I have a set of log file which each file log is for specific machine.
What i am trying to achieve is to use the multiline{} filter to join the multi-line messages in each of the file because i would like to have a single #timestamp for each file.
example data in the log file
title
description
test1
test pass
test end
filter {
multiline {
pattern => "from_start_line to end of line"
what => "previous"
negate => true
}
}
I just want to make all the data in the log file as single event without using the pattern.
pretty much like telling logstash to make a multi-line event until EOF.
You can't do like that. Because logstash will always keep monitoring the file. Therefore the EOF is meaningless for it.
The other way you can do is add some pattern to the end of the logs. For example, add log_end to the end of each log output.
title
description
test1
test pass
test end-log_end
Then you can use this pattern to multiline all the logs.
multiline {
pattern => "log_end$"
negate => true
what => "next"
}
Hope this can help you.
Related
This topic is related but skips the part interesting for me.
I'm using filebeat to read CA Service Desk Manager logs written in a custom format which I cannot change. A single log line looks something like this:
11/07 13:05:26.65 <hostname> dbmonitor_nxd 9192 SIGNIFICANT bpobject.c 2587 Stats: imp(0) lcl(0) rmt(1,1) rmtref(0,0) dbchg(0)
As you can see the date in the beginning has no year information.
I then use logstash to parse the date from the log line. I've got the extra pattern TIMESTAMP defined like this:
TIMESTAMP %{MONTHNUM}[/]%{MONTHDAY}%{SPACE}%{TIME}
And then in logstash.conf I have the following filter:
grok {
patterns_dir => ["./patterns"]
match => { "message" => [
"%{TIMESTAMP:time_stamp}%{SPACE}%{WORD:server_name}%{SPACE}%{DAEMONNAME:object_name}%{SPACE}%{INT:object_id:int}%{SPACE}%{WORD:event_type}%{SPACE}%{USERNAME:object_file}%{SPACE}%{INT:object_line_number:int}%{SPACE}%{GREEDYDATA:log_message}"
]
}
}
date{
match => ["time_stamp", "MM/d HH:mm:ss.SS", "MM/dd HH:mm:ss.SS", "ISO8601"]
}
Currently I have to rely on the automatic timestamp as the time_stamp is indexed as text and I've been fine so far, but occasionally the time the log line was written on the server is not the same as the time it was pushed into ES. Around new year I fear I will run into trouble with this and how the year is deducted from the current time. My questions are:
Is it possible to parse a date field from the data given?
Is there a way to write some advanced logic for the date conversion?
As we're not past the new year yet, is there a way to manually check/ensure the automatic conversion is done correctly?
I want to make log files for nifi processors , i get them form tailFail and split text line by line then check if it is error , info or warn log and route to executescript processors but at this time i have 5 flowfiles and i want to unify this split flowfiles and write it in one flowfile, i tried to use merge content but i think it doesn't fit my task.
I also want to know if nifi custom log return log files for
all processors i have added in my workflow and is it nessecary to
add appenders inside logback.xml.
I want to know if it is possible to unify split log data?
(p.s i tried routeonAttriute also but it doesn't work for me)
my workflow looks like this:
After splitting lines you can use RouteOnContent to check that line matches regexp.
Then if you want to join lines you can use the following script.
That's just an example:
//get 1000 flow file list from incoming queue but not more then 1000
def ffList = session.get(1000)
if(!ffList)return
ffList.each{ff->
session.read(ff, {rawIn ->
//you can write here to a new output flowfile
//but in this example i will just add content into a plain file on disk
new File('./logs/warn.log') << rawIn << '\n'
} as InputStreamCallback)
session.remove(ff)
}
Alright, so what I have is a ruby file that takes an input, and writes it to another ruby file. I do not want to write it as a text file, because I am trying to insert this item into a Hash that can later be accessed in another run of the program, which can only be achieved by writing the info to a text file or another ruby file. In this case I want to write it into another ruby file.Here's the first file:
test_text=gets.chomp
to_write_to=File.open("rubylib.rb", "a")
test_text="hobby => #{test_test},"
to_write_to.puts test_text
This inserts the given info at the BOTTOM of the page. The other file is this: (rubylib.rb)
user_info={
"name" => "bob",,
"favorite_color" => "red"
}
I have a threefold question:
1) Is it possible to add test_text to the hash BEFORE the closing bracket?
2) using this method, will the rubylib.rb file, when run, parse the added text as code, or something else?
3)is there a better way to do this?
What I am trying to do is actually physically write the new data to the Hash so that it is still there the next time the file is run, to store data about the user. Because if I add it the normal way, it will be lost the next time the file is run. Is there a way to store data between runs of a ruby file without writing to a text file?
