how to move and drop an object between two or more canvases in html 5, That means I have an image in one canvas and i want to move this image to the other canvas.
When I use two or more "DIV" in html 5 it is coming without any problem but when I am using canvas it is not coming..help me
$(function() {
$( "#draggable" ).draggable();
$( "#droppable" ).droppable({
drop: function( event, ui ) {
$( this )
.addClass( "ui-state-highlight" )
.find( "p" )
.html( "Dropped!" );
}
});
});
#draggable { width: 100px; height: 100px; padding: 0.5em; float: left; margin: 10px 10px 10px 0; }
#droppable { width: 150px; height: 150px; padding: 0.5em; float: left; margin: 10px; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.2/jquery.min.js"></script>
<link rel="stylesheet" href="//code.jquery.com/ui/1.11.1/themes/smoothness/jquery-ui.css">
<script src="//code.jquery.com/ui/1.11.1/jquery-ui.js"></script>
<div id="draggable" class="ui-widget-content">
<p>Drag me to my target</p>
</div>
<div id="droppable" class="ui-widget-header">
<p>Drop here</p>
</div>
Related
I have an issue with Dompdf not positioning images correct.
The output in browser is ok, but the images are to close to the title in the PDF.
They should also render over the blue bar. I thought this should be possible with either a negative margin-top or a position absolute. But from what I read is that position:absolute inside a position:relative container is (still) not working.
HTML and expected output:
<html>
<head>
<link href="https://fonts.googleapis.com/css?family=Lato:100,100i,300,300i,400,400i,700,700i,900,900i" rel="stylesheet">
<style>
#page { margin: 0px; }
body
{
font-family: 'Lato';
font-size: 13px;
margin: 0px;
padding: 0px;
}
.container
{
padding: 0px 30px;
}
.top_container
{
position: relative;
}
.subgroep
{
color: #2e4660;
font-weight: 700;
padding-top: 30px;
}
.top_container .balk_blauw
{
/*position: absolute;*/
/*bottom: 0px;*/
/*left: 0px;*/
height: 60px;
width: 100%;
background: #2e4660;
margin-top: -60px;
}
.top_container .images
{
position: relative;
z-index: 99;
}
.top_container .images img
{
width: 230px;
margin-top:20px;
}
</style>
</head>
<body>
<div class="top_container">
<div class="container">
<div class="subgroep">Wijnklimaatkast</div>
<div class="images">
<img src="https://www.lhis.nl/producten/WTes1672-21_dicht_gevuld.png" class="image1">
<img src="https://www.lhis.nl/producten/WTes1672-21_open_leeg.png" class="image2">
</div>
</div>
<div class="balk_blauw"></div>
</div>
</body></html>
PDF renders as follows:
Screenshot
PHP Code:
$dompdf_options = new \Dompdf\Options();
$dompdf_options->set('isRemoteEnabled', true);
$dompdf_options->set('chroot', $dirname);
$dompdf = new \Dompdf\Dompdf($dompdf_options);
$dompdf->loadHtml($html);
$dompdf->setPaper('A4', 'portrait');
$dompdf->render();
$dompdf->stream();
This is an issue with how Dompdf aligns element within a line box. There is an ongoing effort to address the issue (WIP).
With the current release you can work around the issue by moving your image block down using relative positioning. You'll also want to set z-indexing a bit differently to better accommodate how Dompdf renders elements.
