Update a table which has a nested table - oracle

Question

My application has users (and subtype applicant) and jobs, with applicants being able to submit applications for jobs. I have objects types and tables set up as below :
create or replace type user_typ as object(
user_id number(19,0),
username nvarchar2(40 char)
)NOT FINAL;
I inherit an applicant_typ from this :
create or replace type applicant_typ under user_typ (
resume_text nclob
);
My design involves jobs to which applicants can apply. To this end, I create an application_typ as follows :
create or replace TYPE Application_typ AS OBJECT (
application_id NUMBER,
candidate applicant_typ,
time_of_app DATE
);
CREATE TYPE Application_tab IS TABLE OF Application_typ;
And now I create an object type called Job_typ, and a table containing those objects, wherein there is a nested table for applications :
CREATE OR REPLACE TYPE Job_typ AS OBJECT (
job_ID NUMBER,
description NVARCHAR2(1000),
name NVARCHAR2(200),
application Application_tab
);
CREATE TABLE Job_tab OF Job_typ
NESTED TABLE application STORE AS application_nt;
All of this works fine. I inserted some jobs into the job_tab table as follows :
INSERT INTO job_tab VALUES (1, 'The Software Developer will be responsible for authoring high-quality software...',
'Software Developer', NULL);
INSERT INTO job_tab VALUES (2, 'This position requires a team player and a self-starter with experience leading... ',
'Project Manager', NULL);
INSERT INTO job_tab VALUES (3, 'In the first year of this unique 24-month program, you rotate through various...',
'Store Manager', NULL);
Note that at this point the nested table attribute 'application' has NULL value for all jobs. Assume that I already have some applicants in a table called applicant_table, which are of type applicant_typ. How do I create and insert a new application for a job?
I tried some things like :
UPDATE job_tab
SET application = application_typ (
1,
Applicant_typ(SELECT VALUE(a) from applicant_table a where user_id=1),
'12-MAY-2014')
WHERE job_id=1
But this doesn't work.

Answer 1

Consider something like this
merge into job_tab D
using (select t.a app_typ from applicant_table t where t.a.user_id = 1) S
on (job_id = 1)
when matched then
update
set application = Application_tab(Application_typ(1,
s.app_typ,
to_date('12-05-2014', 'DD-MM-YYYY')));
Also I will suggest to use some other naming convention, very complicated to understand at first glance.