visual foxpro escape double quote - visual-foxpro

My application creates free foxpro tables and inserts data into them. I get a Syntax Error when inserting a string that has double quotes in it.
here is the string that causes the issue - "TAIL LAMPS-HEIGHT BETWEEN 15" AND 72"". I have tried escaping the double quotes with a /, single quote, a double quote, but nothing helped.
Is there any other way to fix this issue?
any help is much appreciated.
thanks.
This is my insert statement
INSERT INTO NAMEMAIN (ACCIDENT,CHARGE,YEARSTAMP,ZIP,ZONE) VALUES ("1", "TAIL LAMPS-HEIGHT BETWEEN 15\" AND 72\"", 0, " ", "OVPK")

It would be better to see the insert statement you are trying to do. The insert should be from variable references rather than hard strings.
lcSomePart = Thisform.txtboxDescription.Value
insert into YourTable ( somePartField ) values ( lcSomePart )
It should work no problem, but again, without your example, hard to confirm what you are running into.
Another way is VFP allows multiple options to wrap strings if you had it hard-code referenced, such as
lcSomePart = [TAIL LAMPS-HEIGHT BETWEEN 15" and 72"]
lcSomePart = 'TAIL LAMPS-HEIGHT BETWEEN 15" and 72"'
Both versions above work. VFP uses square brackets to identify start/end of a string (as long as they are paired). Also allows single-quotes to act as start/end of string. And if you have a string that has a single-quote within, just use either square or double-quote in the same fashion.
Change your insert to the following, but strongly suggest variables for inserts, especially if coming from data entry fields, but notice, VFP does not do escaping characters, but I changed to just using the square brackets around the string insert..
INSERT INTO NAMEMAIN (ACCIDENT,CHARGE,YEARSTAMP,ZIP,ZONE) VALUES ("1", [TAIL LAMPS-HEIGHT BETWEEN 15" AND 72"], 0, " ", "OVPK")

But what if you have all 3 kinds of delimiters in your text? In that case you can use
lcSomePart = [TAIL [LAMPS-HEIGHT] + ']' + [ BETWEEN "15" and '72']
which results in lcSomePart becoming
TAIL [LAMPS-HEIGHT] BETWEEN "15" and '72'
I perform FoxPro queries from C++ and my FoxPro escape function in my own string class looks like this:
MyString& MyString::doSQLFPEscape() {
for (size_t i=0; i<this->iLen; i++) {
if (this->c_str()[i] == ']') {
this->doInsert("+']'+[", i+1);
i += 5;
}
}
this->doInsert("[").add("]");
return *this;
}

Related

How can I use 'update where' select in FoxPro?

I am totally new to FoxPro (and quite fluent with MySQL).
I am trying to execute this query in FoxPro:
update expertcorr_memoinv.dbf set 'Memo' = (select 'Memo' from expertcorr_memoinv.dbf WHERE Keymemo='10045223') WHERE Keydoc like "UBOA"
I got the error:
function name is missing )
How can I fix it?
In FoxPro SQL statements you would not 'single-quote' column names. In Visual FoxPro version 9 the following sequence would run without errors:
CREATE TABLE expertcorr_memoinv (keydoc Char(20), keymemo M, Memo M)
Update expertcorr_memoinv.dbf set Memo = (select Memo from expertcorr_memoinv.dbf WHERE Keymemo='10045223') WHERE Keydoc like "UBOA"
If you would provide a few sample data and an expected result, we could see whether the line you posted would do what you want after correcting the single-quoted 'Memo' names.
NB 1: "Memo" is a reserved word in FoxPro.
NB 2: As you know, the ";" semicolon is a line-continuation in Visual FoxPro, so that a longer SQL statement can be full; of; those;
So that the Update one-liner could be written as:
Update expertcorr_memoinv ;
Set Memo = (Select Memo From expertcorr_memoinv ;
WHERE Keymemo='10045223') ;
WHERE Keydoc Like "UBOA"
NB 3: Alternatively, you can SQL Update .... From... in Visual FoxPro, similar to the Microsoft SQL Server feature. See How do I UPDATE from a SELECT in SQL Server?
I would do that just as Stefan showed.
In VFP, you also have a chance to use non-SQL statements which make it easier to express yourself. From your code it feels like KeyMemo is a unique field:
* Get the Memo value into an array
* where KeyMemo = '10045223'
* or use that as a variable also
local lcKey
lcKey = '10045223'
Select Memo From expertcorr_memoinv ;
WHERE Keymemo=m.lcKey ;
into array laMemo
* Update with that value
Update expertcorr_memoinv ;
Set Memo = laMemo[1] ;
WHERE Keydoc Like "UBOA"
This is only for divide & conquer strategy that one may find easier to follow. Other than that writing it with a single SQL is just fine.
PS: In VFP you don't use backticks at all.
Single quotes, double quotes and opening closing square brackets are not used as identifiers but all those three are used for string literals.
'This is a string literal'
"This is a string literal"
[This is a string literal]
"My name is John O'hara"
'We need 3.5" disk'
[Put 3.5" disk into John's computer]
There are subtle differences between them, which I think is an advanced topic and that you may never need to know.
Also [] is used for array indexer.
Any one of them could also be used for things like table name, alias name, file name ... (name expression) - still they are string literals, parentheses make it a name expression. ie:
select * from ('MyTable') ...
copy to ("c:\my folder\my file.txt") type delimited

