Oracle performance tuning order by is taking time - oracle

Am having query,in which two fields and getting as output pps_id and total_weight. Here pps_id is the column from the table and total_weight we are calculating from inner query. after doing all process in query we are order by the query by total weight. Its taking more cost and response.Is there any way to improve this query performance.
SELECT PPS_ID, TOTAL_WEIGHT
FROM ( SELECT PPS_ID, TOTAL_WEIGHT
FROM (SELECT pps_id,
ROUND (
( ( (60 * name_pct_match / 100)
+ prs_weight
+ year_weight
+ dt_weight)
/ 90)
* 100)
total_weight
FROM (SELECT pps_id,
ROUND (func_compare_name ('aaaa',
UPPER (name_en),
' ',
60))
name_pct_match,
DECODE (prs_nationality_id, 99, 15, 0)
prs_weight,
10 mother_weight,
100 total_attrib_weight,
CASE
WHEN TO_NUMBER (
TO_CHAR (birth_date, 'yyyy')) =
1986
THEN
5
ELSE
0
END
year_weight,
CASE
WHEN TO_CHAR (
TO_DATE ('12-JAN-86',
'DD-MON-RRRR'),
'dd') =
TO_CHAR (birth_date, 'dd')
AND TO_CHAR (
TO_DATE ('12-JAN-86',
'DD-MON-RRRR'),
'mm') =
TO_CHAR (birth_date, 'mm')
THEN
10
WHEN TO_DATE ('12-JAN-86', 'DD-MON-RRRR') BETWEEN birth_date
- 6
AND birth_date
+ 6
THEN
8
WHEN TO_DATE ('12-JAN-86', 'DD-MON-RRRR') BETWEEN birth_date
- 28
AND birth_date
+ 28
THEN
5
WHEN TO_DATE ('12-JAN-86', 'DD-MON-RRRR') BETWEEN birth_date
- 90
AND birth_date
+ 90
THEN
3
ELSE
0
END
dt_weight
FROM individual_profile
WHERE birth_date = '12-JAN-86'
AND IS_ACTIVE = 1
AND gender_id = 1
AND ROUND (func_compare_name ('aaa',
UPPER (name_en),
' ',
60)) > 20))
WHERE TOTAL_WEIGHT >= 100
ORDER BY total_weight DESC)
WHERE ROWNUM <= 10
i have tried by splitting the query and put values in temp tables and tried but it also taking time. I want to improve the performance of the query

