Error on Partition over row number - oracle

I am creating a sub-query to select distinct entries on a certain column, DIS_COL, then return all other columns for those distinct entries, arbitrarily selecting the first row.
To do this I'm creating a sub-query that selects only first rows using over - partition by, then selecting from that sub-query.
There is an error with my code however; "ORA-00923: FROM keyword not found where expected".
My code is below:
select *
from (
select *,
row_number() over (partition by DIS_COL order by COL_2) as row_number --ORDER BY FIELD DETERMINES WHICH ROW IS THE FIRST ROW AND THUS WHICH ONE IS SELECTED.
from MY_TABLE
) as rows
where row_number = 1
AND CRITERIA_COL = 'CRIT_1'
OR CRITERIA_COL_2 = 'CRIT_2';
How can I correct my code to achieve the desired result?
I am working on an Oracle database.

Remove as rows. It is not proper syntax for the table/query alias. It is syntax for column alias.
select *
from (
select T.*,
row_number() over (partition by DIS_COL order by COL_2) as row_number --ORDER BY FIELD DETERMINES WHICH ROW IS THE FIRST ROW AND THUS WHICH ONE IS SELECTED.
from MY_TABLE t
)
where row_number = 1
AND (CRITERIA_COL = 'CRIT_1'
OR CRITERIA_COL_2 = 'CRIT_2');

It's not the ROW_NUMBER, it's the *, Add an alias to the subquery:
select *
from (
select T.*, -- here
row_number() over (partition by DIS_COL order by COL_2) as row_number --ORDER BY FIELD DETERMINES WHICH ROW IS THE FIRST ROW AND THUS WHICH ONE IS SELECTED.
from MY_TABLE
)T as rows -- and here
where row_number = 1
AND CRITERIA_COL = 'CRIT_1'
OR CRITERIA_COL_2 = 'CRIT_2';

Related

MERGE WITH ROW_NUMBER

I am trying to perform a merge to insert and update as the case may be in a table. However in table 1, I only want it to insert the unique values ​​of the tbl2.rfc field regardless if my other fields change, I only want to show the unique values ​​of said field. I am occupying the ROW_NUMBER function to bring only unique values, but I have not been able to add this function to my merge.
MERGE INTO B69_TBL1 tbl1
USING (SELECT T1.*, ROW_NUMBER() OVER (PARTITION BY T1.rfc ORDER BY T1.rfc DESC) ENUMERADO
FROM B69_TBL2 tbl2
WHEN MATCHED THEN
UPDATE SET
tbl1.id_tbl1 = tbl2.id_con,
tbl1.rfc = tbl2.rfc,
tbl1.rfc = tbl2.name_cont
WHEN NOT MATCHED THEN
INSERT (tbl1.id_tbl1,tbl1.tbl1tipo,tbl1.id_concentrado,tbl1.rfc,
tbl1.name_cont,tbl1.baja_logica,tbl1.last_update)
VALUES (id_tbl1autt.nextval,'1','1',tbl2.id_concentrado,tbl2.rfc,
tbl2.name_cont,'0', '11/05/2021')
) T1
WHERE ENUMERADO=1
AND RFC IS NOT NULL
The error it marks is 00907. 00000 - "missing right parenthesis"
because I had it like this and it fails precisely in the on.
MERGE INTO B69_TBL1 tbl1
USING (SELECT T1.*, ROW_NUMBER() OVER (PARTITION BY T1.rfc ORDER BY T1.rfc DESC) ENUMERADO
ON tbl1.rfc = tbl2.rfc
FROM B69_TBL2 tbl2 )
WHEN MATCHED THEN
UPDATE SET
tbl1.id_alert = tbl2.id_con,
tbl1.rfc = tbl2.rfc,
tbl1.rfc = tbl2.name_cont
WHEN NOT MATCHED THEN
INSERT (tbl1.id_alert,tbl1.alertype,tbl1.id_con,tbl1.rfc,
tbl1.name_cont,tbl1.baja_logica,tbl1.last_update)
VALUES (id_tbl1autt.nextval,'1','1',tbl2.id_con,tbl2.rfc,
tbl2.name_cont,'0', '11/05/2021')
) T1
WHERE ENUMERADO=1
AND RFC IS NOT NULL
Your ON clause is in the wrong place;
You had the tbl2 alias inside the USING query instead of following it;
You do not need the tbl1 aliases before the destination column names in the UPDATE or INSERT;
You are updating the rfc column twice (I removed the second instance);
There was a strange T1 alias after the insert that should be inside the USING query; and
You can use a DATE literal rather than a string.
There may be other errors, as I do not have your tables to test the query.
MERGE INTO B69_TBL1 tbl1
USING (
SELECT T1.*,
ROW_NUMBER() OVER (PARTITION BY T1.rfc ORDER BY T1.rfc DESC) AS ENUMERADO
FROM B69_TBL2 t1
) tbl2
ON tbl1.rfc = tbl2.rfc
WHEN MATCHED THEN
UPDATE SET
id_alert = tbl2.id_con,
rfc = tbl2.rfc
WHEN NOT MATCHED THEN
INSERT (
id_alert,
alertype,
id_con,
rfc,
name_cont,
baja_logica,
last_update
) VALUES (
id_tbl1autt.nextval,
'1',
'1',
tbl2.id_con,
tbl2.rfc,
tbl2.name_cont,
'0',
DATE '2021-05-11'
)
WHERE ENUMERADO=1
AND RFC IS NOT NULL

How to get records from select statement based on one column distinct value in Oracle?