I've done the best I can to give you the info you need and explain the situation as best I can. If you need clarification or more info, please leave a comment and I'll try and get back to you by commenting on that.
Thanks for the help
You should use YAML for this.
Here's how you could create a .yml file with the data you used in your example:
require "yaml"
user_info = { "name" => "bob", "favorite_color" => "red" }
File.write("user_info.yml", user_info.to_yaml)
This creates a file that looks like this:
---
name: bob
favorite_color: red
On a subsequent execution of your program, you can load the .yml file and you'll get back the same Hash that you started with:
user_info = YAML.load_file("user_info.yml")
# => { "name" => "bob", "favorite_color" => "red" }
And you can add new items to the Hash and save it again:
user_info["hobby"] = "fishing"
File.write("user_info.yml", user_info.to_yaml)
Now the file has these contents:
---
name: bob
favorite_color: red
hobby: fishing
Use a database, even SQLite, and it'll let you store data for multiple sessions without any sort of encoding. Writing to a file as you are is really not scalable or practical. You'll slam into some real problems quickly with it.
I'd recommend looking at Sequel and its associated documentation for how to easily work with databases. That's a much more scalable approach and will save you a lot of headaches as you grow your code.
I am already familiar with How can I save an object to a file?
But what if we have to store multiple objects (say hashes) to a file.
I tried appending YAML.dump(hash) to a file from various locations in my code. But the difficult part is reading it back. As yaml dump can extend to many lines, do I have to parse the file? Also this will only complicate code. Is there a better way to achieve this?
PS: Same issue will persist with Marshal.dump. So I prefer YAML as its more human readable.
YAML.dump creates a single Yaml document. If you have several Yaml documents together in a file then you have a Yaml stream. So when you appended the results from several calls to YAML.dump together you would have had a stream.
If you try reading this back using YAML.load you will only get the first document. To get all the documents back you can use YAML.load_stream, which will give you an array with an entry for each of the documents.
An example:
f = File.open('data.yml', 'w')
YAML.dump({:foo => 'bar'}, f)
YAML.dump({:baz => 'qux'}, f)
f.close
After this data.yml will look like this, containing two separate documents:
---
:foo: bar
---
:baz: qux
You can now read it back like this:
all_docs = YAML.load_stream(File.open('data.yml'))
Which will give you an array like [{:foo=>"bar"}, {:baz=>"qux"}].
If you don’t want to load all the documents into an array in one go you can pass a block to load_stream and handle each document as it is parsed:
YAML.load_stream(File.open('data.yml')) do |doc|
# handle the doc here
end
You could manage to save multiple objects by creating a delimiter (something to mark that one object is finished and that you go to the next one). You could then process the file in two steps:
read the file, splitting it around each delimiter
use YAML to restore the hashes from each chunk
Now, this would be a bit cumbersome, as there is a much simpler solution. Let's say you have three hash to save:
student = { first_name: "John"}
restaurant = { location: "21 Jump Street" }
order = { main_dish: "Happy Meal" }
You can simply put them in an array and then dump them:
objects = [student, restaurant, order]
dump = YAML.dump(objects)
You can restore your objects easily:
saved_objects = YAML.load(dump)
saved_student = saved_objects[0]
Depending of your objects relationship, you may prefer to use an Hash to save them instead of an array (so that you can name them instead of depending on the order).
I followed logstash documentation about multiline and tried to experiment it with a basic stdin & stdout configuration, but it does not seem to work. The tag "multiline" is added on the next messages, but they end as separate entries with a "_grokparsefailure" tag.
What am I missing?
Edit: as a reference I was using a stacktrace multiline filter.
Ok that one was a bit tricky, so I thought it might be appreciated if I gave here the solution. I found it in this post: multiline triggers only if the next lines come quickly (within 1~2 second). So when experimenting, if you take your time copying and pasting each line you will think it doesn't work while it actually does.
Please follow the example mentioned in the blog. I successfully implemented multiline with this approach.
For more clarification, please provide your config along with sample input message.
This is my configuration. I use the example from Logstash multiline
input {
stdin {
}
}
filter {
multiline {
# Grok pattern names are valid! :)
pattern => "^%{TIMESTAMP_ISO8601} "
negate => true
what => previous
}
}
output {
stdout {debug => true}
}
With this logs, The multiline function is work on me.
2014-02-24 10:00:01 abcde
1qaz
2014-01-01 11:11:11
2wsx
I enter the logs one by one and wait for 1 minute between each line. So, I didn't have meet your problem. Please verify your configuration.