Oracle SQL: Using Replace function while Inserting

I have a query like this:
INSERT INTO TAB_AUTOCRCMTREQUESTS
(RequestOrigin, RequestKey, CommentText) VALUES ('Tracker', 'OPM03865_0', '[Orange.Security.OrangePrincipal]
em[u02650791]okok
it's friday!')
As expected it is throwing an error of missing comma, due to this it's friday! which has a single quote.
I want to remove this single quote while inserting using Replace function.
How can this be done?
Reason for error is because of the single Quote. In order to correct it, you shall not remove the single quote instead you need to add one more i.e. you need to make it's friday to it''s friday while inserting.
If you need to replace it for sure, then try the below code :
insert into Blagh values(REPLACE('it''s friday', '''', ''),12);
I would suggest using Oracle q quote.
Example:
INSERT INTO TAB_AUTOCRCMTREQUESTS (RequestOrigin, RequestKey, CommentText)
VALUES ('Tracker', 'OPM03865_0',
q'{[Orange.Security.OrangePrincipal] em[u02650791]okok it's friday!}')
You can read about q quote here.
To shorten this article you will follow this format: q'{your string here}' where "{" represents the starting delimiter, and "}" represents the ending delimiter. Oracle automatically recognizes "paired" delimiters, such as [], {}, (), and <>. If you want to use some other character as your start delimiter and it doesn't have a "natural" partner for termination, you must use the same character for start and end delimiters.
Obviously you can't user [] delimiters because you have this in your queries. I sugest using {} delimiters.
Of course you can use double qoute in it it''s with replace. You can omit last parameter in replace because it isn't mandatory and without it it automatically will remove ' character.
INSERT INTO TAB_AUTOCRCMTREQUESTS (CommentText) VALUES (REPLACE('...it''s friday!', ''''))
Single quotes are escaped by doubling them up
INSERT INTO Blagh VALUES(REPLACE('it''s friday', '''', ''),12);
You can try this, (sorry but I don't know why q'[ ] works)
INSERT INTO TAB_AUTOCRCMTREQUESTS
(RequestOrigin, RequestKey, CommentText) VALUES ('Tracker', 'OPM03865_0', q'[[Orange.Security.OrangePrincipal] em[u02650791]okok it's friday!]')
I just got the q'[] from this link Oracle pl-sql escape character (for a " ' ") - this question could be a possible duplicate

