Sorting program with MIPS - sorting

Question

I have some problem when I'm writing a sorting program in MIPS.
The function of this program is like this: Input 10 integers from keyboard and print them out, then sort them and print the sorted array again.
But the output is different from what I expect, some numbers are not sorted, would someone help me?
.data
str1: .asciiz "Please input integer numbers, maximum 10: \n"
str2: .asciiz "The 10 integer numbers you input are: \n"
str3: .asciiz "The numbers you entered are sorted as: \n"
array: .space 40
space: .asciiz " "
.text
.globl main
main:
la $t6, array #load the address of array into $t6
move $t7, $t6
addi $t7, $t7, 40 #point $t7 to the end of the array
jal readin
la $t6, array
la $a0, str2
li $v0, 4
syscall
jal print1 #print out the array before sort
la $t0, array #put the address of array into $t0
add $t0, $t0, 40 #put $t0 to the end of the array
move $t1, $zero #set $t1 as counter of the outerloop
li $t2, 10 #set $t2 as number of the outerloop
la $t3, array #put the address to $t3
jal innerloop
la $a0, str3
li $v0, 4
syscall
la $t3, array
#move $t7, $t3
#add $t7, $t7, 40
jal print2
li $v0, 10
syscall
innerloop:
lb $t4, 0($t3)
lb $t5, 4($t3)
bgt $t4, $t5, swap
addi $t3, $t3, 4
blt $t3, $t0, innerloop #if $t3 < $t0, keep in the innerloop to check two #neighbor numbers
jal outerloop #jump to outerloop if one round is finished
swap:
sb $t4, 4($t3)
sb $t5, 0($t3)
addi $t3, $t3, 4
#sll $t3, $t3, 2
blt $t3, $t0, innerloop #
jr $ra
outerloop:
la $t3, array
addi $t1, $t1, 1 #add the outerloop counter $t1 by one,
addi $t0, $t0, -1
blt $t1, $t2, innerloop #if $t1 < $t2, keep searching
jr $ra
readin:
la $a0, str1 #print str1
li $v0, 4
syscall
li $v0, 5 #read in the number
syscall
sb $v0, ($t6) #store the number in the array
add $t6, $t6, 4
blt $t6, $t7, readin
jr $ra
print1:
lb $a0, ($t6)
li $v0, 1
syscall
li $a0, 32
li $v0, 11 # syscall number for printing character
syscall
add $t6, $t6, 4
blt $t6, $t7, print1
jr $ra
print2:
lb $a0, ($t3)
li $v0, 1
syscall
li $a0, 32
li $v0, 11 # syscall number for printing character
syscall
add $t3, $t3, 4
blt $t3, $t0, print2
jr $ra
And the result in SPIM is like this:
Please input integer numbers, maximum 10:
44
Please input integer numbers, maximum 10:
11
Please input integer numbers, maximum 10:
33
Please input integer numbers, maximum 10:
22
Please input integer numbers, maximum 10:
66
Please input integer numbers, maximum 10:
55
Please input integer numbers, maximum 10:
99
Please input integer numbers, maximum 10:
77
Please input integer numbers, maximum 10:
88
Please input integer numbers, maximum 10:
24
The 10 integer numbers you input are:
44 11 33 22 66 55 99 77 88 24 The numbers you entered are sorted as:
11 33 22 44 55 66 77 88 24 32
Would someone please explain to me why there is a 32 in the end and why they are not sorted properly?