Try the following:
<html>
<head>
<link href="https://fonts.googleapis.com/css?family=Lato:100,100i,300,300i,400,400i,700,700i,900,900i" rel="stylesheet">
<style>
#page { margin: 0px; }
body
{
font-family: 'Lato';
font-size: 13px;
margin: 0px;
padding: 0px;
}
.container
{
padding: 0px 30px;
z-index: 99;
}
.top_container
{
position: relative;
}
.subgroep
{
color: #2e4660;
font-weight: 700;
padding-top: 30px;
}
.top_container .balk_blauw
{
/*position: absolute;*/
/*bottom: 0px;*/
/*left: 0px;*/
height: 60px;
width: 100%;
background: #2e4660;
margin-top: -60px;
}
.top_container .images
{
position: relative;
top: 40px;
z-index: 99;
}
.top_container .images img
{
width: 230px;
margin-top:20px;
}
</style>
</head>
<body>
<div class="top_container">
<div class="container">
<div class="subgroep">Wijnklimaatkast</div>
<div class="images">
<img src="https://www.lhis.nl/producten/WTes1672-21_dicht_gevuld.png" class="image1">
<img src="https://www.lhis.nl/producten/WTes1672-21_open_leeg.png" class="image2">
</div>
</div>
<div class="balk_blauw"></div>
</div>
</body></html>
Follow your issue for updates
I'd like to know how can I code the 3 blocks fader from the Spring.io website. Image here:
It has a dividing line that changes the image gradually as you move it.
This can be done with simple HTML and javascript code. Here's the complete jsfiddle https://jsfiddle.net/zn3b1hov/34/
Basic Idea is very simple.
First, You need 2 SVG images one is colored and another is grayscale. I am using this 2
grayscale-image
colored-image
Now Create 2 absolute div one on top of another and use these images as background.
Then create a slider as wide as the images. I am using HTML range type input
Finally change the top div's width according to sliders value.
Complete HTML, CSS and JS
<style>
#fader-diagram-your-app {
position: relative;
height: 286px;
}
#fader-diagram-modern-java-gray {
position: absolute;
height: 238px;
width: 800px;
margin: 31px auto;
background: url('https://spring.io/img/homepage/diagram-modern-java-gray-9a417697a51646e42df7e9d7f024709d.svg') no-repeat;
background-size: 100%;
}
#fader-diagram-modern-java-color {
position: absolute;
height: 238px;
max-width: 800px;
margin: 31px auto;
overflow: hidden;
width: 200px;
}
#fader-diagram-modern-java-color div {
position: absolute;
height: 238px;
background: url('https://spring.io/img/homepage/diagram-modern-java-color-e10b7eec68b1fe60eefeab0cf20a20da.svg') no-repeat;
background-size: 100%;
width: 800px;
}
#fader {
background-color: #34302d;
width: 6px;
height: 275px;
border-radius: 4px;
position: absolute;
left: 0;
}
#myRange {
width: 800px;
position: absolute;
top: 50%;
}
</style>
<div id="fader-diagram-your-app">
<div class="sidebyside" id="fader-diagram">
<div id="fader-diagram-modern-java-gray"></div>
<div id="fader-diagram-modern-java-color" style="width: 39.6875px;">
<div></div>
</div>
<div id="fader">
</div>
<input type="range" min="0" max="800" value="0" class="slider" id="myRange">
</div>
</div>
<script>
var slider = document.getElementById("myRange");
var coloredImage = document.getElementById("fader-diagram-modern-java-color");
var fader = document.getElementById("fader");
slider.oninput = function() {
coloredImage.style.width = this.value + "px";
fader.style.left = this.value + "px";
}
</script>
I'm trying to scroll content vertically in a div. However, I would like it to loop, so that when the last item in the div reaches the top of the container, the first items follow it, and if the first item is already at the top of my container, I don't want the previous button to work, but I'm not sure how to do either of these two things. Any help would be appreciated.
JSFIDDLE
HTML
<div class="container">
<div class="block block-1">1</div>
<div class="block block-2">2</div>
<div class="block block-3">3</div>
<div class="block block-4">4</div>
<div class="block block-5">5</div>
<div class="block block-6">6</div>
</div>
<button id="prev">Previous</button>
<button id="next">Next</button>
jQuery
$( "#prev" ).click(function()
{
$( ".block" ).animate({ "top": "+=50px" }, "slow" );
});
$( "#next" ).click(function()
{
$( ".block" ).animate({ "top": "-=50px" }, "slow" );
});
CSS
.container
{
position: relative;
background-color: #f5f5f5;
width: 590px;
height: 330px;
overflow: hidden;
font-family: arial, sans;
font-weight: bold;
text-align: center;
margin-bottom: 20px;
}
.block
{
position: absolute;
width: 90px;
height: 90px;
color: #fff;
}
.block-1
{
background-color: #900;
}
.block-2
{
top: 100px;
background-color: #090;
}
.block-3
{
top: 200px;
background-color: #009;
}
.block-4
{
top: 300px;
background-color: #990;
}
.block-5
{
top: 400px;
background-color: #909;
}
.block-6
{
top: 500px;
background-color: #099;
}
If you want it to loop, you can do a test where every time a div's vertical position goes out of bounds, it gets moved to the bottom of the pile, and reverse this when scrolling up. Essentially you just cut and paste the elements in the right order using $.remove(), $.append(), $.clone().