How to read csv using LINQ ,some columns contain ,

i have a CSV in the below way. "India,Inc" is a company name which is single value which contains , in it
How to Get the Values in LINQ
12321,32432,423423,Kevin O'Brien,"India,Inc",234235,23523452,235235
Assuming that you will always have the columns that you specify and that the only variable is that company name can have commas inside, this UGLY code can help you achieve your goal.
var file = File.ReadLines("test.csv");
var value = from p in file
select new string[]
{ p.Split(',')[0],
p.Split(',')[1],
p.Split(',')[2],
p.Split(',')[3],
p.Split(',').Count() == 7 ? p.Split(',')[4] :
(p.Split(',').Count() > 7 ? String.Join(",",p.Split(',').Skip(4).Take(p.Split(',').Count() - 7).ToArray() ) : ""),
p.Split(',')[p.Split(',').Count() - 3],
p.Split(',')[p.Split(',').Count() - 2],
p.Split(',')[p.Split(',').Count() - 1]
};
A regular expression would work, bit nasty due to the recursive nature but it does achieve your goal.
List<string> matches = new List<string>();
string subjectString = "12321,32432,423423,Kevin O'Brien,\"India,Inc\",234235,23523452,235235";
Regex regexObj = new Regex(#"(?<="")\b[123456789a-z,']+\b(?="")|[123456789a-z']+", RegexOptions.IgnoreCase);
Match matchResults = regexObj.Match(subjectString);
while (matchResults.Success)
{
matches.Add(matchResults.Value);
// matched text: matchResults.Value
// match start: matchResults.Index
// match length: matchResults.Length
matchResults = matchResults.NextMatch();
}
This should suffice in most cases. It handles quoted strings, strings with double quotes within them, and embedded commas.
var subjectString = "12321,32432,423423,Kevin O'Brien,\"India,Inc\",234235,\"Test End\"\"\",\"\"\"Test Start\",\"Test\"\"Middle\",23523452,235235";
var result=Regex.Split(subjectString,#",(?=(?:[^""]*""[^""]*"")*[^""]*$)")
.Select(x=>x.StartsWith("\"") && x.EndsWith("\"")?x.Substring(1,x.Length-2):x)
.Select(x=>x.Replace("\"\"","\""));
It does however break, if you have a field with a single double quote inside it, and the string itself is not enclosed in double quotes -- this is invalid in most definitions of a CSV file, where any field that contains CR, LF, Comma, or Double quote must be enclosed in double quotes.
You should be able to reuse the same Regex expression to break on lines as well for small CSV files. Larger ones you would want a better implementation. Replace the double quotes with LF, and remove the matching ones (unquoted LF's). Then use the regular expression again replacing the quotes with CR, and split on matching.
Another option is to use CSVHelper and not traying to reinvent the wheel
var csv = new CsvHelper.CsvReader(new StreamReader("test.csv"));
while (csv.Read())
{
Console.WriteLine(csv.GetField<int>(0));
Console.WriteLine(csv.GetField<string>(1));
Console.WriteLine(csv.GetField<string>(2));
Console.WriteLine(csv.GetField<string>(3));
Console.WriteLine(csv.GetField<string>(4));
}
Guide
I would recommend LINQ to CSV, because it is powerful enough to handle special characters including commas, quotes, and decimals. They have really worked a lot of these issues out for you.
It only takes a few minutes to set up and it is really worth the time because you won't run into these types of issues down the road like you would with custom code. Here are the basic steps, but definitely follow the instructions in the link above.
Install the Nuget package
Create a class to represent a line item (name the fields the way they're named in the csv)
Use CsvContext.Read() to read into an IEnumerable which you can easily manipulate with LINQ
Use CsvContext.Write() to write a List or IEnumerable to a CSV
This is very easy to setup, has very little code, and is much more scalable than doing it yourself.
becuase you're only reading values delminated bycommas, the spaces shouldn't cause an issue if you just treat them like any other character.
var values = File.ReadLines(path)
SelectMany(line => line.Split(','));

Ruby RegEx Commas Within Quotes [duplicate]

