Unix shell group files extensions by size - bash

Question

i want to group and sort files sizes by extensions in current and all subfolders
for i in `find . -type f -name '*.*' | sed 's/.*\.//' | sort | uniq `
do
echo $i
done
got code which gets all files extensions in current and all subfolders
now i need to sum all files sizes by those extensions and print them
Any ideas how this could be done?
example output:
sh (files sizes sum by sh extension)
pl (files sizes sum by pl extension)
c (files sizes sum by c extension)

Answer 1

I would use a loop, so that you can provide a different extension every time and find just the files with that extension:
for extension in c php pl ...
do
find . -type f -name "*.$extension" -print0 | du --files0-from=- -hc
done
The sum is based on the answer in total size of group of files selected with 'find'.
In case you want the very specific output you mention in the question, you can store the last line and then print it together with the extension name:
for extension in c php pl ...
do
sum=$(find . -type f -name "*.$extension" -print0 | du --files0-from=- -hc | tail -1)
echo "$extension ($sum)"
done

Answer 2

If you don't want to name file extensions beforehand, the stat(1) program has a format option (-c) that can make tasks like this a bit easier, if you're on a system that includes it, and xargs(1) usually helps performance.
#!/bin/sh
find . -type f -name '*.*' -print0 |
xargs -0 stat -c '%s %n' |
sed 's/ .*\./ /' |
awk '
{
sums[$2] += $1
}
END {
for (key in sums) {
printf "%s %d\n", key, sums[key]
}
}'