Pig Latin converter - ruby

I'm currently working on an exercise which involves converting the sentence "The quick brown fox" to “Hetay uickqay rownbay oxfay”
def translate(sent)
sent = sent.downcase
vowels = ['a', 'e', 'i', 'o', 'u']
words = sent.split(' ')
result = []
words.each_with_index do |word, i|
translation = ''
qu = false
if vowels.include? word[0]
translation = word + 'ay'
result.push(translation)
else
word = word.split('')
count = 0
word.each_with_index do |char, index|
if vowels.include? char
# handle words that start with 'qu'
if char == 'u' and translation[-1] == 'q'
qu = true
translation = words[i][count..words[i].length] + translation + 'ay'
result.push(translation)
next
end
break
else
# handle words with 'qu' in middle
if char == 'q' and translation[i-1] == 'u'
qu = true
translation = words[i][count +1..words[i].length] + 'ay'
result.push(translation)
next
else
translation += char
end
count += 1
end
end
# translation of consonant words without "qu"
if not qu
translation = words[i][count..words[i].length] + translation + 'ay'
result.push(translation)
end
end
end
result.join(' ')
end
puts translate("The quick brown fox")
However, I'm getting "ethay uickqay ownbray oxfay" instead of “Hetay uickqay rownbay oxfay”.
Where are the areas that needs correction? I couldn't pinpoint the problem. Could you show me the solution?

This is a very procedural and complex way of going about this. I'm not sure what your rules for checking q and u are for, since the pig latin translation rules make no mention of qu as a special case:
A far simpler way is to split the sentence into an array of words, and transform each word as required:
def translate(sent)
translation = sent.split(' ').map do |w|
vowels = %w(a e i o u)
word = w.downcase.split('')
if vowels.include? word[0]
"#{word}way"
else
"%s%say" % [word[1..-1], word[0]]
end
end
translation.join(' ').capitalize
end
puts translate("The quick brown fox")
# outputs Hetay uickqay rownbay oxfay
And, for 1.9 and likely above:
def translate(sent)
translation = sent.split(' ').map do |w|
vowels = %w(a e i o u)
word = w.downcase.split('')
if vowels.include? word[0]
"#{word.join}way"
else
"%s%say" % [word[1..-1].join, word[0]]
end
end
translation.join(' ').capitalize
end
puts translate("The quick brown fox")
Obviously, both of these are examples and can likely be made far better with work. But they serve to illustrate the point.
This makes use of map and join, and can probably be optimised further. The key difference between this method and yours is that you are attempting to build up a map of the translation iteratively, when you probably do not need to. Use the enumeration functions, they are part of what makes the functional programming style more expressive. Learn to think "how do I permute this data set to get my desired response" as opposed to "What steps do I need to perform to get my desired response".

Related

How to I get the right output when there is more than vowel in each word? My code only works with one vowel in each word

