I have a URL like below.
/shows/the-ruby-book/meta-programming/?play=5b35a825-d372-4375-b2f0-f641a38067db"
I need to extract only the id of the play (i.e. 5b35a825-d372-4375-b2f0-f641a38067db) using regular expression. How can I do it?
I would not use a regexp to parse a url. I would use Ruby's libraries to handle URLs:
require 'uri'
url = '/shows/the-ruby-book/meta-programming/?play=5b35a825-d372-4375-b2f0-f641a38067db'
uri = URI.parse(url)
params = URI::decode_www_form(uri.query).to_h
params['play']
# => 5b35a825-d372-4375-b2f0-f641a38067db
You can do:
str = '/shows/the-ruby-book/meta-programming/?play=5b35a825-d372-4375-b2f0-f641a38067db'
match = str.match(/.*\?play=([^&]+)/)
puts match[1]
=> "5b35a825-d372-4375-b2f0-f641a38067db"
The regex /.*\?play=([^&]+)/ will match everything up until ?play=, and then capture anything that is not a & (the query string parameter separator)
A match will create a MatchData object, represented here by match variable, and captures will be indices of the object, hence your matched data is available at match[1].
url = '/shows/the-ruby-book/meta-programming/?play=5b35a825-d372-4375-b2f0-f641a38067db'
url.split("play=")[1] #=> "5b35a825-d372-4375-b2f0-f641a38067db"
Ruby's built-in URI class has everything needed to correctly parse, split and decode URLs:
require 'uri'
uri = URI.parse('/shows/the-ruby-book/meta-programming/?play=5b35a825-d372-4375-b2f0-f641a38067db')
URI::decode_www_form(uri.query).to_h['play'] # => "5b35a825-d372-4375-b2f0-f641a38067db"
If you're using an older Ruby that doesn't support to_h, use:
Hash[URI::decode_www_form(uri.query)]['play'] # => "5b35a825-d372-4375-b2f0-f641a38067db"
You should use URI, rather than try to split/extract using a regexp, because the query of a URI will be encoded if any values are not within the characters allowed by the spec. URI, or Addressable::URI, will decode those back to their original values for you.
Related
I want to replace 'hoge' to 'foo' with regex. But the user's value is dynamic so I can't use str.gsub('hoge', 'foo').
str = '?user=hoge&tab=fuga'
What should I do?
Don't do this with a regular expression.
This is how to manipulate URIs using the existing wheels:
require 'uri'
str = 'http://example.com?user=hoge&tab=fuga'
uri = URI.parse(str)
query = URI.decode_www_form(uri.query).to_h # => {"user"=>"hoge", "tab"=>"fuga"}
query['user'] = 'foo'
uri.query = URI.encode_www_form(query)
uri.to_s # => "http://example.com?user=foo&tab=fuga"
Alternately:
require 'addressable'
uri = Addressable::URI.parse('http://example.com?tab=fuga&user=hoge')
query = uri.query_values # => {"tab"=>"fuga", "user"=>"hoge"}
query['user'] = 'foo'
uri.query_values = query
uri.to_s # => "http://example.com?tab=fuga&user=foo"
Note that in the examples the order of the parameters changed, but the code handled the difference without problems.
The reason you want to use URI or Addressable is because parameters and values have to be correctly encoded when they contain illegal characters. URI and Addressable know the rules and will follow them, whereas naive code assumes it's OK to not bother with encoding, causing broken URIs.
URI is part of the Ruby Standard Library, and Addressable is more full-featured. Take your pick.
You can try below regex
([?&]user=)([^&]+)
DEMO
You probably want to find out what the user query maps to first before using a .gsub to replace whatever value it is.
First, parse the URL string into an URI object using the URI module. And then, you can use the CGI query methods to get the key value pairs of the query params off the URI object using the CGI module. And finally, you can .gsub off the values in that hash.
Say I have a string like this: "http://something.example.com/directory/"
What I want to do is to parse this string, and extract the "something" from the string.
The first step, is to obviously check to make sure that the string contains "http://" - otherwise, it should ignore the string.
