Need help validating if user input is a number - ruby

I have the following code:
def say(msg)
puts "=> #{msg}"
end
def do_math(num1, num2, operation)
case operation
when '+'
num1.to_i + num2.to_i
when '-'
num1.to_i - num2.to_i
when '*'
num1.to_i * num2.to_i
when '/'
num1.to_f / num2.to_f
end
end
say "Welcome to my calculator!"
run_calculator = 'yes'
while run_calculator == 'yes'
say "What's the first number?"
num1 = gets.chomp
say "What's the second number?"
num2 = gets.chomp
say "What would you like to do?"
say "Enter '+' for Addition, '-' for Subtraction, '*' for Multiplication, or '/' for Division"
operation = gets.chomp
if num2.to_f == 0 && operation == '/'
say "You cannot devide by 0, please enter another value!"
num2 = gets.chomp
else
result = do_math(num1, num2, operation)
end
say "#{num1} #{operation} #{num2} = #{result}"
say "Would you like to do another calculation? Yes / No?"
run_calculator = gets.chomp
if run_calculator.downcase == 'no'
say "Thanks for using my calculator!"
elsif run_calculator.downcase == 'yes'
run_calculator = 'yes'
else
until run_calculator.downcase == 'yes' || run_calculator.downcase == 'no'
say "Please enter yes or no!"
run_calculator = gets.chomp
end
end
end
I need it to take the num1 and num2 variables that the user inputs and validate that they are numbers and return a message if they aren't.
I would like to use a Regex, but I don't know if I should create a method for this or just wrap it in a loop.

The Integer method will raise an exception when the given string is not a valid number, whereas to_i will fail silently (which I think is not desired behavior):
begin
num = Integer gets.chomp
rescue ArgumentError
say "Invalid number!"
end
If you want a regex solution, this will also work (although I recommend the method above):
num = gets.chomp
unless num =~ /^\d+$/
say "Invalid number!"
end

You would often see each section written something like this:
ERR_MSG = "You must enter a non-negative integer"
def enter_non_negative_integer(instruction, error_msg)
loop do
puts instruction
str = gets.strip
return str.to_i if str =~ /^\d+$/
puts error_msg
end
end
x1 = enter_non_negative_integer("What's the first number?", ERR_MSG)
x2 = enter_non_negative_integer("What's the second number?", ERR_MSG)
Here's possible dialog:
What's the first number?
: cat
You must enter a non-negative integer
What's the first number?
: 4cat
You must enter a non-negative integer
What's the first number?
: 22
#=> 22
What's the second number?
: 51
#=> 51
x1 #=> 22
x2 #=> 51

Related

How to use a boolean for user input validation

Here's part of my code, the first part of the ˚ statement works, but I would like a separate message to appear for a non-numerical input such as "$boo", "ten", "idk").
puts "Candy Sold: "
candy_sold = gets.chomp.to_i
until candy_sold >= 0
if candy_sold < 0
puts "Please enter a positive number:"
candy_sold = gets.chomp.to_i
elsif candy_sold.class == String # This is where the issue is
puts "Please enter a positive number:"
candy_sold = gets.chomp.to_i
end
end
If I am understanding your question correct, you just want to allow only positive numbers. In this case, you can use the cover? method with a range.
puts "Candy Sold: "
candy_sold = gets.chomp
until ('0'..'9').cover? candy_sold
puts "Please enter a positive number"
candy_sold = gets.chomp
end
Candy Sold:
> Hello
=> Please enter a positive number
> -97
=> Please enter a positive number
> -0
=> Please enter a positive number
> 1
=> nil
If you check already converted number there is no way to tell if it was initially valid format or not. You have to compare with initial input somehow.
One of the solutions:
ask_for_amount = true
while ask_for_amount
candy_number_input = gets.chomp.strip
candy_sold = candy_number_input.to_i
if candy_number_input != candy_sold.to_s
puts "Please enter a valid positive number:"
elsif candy_sold < 0
puts "Please enter a positive number:"
else
ask_for_amount = false
end
end

