I have an xpage application and i simply want to count open sessions (anonymous users) or logged in users or both, and display this info on a page.
This question http://bit.ly/1sUMt8m is still open without solution.
Any ideas how to do that?
You can obtain this information from the console. show users will give you all users and their open databases. show opendatabases shows the databases and reads. See the documentation for details.
So you could use sessionAsSigner and issue the console command from your code. Add -xml to get the response in a format you can parse with certainty.
The measure is slightly crude since a user could have closed a window while the session is still valid.
Short of that you would need some JS trickery
Related
I have a unique requirement, I have setup a PC which would auto login to a particular user id say 'autologinuser', when ever we switch on the PC it would automatically logs into 'autologinuser' as configured.
During the login, it would show which using is getting logged in with welcome text under it.
I would like to hide the user name and don't want to visible during auto login process, only windows text should be visible.
Can this be possible?
Thanks & Regards,
-Anil Katta
Looks like windows operating system don't provide this feature at this point of time, and there is no specific registry to do so.
May be this feature good to expect in future releases.
I'm trying to find a list of users for a specific project (by projectKey) who possess the issueadmin permission. I've found a documented API that gets me pretty close:
api/permissions/search_project_permissions
but the response that I get back only has summary information: counts of groups/users for each permission type.
search_project_permissions response
Does anybody know if there's a way to get to the login details for the users?
There is an "internal" web service (meaning it could change without notice!) that does this. You'll use it like so:
http://myserver.myco.com/api/permissions/users?projectId=[project guid]&permission=issueadmin
In Web API interface use the "Show Internal API" checkbox at the top of the left column to see it.
just noticed in Sonarqube v6.7 it works as follows:
https://sonarqube.dhl.com/api/permissions/users?projectKey=<KEY>
https://sonarqube.dhl.com/api/permissions/users?projectKey=<KEY>&permission=issueadmin
https://sonarqube.dhl.com/api/permissions/users?projectKey=<KEY>&permission=issueadmin&permission=scan
All possible permissions are (reg. Browse, See Source Code, Administer Issues, Administer and Execute Analysis):
admin
codeviewer
issueadmin
scan
user
There are many sites such as www.tf2outpost.com and www.bazaar.tf where users can add other steam users through the click of a button. How exactly do you accomplish this? There's nothing in the web API that shows you how to add friends.
EDIT: I have found this code: steam://friends/add/some_steam_id Can you modify this code to block/remove people if you have their steam id?
All that URL does is ask your locally installed Steam client to add a fried of the id matching the number after /add/. So if you have another users steam id you can add them by putting their id in that URL like this: steam://friends/add/your_new_friends_id
you can try this yourself by just pasting the url in most any internet browser and steam will popup with a message saying "Your New Friend has been added to your friends list"
Currently the friends command accepts the following subcommands:
add/<id>
Adds user with specified id number
friends/<id>
Shows list of users with whom you recently played
joinchat/<id>
Joins a chat with a specified id number
message/<id>
Send a message
players
Shows table of recent players you've played with
settings/hideoffline
Toggle offline friends from friends list
settings/showavatars
Toggle avatars in friends list
settings/sortbyname
Sorts friends list by name
status/away
Sets status as away
status/busy
Sets status as busy
status/trade
Sets status as looking to trade
status/play
Sets status as looking to play
status/offline
Sets status as offline
status/online
Sets status as online
It appears there currently is no command (at least not public) for blocking/removing people. Such a command would be fairly useless, and would allow for... mischief. You should just manually remove/block people you no longer wish to be friends with; there would be no convenience added from being able to do this from a browser. What exactly are you trying to accomplish?
See the Steam Browser API documentation for complete details about the friends command and other commands.
P.S. its probably a good idea to avoid posting other peoples steam user ids here.
I was playing around with hwi, I got it started.Now I can see the different schemas which are present. But I don't know how to query them. I tried to check hive wiki (https://cwiki.apache.org/confluence/display/Hive/HiveWebInterface) but they dont seem to have much information put over there. There seems to be a Running a query section in Walk through but it says image not found.
Anybody who has used HWI to query please suggest a way to use it.
Try these steps :
Open HWI : http://localhost:9999/hwi/index.jsp
Click on Authorize in the left pane. This will open the Change User Info section. Enter the username and hit submit to complete the authorization process. Upon successful authorization you'll see Authorization is complete at the top of your page.
Now click on Create Session, enter some session name and hit Submit.
Once you submit the session name you'll get the Manage Session screen. This is the place where all the action will take place. Come down to the Session Details section and enter a file name, say /Users/tariq/res.txt, in the Result File box. This is the file where the result of your query will get stored. If you expect your result to be very huge you can just enter /dev/null over there. Remember the result file is local to the web server. Similarly enter the error file if you wish.
Now come down to the Query box and write the query you want to execute.
Come down further to the Start Query drop down list, click on it and elect YES and hit Submit.
You should be able to see the file /Users/tariq/res.txt by now containing the result of your query. You can also view the result by clicking on View File option which will appear next to the Result File box upon the successful completion of your query.
HTH
Take a look at Hue - http://cloudera.github.io/hue/
This project is bundled with the Cloudera installation and seems to work rather well.
Best,
Sukrit
I kick off 5 uploads (of varying size) via the BackgroundTransferService. I have the following questions about the way it works:
It seems that on the emulator it does 2 uploads at a time. Is this how it works on the actual device? Can I programmatically change this behavior?
Can I count on the uploads going out in the order that I submitted them? I seem to be getting conflicting results in my testing.
When I inspect the BackgroundTransferService in my application, does it contain requests from other apps as well or just mine?
Do I need to reconnect events for all the BackgroundTransferRequest objects when coming back from being tombstoned? What about coming back from being reactivated?
Do I need to disconnect events from the BackgroundTransferRequest when I remove it from the BackgroundTransferService.Requests collection?
When I try to upload a non-existing URL:Port (on the localhost), the TransferStatus is reported as WaitingForNonVoiceBlockingNetwork. The upload never actually completes/fails. Is this how it is on the device? Should I remove the request when it encounters this TransferStatus?
You cannot influence the behaviour of the BTS. If you don't like the way it works you can write the transfer functionality as part of your own application but then you have to handle running in the background yourself.
There is no guarantee on sequence.
The BTS may be handling requests from other apps but you won't be able to see the details. Requests() will only return details for your app.
Surely a quick test will tell you this.
It's good practice to.
Have you checked the TransferError property whe you reach this situation? This is a perfectly valild status in other situations and so you shouldn't treat this as a automatic fail.