But, how do I then just extract the "something" in that string? Assume that all the strings that this will be evaluating will have a similar structure (i.e. I am trying to extract the subdomain of the URL - if the string being examined is indeed a valid URL - where valid is starts with "http://").
Thanks.
P.S. I know how to check the first part, i.e. I can just simply split the string at the "http://" but that doesn't solve the full problem because that will produce "http://something.example.com/directory/". All I want is the "something", nothing else.
I'd do it this way:
require 'uri'
uri = URI.parse('http://something.example.com/directory/')
uri.host.split('.').first
=> "something"
URI is built into Ruby. It's not the most full-featured but it's plenty capable of doing this task for most URLs. If you have IRIs then look at Addressable::URI.
You could use URI like
uri = URI.parse("http://something.example.com/directory/")
puts uri.host
# "something.example.com"
and you could then just work on the host.
Or there is a gem domainatrix from Remove subdomain from string in ruby
require 'rubygems'
require 'domainatrix'
url = Domainatrix.parse("http://foo.bar.pauldix.co.uk/asdf.html?q=arg")
url.public_suffix # => "co.uk"
url.domain # => "pauldix"
url.subdomain # => "foo.bar"
url.path # => "/asdf.html?q=arg"
url.canonical # => "uk.co.pauldix.bar.foo/asdf.html?q=arg"
and you could just take the subdomain.
Well, you can use regular expressions.
Something like /http:\/\/([^\.]+)/, that is, the first group of non '.' letters after http.
Check out http://rubular.com/. You can test your regular expressions against a set of tests too, it's great for learning this tool.
with URI.parse you can get:
require "uri"
uri = URI.parse("http://localhost:3000")
uri.scheme # http
uri.host # localhost
uri.port # 3000
I have a bunch of URLs which I would like to clean. They all contain UTM parameters, which are not necessary, or rather harmful in this case. Example:
http://houseofbuttons.tumblr.com/post/22326009438?utm_source=feedburner&utm_medium=feed&utm_campaign=Feed%3A+HouseOfButtons+%28House+of+Buttons%29
All potential parameters begin with utm_.
How can I remove them easily with a ruby script / structure without destroying other potentialy "good" URL parameters?
You can apply a regex to the urls to clean them up. Something like this should do the trick:
url = 'http://houseofbuttons.tumblr.com/post/22326009438?utm_source=feedburner&utm_medium=feed&utm_campaign=Feed%3A+HouseOfButtons+%28House+of+Buttons%29&normal_param=1'
url.gsub(/&?utm_.+?(&|$)/, '') => "http://houseofbuttons.tumblr.com/post/22326009438?normal_param=1"
This uses the URI lib to deconstruct and change the querystring (no regex):
require 'uri'
str ='http://houseofbuttons.tumblr.com/post/22326009438?utm_source=feedburner&utm_medium=feed&utm_campaign=Feed%3A+HouseOfButtons+%28House+of+Buttons%29&normal_param=1'
uri = URI.parse(str)
clean_key_vals = URI.decode_www_form(uri.query).reject{|k, _| k.start_with?('utm_')}
uri.query = URI.encode_www_form(clean_key_vals)
p uri.to_s #=> "http://houseofbuttons.tumblr.com/post/22326009438?normal_param=1"
How do I encode or 'escape' the URL before I use OpenURI to open(url)?
We're using OpenURI to open a remote url and return the xml:
getresult = open(url).read
The problem is the URL contains some user-input text that contains spaces and other characters, including "+", "&", "?", etc. potentially, so we need to safely escape the URL. I saw lots of examples when using Net::HTTP, but have not found any for OpenURI.
We also need to be able to un-escape a similar string we receive in a session variable, so we need the reciprocal function.
Don't use URI.escape as it has been deprecated in 1.9.
Rails' Active Support adds Hash#to_query:
{foo: 'asd asdf', bar: '"<#$dfs'}.to_query
# => "bar=%22%3C%23%24dfs&foo=asd+asdf"
Also, as you can see it tries to order query parameters always the same way, which is good for HTTP caching.