Related

Generating random INTERVAL

I have a function below that returns a random INTERVAL between a range of hours, which appears to be working fine but is currently limited to hours only.
I would would like to expand this functionality to also support returning a random INTERVAL for days, minutes by passing in a literal (ie 'DAY', 'MINUTE' or 'SECOND')
For example if I call random_interval (1,4, 'DAY') I would get something like this +000000002 11:24:43.000000000 or if i call random_interval (20,40, 'MINUTE') I would get something like
+000000000 00:24:44.000000000
Thanks in advance to all who answer and for your time and expertise.
CREATE OR REPLACE FUNCTION random_interval(
p_min_hours IN NUMBER,
p_max_hours IN NUMBER
) RETURN INTERVAL DAY TO SECOND
IS
BEGIN
RETURN floor(dbms_random.value(p_min_hours, p_max_hours)) * interval '1' hour
+ floor(dbms_random.value(0, 60)) * interval '1' minute
+ floor(dbms_random.value(0, 60)) * interval '1' second;
END random_interval;
/
SELECT random_interval(1, 10) as random_val FROM dual CONNECT BY level <= 10 order by 1
RANDOM_VAL
+000000000 01:04:03.000000000
+000000000 03:14:52.000000000
+000000000 04:39:42.000000000
+000000000 05:00:39.000000000
+000000000 05:03:28.000000000
+000000000 07:03:19.000000000
+000000000 07:06:13.000000000
+000000000 08:50:55.000000000
+000000000 09:10:02.000000000
+000000000 09:26:44.000000000
Try giving this a shot instead
CREATE OR REPLACE FUNCTION random_interval(
p_min IN NUMBER,
p_max IN NUMBER,
p_period VARCHAR2
) RETURN INTERVAL DAY TO SECOND
IS
BEGIN
IF p_period = 'HOUR' THEN
RETURN floor(dbms_random.value(p_min, p_max)) * interval '1' hour
+ floor(dbms_random.value(0, 60)) * interval '1' minute
+ floor(dbms_random.value(0, 60)) * interval '1' second;
ELSE IF p_period = 'DAY' THEN
RETURN floor(dbms_random.value(p_min, p_max)) * interval '1' day
+ floor(dbms_random.value(0, 24)) * interval '1' hour
+ floor(dbms_random.value(0, 60)) * interval '1' minute
+ floor(dbms_random.value(0, 60)) * interval '1' second;
ELSE IF p_period = 'MINUTE' THEN
RETURN floor(dbms_random.value(p_min, p_max)) * interval '1' minute
+ floor(dbms_random.value(0, 60)) * interval '1' second;
ELSE IF p_period = 'SECOND' THEN
RETURN floor(dbms_random.value(p_min, p_max)) * interval '1' second;
ELSE
RETURN NULL;
END IF;
END random_interval;
/
SELECT random_interval(1, 10, 'DAY') as random_val FROM dual CONNECT BY level <= 10 order by 1
RANDOM_VAL
+000000003 02:46:09.000000000
+000000004 19:19:56.000000000
+000000002 11:24:43.000000000
+000000002 16:20:44.000000000
+000000001 22:24:30.000000000
+000000002 15:14:38.000000000
+000000003 00:48:03.000000000
+000000003 18:08:13.000000000
+000000002 01:05:34.000000000
+000000002 08:12:19.000000000
You don't need a user-defined function as you can use the built-in functions DBMS_RANDOM.VALUE(lower_bound, upper_bound) and NUMTODSINTERVAL(amount, duration):
SELECT NUMTODSINTERVAL(
DBMS_RANDOM.VALUE(1, 3),
'MINUTE'
)
FROM DUAL;
Which will generate a random interval greater than or equal to 1 minute and less than 3 minutes (with a random about of seconds).
If you did want to wrap it into a function then:
CREATE FUNCTION random_interval(
p_min IN NUMBER,
p_max IN NUMBER,
p_duration IN VARCHAR2
) RETURN INTERVAL DAY TO SECOND
IS
BEGIN
RETURN NUMTODSINTERVAL(DBMS_RANDOM.VALUE(p_min, p_max), p_duration);
END;
/
If you want the seconds to be an integer then:
CREATE OR REPLACE FUNCTION random_interval(
p_min IN NUMBER,
p_max IN NUMBER,
p_duration IN VARCHAR2
) RETURN INTERVAL DAY TO SECOND
IS
v_interval INTERVAL DAY TO SECOND := NUMTODSINTERVAL(DBMS_RANDOM.VALUE(p_min, p_max), p_duration);
BEGIN
RETURN ( EXTRACT(DAY FROM v_interval) * 24 * 60 * 60
+ EXTRACT(HOUR FROM v_interval) * 60 * 60
+ EXTRACT(MINUTE FROM v_interval) * 60
+ FLOOR(EXTRACT(SECOND FROM v_interval))
) * INTERVAL '1' SECOND;
END;
/
fiddle

