words, 'expand' the variable), you must use $.
$var # use the variable
${var} # same as above
${var}bar # expand var, and append "bar" too
$varbar # same as ${varbar}, i.e expand a variable called varbar, if it exists.
This has confused me sometimes - in other languages we refer to the variable in the same way, regardless of whether it's on the left or right of an assignment. But shell-scripting is different, $var=10 doesn't do what you might think it does!
You use {} for grouping. The braces are required to dereference array elements. Example:
dir=(*) # store the contents of the directory into an array
echo "${dir[0]}" # get the first entry.
echo "$dir[0]" # incorrect
You are also able to do some text manipulation inside the braces:
STRING="./folder/subfolder/file.txt"
echo ${STRING} ${STRING%/*/*}
Result:
./folder/subfolder/file.txt ./folder
or
STRING="This is a string"
echo ${STRING// /_}
Result:
This_is_a_string
You are right in "regular variables" are not needed... But it is more helpful for the debugging and to read a script.
Curly braces are always needed for accessing array elements and carrying out brace expansion.
It's good to be not over-cautious and use {} for shell variable expansion even when there is no scope for ambiguity.
For example:
dir=log
prog=foo
path=/var/${dir}/${prog} # excessive use of {}, not needed since / can't be a part of a shell variable name
logfile=${path}/${prog}.log # same as above, . can't be a part of a shell variable name
path_copy=${path} # {} is totally unnecessary
archive=${logfile}_arch # {} is needed since _ can be a part of shell variable name
So, it is better to write the three lines as:
path=/var/$dir/$prog
logfile=$path/$prog.log
path_copy=$path
which is definitely more readable.
Since a variable name can't start with a digit, shell doesn't need {} around numbered variables (like $1, $2 etc.) unless such expansion is followed by a digit. That's too subtle and it does make to explicitly use {} in such contexts:
set app # set $1 to app
fruit=$1le # sets fruit to apple, but confusing
fruit=${1}le # sets fruit to apple, makes the intention clear
See:
Allowed characters in Linux environment variable names
The end of the variable name is usually signified by a space or newline. But what if we don't want a space or newline after printing the variable value? The curly braces tell the shell interpreter where the end of the variable name is.
Classic Example 1) - shell variable without trailing whitespace
TIME=10
# WRONG: no such variable called 'TIMEsecs'
echo "Time taken = $TIMEsecs"
# What we want is $TIME followed by "secs" with no whitespace between the two.
echo "Time taken = ${TIME}secs"
Example 2) Java classpath with versioned jars
# WRONG - no such variable LATESTVERSION_src
CLASSPATH=hibernate-$LATESTVERSION_src.zip:hibernate_$LATEST_VERSION.jar
# RIGHT
CLASSPATH=hibernate-${LATESTVERSION}_src.zip:hibernate_$LATEST_VERSION.jar
(Fred's answer already states this but his example is a bit too abstract)
Following SierraX and Peter's suggestion about text manipulation, curly brackets {} are used to pass a variable to a command, for instance:
Let's say you have a sposi.txt file containing the first line of a well-known Italian novel:
> sposi="somewhere/myfolder/sposi.txt"
> cat $sposi
Ouput: quel ramo del lago di como che volge a mezzogiorno
Now create two variables:
# Search the 2nd word found in the file that "sposi" variable points to
> word=$(cat $sposi | cut -d " " -f 2)
# This variable will replace the word
> new_word="filone"
Now substitute the word variable content with the one of new_word, inside sposi.txt file
> sed -i "s/${word}/${new_word}/g" $sposi
> cat $sposi
Ouput: quel filone del lago di como che volge a mezzogiorno
The word "ramo" has been replaced.

Bash assignment value to variable as command substitution and print value output

I would like to achieve this in Bash: echo $(a=1)and print the value of variable a
I test eval, $$a,{}, $() but none of them work as most of the times either I got literally a=1 or in one case (I don't remember which) it tried to execute the value.
I known that I can do: a=1;echo $a but because I'm little fun one command per line (even if sometimes is getting little complicated) I was wondering if is possible to do this either with echo or with printf
If you know that $a is previously unset, you can do this using the following syntax:
echo ${a:=1}
This, and other types of parameter expansion, are defined in the POSIX shell command language specification.
If you want to assign a numeric value, another option, which doesn't depend on the value previously being unset, would be to use an arithmetic expansion:
echo $(( a = 1 ))
This assigns the value and echoes the number that has been assigned.
It's worth mentioning that what you're trying to do cannot be done in a subshell by design because a child process cannot modify the environment of its parent.