Ruby Standard Library to the rescue:
require 'uri'
user_text = URI.escape(user_text)
url = "http://example.com/#{user_text}"
result = open(url).read
See more at the docs for the URI::Escape module. It also has a method to do the inverse (unescape)
The main thing you have to consider is that you have to escape the keys and values separately before you compose the full URL.
All the methods which get the full URL and try to escape it afterwards are broken, because they cannot tell whether any & or = character was supposed to be a separator, or maybe a part of the value (or part of the key).
The CGI library seems to do a good job, except for the space character, which was traditionally encoded as +, and nowadays should be encoded as %20. But this is an easy fix.
Please, consider the following:
require 'cgi'
def encode_component(s)
# The space-encoding is a problem:
CGI.escape(s).gsub('+','%20')
end
def url_with_params(path, args = {})
return path if args.empty?
path + "?" + args.map do |k,v|
"#{encode_component(k.to_s)}=#{encode_component(v.to_s)}"
end.join("&")
end
def params_from_url(url)
path,query = url.split('?',2)
return [path,{}] unless query
q = query.split('&').inject({}) do |memo,p|
k,v = p.split('=',2)
memo[CGI.unescape(k)] = CGI.unescape(v)
memo
end
return [path, q]
end
u = url_with_params( "http://example.com",
"x[1]" => "& ?=/",
"2+2=4" => "true" )
# "http://example.com?x%5B1%5D=%26%20%3F%3D%2F&2%2B2%3D4=true"
params_from_url(u)
# ["http://example.com", {"x[1]"=>"& ?=/", "2+2=4"=>"true"}]
Ruby has the built-in URI library, and the Addressable gem, in particular Addressable::URI
I prefer Addressable::URI. It's very full featured and handles the encoding for you when you use the query_values= method.
I've seen some discussions about URI going through some growing pains so I tend to leave it alone for handling encoding/escaping until these things get sorted out:
http://osdir.com/ml/ruby-core/2010-06/msg00324.html
http://osdir.com/ml/lang-ruby-core/2009-06/msg00350.html
http://osdir.com/ml/ruby-core/2011-06/msg00748.html
How can I check if a string is a valid URL?
For example:
http://hello.it => yes
http:||bra.ziz, => no
If this is a valid URL how can I check if this is relative to a image file?
Notice:
As pointed by #CGuess, there's a bug with this issue and it's been documented for over 9 years now that validation is not the purpose of this regular expression (see https://bugs.ruby-lang.org/issues/6520).
Use the URI module distributed with Ruby:
require 'uri'
if url =~ URI::regexp
# Correct URL
end
Like Alexander Günther said in the comments, it checks if a string contains a URL.
To check if the string is a URL, use:
url =~ /\A#{URI::regexp}\z/
If you only want to check for web URLs (http or https), use this:
url =~ /\A#{URI::regexp(['http', 'https'])}\z/
Similar to the answers above, I find using this regex to be slightly more accurate:
URI::DEFAULT_PARSER.regexp[:ABS_URI]
That will invalidate URLs with spaces, as opposed to URI.regexp which allows spaces for some reason.
I have recently found a shortcut that is provided for the different URI rgexps. You can access any of URI::DEFAULT_PARSER.regexp.keys directly from URI::#{key}.
For example, the :ABS_URI regexp can be accessed from URI::ABS_URI.
The problem with the current answers is that a URI is not an URL.
A URI can be further classified as a locator, a name, or both. The
term "Uniform Resource Locator" (URL) refers to the subset of URIs
that, in addition to identifying a resource, provide a means of
locating the resource by describing its primary access mechanism
(e.g., its network "location").