Not a singlenot a single-group group function ORA-00937: Oracle

What can I do at the highest level to change this error
ORA-00937: not a single-group group function
00937. 00000 - "not a single-group group function"
*Cause:
*Action:
Error at Line: 3 Column: 5
select
year,
Net_TWRR_PERIOD,
round(((CASE WHEN MOD(SUM(CASE WHEN
( Net_TWRR_PERIOD ) <0 then 1 else 0 end ), 2 )=1 THEN -1 ELSE 1 END * EXP(SUM(LN(ABS(Net_TWRR_PERIOD)))))-1)*100,2)
from (select
year,
round(((CASE WHEN MOD(SUM(CASE WHEN (Net_TWRR ) <0 then 1 else 0 end ), 2 )=1 THEN -1 ELSE 1 END * EXP(SUM(LN(ABS(Net_TWRR)))))-1)*100,2) as Net_TWRR_PERIOD
from
(select ( net_rate_of_return / 100 + 1) as Net_TWRR,
year
from eom
WHERE id = '2'
and start_date < '09-September-2022'
) group by year order by year)
you are using the SUM functiion and the GROUP BY is missing in the outermost SQL.
create table eom(year number(4), start_date date, net_rate_of_return number (10,4), id number(4))
SELECT year,
Net_TWRR_PERIOD,
ROUND (
( ( CASE
WHEN MOD (
SUM (
CASE
WHEN (Net_TWRR_PERIOD) < 0 THEN 1
ELSE 0
END),
2) = 1
THEN
-1
ELSE
1
END
* EXP (SUM (LN (ABS (Net_TWRR_PERIOD)))))
- 1)
* 100,
2)
FROM ( SELECT year,
ROUND (
( ( CASE
WHEN MOD (
SUM (
CASE
WHEN (Net_TWRR) < 0 THEN 1
ELSE 0
END),
2) = 1
THEN
-1
ELSE
1
END
* EXP (SUM (LN (ABS (Net_TWRR)))))
- 1)
* 100,
2)
AS Net_TWRR_PERIOD
FROM (SELECT (net_rate_of_return / 100 + 1) AS Net_TWRR, year
FROM eom
WHERE id = '2' AND start_date < '09-September-2022')
GROUP BY year
ORDER BY year, Net_TWRR_PERIOD)
GROUP BY year, Net_TWRR_PERIOD
You have the outer query:
select year,
Net_TWRR_PERIOD,
round(
(
CASE
WHEN MOD(SUM(CASE WHEN Net_TWRR_PERIOD < 0 then 1 else 0 end ), 2)=1
THEN -1
ELSE 1
END
* EXP(SUM(LN(ABS(Net_TWRR_PERIOD))))
-1
) * 100,
2
)
from ( ... )
Which has a mix of aggregated columns and non-aggregated columns and you do not have a GROUP BY clause (in that outer query). You need to make sure all columns are either aggregated or contained in a GROUP BY.
So, change the outer query to:
select year,
Net_TWRR_PERIOD,
round(
(
CASE
WHEN MOD(SUM(CASE WHEN Net_TWRR_PERIOD < 0 then 1 else 0 end ), 2)=1
THEN -1
ELSE 1
END
* EXP(SUM(LN(ABS(Net_TWRR_PERIOD))))
-1
) * 100,
2
)
from ( ... )
GROUP BY year, Net_TWRR_PERIOD