i am using kendo sortable data source is kendo observable array,
when we sorting the divs we are updating the array object in change event,
but array is updating properly but ui is not updating.
can u please help me.
<!DOCTYPE html>
<html>
<head>
<title></title>
<link href="http://cdn.kendostatic.com/2014.1.528/styles/kendo.common.min.css" rel="stylesheet" />
<link href="http://cdn.kendostatic.com/2014.1.528/styles/kendo.default.min.css" rel="stylesheet" />
<link href="http://cdn.kendostatic.com/2014.1.528/styles/kendo.dataviz.min.css" rel="stylesheet" />
<link href="http://cdn.kendostatic.com/2014.1.528/styles/kendo.dataviz.default.min.css" rel="stylesheet" />
<script src="http://cdn.kendostatic.com/2014.1.528/js/jquery.min.js"></script>
<script src="http://cdn.kendostatic.com/2014.1.528/js/kendo.all.min.js"></script>
</head>
<body>
<div id="example">
<div id="playlist">
<ul id="sortable-basic" data-bind="source:items" data-template="template">
</ul>
</div>
<script type="text/x-kendo-tmpl" id="template">
<li class="sortable">#:value#<span>#:time#</span></li>
</script>
<script>
var data;
$(document).ready(function () {
data = kendo.observable({
items: new kendo.data.ObservableArray([
{ value: 'Papercut', time: '3:12' },
{ value: 'One Step Closer ', time: '4:10' },
{ value: 'With You ', time: '5:00' },
{ value: 'Points of Authority ', time: '2:59' }]
)
});
kendo.bind($('#playlist'), data);
$("#sortable-basic").kendoSortable({
change: function (e) {
var daa = data.items.splice(e.oldIndex, 1);
data.items.splice(e.newIndex, 0, daa[0]);
}
});
});
</script>
<style>
#example
{
-webkit-user-select: none;
-moz-user-select: none;
-ms-user-select: none;
user-select: none;
}
#playlist
{
margin: 30px auto;
width: 300px;
background-color: #f3f5f7;
border-radius: 4px;
border: 1px solid rgba(0,0,0,.1);
}
#playlist-title
{
height: 80px;
border-radius: 4px 4px 0 0;
border-bottom: 1px solid rgba(0,0,0,.1);
}
#playlist-title span
{
display: none;
}
#sortable-basic
{
padding: 0;
margin: 0;
}
li.sortable
{
list-style-type: none;
padding: 6px 8px;
margin: 0;
color: #666;
font-size: 1.2em;
}
li.sortable:last-child
{
border-bottom: 0;
border-radius: 0 0 4px 4px;
}
li.sortable span
{
display: block;
float: right;
color: #666;
}
li.sortable:hover
{
background-color: #dceffd;
}
li.hint
{
display: block;
width: 200px;
background-color: #52aef7;
color: #fff;
}
li.hint:after
{
content: "";
display: block;
width: 0;
height: 0;
border-top: 6px solid transparent;
border-bottom: 6px solid transparent;
border-left: 6px solid #52aef7;
position: absolute;
left: 216px;
top: 8px;
}
li.hint:last-child
{
border-radius: 4px;
}
li.hint span
{
color: #fff;
}
li.placeholder
{
background-color: #dceffd;
color: #52aef7;
text-align: right;
}
</style>
</div>
</body>
</html>
I think I found your problem. It seems to be the change function, just remove it and you can sort your list.
I've not used kendoSortable but I would assume that it is already maintaining the array sort because you have bound the array to the kendoSortable. That's the purpose of binding, it keeps the data and elements in sync for you. What you're doing in the change event is simply undoing the work that the binding just did, that is, sort the elements AND the bound array.