Aba is a German children’s game where secret messages are exchanged. In Aba,
after every vowel we add “b” and add that same vowel.
Write a method aba_translate that takes in a sentence string and returns a new
sentence representing its Aba translation. Capitalized words of the original sentence
should be properly capitalized in the new sentence.
aba_translate(“Cats and dogs”) #=> “Cabats aband dobogs”
aba_translate(“Everyone can code”) #=> “Ebeveryobonebe caban cobodebe”
aba_translate(“Africa is Africa in German”) #=> “Abafribicaba ibis Abafribicaba ibin
Gebermaban”
My code:
def aba_translate(sentence)
translation = []
words = sentence.split(" ")
vowels = "aeiou"
vowel = ""
before = ""
after = ""
full = ""
words.each do |word|
word.each_char.with_index do |char, idx|
if vowels.include?(char)
vowel = char
before = word[0...idx]
after = word[idx+1..-1]
full = before + vowel + "b" + vowel + after
translation << full
end
end
end
return translation.join(" ")
end
puts aba_translate("Cats and dogs")
puts aba_translate("Everyone can code")
puts aba_translate("Africa is Africa in German")
Your code generates a whole new word every time it sees a vowel. Instead you need to build each word character by character and make changes when it sees a vowel.
def aba_translate(sentence)
translation = []
words = sentence.split(" ")
vowels = "aeiouAEIOU"
words.each do |word|
full = ""
word.each_char.with_index do |char, idx|
full += char
if vowels.include?(char)
full = full + "b" + char.downcase
end
end
translation << full
end
return translation.join(" ")
end
Every time you find a vowel, you take the entire string before the vowel and the entire string after the vowel and add it to the result.
So, for a word like "code", that means you first produce the output c + obo + de and then the output cod + ebe.
However, what you actually need to do is simply keep the part you have processed instead of duplicating it.
You can do this by either changing your logic to keep track of up to which index you have already processed the word, or alternatively by processing it character-by-character instead of chunk-by-chunk.
However for problems like this, Regex are usually a much better solution:
VOWELS = 'aeiou'
def aba_translate(sentence)
sentence.gsub(Regexp.union(*VOWELS.chars), '\0b\0')
end
or just making VOWELS a Regexp in the first place:
VOWELS = /[aeiou]/.freeze
def aba_translate(sentence)
sentence.gsub(VOWELS, '\0b\0')
end
I think the nested loops complicates it since you can solve the problem with just one loop. Here you just need to initialize a string and a string of vowels to check each character. While you iterate through each character you shovel it into the empty string, and then you check if it is a vowel you shovel b + that vowel's lowercase version to account for the uppercase instances. Then you finally return the new string.
def aba_translate(string)
new_string = ""
vowels = "AEIOUaeiou"
string.each_char do |char|
new_string << char
if vowels.include?(char)
new_string << "b" + char.downcase
end
end
return new_string
end
Here's my beginner-friendly solution
def aba_translate(sent)
vowels = "AEIOUaeiou"
aba_sent = ""
sent.each_char do |char|
if vowels.include?(char)
aba_sent += char + "b" + char.downcase
else
aba_sent += char
end
end
return aba_sent
end

Ruby Multiple Words Pig Latin

I'm having trouble with a Ruby pig latin translator translating 2 or more words. I've successfully figured out how to translate words beginning with a vowel, consonant, or two consonants with my function translate, and I'm wanting to create a second function, translate_words, that uses .map with the first function.
When the string, "eat pie", gets submitted, the output is "eat pieay". It only changes the second word and also does it incorrectly (should be "eatay iepay"). I've looked at multiple other solutions on SO without luck. I'm still very new with regex so those solutions were a little over my head.
This project works with RSpec and I've added the test code below mine.
Here's my code:
def translate(input)
pig_string = ''
if input[0] =~ /[aeiou]/
return input + 'ay'
elsif input[0] =~ /[^aeiou]/ && input[1] =~ /[aeiou]/
return input[1..-1] + input[0] + 'ay'
elsif input[0..1] =~ /[^aeiou]/
return input[2..-1] + input[0..1] + 'ay'
else
return input[0] + input + 'ay'
end
end
def translate_words(multi_words)
word_count = multi_words.split.size
if word_count > 1
multi_words.map! do |word|
translate(word)
end
end
end
RSpec:
it "translates two words" do
s = translate("eat pie")
expect(s).to eq("eatay iepay")
end
As per comments above by bitsapien and Sergio Tulentsev :
def translate_words(multi_words)
multi_words.split.map do |word|
translate(word)
end.join(' ')
end
map will suffice instead of map!.
translate_words('eat plie') #=> "eatay ieplay"

Why does my ruby pig latin translator not capitalize the first word of a string properly?