Please help me with next problem:
And the result should be:
filtered by iban_code distinct
You can use row_number analytical function.
Select * from
(Select t.*,
Row_number()
over (partition by per_id, iban_code
order by main_bank_account desc) as rn
From your_table t)
Where rn=1;
Cheers!!

How to select data from multiple row into one row with multiple column dynamically?

I am trying to select multiple rows of data into one row through multiple columns which will change dynamically.
This is in Oracle database. I want to count repeated work done by the LEAD_TECHNISIAN_ID within a duration. If the difference of last work delivery date and new work receive date is 15 or below 15 then LEAD_TECHNISIAN_ID has one repeated work.
List item
SELECT *
FROM (WITH CTE AS (
SELECT ROW_NUMBER () OVER (ORDER BY ID) AS RW,
RECEIVED_DATE,
DELIVERY_DATE,
SERVICE_NO,
LEAD_TECHNISIAN_ID,
ID,
SERVICE_CENTER
FROM ( SELECT cc.SERVICE_CENTER,
CC.ID,
CC.BARCODE,
TRUNC (cc.CREATED_DATE) RECEIVED_DATE,
TRUNC (CC.DELIVERY_DATE) DELIVERY_DATE,
cc.SERVICE_NO,
CC.LEAD_TECHNISIAN_ID
FROM customer_complains cc
WHERE cc.BARCODE IN (SELECT BARCODE
FROM (SELECT BARCODE,
COUNT (BARCODE)
FROM customer_complains c
WHERE c.BARCODE <> 'UNDEFINE'
AND C.BARCODE = NVL ('351950102757821', BARCODE)
AND c.SEGMENT3 = NVL ('',c.SEGMENT3)
AND c.SEGMENT3 IN (SELECT SEGMENT3
FROM ITEM_MST
WHERE PRODUCT_GROUP = NVL ('',PRODUCT_GROUP))
GROUP BY c.BARCODE
HAVING COUNT (c.BARCODE) >1))
ORDER BY ID DESC)
ORDER BY ID DESC)
SELECT a.id,
a.DELIVERY_DATE,
a.RECEIVED_DATE,
b.RECEIVED_DATE PRE_RCV,
b.DELIVERY_DATE PRE_DEL,
(a.RECEIVED_DATE - b.DELIVERY_DATE) AS DIFF,
a.SERVICE_NO,
a.LEAD_TECHNISIAN_ID,
b.LEAD_TECHNISIAN_ID PRE_TECH --, a.DELIVERY_DATE
FROM CTE a
LEFT JOIN CTE b ON a.RW = b.RW + 1
)
WHERE DIFF <= 15
Here is the output for a specific barcode. but when I try for All the barcode I have in My Customer_complains table. The query provides irrelevant output.
Currently your code is giving numbers 1,2,3,4... to rows irrespective of LEAD_TECHNISIAN_ID and then you are joining it with RW. It will not consider LEAD_TECHNISIAN_ID while giving row numbers.
RW must start with 1 for each LEAD_TECHNISIAN_ID.
You just need to change calculation of RW as following:
ROW_NUMBER () OVER (PARTITION BY LEAD_TECHNISIAN_ID ORDER BY ID) AS RW
Cheers!!

Inserting from a SELECT but changing one column in the middle?

Wondering if there is a way to insert a row into a table from another, with exception of one column in the middle without specifying all the column name? I have 128 columns in the table.
I created a view to store the original records.
CREATE VIEW V_TXN_STG AS
SELECT * FROM TXN_STG;
In table TXN_STG, only one column BRN_CODE is changing.
Something like this doesn't work, because the column is not on the last, but somewhere middle of table structure.
INSERT INTO TXN_STG
SELECT v.*, 'BRN-001' AS BRN_CODE
FROM V_TXN_STG v;
I don't believe that this is possible without explicitly specifying the columns in your select.
first you have to get the columns:
SELECT listagg(column_name, ',') within group (order by column_name) columns
FROM all_tab_columns
WHERE table_name = 'AAA' --Table to insert too
and column_name <> 'B' -- column name you want to exclude
GROUP BY table_name;
Then insert that result on the first row:
insert into aaa(A,C) -- A,C is my result from above,I have excluded column B
select *
from (select 'a' A,'q' AMOUNT,'c' C from dual union all -- my sample data
select 'a','a','c' from dual union all
select 'a','b','c' from dual union all
select 'a','c','c' from dual union all
select 'a','d','c' from dual )
pivot
(
max(1)
for (AMOUNT) -- the column you want to remove from the sample data
IN ()
)
where 1=1
order by A;

selecting records from hive table where there are duplicates with a given criteria

Table 1 has duplicate entries in column A with same frequency values. I need to select one random record out of those .If the duplicate entry contain 'unknown' as a column B value ( like in record "d") select one from other rows . I need a select statement which satisfy the above . Thanks .
These conditions can be prioritized using a case expression in order by with a function like row_number.
select A,B,frequency,timekey
from (select t.*
,row_number() over(partition by A order by cast((B = 'unknown') as int), B) as rnum
from tbl t
) t
where rnum = 1
Here for each group of A rows, we prioritize rows other than B = 'unknown' first, and then in the order of B values.
Use row_number analytic function. If you want to select not unknown record first, then use the query below:
select A, B, Frequency, timekey
from
(select
A, B, Frequency, timekey,
row_number() over(partition by A,Frequency order by case when B='unknown' then 1 else 0 end) rn
)s where rn=1
And if you want to select unknown if they exist, use this row_number in the query above:
row_number() over(partition by A,Frequency order by case when B='unknown' then 0 else 1 end) rn

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