I would like to find a regex that will pick out all commas that fall outside quote sets.
For example:
'foo' => 'bar',
'foofoo' => 'bar,bar'
This would pick out the single comma on line 1, after 'bar',
I don't really care about single vs double quotes.
Has anyone got any thoughts? I feel like this should be possible with readaheads, but my regex fu is too weak.
This will match any string up to and including the first non-quoted ",". Is that what you are wanting?
/^([^"]|"[^"]*")*?(,)/
If you want all of them (and as a counter-example to the guy who said it wasn't possible) you could write:
/(,)(?=(?:[^"]|"[^"]*")*$)/
which will match all of them. Thus
'test, a "comma,", bob, ",sam,",here'.gsub(/(,)(?=(?:[^"]|"[^"]*")*$)/,';')
replaces all the commas not inside quotes with semicolons, and produces:
'test; a "comma,"; bob; ",sam,";here'
If you need it to work across line breaks just add the m (multiline) flag.
The below regexes would match all the comma's which are present outside the double quotes,
,(?=(?:[^"]*"[^"]*")*[^"]*$)
DEMO
OR(PCRE only)
"[^"]*"(*SKIP)(*F)|,
"[^"]*" matches all the double quoted block. That is, in this buz,"bar,foo" input, this regex would match "bar,foo" only. Now the following (*SKIP)(*F) makes the match to fail. Then it moves on to the pattern which was next to | symbol and tries to match characters from the remaining string. That is, in our output , next to pattern | will match only the comma which was just after to buz . Note that this won't match the comma which was present inside double quotes, because we already make the double quoted part to skip.
DEMO
The below regex would match all the comma's which are present inside the double quotes,
,(?!(?:[^"]*"[^"]*")*[^"]*$)
DEMO
While it's possible to hack it with a regex (and I enjoy abusing regexes as much as the next guy), you'll get in trouble sooner or later trying to handle substrings without a more advanced parser. Possible ways to get in trouble include mixed quotes, and escaped quotes.
This function will split a string on commas, but not those commas that are within a single- or double-quoted string. It can be easily extended with additional characters to use as quotes (though character pairs like « » would need a few more lines of code) and will even tell you if you forgot to close a quote in your data:
function splitNotStrings(str){
var parse=[], inString=false, escape=0, end=0
for(var i=0, c; c=str[i]; i++){ // looping over the characters in str
if(c==='\\'){ escape^=1; continue} // 1 when odd number of consecutive \
if(c===','){
if(!inString){
parse.push(str.slice(end, i))
end=i+1
}
}
else if(splitNotStrings.quotes.indexOf(c)>-1 && !escape){
if(c===inString) inString=false
else if(!inString) inString=c
}
escape=0
}
// now we finished parsing, strings should be closed
if(inString) throw SyntaxError('expected matching '+inString)
if(end<i) parse.push(str.slice(end, i))
return parse
}
splitNotStrings.quotes="'\"" // add other (symmetrical) quotes here
Try this regular expression:
(?:"(?:[^\\"]+|\\(?:\\\\)*[\\"])*"|'(?:[^\\']+|\\(?:\\\\)*[\\'])*')\s*=>\s*(?:"(?:[^\\"]+|\\(?:\\\\)*[\\"])*"|'(?:[^\\']+|\\(?:\\\\)*[\\'])*')\s*,
This does also allow strings like “'foo\'bar' => 'bar\\',”.
MarkusQ's answer worked great for me for about a year, until it didn't. I just got a stack overflow error on a line with about 120 commas and 3682 characters total. In Java, like this:
String[] cells = line.split("[\t,](?=(?:[^\"]|\"[^\"]*\")*$)", -1);
Here's my extremely inelegant replacement that doesn't stack overflow:
private String[] extractCellsFromLine(String line) {
List<String> cellList = new ArrayList<String>();
while (true) {
String[] firstCellAndRest;
if (line.startsWith("\"")) {
firstCellAndRest = line.split("([\t,])(?=(?:[^\"]|\"[^\"]*\")*$)", 2);
}
else {
firstCellAndRest = line.split("[\t,]", 2);
}
cellList.add(firstCellAndRest[0]);
if (firstCellAndRest.length == 1) {
break;
}
line = firstCellAndRest[1];
}
return cellList.toArray(new String[cellList.size()]);
}
#SocialCensus, The example you gave in the comment to MarkusQ, where you throw in ' alongside the ", doesn't work with the example MarkusQ gave right above that if we change sam to sam's: (test, a "comma,", bob, ",sam's,",here) has no match against (,)(?=(?:[^"']|["|'][^"']")$). In fact, the problem itself, "I don't really care about single vs double quotes", is ambiguous. You have to be clear what you mean by quoting either with " or with '. For example, is nesting allowed or not? If so, to how many levels? If only 1 nested level, what happens to a comma outside the inner nested quotation but inside the outer nesting quotation? You should also consider that single quotes happen by themselves as apostrophes (ie, like the counter-example I gave earlier with sam's). Finally, the regex you made doesn't really treat single quotes on par with double quotes since it assumes the last type of quotation mark is necessarily a double quote -- and replacing that last double quote with ['|"] also has a problem if the text doesn't come with correct quoting (or if apostrophes are used), though, I suppose we probably could assume all quotes are correctly delineated.
MarkusQ's regexp answers the question: find all commas that have an even number of double quotes after it (ie, are outside double quotes) and disregard all commas that have an odd number of double quotes after it (ie, are inside double quotes). This is generally the same solution as what you probably want, but let's look at a few anomalies. First, if someone leaves off a quotation mark at the end, then this regexp finds all the wrong commas rather than finding the desired ones or failing to match any. Of course, if a double quote is missing, all bets are off since it might not be clear if the missing one belongs at the end or instead belongs at the beginning; however, there is a case that is legitimate and where the regex could conceivably fail (this is the second "anomaly"). If you adjust the regexp to go across text lines, then you should be aware that quoting multiple consecutive paragraphs requires that you place a single double quote at the beginning of each paragraph and leave out the quote at the end of each paragraph except for at the end of the very last paragraph. This means that over the space of those paragraphs, the regex will fail in some places and succeed in others.
Examples and brief discussions of paragraph quoting and of nested quoting can be found here http://en.wikipedia.org/wiki/Quotation_mark .