How to add a loop in calculator program

I created a calculator in ruby. I am wondering how to put this in a loop so I don't have to run it constantly. I am new to programming so please understand I am I just trying to learn. I would appreciate any help provided.
puts "Hello, My name is Calvin The Calculator and I am a calculator that can do basic functions such as Adding, Subtracting, Multiplying and Dividing"
puts "Press a and enter to enable my services"
enable = gets.chomp
if enable == "a"
puts "Choose which operation you want to do. + for adding, - for subtraction, * for multiplication and / for division"
else
"Puts Im Waiting..."
end
which_operation = gets.chomp
if which_operation == "+"
puts "What is the first number you want to add"
adding_first_number = gets.chomp.to_i
puts "What is the second number you want to add to #{adding_first_number}"
adding_second_number = gets.chomp.to_i
puts "#{adding_first_number} + #{adding_second_number} is #{adding_first_number + adding_second_number}"
else
end
if which_operation == "-"
puts "What is the first number you want to subtract"
subtracting_first_number = gets.chomp.to_i
puts "What is the number you want to subtract from #{subtracting_first_number}"
subtracting_second_number = gets.chomp.to_i
puts "#{subtracting_first_number} - #{subtracting_second_number} is #{subtracting_first_number - subtracting_second_number}"
else
end
if which_operation == "*"
puts "What is the first number you want to multiple"
multiplying_first_number = gets.chomp.to_i
puts "What is the number you want to multiple #{multiplying_first_number} by"
multiplying_second_number = gets.chomp.to_i
puts "#{multiplying_first_number} * by #{multiplying_second_number} is #{multiplying_first_number * multiplying_second_number}"
else
end
if which_operation == "/"
puts "What is the first number to your divison question?"
dividing_first_number = gets.chomp.to_i
puts "What is the divisor?"
dividing_second_number = gets.chomp.to_i
puts "#{dividing_first_number} divided by #{dividing_second_number} is #{dividing_first_number / dividing_second_number}"
else
end
For example:
until (which_operation = gets.chomp).empty?
if which_operation == "+"
...
end
if which_operation == "-"
...
end
if which_operation == "*"
...
end
if which_operation == "/"
...
end
end
This loop will work until you press Enter without entering any text before it.
P.S.: Better use case operator instead of multiple if.
P.P.S.: All your code, after loop addition and without case operator, will be:
puts "Hello, My name is Calvin The Calculator and I am a calculator that can do basic functions such as Adding, Subtracting, Multiplying and Dividing"
puts "Press a and enter to enable my services"
until gets.chomp == "a"
puts "I'm Waiting..."
end
puts "Choose which operation you want to do. + for adding, - for subtraction, * for multiplication and / for division"
until (which_operation = gets.chomp).empty?
if which_operation == "+"
puts "What is the first number you want to add"
adding_first_number = gets.chomp.to_i
puts "What is the second number you want to add to #{adding_first_number}"
adding_second_number = gets.chomp.to_i
puts "#{adding_first_number} + #{adding_second_number} is #{adding_first_number + adding_second_number}"
elsif which_operation == "-"
puts "What is the first number you want to subtract"
subtracting_first_number = gets.chomp.to_i
puts "What is the number you want to subtract from #{subtracting_first_number}"
subtracting_second_number = gets.chomp.to_i
puts "#{subtracting_first_number} - #{subtracting_second_number} is #{subtracting_first_number - subtracting_second_number}"
elsif which_operation == "*"
puts "What is the first number you want to multiple"
multiplying_first_number = gets.chomp.to_i
puts "What is the number you want to multiple #{multiplying_first_number} by"
multiplying_second_number = gets.chomp.to_i
puts "#{multiplying_first_number} * by #{multiplying_second_number} is #{multiplying_first_number * multiplying_second_number}"
elsif which_operation == "/"
puts "What is the first number to your divison question?"
dividing_first_number = gets.chomp.to_i
puts "What is the divisor?"
dividing_second_number = gets.chomp.to_i
puts "#{dividing_first_number} divided by #{dividing_second_number} is #{dividing_first_number / dividing_second_number}"
end
puts "\nLet's try again: "
end