pl sql payment calculation

I need help with PVA calculation in PL/SQL .I have formula:
Annuity = r * PVA Ordinary / [1 – (1 + r)-n]
Where:
PVA Ordinary = Present value of an ordinary annuity
r = Effective interest rate
n = Number of periods.
enter image description here
You can use:
DECLARE
principal NUMBER := 9000;
r NUMBER := 0.015;
n NUMBER := 5;
start_dt DATE := DATE '2022-07-14';
payment NUMBER := r * principal / (1 - POWER(1 + r, -n));
amt NUMBER := principal;
interest NUMBER;
pmt_dt DATE;
BEGIN
FOR i IN 1 .. n LOOP
pmt_dt := ADD_MONTHS(start_dt, i);
pmt_dt := pmt_dt + CASE pmt_dt - TRUNC(pmt_dt, 'IW')
WHEN 5 THEN 2 -- Saturday
WHEN 6 THEN 1 -- Sunday
ELSE 0 -- Weekday
END;
interest := amt * r;
amt := amt - payment + interest;
DBMS_OUTPUT.PUT_LINE(
TO_CHAR(i, 'fm0')
|| ', ' || TO_CHAR(pmt_dt, 'YYYY-MM-DD (DY)')
|| ', ' || TO_CHAR(payment, '9990.00')
|| ', ' || TO_CHAR(interest, '990.00')
|| ', ' || TO_CHAR(payment - interest, '9990.00')
|| ', ' || TO_CHAR(amt, '9990.00')
);
END LOOP;
END;
/
Which outputs:
1, 2022-08-15 (MON), 1881.80, 135.00, 1746.80, 7253.20
2, 2022-09-14 (WED), 1881.80, 108.80, 1773.01, 5480.19
3, 2022-10-14 (FRI), 1881.80, 82.20, 1799.60, 3680.59
4, 2022-11-14 (MON), 1881.80, 55.21, 1826.60, 1853.99
5, 2022-12-14 (WED), 1881.80, 27.81, 1853.99, -0.00
Or, in SQL using a MODEL clause:
WITH data (id, start_date, principal, rate, period ) AS (
SELECT 1, DATE '2022-07-14', 9000, 0.015, 5 FROM DUAL
)
SELECT pmt_dt + CASE pmt_dt - TRUNC(pmt_dt, 'IW')
WHEN 5 THEN 2
WHEN 6 THEN 1
ELSE 0
END AS pmt_dt,
ROUND(payment, 2) AS payment,
ROUND(interest, 2) AS interest,
ROUND(payment - interest, 2) AS reduction,
ROUND(balance, 2) AS balance
FROM data
MODEL
PARTITION BY (id)
DIMENSION BY (1 AS key)
MEASURES (
start_date,
principal,
rate,
period,
DATE '1900-01-01' AS pmt_dt,
rate * principal / (1 - POWER(1 + rate, -period)) AS payment,
0 AS interest,
0 AS balance
)
RULES SEQUENTIAL ORDER ITERATE (100) UNTIL (balance[ITERATION_NUMBER+1] <= 0) (
payment[ITERATION_NUMBER+1] = payment[1],
pmt_dt[ITERATION_NUMBER+1] = ADD_MONTHS(start_date[1], ITERATION_NUMBER+1),
interest[ITERATION_NUMBER + 1]
= COALESCE(balance[ITERATION_NUMBER],principal[1]) * rate[1],
balance[ITERATION_NUMBER+1]
= COALESCE(balance[ITERATION_NUMBER],principal[1])
- payment[1] + interest[ITERATION_NUMBER+1]
)
ORDER BY id, key
Which outputs:
PMT_DT
PAYMENT
INTEREST
REDUCTION
BALANCE
15-AUG-22
1881.8
135
1746.8
7253.2
14-SEP-22
1881.8
108.8
1773.01
5480.19
14-OCT-22
1881.8
82.2
1799.6
3680.59
14-NOV-22
1881.8
55.21
1826.6
1853.99
14-DEC-22
1881.8
27.81
1853.99
0
db<>fiddle here

Oracle 11g Sql convert date from blob field

I have a problem in converting a date value stored in a blob field in Oracle 11g sql command. When i execute the sql:
select dump(HIGH_VALUE) from all_tab_columns where COLUMN_NAME='TARIH'
i receive the following result;
Typ=23 Len=7: 120,116,3,6,1,1,1
I know that these numbers represent a date (not datetime), but i don't know how to extract the date from this result.
Thanks in advance,
Alper
Oracle stores dates in tables as 7-bytes
byte 1 - century + 100
byte 2 - (year MOD 100 ) + 100
byte 3 - month
byte 4 - day
byte 5 - hour + 1
byte 6 - minute + 1
byte 7 - seconds+ 1
So 120,116,3,6,1,1,1 converts to:
byte 1 - century = 120 - 100 = 20
byte 2 - year = 116 - 100 = 16
byte 3 - month = 3
byte 4 - day = 6
byte 5 - hour = 1 - 1 = 0
byte 6 - minute = 1 - 1 = 0
byte 7 - seconds = 1 - 1 = 0
So 2016-03-06T00:00:00
Oracle Setup:
CREATE TABLE file_upload ( file_blob BLOB );
INSERT INTO file_upload VALUES (
utl_raw.cast_to_raw(
CHR(120) || CHR(116) || CHR(3) || CHR(6) || CHR(1) || CHR(1) || CHR(1)
)
);
Query:
SELECT DUMP( DBMS_LOB.SUBSTR( file_blob, 7, 1 ) ) AS dmp,
TO_DATE(
TO_CHAR(
( ASCII( SUBSTR( chars, 1, 1 ) ) - 100 ) * 100
+ ASCII( SUBSTR( chars, 2, 1 ) ) - 100,
'0000'
)
|| TO_CHAR( ASCII( SUBSTR( chars, 3, 1 ) ), '00' )
|| TO_CHAR( ASCII( SUBSTR( chars, 4, 1 ) ), '00' )
|| TO_CHAR( ASCII( SUBSTR( chars, 5, 1 ) ) - 1, '00' )
|| TO_CHAR( ASCII( SUBSTR( chars, 6, 1 ) ) - 1, '00' )
|| TO_CHAR( ASCII( SUBSTR( chars, 7, 1 ) ) - 1, '00' ),
'YYYYMMDDHH24MISS'
) AS converted_date
FROM (
SELECT file_blob,
UTL_RAW.CAST_TO_VARCHAR2(DBMS_LOB.SUBSTR( file_blob, 7, 1 ) ) AS chars
FROM file_upload
);
Output:
DMP CONVERTED_DATE
------------------------------- -------------------
Typ=23 Len=7: 120,116,3,6,1,1,1 2016-03-06 00:00:00