Since URLs are a subset of URIs, it is clear that matching specifically for URIs will successfully match undesired values. For example, URNs:
"urn:isbn:0451450523" =~ URI::regexp
=> 0
That being said, as far as I know, Ruby doesn't have a default way to parse URLs , so you'll most likely need a gem to do so. If you need to match URLs specifically in HTTP or HTTPS format, you could do something like this:
uri = URI.parse(my_possible_url)
if uri.kind_of?(URI::HTTP) or uri.kind_of?(URI::HTTPS)
# do your stuff
end
I prefer the Addressable gem. I have found that it handles URLs more intelligently.
require 'addressable/uri'
SCHEMES = %w(http https)
def valid_url?(url)
parsed = Addressable::URI.parse(url) or return false
SCHEMES.include?(parsed.scheme)
rescue Addressable::URI::InvalidURIError
false
end
This is a fairly old entry, but I thought I'd go ahead and contribute:
String.class_eval do
def is_valid_url?
uri = URI.parse self
uri.kind_of? URI::HTTP
rescue URI::InvalidURIError
false
end
end
Now you can do something like:
if "http://www.omg.wtf".is_valid_url?
p "huzzah!"
end
For me, I use this regular expression:
/\A(http|https):\/\/[a-z0-9]+([\-\.]{1}[a-z0-9]+)*\.[a-z]{2,5}(:[0-9]{1,5})?(\/.*)?\z/ix
Option:
i - case insensitive
x - ignore whitespace in regex
You can set this method to check URL validation:
def valid_url?(url)
return false if url.include?("<script")
url_regexp = /\A(http|https):\/\/[a-z0-9]+([\-\.]{1}[a-z0-9]+)*\.[a-z]{2,5}(:[0-9]{1,5})?(\/.*)?\z/ix
url =~ url_regexp ? true : false
end
To use it:
valid_url?("http://stackoverflow.com/questions/1805761/check-if-url-is-valid-ruby")
Testing with wrong URLs:
http://ruby3arabi - result is invalid
http://http://ruby3arabi.com - result is invalid
http:// - result is invalid
http://test.com\n<script src=\"nasty.js\"> (Just simply check "<script")
127.0.0.1 - not support IP address
Test with correct URLs:
http://ruby3arabi.com - result is valid
http://www.ruby3arabi.com - result is valid
https://www.ruby3arabi.com - result is valid
https://www.ruby3arabi.com/article/1 - result is valid
https://www.ruby3arabi.com/websites/58e212ff6d275e4bf9000000?locale=en - result is valid
In general,
/^#{URI::regexp}$/
will work well, but if you only want to match http or https, you can pass those in as options to the method:
/^#{URI::regexp(%w(http https))}$/
That tends to work a little better, if you want to reject protocols like ftp://.
This is a little bit old but here is how I do it. Use Ruby's URI module to parse the URL. If it can be parsed then it's a valid URL. (But that doesn't mean accessible.)
URI supports many schemes, plus you can add custom schemes yourself:
irb> uri = URI.parse "http://hello.it" rescue nil
=> #<URI::HTTP:0x10755c50 URL:http://hello.it>
irb> uri.instance_values
=> {"fragment"=>nil,
"registry"=>nil,
"scheme"=>"http",
"query"=>nil,
"port"=>80,
"path"=>"",
"host"=>"hello.it",
"password"=>nil,
"user"=>nil,
"opaque"=>nil}
irb> uri = URI.parse "http:||bra.ziz" rescue nil
=> nil
irb> uri = URI.parse "ssh://hello.it:5888" rescue nil
=> #<URI::Generic:0x105fe938 URL:ssh://hello.it:5888>
[26] pry(main)> uri.instance_values
=> {"fragment"=>nil,
"registry"=>nil,
"scheme"=>"ssh",
"query"=>nil,
"port"=>5888,
"path"=>"",
"host"=>"hello.it",
"password"=>nil,
"user"=>nil,
"opaque"=>nil}
See the documentation for more information about the URI module.
You could also use a regex, maybe something like http://www.geekzilla.co.uk/View2D3B0109-C1B2-4B4E-BFFD-E8088CBC85FD.htm assuming this regex is correct (I haven't fully checked it) the following will show the validity of the url.
url_regex = Regexp.new("((https?|ftp|file):((//)|(\\\\))+[\w\d:\##%/;$()~_?\+-=\\\\.&]*)")
urls = [
"http://hello.it",
"http:||bra.ziz"
]
urls.each { |url|
if url =~ url_regex then
puts "%s is valid" % url
else
puts "%s not valid" % url
end
}
The above example outputs:
http://hello.it is valid
http:||bra.ziz not valid