Check if a number entered by the user with gets.chomp is a float in ruby [duplicate]

This question already has answers here:
Determine if a string is a valid float value
(9 answers)
Closed 5 years ago.
I have looked for this a long time now and can't find a satisfactory answer.
I wold like to know how can I check if the number entered by the user is a float. If is a float it is supposed to be an invalid number.
I have something but the result is always true/Integer
Here is what I have so far.
puts "What are the first number you want to divide"
number1 = gets.chomp.to_i
puts "What is the second number?"
number2 = gets.chomp.to_i
def is_float(variable)
return variable % 1 == 0
end
if (number1 == 0) && (number2 == 0)
puts "Invalid input"
elsif (is_float(number1) == false) || (is_float(number2) == false)
puts "Invalid input"
else
def divide(number1, number2)
return number1 / number2
end
division_result = divide(number1, number2)
def reminder(number1, number2)
return number1 % number2
end
reminder_results = reminder(number1, number2)
puts ""
puts "Your result is #{division_result}"
puts "Your reminder is #{reminder_results}"
end
puts "What are the first number you want to divide"
number1 = gets.chomp.to_i
=> 100
puts "What is the second number?"
number2 = gets.chomp.to_i
=> 3
# Regular math
result_a = number1 / number2
puts "#{number1} / #{number2} = #{result_a}"
=> 100 / 3 = 33 # Integer class persists...
# Use a ruby library instead! Numeric#divmod
result_b = number1.divmod(number2)
puts "Result: #{result_b}"
=> [33, 1] # [quotient, modulus]