I am trying to write a program that translates a string with some capitalized words and punctuation into Pig Latin. Here are the conditions:
1) words beginning with a vowel should just tack on "ay".
2) words beginning with a single phoneme like "sch" or "qu" or "squ" or "ch" should move all of those characters to the end, not just the first letter, and then tack on "ay".
3) the regular pig latin rules for a word beginning with one consonant (i.e., "Well," => 'Ellway,").
4) capitalization and punctuation should be preserved, but the initial letter would change if the letter doesn't begin with a vowel. So "Well," would become "Ellway,".
Everything works, except for the first word of my string. The fourth condition is never met with the first word of a string. So, for example, "Well," becomes "ellWay,". So punctuation works, but the capitalization isn't working properly.
Edit: I have realized that this issue occurs only when the word does NOT begin with a vowel. So, "Actually," becomes "Actuallyay," (which it should), but "Quaint," becomes "aintQuay,", when it should be "Aintquay,". So, here is the code where I actually pass the pig latin into the array named pig_latin:
string = string.split(' ')
pig_latin = []
string.each do |word|
if vowels.include?(word[0])
pig_latin << word + "ay"
elsif (consonants.include?(word[0]) && consonants.include?(word[1]) && consonants.include?(word[2])) || word[1..2].include?('qu')
pig_latin << (word[3..-1] + word[0..2] + "ay")
elsif (consonants.include?(word[0]) && consonants.include?(word[1])) || word[0..1].include?('qu')
pig_latin << (word[2..-1] + word[0..1] + "ay")
else
pig_latin << (word[1..-1] + word[0] + "ay")
end
end
Here is the part of my code that handles the capitalization and punctuation. To clarify, pig_latin is the array with the pig-latinized phrase passed into it. uppercase_alphabet is an array i created to include all uppercase letters:
idx1 = 0
while idx1 < pig_latin.count
word = pig_latin[idx1]
idx2 = 0
while idx2 < word.length
if uppercase_alphabet.include?(word[idx2])
word[idx2] = word[idx2].downcase
word[0] = word[0].upcase
end
if punctuation.include?(word[idx2])
word[word.length], word[idx2] = word[idx2], ''
end
idx2 += 1
end
idx1 += 1
end
pig_latin.join(' ')
Edit: Here is the code outlining the various arrays I'm using:
vowels = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']
lowercase_alphabet = ('a'..'z').to_a
uppercase_alphabet = ('A'..'Z').to_a
alphabet = lowercase_alphabet + uppercase_alphabet
punctuation = ['.', ',', ';', '?', '!', ':']
consonants = []
alphabet.each do |letter|
consonants << letter unless vowels.include?(letter)
end
And, here are the errors I'm getting when I run the test with the following string: "Well, I have, not even. seen that movie." (I understand the punctuation makes no sense).
1) #translate retains punctuation from the original phrase
Failure/Error: s.should == "Ellway, Iay avehay, otnay evenay. eensay atthay oviemay."
expected: "Ellway, Iay avehay, otnay evenay. eensay atthay oviemay."
got: "ellWay, Iay avehay, otnay evenay. eensay atthay oviemay." (using ==)
# ./spec/04_pig_latin_spec.rb:83:in `block (2 levels) in <top (required)>
It is hard to debug imaginary code. You are asking people why your code doesn't work without providing the values of some key variables.
Her are some tips:
1) A String works just like an Array, so you don't have to create an
Array of individual letters, which forces you to type all the commas and quote marks:
vowels = 'aeiou'
vowels.include?('a') #=>true
2) You don't have to include caps in your arrays of consonants and vowels, instead you can downcase before calling include?():
ch = 'A'
vowels.include?(ch.downcase) #=> true
3) When you are debugging, puts and p(for Arrays, Hashes) are your friend. You can find out which elsif branches are executing by adding puts/p statements:
if vowels.include?(word[0])
puts 'X'
pig_latin << word + "ay"
elsif (consonants.include?(word[0]) && consonants.include?(word[1]) && consonants.include?(word[2])) || word[1..2].include?('qu')
puts 'A'
pig_latin << (word[3..-1] + word[0..2] + "ay")
elsif (consonants.include?(word[0]) && consonants.include?(word[1])) || word[0..1].include?('qu')
puts 'B'
pig_latin << (word[2..-1] + word[0..1] + "ay")
else
puts 'C'
pig_latin << (word[1..-1] + word[0] + "ay")
end
end
4) When you are comparing strings, you can use ==. Instead of this:
word[0..1].include?('qu')
...you can write:
if word[0..1].downcase == 'qu'
It's more efficient to use == when you can.
5) Your if conditionals are too complex. If you know what regexes are, you can simplify things by extracting the consonants at the beginning of a word, and then using if statements to test what the consonants are:
words = %w{
schlepp
quail
squall
checkers
}
consonants = ('a'..'z').to_a.join.tr('aeiou', '')
words.each do |word|
md = word.match(/
\A #match start of string, followed by...
[#{consonants}]+ #a consonant, 1 or more times
/x)
if md
starting_consonants = md[0]
#Test for starting_consonants here, e.g.
#if starting_consonants == 'q' and word[1] == 'u'
# do something
else #then word starts with a vowel
...
end
end
--output:--
schl
q
sq
ch
You can limit the number of consonants extracted to three like this:
[#{consonants}]{1,3}
6) I would handle capitalization at the same time you change the words--then you won't have to search through all the letters in every word. First thing, check for capitalization of first letter (then set a flag variable, e.g. capitalized = true). Then downcase the first letter. Then after you change the word, if there was a capital, upcase the first letter(you can also call capitalize(), but the result can be different than just calling upcase() on the first letter). That way you don't have to search through the whole word in your complicated nested loop. Be sure to set the flag variable back to false.
7) In ruby, you rarely use while loops and increment a counter:
while idx2 < word.length
char = word[idx2]
...
...
idx2 += 1
end
Instead, you use each() loops:
word.each_char do |char|
#do something with char
end

