Django with request in ajax - ajax

Question

This is my request in ajax,
var req=$.ajax({
type: "POST",
url: '/create/travel', // or just url: "/my-url/path/"
data: {
csrfmiddlewaretoken: document.getElementsByName('csrfmiddlewaretoken')[0].value,
startPlace:nameStart,
startLng:lngStart,
startLat:latStart,
endPlace:nameEnd,
...
}
});
Then, it is my view
def createT(request):
if request.is_ajax():
#print(request.POST['board'])
print(Car.objects.get(number_plate=request.POST['number_plate']))
travel1=Travel.objects.create(
name=request.POST['name_travel'],
startPlace=request.POST['startPlace'],
...
)
return render_to_response('travel/meTravel.html',{},context_instance=RequestContext(request))
But django not go to the template, i dont know how i go to other view or open other page, other template,
Simply when i come to this view, i cannot open other view, single django stay in the same page. =$
Help me! Tanks ,

Answer 1

finally, I make a form and send the normal request, Tanks for all...
class TravelForm(ModelForm):
class Meta:
model = Travel
exclude=("responsible",)
widgets = {
'date': DateTimeWidget (attrs={'id':"date"},use_tz=True,bootstrap_version=3)
}
def __init__(self, user, *args, **kwargs):
super(TravelForm, self).__init__(*args, **kwargs)
self.fields['number_plate'].queryset = Car.objects.filter(proprietor=user)
and my view
def TravelCreate(request):
if request.method == "POST":
form = TravelForm(request.user.id, request.POST)
print("POST HERE-----------------=)")
print(form.is_valid())
if form.is_valid():
obj=form.save(commit=False)
obj.responsible = request.user
obj.save()
return HttpResponseRedirect('/TravelsMe')
else:
form = TravelForm(request.user.id)
return render_to_response('travel/travel_form.html', {'form':form}, context_instance=RequestContext(request))
And some code of ajax,