Using `each` to check whether all values are the same - ruby

Question

I'm trying to evaluate whether every space value is equal to either "X" or "O". Can I use each to do that? Is there a better way?
if #spaces.each {|x| x=="O" || x=="X"}
#winner = true
puts "It's a tie!"
break
end
ETA: all? doesn't seem to be working, either. I got this error referring to the line with the block:
tictac.rb:47: syntax error, unexpected '|', expecting '}'
{|x| x=="O" || x=="X"}
^
tictac.rb:47: syntax error, unexpected '}', expecting keyword_end
Here is the entire TicTacToe I'm working on:
class Board
def initialize
#spaces = [1, 2, 3, 4, 5, 6, 7, 8, 9]
self.print_board
#winner = false
#turn = "X"
end
def print_board
puts
puts " " + #spaces[0].to_s + " " + #spaces[1].to_s + " " + #spaces[2].to_s
puts " " + #spaces[3].to_s + " " + #spaces[4].to_s + " " + #spaces[5].to_s
puts " " + #spaces[6].to_s + " " + #spaces[7].to_s + " " + #spaces[8].to_s
puts
end
def mark(turn, move)
space = #spaces.index(move)
#spaces[space] = turn
self.print_board
end
def play
while #winner == false
puts "where would you like to put your #{#turn}?"
move = gets.chomp.to_i
self.mark(#turn, move)
if
#spaces[0] == #turn && #spaces[1] == #turn && #spaces[2] == #turn ||
#spaces[3] == #turn && #spaces[4] == #turn && #spaces[5] == #turn ||
#spaces[6] == #turn && #spaces[7] == #turn && #spaces[8] == #turn ||
#spaces[0] == #turn && #spaces[3] == #turn && #spaces[6] == #turn ||
#spaces[1] == #turn && #spaces[4] == #turn && #spaces[7] == #turn ||
#spaces[2] == #turn && #spaces[5] == #turn && #spaces[8] == #turn ||
#spaces[0] == #turn && #spaces[4] == #turn && #spaces[8] == #turn ||
#spaces[2] == #turn && #spaces[4] == #turn && #spaces[6] == #turn
#winner = true
puts "#{#turn} is the winner!"
break
elsif #spaces.all?
{|x| x=="O" || x=="X"}
#winner = true
puts "It's a tie!"
break
else
#turn == "X"? #turn = "O" : #turn = "X"
end
end
end
end
game = Board.new
game.play
I marked an answer that worked, and I guess all? was better than my each, but I'm still curious why changing it to all? didn't seem to work.

Answer 1

#spaces.all? { |x| x=="O" || x=="X" }
You cannot put a newline between a method call and its block. That makes Ruby think you're calling the method without a block and defining a Hash.

Answer 2

All elements of #spaces will be "O" or "X" if
(#spaces - ["O", "X"]).empty?
is true.
#spaces = ["O", "X", "X", "O"]
(#spaces - ["O", "X"]).empty?
#=> true
#spaces = ["O", "X", "X", "O", "cat"]
(#spaces - ["O", "X"]).empty?
#=> false

Answer 3

Chain Array#Uniq and Array#Size
Refactor your check into a method which takes an array of box entries (e.g. "X" or "O"), or a variable holding such an array. The method will return true if all letters in the array are the same, because there will only be one unique character. For example:
def check_spaces letters
true if letters.uniq.size == 1
end
check_spaces %w[X X X] #=> true
check_spaces %w[O O O] #=> true
check_spaces %w[O X O] #=> nil
If you do this, you can even assign the result of #check_spaces directly to #winner, like so:
#winner = check_spaces %w[X X X]
#=> true
#winner = check_spaces %w[X O X]
#=> nil