Ruby Pig Latin Multiple Arguments

Hi I'm trying to write code for to convert strings to pig latin
def translate(str)
alpha = ('a'..'z').to_a
vowels = %w[a e i o u]
consonants = alpha - vowels
if vowels.include?(str[0])
str + 'ay'
elsif str[0..1] == 'qu'
str[2..-1]+'quay'
elsif consonants.include?(str[0]) && str[1..2]=='qu'
str[3..-1]+str[0..2]+'ay'
elsif consonants.include?(str[0]) && consonants.include?(str[1]) && consonants.include?(str[2])
str[3..-1] + str[0..2] + 'ay'
elsif consonants.include?(str[0]) && consonants.include?(str[1])
str[2..-1] + str[0..1] + 'ay'
elsif consonants.include?(str[0])
str[1..-1] + str[0] + 'ay'
elsif str[0..1] == 'qu'
str[2..-1]+'quay'
else
return str
end
end
This code works perfect for converting one word strings, for example: translate("monkey").
What i'm trying to do is make it possible for this code to accept multiple words as well (within the same string)...following the above criteria for converting into pig latin, example:
translate("please help") => "easeplay elphay"
thanks much!
Since you already know how to translate a single word why not just split up the task into two methods:
def translate(str)
str.split.map { |word| translate_word(word) }.join
end
def translate_word(str)
# Your old translate code here
end
What I would do for this is:
use the #split method to make your str variable into an array of words (or 1 word if its only 1 word).
afterwards you can use the array#each method to iterate through each array index.
i.e.
str = "hello"
str = str.split(" ") # str now equals ["hello"]
for multiple variables:
str = "hello world"
str- str.split(" ") #now equals ["hello", "world"]
then you can use the .each method:
str.each do |<variable name you want to use>|
<how you want to manipulate the array>
end
for the pig latin program you could do:
str.each do|element|
if vowels.include?(element)
<do whatever you want here>
elsif
<do whatever>
else
<do whatver>
end
end
this will iterate through each element in the array and translate it (if there is only one element it will still work)

