How do I find the middle of three numbers in shell script - bash

Question

#!/bin/bash
echo "Enter three numbers and this program will give you the middle number : " ; read num1 ; read num2 ; read num3
if [ "$num1" -gt "$num2" ] && [ "$num1" -lt "$num3" ] || [ "$num1" -lt "$num2" ] && [ "$num1" -gt "$num3" ]; then
{
echo "The middle number is $num1"
}
elif [ "$num2" -gt "$num1" ] && [ "$num2" -lt "$num3" ] || [ "$num2" -lt "$num1" ] && [ "$num2" -gt "$num3" ]; then
{
echo "The middle number is $num2"
}
elif [ "$num3" -gt "$num1" ] && [ "$num3" -lt "$num2" ] || [ "$num3 -lt "$num1" ] && [ "$num3" -gt "$num2" ]; then
{ echo "The middle number is $num3" }
fi
The problem I have is with the or condition. I input the numbers 1, 2, and 3, but I get the middle number as 1 all the time.

Answer 1

How about this:
getmid() {
if (( $1 <= $2 )); then
(( $1 >= $3 )) && { echo $1; return; }
(( $2 <= $3 )) && { echo $2; return; }
fi;
if (( $1 >= $2 )); then
(( $1 <= $3 )) && { echo $1; return; }
(( $2 >= $3 )) && { echo $2; return; }
fi;
echo $3;
}
# All permutations of 1, 2 and 3 print 2.
getmid 1 2 3
getmid 2 1 3
getmid 1 3 2
getmid 3 1 2
getmid 2 3 1
getmid 3 2 1

Answer 2

This one should work:
#!/bin/bash
echo "Enter three numbers and this program will give you the middle number : " ; read num1 ; read num2 ; read num3;
if [ "$num1" -gt "$num2" ] && [ "$num1" -lt "$num3" ]; then
{
echo "The middle number is" $num1 ;
}
elif [ "$num1" -lt "$num2" ] && [ "$num1" -gt "$num3" ]; then
{
echo "The middle number is" $num1 ;
}
elif [ "$num2" -gt "$num1" ] && [ "$num2" -lt "$num3" ]; then
{
echo "The middle number is" $num2 ;
}
elif [ "$num2" -lt "$num1" ] && [ "$num2" -gt "$num3" ]; then
{
echo "The middle number is" $num2 ;
}
elif [ "$num3" -gt "$num1" ] && [ "$num3" -lt "$num2" ]; then
{
echo "The middle number is" $num3 ;
}
elif [ "$num3" -lt "$num1" ] && [ "$num3" -gt "$num2" ]; then
{
echo "The middle number is" $num3 ;
}
fi