I have a search form in navigation created with form_open() and the action from the search controller. Now when I want to submit something and disable the form for visualize a processing operation site CodeIgniter shows:
An Error Was Encountered
The action you have requested is not allowed.
View File 4 Example:
<?php echo form_open(array('class' => 'searchform')); ?>
<input type="text" name="search" value="..." />
<input type="submit" name="s" value="..." />
</form>
JS Code:
$('form.searchform').submit(function()
{
$('form.searchform input').attr('disabled', 'true');
});
Related
i have two views, view-1 and view-2.
view-1 has form, which will store data temporary.
i want to get data from view-1 and send it to view-2, which has user profile, where temporary data from view-1 will be shown.
how we can achieve it in Laravel, i know we can store data in SQL
and then fetch it, but how to do it without storing to SQL.
my code:
view: 1
<form >
<div class="form-group">
<label class="col-form-label" >Date</label>
<input type="text" name="sdate" class="form-control">
<input type="submit" class="btn btn-primary" value="Add date" >
</div>
</form>
view 2 Controller:
public function report2($id)
{
$teacher = Teacher::teacher($id);
return View('teachers.report2' ,compact('teacher','today','sdate'));
}
Route:
Route::get('teachers/{id}/report2', 'TeachersController#report2');
Use session, for example in view1 you pass variable of date do this on your controller of view 1
session(['sdate' => $request->sdate]);
and then you can get the value of the session in your controller or view by calling this
$date = session('sdate');
further reading see the docs
i was able to do it using simple php;
in view 1 i added this code:
<form action="report2" method="get">
Date: <input type="text" name="today" placeholder="Date of Birth" class="datepicker form-control"><br>
<input type="submit">
</form>
Laravel view 2:
<?php echo $_GET["today"]; ?><br>
I'm building the website based on Joomla 3. I need to disable the validation of the fields: name, username, password1 (the second, because the first is password2) and email2 and use email1 as username (I installed the plugin Email for user authorization).
I have tried to remove these fields in file components/com_users/models/forms/registration.xml but the validation is still remaining. If I don't remove them but only change the rows required="true" to false for these fields the registration doesn't work at all and any user stored in the DB. How can I disable these fields?
It's not an easy workaround, and you will need some basic knowledge of Joomla and PHP, but I'll try to explain it to you as simple as i can.
>>> Creating view template override
First of all you will need to create your Registration view template override (to keep it Joomla update proof). To do so, create folder /templates/YOUT_TEMPLATE/html/com_users/registration and copy /components/com_users/views/registration/tmpl/default.php file there.
From now on you can modify registration output in your template folder.
>>> Modifying registration form output
By default Joomla takes all fields from form file /components/com_users/models/forms/registration.xml, where they are defined, and outputs them in a view. But if we don't want to use ALL the fields, we need to output fields manually.
My example code only output E-mail and Password fields for registration. Here's a sample code to do so: (default.php file)
<?php
defined('_JEXEC') or die;
JHtml::_('behavior.keepalive');
?>
<div class="grid_8" id="register_block">
<div class="content_block">
<h1>Registracija</h1>
<div class="login<?php echo $this->pageclass_sfx?>">
<form id="member-registration" action="<?php echo JRoute::_('index.php?option=com_users&task=registration2.register'); ?>" method="post" enctype="multipart/form-data">
<div>
<div class="login-fields">
<label id="jform_email1-lbl" for="jform_email1">E-mail:</label>
<input type="text" name="jform[email1]" id="jform_email1" value="" size="30">
</div>
<div class="login-fields">
<label id="jform_password1-lbl" for="jform_password1">Password:</label>
<input type="password" name="jform[password1]" id="jform_password1" value="" autocomplete="off" size="30">
</div>
<button type="submit" class="button"><?php echo JText::_('JREGISTER');?></button>
<input type="hidden" name="option" value="com_users" />
<input type="hidden" name="task" value="registration2.register" />
<?php echo JHtml::_('form.token');?>
</div>
</form>
</div>
</div>
</div>
Please note, that I've also replaced task value from registration.register to registration2.register, I did this to bypass some of validation rules using my own controller.
>>> Creating controller override
Locate file /components/com_users/controllers/registration.php and create a copy of it called registration2.php in same folder.
Open file registration2.php and change It's class name from UsersControllerRegistration to UsersControllerRegistration2
From now on Joomla registration form will use this class to create a new user.
Find a method called register and find this line:
$requestData = JRequest::getVar('jform', array(), 'post', 'array');
This is where Joomla get's registration form data. Add the following lines:
$requestData['name'] = $requestData['email1'];
$requestData['username'] = $requestData['email1'];
$requestData['email2'] = $requestData['email1'];
$requestData['password2'] = $requestData['password1'];
It will add missing registration info, and help you pass validation.
NOTE: This is a sample code, to show the main logic. If anyone has a better solution, I'd be more than happy to hear it.