Pig-Latin method translation

Trying to write Method in ruby that will translate a string in pig-latin , the rule :
Rule 1: If a word begins with a vowel sound, add an "ay" sound to the end of the word.
Rule 2: If a word begins with a consonant sound, move it to the end of the word, and then add an "ay" sound to the end of the word and also when the word begins with 2 consonants , move both to the end of the word and add an "ay"
As a newbie , my prob is the second rule , when the word begin with only one consonant it work , but for more than one , I have trouble to make it work ,Can somebody look at the code and let me know how i can code that differently and probably what is my mistake , probably the code need refactoring. Thanks , so far i come up with this code :
def translate (str)
str1="aeiou"
str2=(/\A[aeiou]/)
vowel = str1.scan(/\w/)
alpha =('a'..'z').to_a
con = (alpha - vowel).join
word = str.scan(/\w/)
if #first rule
str =~ str2
str + "ay"
elsif # second rule
str != str2
s = str.slice!(/^./)
str + s + "ay"
elsif
word[0.1]=~(/\A[con]/)
s = str.slice!(/^../)
str + s + "ay"
else
word[0..2]=~(/\A[con]/)
s = str.slice!(/^.../)
str + s + "ay"
end
end
translate("apple") should == "appleay"
translate("cherry") should == "errychay"
translate("three") should == "eethray"
No need for all those fancy regexes. Keep it simple.
def translate str
alpha = ('a'..'z').to_a
vowels = %w[a e i o u]
consonants = alpha - vowels
if vowels.include?(str[0])
str + 'ay'
elsif consonants.include?(str[0]) && consonants.include?(str[1])
str[2..-1] + str[0..1] + 'ay'
elsif consonants.include?(str[0])
str[1..-1] + str[0] + 'ay'
else
str # return unchanged
end
end
translate 'apple' # => "appleay"
translate 'cherry' # => "errychay"
translate 'dog' # => "ogday"
This will handle multiple words, punctuation, and words like 'queer' = 'eerquay' and 'school' = 'oolschay'.
def translate (sent)
vowels = %w{a e i o u}
sent.gsub(/(\A|\s)\w+/) do |str|
str.strip!
while not vowels.include? str[0] or (str[0] == 'u' and str[-1] == 'q')
str += str[0]
str = str[1..-1]
end
str = ' ' + str + 'ay'
end.strip
end
okay this is an epic pig latin translator that I'm sure could use a bit of refactoring, but passes the tests
def translate(sent)
sent = sent.downcase
vowels = ['a', 'e', 'i', 'o', 'u']
words = sent.split(' ')
result = []
words.each_with_index do |word, i|
translation = ''
qu = false
if vowels.include? word[0]
translation = word + 'ay'
result.push(translation)
else
word = word.split('')
count = 0
word.each_with_index do |char, index|
if vowels.include? char
# handle words that start with 'qu'
if char == 'u' and translation[-1] == 'q'
qu = true
translation = words[i][count + 1..words[i].length] + translation + 'uay'
result.push(translation)
next
end
break
else
# handle words with 'qu' in middle
if char == 'q' and word[i+1] == 'u'
qu = true
translation = words[i][count + 2..words[i].length] + 'quay'
result.push(translation)
next
else
translation += char
end
count += 1
end
end
# translation of consonant words without qu
if not qu
translation = words[i][count..words[i].length] + translation + 'ay'
result.push(translation)
end
end
end
result.join(' ')
end
So this will give the following:
puts translate('apple') # "appleay"
puts translate("quiet") # "ietquay"
puts translate("square") # "aresquay"
puts translate("the quick brown fox") # "ethay ickquay ownbray oxfay"
def translate(sentence)
sentence.split(" ").map do |word|
word = word.gsub("qu", " ")
word.gsub!(/^([^aeiou]*)(.*)/,'\2\1ay')
word = word.gsub(" ", "qu")
end
end
That was fun! I don't like the hack for qu, but I couldn't find a nice way to do that.
So for this pig latin clearly I skipped and\an\in and singular things like a\I etc. I know that wasn't the main question but you can just leave out that logic if it's not for your use case. Also this goes for triple consonants if you want to keep it with one or two consonants then change the expression from {1,3} to {1,2}
All pig latin is similar so just alter for your use case. This is a good opportunity to use MatchData objects. Also vowel?(first_letter=word[0].downcase) is a style choice made to be more literate so I don't have to remember that word[0] is the first letter.
My answer is originally based off of Sergio Tulentsev's answer in this thread.
def to_pig_latin(sentence)
sentence.gsub('.','').split(' ').collect do |word|
translate word
end.compact.join(' ')
end
def translate(word)
if word.length > 1
if word == 'and' || word == 'an' || word == 'in'
word
elsif capture = consonant_expression.match(word)
capture.post_match.to_s + capture.to_s + 'ay'