Using {} with variable in Bash [duplicate]

In shell scripts, when do we use {} when expanding variables?
For example, I have seen the following:
var=10 # Declare variable
echo "${var}" # One use of the variable
echo "$var" # Another use of the variable
Is there a significant difference, or is it just style? Is one preferred over the other?
In this particular example, it makes no difference. However, the {} in ${} are useful if you want to expand the variable foo in the string
"${foo}bar"
since "$foobar" would instead expand the variable identified by foobar.
Curly braces are also unconditionally required when:
expanding array elements, as in ${array[42]}
using parameter expansion operations, as in ${filename%.*} (remove extension)
expanding positional parameters beyond 9: "$8 $9 ${10} ${11}"
Doing this everywhere, instead of just in potentially ambiguous cases, can be considered good programming practice. This is both for consistency and to avoid surprises like $foo_$bar.jpg, where it's not visually obvious that the underscore becomes part of the variable name.
Variables are declared and assigned without $ and without {}. You have to use
var=10
to assign. In order to read from the variable (in other words, 'expand' the variable), you must use $.
$var # use the variable
${var} # same as above
${var}bar # expand var, and append "bar" too
$varbar # same as ${varbar}, i.e expand a variable called varbar, if it exists.
This has confused me sometimes - in other languages we refer to the variable in the same way, regardless of whether it's on the left or right of an assignment. But shell-scripting is different, $var=10 doesn't do what you might think it does!
You use {} for grouping. The braces are required to dereference array elements. Example:
dir=(*) # store the contents of the directory into an array
echo "${dir[0]}" # get the first entry.
echo "$dir[0]" # incorrect
You are also able to do some text manipulation inside the braces:
STRING="./folder/subfolder/file.txt"
echo ${STRING} ${STRING%/*/*}
Result:
./folder/subfolder/file.txt ./folder
or
STRING="This is a string"
echo ${STRING// /_}
Result:
This_is_a_string
You are right in "regular variables" are not needed... But it is more helpful for the debugging and to read a script.
Curly braces are always needed for accessing array elements and carrying out brace expansion.
It's good to be not over-cautious and use {} for shell variable expansion even when there is no scope for ambiguity.
For example:
dir=log
prog=foo
path=/var/${dir}/${prog} # excessive use of {}, not needed since / can't be a part of a shell variable name
logfile=${path}/${prog}.log # same as above, . can't be a part of a shell variable name
path_copy=${path} # {} is totally unnecessary
archive=${logfile}_arch # {} is needed since _ can be a part of shell variable name
So, it is better to write the three lines as:
path=/var/$dir/$prog
logfile=$path/$prog.log
path_copy=$path
which is definitely more readable.
Since a variable name can't start with a digit, shell doesn't need {} around numbered variables (like $1, $2 etc.) unless such expansion is followed by a digit. That's too subtle and it does make to explicitly use {} in such contexts:
set app # set $1 to app
fruit=$1le # sets fruit to apple, but confusing
fruit=${1}le # sets fruit to apple, makes the intention clear
See:
Allowed characters in Linux environment variable names
The end of the variable name is usually signified by a space or newline. But what if we don't want a space or newline after printing the variable value? The curly braces tell the shell interpreter where the end of the variable name is.
Classic Example 1) - shell variable without trailing whitespace
TIME=10
# WRONG: no such variable called 'TIMEsecs'
echo "Time taken = $TIMEsecs"
# What we want is $TIME followed by "secs" with no whitespace between the two.
echo "Time taken = ${TIME}secs"
Example 2) Java classpath with versioned jars
# WRONG - no such variable LATESTVERSION_src
CLASSPATH=hibernate-$LATESTVERSION_src.zip:hibernate_$LATEST_VERSION.jar
# RIGHT
CLASSPATH=hibernate-${LATESTVERSION}_src.zip:hibernate_$LATEST_VERSION.jar
(Fred's answer already states this but his example is a bit too abstract)
Following SierraX and Peter's suggestion about text manipulation, curly brackets {} are used to pass a variable to a command, for instance:
Let's say you have a sposi.txt file containing the first line of a well-known Italian novel:
> sposi="somewhere/myfolder/sposi.txt"
> cat $sposi
Ouput: quel ramo del lago di como che volge a mezzogiorno
Now create two variables:
# Search the 2nd word found in the file that "sposi" variable points to
> word=$(cat $sposi | cut -d " " -f 2)
# This variable will replace the word
> new_word="filone"
Now substitute the word variable content with the one of new_word, inside sposi.txt file
> sed -i "s/${word}/${new_word}/g" $sposi
> cat $sposi
Ouput: quel filone del lago di como che volge a mezzogiorno
The word "ramo" has been replaced.

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