How do I split this certain kind of string into an array in ruby [duplicate]

I would like to find a regex that will pick out all commas that fall outside quote sets.
For example:
'foo' => 'bar',
'foofoo' => 'bar,bar'
This would pick out the single comma on line 1, after 'bar',
I don't really care about single vs double quotes.
Has anyone got any thoughts? I feel like this should be possible with readaheads, but my regex fu is too weak.
This will match any string up to and including the first non-quoted ",". Is that what you are wanting?
/^([^"]|"[^"]*")*?(,)/
If you want all of them (and as a counter-example to the guy who said it wasn't possible) you could write:
/(,)(?=(?:[^"]|"[^"]*")*$)/
which will match all of them. Thus
'test, a "comma,", bob, ",sam,",here'.gsub(/(,)(?=(?:[^"]|"[^"]*")*$)/,';')
replaces all the commas not inside quotes with semicolons, and produces:
'test; a "comma,"; bob; ",sam,";here'
If you need it to work across line breaks just add the m (multiline) flag.
The below regexes would match all the comma's which are present outside the double quotes,
,(?=(?:[^"]*"[^"]*")*[^"]*$)
DEMO
OR(PCRE only)
"[^"]*"(*SKIP)(*F)|,
"[^"]*" matches all the double quoted block. That is, in this buz,"bar,foo" input, this regex would match "bar,foo" only. Now the following (*SKIP)(*F) makes the match to fail. Then it moves on to the pattern which was next to | symbol and tries to match characters from the remaining string. That is, in our output , next to pattern | will match only the comma which was just after to buz . Note that this won't match the comma which was present inside double quotes, because we already make the double quoted part to skip.
DEMO
The below regex would match all the comma's which are present inside the double quotes,
,(?!(?:[^"]*"[^"]*")*[^"]*$)
DEMO
While it's possible to hack it with a regex (and I enjoy abusing regexes as much as the next guy), you'll get in trouble sooner or later trying to handle substrings without a more advanced parser. Possible ways to get in trouble include mixed quotes, and escaped quotes.
This function will split a string on commas, but not those commas that are within a single- or double-quoted string. It can be easily extended with additional characters to use as quotes (though character pairs like « » would need a few more lines of code) and will even tell you if you forgot to close a quote in your data:
function splitNotStrings(str){
var parse=[], inString=false, escape=0, end=0
for(var i=0, c; c=str[i]; i++){ // looping over the characters in str
if(c==='\\'){ escape^=1; continue} // 1 when odd number of consecutive \
if(c===','){
if(!inString){
parse.push(str.slice(end, i))
end=i+1
}
}
else if(splitNotStrings.quotes.indexOf(c)>-1 && !escape){
if(c===inString) inString=false
else if(!inString) inString=c
}
escape=0
}
// now we finished parsing, strings should be closed
if(inString) throw SyntaxError('expected matching '+inString)
if(end<i) parse.push(str.slice(end, i))
return parse
}
splitNotStrings.quotes="'\"" // add other (symmetrical) quotes here
Try this regular expression:
(?:"(?:[^\\"]+|\\(?:\\\\)*[\\"])*"|'(?:[^\\']+|\\(?:\\\\)*[\\'])*')\s*=>\s*(?:"(?:[^\\"]+|\\(?:\\\\)*[\\"])*"|'(?:[^\\']+|\\(?:\\\\)*[\\'])*')\s*,
This does also allow strings like “'foo\'bar' => 'bar\\',”.