elsif vowel?(first_letter=word[0].downcase)
word + 'ay'
elsif vowel?(last_letter=word[-1].downcase)
move_last_letter(word) + 'ay'
end
else
word
end
end
# Move last letter to beginning of word
def move_last_letter(word)
word[-1] + word[0..-2]
end
private
def consonant_expression
# at the beginning of a String
# capture anything not a vowel (consonants)
# capture 1, 2 or 3 occurences
# ignore case and whitespace
/^ [^aeiou] {1,3}/ix
end
def vowel?(letter)
vowels.include?(letter)
end
def vowels
%w[a e i o u]
end
Also just for the heck of it I'll include my dump from a pry session so you all can see how to use MatchData. MINSWAN. It's stuff like this that makes ruby great.
pry > def consonant_expression
pry * /^ [^aeiou] {1,3}/ix
pry * end
=> :consonant_expression
pry > consonant_expression.match('Stream')
=> #<MatchData "Str">
pry > capture = _
=> #<MatchData "Str">
pry > ls capture
MatchData#methods:
== begin end hash length offset pre_match regexp string to_s
[] captures eql? inspect names post_match pretty_print size to_a values_at
pry >
pry > capture.post_match
=> "eam"
pry > capture
=> #<MatchData "Str">
pry > capture.to_s
=> "Str"
pry > capture.post_match.to_s
=> "eam"
pry > capture.post_match.to_s + capture.to_s + 'ay'
=> "eamStray"
pry >
If I understood your question correctly, you can just directly check if a character is a vowel or consonant and then use array ranges to get the part of the string you want.
vowels = ['a', 'e', 'i', 'o', 'u']
consonants = ('a'..'z').to_a - vowels
return str + "ay" if vowels.include?(str[0])
if consonants.include?(str[0])
return str[2..-1] + str[0..1] + "ay" if consonants.include?(str[1])
return str[1..-1] + str[0] + "ay"
end
str
Here's a solution that handles the "qu" phoneme as well as other irregular characters. Had a little trouble putting the individual words back into a string with the proper spacing. Would appreciate any feedback!
def translate(str)
vowels = ["a", "e", "i", "o", "u"]
new_word = ""
str.split.each do |word|
vowel_idx = 0
if vowels.include? word[0]
vowel_idx = 0
elsif word.include? "qu"
until word[vowel_idx-2]+word[vowel_idx-1] == "qu"
vowel_idx += 1
end
else
until vowels.include? word[vowel_idx]
vowel_idx += 1
end
end
idx_right = vowel_idx
while idx_right < word.length
new_word += word[idx_right]
idx_right += 1
end
idx_left = 0
while idx_left < vowel_idx
new_word += word[idx_left]
idx_left += 1
end
new_word += "ay "
end
new_word.chomp(" ")
end
I done gone did one too
def translate(string)
vowels = %w{a e i o u}
phrase = string.split(" ")
phrase.map! do |word|
letters = word.split("")
find_vowel = letters.index do |letter|
vowels.include?(letter)
end
#turn "square" into "aresquay"
if letters[find_vowel] == "u"
find_vowel += 1
end
letters.rotate!(find_vowel)
letters.push("ay")
letters.join
end
return phrase.join(" ")
end
def piglatinize(word)
vowels = %w{a e i o u}
word.each_char do |chr|
index = word.index(chr)
if index != 0 && vowels.include?(chr.downcase)
consonants = word.slice!(0..index-1)
return word + consonants + "ay"
elsif index == 0 && vowels.include?(chr.downcase)
return word + "ay"
end
end
end
def to_pig_latin(sentence)
sentence.split(" ").collect { |word| piglatinize(word) }.join(" ")
end
This seems to handle all that I've thrown at it including the 'qu' phoneme rule...
def translate str
letters = ('a'..'z').to_a
vowels = %w[a e i o u]
consonants = letters - vowels
str2 = str.gsub(/\w+/) do|word|
if vowels.include?(word.downcase[0])
word+'ay'
elsif (word.include? 'qu')
idx = word.index(/[aeio]/)
word = word[idx, word.length-idx] + word[0,idx]+ 'ay'
else
idx = word.index(/[aeiou]/)
word = word[idx, word.length-idx] + word[0,idx]+'ay'
end
end
end
I'm grabbing the words with the 'qu' phoneme and then checking all the other vowels [excluding u].
Then I split the word by the index of the first vowel (or vowel without 'u' for the 'qu' cases) and dropping the word part before that index to the back of the word. And adding 'ay' ftw.
Many of the examples here are fairly long. Here's some relatively short code I came up with. It handles all cases including the "qu" problem! Feedback always appreciated (I'm pretty new to coding).
$vowels = "aeiou"
#First, I define a method that handle's a word starting with a consonant
def consonant(s)
n = 0
while n < s.length
if $vowels.include?(s[n]) && s[n-1..n] != "qu"
return "#{s[n..-1]}#{s[0..n-1]}ay"
else
n += 1
end
end
end
#Then, I write the main translate method that decides how to approach the word.
def translate(s)
s.split.map{ |s| $vowels.include?(s[0]) ? "#{s}ay" : consonant(s) }.join(" ")
end

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