send the unix output to a csv file - bash

Question

I want to put the output data from unix command to a csv file.
Suppose the output which I am getting is :
A
B
C
I want to put this data in .csv file as
A B C
in three different columns but same row.

Answer 1

Try this :
printf '%s\n' A B C | paste -sd ' ' >> file.csv
or more classical for a CSV (delimiter with a , :
printf '%s\n' A B C | paste -sd ',' >> file.csv
printf '%s\n' A B C is just an example to have the same sample input as you. My solution works with spaces in a same line too.
EDIT from your comments, you seems to need to treat with a for loop, so :
for i in {0..5}; do printf '%s\n' {A..C} | paste -sd " " >> file.csv; done
or in pseudo code :
for ...:
unix_command | paste -sd " " >> file.csv
endfor

Answer 2

unix_command | tr "\n" " " > file.csv
or
unix_command | awk 'ORS=FS' > file.csv
Disadvantage in both cases: one trailing space

Answer 3

For my understanding, #Django needs three line into one line.
paste -d ' ' - - - < infile
If you need output as csv format (split by ,), you can use this
paste -d ',' - - - < infile
Here is the test result
$ cat infile
Manoj Mishra
Japan
Environment.
Michael Jackson
America
Environment.
$ paste -d ',' - - - < infile
Manoj Mishra,Japan,Environment.
Michael Jackson,America,Environment.

Answer 4

A more general answer
If the output of your command is multi-line and you want to put the
quoted output in csv format, n items per line, the following script
could be handy.
The groupby program reads from stdin and
quotes each input line
groups n quoted input lines in a csv record, using a comma as a separator
optionally, using the -s optional argument, the program discards the
last line of its output if said last line doesn't contain exactly n
items.
The -h option, as usual, echoes an usage line and exits.
Specifying another option the program prints the usage line and exits
in error.
The code
% cat groupby
#!/bin/sh
usage () { echo Usage: $0 [-s] n --- -s is for \"strict\", outputs only records of n items. ; exit $1 ; }
s=0
while getopts :sh o ; do
case "${o}" in
s) s=1 ; shift ;;
h) usage 0 ;;
*) usage 1 ;;
esac
done
awk -v n=$1 -v s=$s -v q='"' '
NR==1 {buf = q $0 q ; next}
NR%n==1 {print buf; buf = q $0 q ; next}
{buf = buf "," q $0 q}
END {if(!s||NR%n==0)print buf}'
%
An example of usage
% chmod +x groupby
% echo -e "1\n2\n3\n4\n5" | ./groupby 3
"1","2","3"
"4","5"
% echo -e "1\n2\n3\n4\n5\n6" | ./groupby 3
"1","2","3"
"4","5","6"
echo -e "1\n2\n3\n4\n5\n6\n7" | ./groupby 3
"1","2","3"
"4","5","6"
"7"
% echo -e "1\n2\n3\n4\n5\n6\n7\n8" | ./groupby -s 4
"1","2","3","4"
"5","6","7","8"
% echo -e "1\n2\n3\n4\n5\n6\n7" | ./groupby -s 4
"1","2","3","4"
%
A different angle
I changed the defaults to suit best the OP requirements, and introduced other options, see the usage string for details
#!/bin/sh
usage () { echo 'Usage: '$0' [-s] [-q quote_char] [-c separator_char] n
Reads lines from stdin and prints them grouped by n and separated by spaces.
Optional arguments:
-s is for "strict", outputs only records of n items;
-q quote_char, forces quoting of each input line;
-c separator_char, changes the field separator,
interesting alternatives are tab, comma, semicolon etc;
-h prints this help and exits.' ; exit $1 ; }
# Default options
s=0 ; q='' ; c=' '
# Treatment of optional arguments
while getopts :shc:q: o ; do
case "${o}" in
s) s=1 ; ;;
c) c="${OPTARG}" ;;
q) q="${OPTARG}" ;;
h) usage 0 ;;
*) usage 1 ;;
esac
done
shift $(($OPTIND-1))
# awk code
awk -v n=$1 -v s=$s -v q="$q" -v c="$c" '
NR==1 {buf = q $0 q ; next}
NR%n==1 {print buf; buf = q $0 q ; next}
{buf = buf c q $0 q}
END {if(!s||NR%n==0)print buf}'

Answer 5

just use xargs.
eg:
less filename| xargs >> filename.csv