MarkusQ's answer worked great for me for about a year, until it didn't. I just got a stack overflow error on a line with about 120 commas and 3682 characters total. In Java, like this:
String[] cells = line.split("[\t,](?=(?:[^\"]|\"[^\"]*\")*$)", -1);
Here's my extremely inelegant replacement that doesn't stack overflow:
private String[] extractCellsFromLine(String line) {
List<String> cellList = new ArrayList<String>();
while (true) {
String[] firstCellAndRest;
if (line.startsWith("\"")) {
firstCellAndRest = line.split("([\t,])(?=(?:[^\"]|\"[^\"]*\")*$)", 2);
}
else {
firstCellAndRest = line.split("[\t,]", 2);
}
cellList.add(firstCellAndRest[0]);
if (firstCellAndRest.length == 1) {
break;
}
line = firstCellAndRest[1];
}
return cellList.toArray(new String[cellList.size()]);
}
#SocialCensus, The example you gave in the comment to MarkusQ, where you throw in ' alongside the ", doesn't work with the example MarkusQ gave right above that if we change sam to sam's: (test, a "comma,", bob, ",sam's,",here) has no match against (,)(?=(?:[^"']|["|'][^"']")$). In fact, the problem itself, "I don't really care about single vs double quotes", is ambiguous. You have to be clear what you mean by quoting either with " or with '. For example, is nesting allowed or not? If so, to how many levels? If only 1 nested level, what happens to a comma outside the inner nested quotation but inside the outer nesting quotation? You should also consider that single quotes happen by themselves as apostrophes (ie, like the counter-example I gave earlier with sam's). Finally, the regex you made doesn't really treat single quotes on par with double quotes since it assumes the last type of quotation mark is necessarily a double quote -- and replacing that last double quote with ['|"] also has a problem if the text doesn't come with correct quoting (or if apostrophes are used), though, I suppose we probably could assume all quotes are correctly delineated.
MarkusQ's regexp answers the question: find all commas that have an even number of double quotes after it (ie, are outside double quotes) and disregard all commas that have an odd number of double quotes after it (ie, are inside double quotes). This is generally the same solution as what you probably want, but let's look at a few anomalies. First, if someone leaves off a quotation mark at the end, then this regexp finds all the wrong commas rather than finding the desired ones or failing to match any. Of course, if a double quote is missing, all bets are off since it might not be clear if the missing one belongs at the end or instead belongs at the beginning; however, there is a case that is legitimate and where the regex could conceivably fail (this is the second "anomaly"). If you adjust the regexp to go across text lines, then you should be aware that quoting multiple consecutive paragraphs requires that you place a single double quote at the beginning of each paragraph and leave out the quote at the end of each paragraph except for at the end of the very last paragraph. This means that over the space of those paragraphs, the regex will fail in some places and succeed in others.
Examples and brief discussions of paragraph quoting and of nested quoting can be found here http://en.wikipedia.org/wiki/Quotation_mark .

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