As per telerik,
https://www.telerik.com/forums/sortable-and-moving-items-in-observable-arrays
You have to do this manually and attaching sortable to an array doesn't do anything automatically. So what you are doing is correct, however even though your changes reflect correctly in observable array it doesn't on screen.
So we have to trigger clear and change event, to sync UI with the array. There may be a better way invoke sync without having to clear out array but this was a hack that worked for me.
Here is a sample code where we clear the array and then re-insert which fixes the issue.
$("#sortable-basic").kendoSortable({
change: function (e) {
var daa = data.items.splice(e.oldIndex, 1);
data.items.splice(e.newIndex, 0, daa[0]);
var copiedArray = data.items.splice(0, data.items.length);
$.each(copiedArray,
function (index, item) {
data.items.push(item);
});
}
});
After learning JS for about a month now and completing around 4 courses I am still unable to work out how to change an image when clicking a thumbnail! What I want to do is simple, I just want to change the Main Image when a thumbnail is clicked! In this example there are two thumbnail images in a div and a main image above them. I just want to change the main image when a thumbnail is clicked. I know this is DOM Manipulation and think it is: document.getElementById.....?
I have make a small page so that I can learn / try different things and and finally giving up and asking for help! The code is as follows:
#MainContainer {
position: relative;
margin:0px auto;
width: 500px;
height: 400px;
border: 1px solid black;
}
#MainImage {
position: absolute;
top: 10px;
left: 50px;
width: 398px;
height: 265px;
background: url(MainImage01.jpg);
border: 1px solid black;
}
#TNBodyContainer {
position: absolute;
top: 290px;
left: 100px;
border: 1px solid black;
width: 268px;
height: 88px;
}
#TNOne {
position: relative;
width: 133px;
height: 88px;
background: url(SmallImage01.jpg);
}
#TNTwo {
position: relative;
left:135px;
width: 133px;
height: 88px;
background: url(SmallImage02.jpg);
}
<body>
<div id="MainContainer">
<div id="MainImage"></div>
<div id="TNBodyContainer">
<div id="TNOne">
<div id="TNTwo"></div>
</div>
</div>
Thank you very much for any help.
Margate
You need to add some scripting to change the image when either of the thumbnails are clicked. This function is called when the page is loaded. Change the image names to suit.
This should be placed in the section of the html page.
<script>
window.onload = function() {
var mainImg = document.getElementById('Main');
document.getElementById('TNOne').onclick = function() {
mainImg.src = 'main1.jpg';
//alert('one clicked');
};
document.getElementById('TNTwo').onclick = function() {
mainImg.src = 'main2.jpg';
//alert('two clicked');
};
};
</script>
The two thumbnail divs become <img> tags with the same IDs.
Similarly the main <img> is defined also (with id="Main"). Now the elements
are clickable.
<div id="MainContainer">
<div id="MainImage">
<img id="Main" src="MainImage01.jpg"</img>
</div>
<div id="TNBodyContainer">
<img id="TNOne" src="thumb1.jpg"></img>
<img id="TNTwo" src="thumb2.jpg"></img>
</div>
</div>
Finally CSS for the thumbnails, here float is used to keep the thumbnails in the same line within the TNBodyContainer div.
TNOne {
width: 133px;
height: 88px;
float:left;
}
#TNTwo {
width: 133px;
height: 88px;
float:left;
}
To change the image in the CSS background property, you need to use
document.getElementById("MainImage").style.background
The right way to go is to add event listeners:
document.getElementById("TNOne").addEventListener("click", function (event) {
setImage(event);
}, false);
document.getElementById("TNTwo").addEventListener("click", function (event) {
setImage(event);
}, false);
}
They both call the same function, but with event it is possible to see which one "clicked" with "event.target.id".
You can then decide what you want to do with for instance a switch statement. basically saying: if event.target.id == "TNOne".
You can see all this I made you a fiddle: http://jsfiddle.net/djwave28/32pQD/3/
There are some slight changes in your HTML and CSS too.