Programming a basic calculator in Ruby

This is my first foray into computer programming. I have chosen to learn Ruby, and I am enjoying it quite a bit. However, I am a little confused as to why the answer will not output properly in this bit of code.
def addition_function
puts "Which numbers would you like to add?"
#n1 = gets.chomp
#n2 = gets.chomp
#n1 + #n2 == #answer
puts "The sum is... #{#answer}"
end
def subtraction_function
puts "Which numbers would you like to subtract?"
#n1 = gets.chomp.to_i
#n2 = gets.chomp.to_i
#n1 - #n2 == #answer
puts "The answer is... #{#answer}"
end
def multiplication_function
puts "Which numbers would you like to multiply?"
#n1 = gets.chomp
#n2 = gets.chomp
#n1 * #n2 == #answer
puts "The answer is... #{#answer}"
end
puts "Would you like to [add], [multiply], or [subtract]?"
response = gets.chomp
if response == "add" then
addition_function
end
if response == "subtract" then
subtraction_function
end
if response == "multiply" then
multiplication_function
end
I know this is probably horrible code... but could someone help steer me in the right direction?
Consider this code:
def get_int_values
[gets, gets].map{ |s| s.chomp.to_i }
end
puts "Would you like to [add], [multiply], or [subtract]?"
response = gets.chomp
case response.downcase
when 'add'
puts "Which numbers would you like to add?"
operator = :+
when 'subtract'
puts "Which numbers would you like to subtract?"
operator = :-
when 'multiply'
puts "Which numbers would you like to multiply?"
operator = :*
end
answer = get_int_values.inject(operator)
puts "The answer is... #{ answer }"
The idea is to follow the "DRY" principle: "DRY" means "Don't Repeat Yourself", which the vast majority of the time, is a really good thing.
To help avoid typing mistakes I'd recommend doing something like:
puts "Would you like to [a]dd, [m]ultiply, or [s]ubtract?"
response = gets.chomp
case response[0].downcase
then change the when clauses to match the first letter of the desired operation.
Which will work unless response is empty. You can figure out how to handle that.
another way to obtain answer, once operator is determined, is answer = gets.to_i.send(operator, gets.to_i)
That's true, but here's why I refactored the code the way I did: If, for some reason, there was a need to operate on more than two values, only one thing has to be changed:
[gets, gets].map{ |s| s.chomp.to_i }
could become:
[gets, gets, gets].map{ |s| s.chomp.to_i }
Or, better, could be transformed to something like:
def get_int_values(n)
n.times.map { gets.chomp.to_i }
end
Nothing else will have to change except to find out how many values are needed.
Now, to do it all right would require different text to alert the user that multiple values are expected, but that's easily done by letting letting the user say how many they want to enter, and then prompting for each gets:
def get_int_values(n)
n.times.map.with_index { |n|
print "Enter value ##{ 1 + n }: "
gets.chomp.to_i
}
end
puts "Would you like to [add], [multiply], or [subtract]?"
response = gets.chomp
puts "How many values?"
num_of_values = gets.to_i
case response.downcase
when 'add'
puts "Which numbers would you like to add?"
operator = :+
when 'subtract'
puts "Which numbers would you like to subtract?"
operator = :-
when 'multiply'
puts "Which numbers would you like to multiply?"
operator = :*
end
answer = get_int_values(num_of_values).inject(operator)
puts "The answer is... #{ answer }"
inject can scale up easily because it doesn't presuppose knowledge about the number of values being operated on.
I think with_index in n.times.map.with_index is an artifact you forgot to delete.
It was deliberate but I like this better:
def get_int_values(n)
1.upto(n).map { |n|
print "Enter value ##{ n }: "
gets.chomp.to_i
}
end
Your assignments are on the wrong side of the statement. You should have answer = n1 * n2,
which is not the same as answer == n1 * n2 (this is a check for equality, using ==). The expression always goes on the right, and the variable the result is assigned to goes on the left -- this is pretty much universal, but not necessarily intuitive coming from algebra.
Also: using an # prior to a variable name differentiates it as an instance variable, or member, of a class. From what you've shown here you don't need to include those, just normally scoped variables are required for this use.
Check out this question for more on that part.
The "#" sigil is used to indicate a class instance variable, you have no class so don't use it.
#n1 + #n2 == #answer
Is a boolean expression evaluating whether #n1 + #n2 is equal to #answer.
It will evaluate to true or false.... but you don't make use of the answer.
What you want is ...
answer = n1 + n2
I strongly recommend you always run Ruby with the -w option. It will save you much much heartache.
Please indent your "end"'s to match your "def" (or "if").
You repeat n1 = gets.chomp.to_i all over the place, do it once and pass the answers as a parameter...
response = gets.chomp
n1 = gets.chomp.to_i
n2 = gets.chomp.to_i
if response == "add" then
addition_function( n1, n2)
elsif...
A few suggestions not mentioned by others:
Shorten your method (not "function") names and use verbs (e.g., add instead of addition_method).
As well as using local variables rather than instance variables (mentioned by others), eliminate them where you can. For example, you could simplify
.
def add
puts "Which numbers would you like to add?"
n1 = gets.to_i
n2 = gets.to_i
answer = n1 + n2
puts "The sum is... #{answer}"
end
to
def add
puts "Which numbers would you like to add?"
puts "The sum is... #{gets.to_i + gets.to_i}"
end
Notice I've used the Ruby convention of indenting two spaces.
You don't need chomp here (though it does no harm), because "123followed by \n or any other non-digits".to_i => 123.
A case statement would work well at the end (and let's loop until the user chooses to quit):
.
loop do
puts "Would you like to [add], [multiply], [subtract] or [quit]?"
case gets.chomp
when "add"
add
when "subtract"
subtract
when "multiply"
multiply
when "quit"
break
end
or just
def quit() break end
loop do
puts "Would you like to [add], [multiply], [subtract] or [quit]?"
send(gets.chomp)
end
Here we do need chomp. You could replace loop do with while true do or use other equivalent constructs.
class Calculator
def Calc
puts"==well come to mobiloitte calculator=="
puts "enter the first operand:"
#op1 = gets.chomp
return if #op1=="q"
#o1=#op1.to_i
puts "entre the second operand:"
#op2 = gets.chomp
return if #op2=="q"
#o2=#op2.to_i
strong text puts "enter any one operator of your choice (add,sub,mul,div,mod)"
operator = gets.chomp
case operator
when 'add' then #s=#o1+#o2 ; puts "\n ##o1 + ##o2 =##s"
when 'sub' then #t=#o1-#o2 ; puts "\n ##o1 - ##o2 =##t"
when 'mul' then #l=#o1*#o2 ; puts "\n ##o1 * ##o2 =##l"
when 'div' then #r=#o1/#o2 ; puts "\n ##o1 \ ##o2 =##r"
when 'md' then #d=#o1%#o2 ; puts "\n ##o1 % ##o2 =##d"
else
puts"invalide input"
end
end
end
obj= Calculator.new
$f=obj.Calc
You are using #n1 + #n2 == #answer to try and set the answer. What you want to do is #answer = #n1 + #n2.
= is assignment, == is a comparison operator.
Also, you will need to #n1 = gets.chomp.to_i. This will convert your input to an integer from a string. Do that with #n2 as well.
You also do not need to use the # before each of your variables. That should only be used when you are dealing with classes, which you do not appear to be doing.
print "enter number 1 : "
n1 = gets.chomp.to_f
print "enter number 2 : "
n2 = gets.chomp.to_f
print "enter operator: "
op = gets.chomp
if op == '+'
puts "#{n1} + #{n2} = #{n1 + n2}"
elsif op == '-'
puts "#{n1} - #{n2} = #{n1 - n2}"
elsif op == '*'
puts "#{n1} * #{n2} = #{n1 * n2}"
elsif op == '/'
puts "#{n1} / #{n2} = #{n1 / n2}"
end
puts "Would you like to
0 ---- [exit],
1 ---- [add],
2 ---- [subtract],
3 ---- [multiply],
4 ---- [divide]"
response = gets.chomp
case response.downcase
when '1'
def addition_function
puts "Which numbers would you like to add?"
n1 = gets.to_i
n2 = gets.to_i
answer = n1 + n2
puts "The sum is... #{n1} + #{n2} = #{answer}"
end
addition_function()
#Subtract
when '2'
def subtraction_function
puts "Which numbers would you like to subtact?"
n1 = gets.to_i
n2 = gets.to_i
answer = n1 - n2
puts "The subtraction is... #{n1} - #{n2} = #{answer}"
end
subtraction_function()
#Multiply
when '3'
def multiplication_function
puts "Which numbers would you like to multiply?"
n1 = gets.to_i
n2 = gets.to_i
answer = n1 * n2
puts "The multiplication is... #{n1} * #{n2} = #{answer}"
end
multiplication_function()
#Division
when '4'
def division_function
puts "Which numbers would you like to divide?"
n1 = gets.to_i
n2 = gets.to_i
answer = n1 / n2
puts "The division is... #{n1} / #{n2} = #{answer}"
end
division_function()
else '0'
puts "Exit! Thank You for using us!"
end
#ruby script to do the calculator
puts " enter the number1"
in1=gets.to_i
puts " enter the number2"
in2=gets.to_i
puts "enter the operator"
op=gets.chomp
case op
when '+'
plus=in1+in2
puts "#{in1+in2}"
#puts "#{plus}"
when '-'
min=in1-in2
puts "#{min}"
when '*'
mul= in1*in2
puts "#{mul}"
when '/'
div=in1/in2
puts "#{div}"
else
puts "invalid operator"
end
begin
puts 'First number:'
a = $stdin.gets.chomp.to_i
puts 'Second number:'
b = $stdin.gets.chomp.to_i
operation = nil
unless ['+', '-', '*', '/', '**'].include?(operation)
puts 'Choose operation: (+ - * /):'
operation = $stdin.gets.chomp
end
result = nil
success = false
case operation
when '+'
result = (a + b).to_s
when '-'
result = (a - b).to_s
when '*'
result = (a * b).to_s
when '/'
result = (a / b).to_s
when '**'
result = (a**b).to_s
else
puts 'There is not such kind of operation'
end
success = true
puts "Результат: #{result}"
rescue ZeroDivisionError => e
puts "You tried to devide number by zero! Error: #{e.message}"
end
if success
puts "\nSuccess!"
else
puts "\nSomething goes wrong :("
end
puts ("plz enter a number :")
num1 = gets.chomp.to_f
puts ("plz enter a another number")
num2 = gets.chomp.to_f
puts ("plz enter the operation + , - , x , / ")
opp = gets.chomp
if opp == "+"
puts (num1 + num2)
elsif opp == "-"
puts (num1 - num2)
elsif opp == "x"
puts (num1 * num2)
elsif opp == "/"
puts (num1 / num2)
else puts ("try again :|")
end