Following same idea, a simpler solution might be just including hidden inputs with values in com_users\views\registration\tmpl\default.php above
<button type="submit" class="btn btn-primary validate"><?php echo JText::_('JREGISTER');?></button>
add
<input type="hidden" id="jform[username]" name="jform[username]" value="username" />
<input type="hidden" id="jform_name" name="jform[name]" value="name" />
It would pass the validation and you would no longer need to override controllers etc.
I have a form on my website that pushes to my e-mail address. Previously before I wrote an ajax function the form would successfully push to my e-mail address. Only problem is when the user fills out the form it takes them to another page upon submitting the form. The HTML for my form is below.
<form id="contact" method="post" action="E-mail-form.php" name="EmailFromMyWebsite">
<label for="name">Name</label> <br>
<input type="text" name="name" class="required" placeholder="Your Name" title=" (Your name is required)"> <br />
<label for="email">E-mail</label> <br>
<input type="email" name="email" class="required email" placeholder="Name#email.com" title=" (Your email is required)"> <br />
<label for="message">Message/Comment</label> <br>
<textarea name="message" class="required" placeholder="Leave a brief message" title=" (Please leave me a brief message)"></textarea> <br />
<input type="submit" name="submit" id="submit" value="Send Message" />
</form>
</div><!-- /end #contact-form -->
The ajax call I wrote is...
$("#submit").on('click', function(){
var formData = $('#contact').serialize();
$.ajax({
type:"POST",
data:"formData",
url:"Email-form.php",
success: function(data){
$('#contact').html('<p>Your message has been sent</p>');
}
});
});
My javaScript console shows no errors so I think the problem is with my jQuery logic. On Chrome when I click submit I am redirected to my homepage. On Firefox the form submits but I am redirected to another page, therefore it is completely ignoring my AJAX call. Can someone with AJAX experience tell me what I'm doing wrong? Also I would love to attach a message if the call fails. Can I add 'failure:' and for the value put a function just like I did for success?
You have two issues
your form is submitting normally
you're attempting to post the wrong data
To prevent the form from submitting you can return false from the jQuery click handler or call preventDefault from the event object.
You are sending a string "formData" as the form data instead of the string in the formData variable
$("#submit").on('click', function(event){
var formData = $('#contact').serialize();
$.ajax({
type:"POST",
data:formData,
url:"Email-form.php",
success: function(data){
$('#contact').html('<p>Your message has been sent</p>');
}
});
event.preventDefault();
// or
return false;
});
There's a good chance that the normal form submit action is still taking place, even though you have an AJAX call as well. An easy fix for this may be to simply change the button type from submit to button. That way your click handler will still work, but it won't perform the default action of submitting the form on its own.
<input type="button" name="submit" id="submit" value="Send Message" />
I've created a custom form, similar to a customer registration form, in Magento.
i want to prepopulate this form when an error messages arises.
Does anyone know how I can prepopulate a custom form in Magento?
Without seeing you code it is hard to say which method will method will work, but one of these method should work.
Using JavaScript Validation - client side validate, only post if all require info is correct
<form name="my-form" id="my-form" method="post">
<label for="username">
< ?php echo $this->__("User name") ?> <span>*</span></label><br />
<input type="text" id="username" name="username" class="input-text required-entry"/>
.....
</form>
<script type=”text/javascript”>
//< ![CDATA[
var customForm = new VarienForm('my-form');
//]]>
</script>
See a list of all the validation class name
Repopulate field
To get a list of all the post variable information that the customer fill out
Mage::app()->getRequest()->getPost();
To get a form field (eg. <input type='text' name='firstname' ... />)
Mage::app()->getRequest()->getPost('firstname');
So in you .phtml try (this will not work if you doing a redirect on error)
<input type='text' name='firstname' value="<?php echo Mage::app()->getRequest()->getPost('firstname');?>" />
If the above doesnt work then you need the save the post info into a session.
In your controller if validation fail save the information to customer session
Mage::getSingleton( 'customer/session' )->setData( 'yourFormName', Mage::app()->getRequest()->getPost() );
In your phtml template, print the data if 'yourFormName' variable session exist.
I am having issue making a form be sent using ajax.
Here is my code:
<form id="form" method="get">
<input type="text" name="name" id="name"><br>
<input type="text" name="email" name="email"><br>
<input type="submit" id="submit" value="submit">
</form>
$('#submit').click(function(event){
alert('ajax');
});
The "ajax" alert shows, but then the page gets reloaded! How can I stop this behaviour?
You have to use preventDefault
$('#submit').click(function(event){
event.preventDefault();
alert('ajax');
});
use $.submit() instead of click :)
$('#form').submit(function(event){
alert('ajax');
// here some ajax functions for sending via get or post ;)
return false; // this stops loading the action site.. its something like e.preventDefault() on links
});