Convert integer into percentage

I don't know how to convert integer into percentage, please help me. Thank you
Here's the query:
SELECT 'Data' || ',' ||
TO_CHAR(D.DTIME_DAY,'MM/dd/yyyy') || ',' ||
NVL(o.CNT_OPENED,0) || ',' || --as cnt_opened
NVL(c.CNT_CLOSED,0) --as cnt_closed
FROM OWNER_DWH.DC_DATE d
LEFT JOIN (SELECT TRUNC(t.CREATE_TIME, 'MM') AS report_date,
count(*) AS cnt_opened
FROM APP_ACCOUNT.OTRS_TICKET t
WHERE t.CREATE_TIME BETWEEN SYSDATE -120 AND SYSDATE
GROUP BY TRUNC(t.CREATE_TIME, 'MM')) o
ON d.DTIME_DAY=o.REPORT_DATE
LEFT JOIN (SELECT TRUNC(t.CLOSE_TIME, 'MM') as report_date,
count(*) AS cnt_closed
FROM APP_ACCOUNT.OTRS_TICKET t
WHERE t.CLOSE_TIME BETWEEN SYSDATE -120 AND SYSDATE
GROUP BY TRUNC(t.CLOSE_TIME, 'MM')) c
ON D.DTIME_DAY=c.REPORT_DATE
WHERE d.DTIME_DAY BETWEEN SYSDATE -120 AND TRUNC(SYSDATE) -1 AND
d.DTIME_DAY = TRUNC(d.DTIME_DAY, 'MM') AND
TRUNC(d.DTIME_DAY,'MM')= d.DTIME_DAY
ORDER BY D.DTIME_DAY;
The output of that query:
Data,10/01/2013,219,201
Data,11/01/2013,249,234
Data,12/01/2013,228,224
Data,01/01/2014,269,256
example output that I need is like this:
Data,10/01/2013,219, 52%, 201, 45%
Data,11/01/2013,249, 75%, 234, 60%
.......
........
Formula:
create_time + close time = total / create_time (for cnt_opened each column) = percentage
create_time + close time = total / close_time (for cnt_closed each column) = percentage
Try this:
Basically just add the total of CNT_OPENED and CNT_CLOSED, then whichever you want to take the percentage of, multiply that by 100 and divide by the sum.
For instance, CNT_OPENED = 219 and CNT_CLOSED = 201 so the total is 420. Multiply CNT_OPENED by 100 and then divide by 420 -> (219 * 100) / 420 = 52. Do the same thing with CNT_CLOSED.
Note that this WILL result in an exception if both CNT_OPENED and CNT_CLOSED are 0.
SELECT 'Data'
||','||TO_CHAR(D.DTIME_DAY,'MM/dd/yyyy')
||','||NVL(o.CNT_OPENED,0) --as cnt_opened
||','||(NVL(o.CNT_OPENED,0) * 100) / (NVL(o.CNT_OPENED,0) + NVL(o.CNT_CLOSED,0)) || '%'
||','||NVL(c.CNT_CLOSED,0) --as cnt_closed
||','||(NVL(o.CNT_CLOSED,0) * 100) / (NVL(o.CNT_OPENED,0) + NVL(o.CNT_CLOSED,0)) || '%'
That will also potentially give you a million decimal places, so if you only want to take it out to a couple, simply use the TRUNC function and specify your precision (2 decimal places in this case):
TRUNC((NVL(o.CNT_OPENED,0) * 100) / (NVL(o.CNT_OPENED,0) + NVL(o.CNT_CLOSED,0)), 2)

Resources