Regular expression to match number formats

I'm trying to write a small program that asks a user to input a number and the program will determine if it's a valid number. The user can enter any kind of number (integer, float, scientific notation, etc.).
My question is what regular expression should be used to keep something like "7w" from being matched as a valid number? Also I would like the number 0 to exit the loop and end the program, but as it's written now 0 is matching valid like any other number. Any insight please?
x = 1
while x != 0
puts "Enter a string"
num = gets
if num.match(/\d+/)
puts "Valid"
else
puts "invalid"
end
if num == 0
puts "End of program"
x = num
end
end
You need to execute this script from the command line, not a text editor, as you will be prompt to enter a number.
This is the ultra compact version
def validate(n)
if (Float(n) != nil rescue return :invalid)
return :zero if n.to_f == 0
return :valid
end
end
print "Please enter a number: "
puts "#{num = gets.strip} is #{validate(num)}"
Output:
Please enter a number: 00
00 is zero
Here is a longer version that problably you can extend it to tweak it to your needs.
class String
def numeric?
Float(self) != nil rescue false
end
end
def validate(n)
if n.numeric?
return :zero if n.to_f == 0
return :valid
else
return :invalid
end
end
print "Please enter a number: "
puts "#{num = gets.strip} is #{validate(num)}"
And here is a test for all the possible cases
test_cases = [
"33", #int pos
"+33", #int pos
"-33", #int neg
"1.22", #float pos
"-1.22", #float neg
"10e5", #scientific notation
"X", #STRING not numeric
"", #empty string
"0", #zero
"+0", #zero
"-0", #zero
"0.00000", #zero
"+0.00000", #zero
"-0.00000", #zero
"-999999999999999999999995444444444444444444444444444444444444434567890.99", #big num
"-1.2.3", #version number
" 9 ", #trailing spaces
]
puts "\n** Test cases **"
test_cases.each do |n|
puts "#{n} is #{validate(n)}"
end
Which outputs:
Please enter a number: 12.34
12.34 is valid
** Test cases ** 33 is valid
+33 is valid
-33 is valid
1.22 is valid
-1.22 is valid
10e5 is valid
X is invalid
is invalid
0 is zero
+0 is zero
-0 is zero
0.00000 is zero
+0.00000 is zero
-0.00000 is zero
-999999999999999999999995444444444444444444444444444444444444434567890.99 is valid
-1.2.3 is invalid
9 is valid
Source for the idea of checking if its numeric:
How can I see if the string is numeric?
http://mentalized.net/journal/2011/04/14/ruby_how_to_check_if_a_string_is_numeric/
To start with, you are overcomplicating the loop, secondly, your regular expression needs to be a bit more explicit. Try something like this:
x = 1
while x != 0
puts "Enter a string"
num = gets.chomp
if num == "0"
puts "exiting with 0"
exit 0
elsif num.match(/^[0-9](\.[0-9])?$+/)
puts "Valid"
else
puts "invalid"
end
end
This expression will match any number that contains a digit or a decimal, and will fail to match anything containing letters. If the string entered is exactly 0, the script will exit with status 0.

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