Dungeon generation algorithm - algorithm

I am trying to create an algorithm which would generate dungeon with following rules:
In the center is 2x2 cells starting area. Only one side is accessible to a corridor (see blue square)
Map contains two 3x3 areas. When laying out map, they act as corridors. (see green squares)
Every room is 3x2 cells rectangle.
Each room must have exactly one entry point (door) from a corridor.
If no corridors available, room's entry point can be a secret passage from neighboring room. (see red squares)
No room can have more than one secret passage.
No corridor can have width of more than one cell at any point.
No cell in the map can remain unused.
Map is a rectangle with predetermined dimensions
The last two conditions is what's giving me problems. I can't come up with an idea on how to handle it other then iterative and/or random approach, both of which are excruciatingly slow at best. What would be a good way to handle this dungeon efficiency problem in reasonable time?
Here is an example of such dungeon with map size 24x21:

For •No cell in the map can remain unused perhaps perform a post-process that converts all such into hidden rooms, with a randomly created hidden exit/entry.
For •Map is a rectangle with predetermined dimensions perhaps establish a minimum room width and upon approaching within twice the allocated limit set the width of the next room to the remaining space.
The key to many efficiency challenges in game programming is to choose suitable approximations that will be invisible (or nearly so) to the player.

Related

How to represent a sphere surface in computer memory?

As the title suggest my problem lies in some representation of a sphere surface in computer memory. For simplicity, let's say we are making a chess game where the board is on a sphere. If the board was a classic flat board, then the solution is simple: use a 2D table.
But I don't know what kind of a memory structure I should chose for a sphere. Namely, what I want from this representation are:
If I move a pawn stubbornly in one direction, then I should return to the point where I started,
During such "journey" I should cross a point directly on the other side of the sphere (I mean to avoid a common "error" in a 2D game where moving pass an edge of a board will move an object to the opposite edge, thus making the board a torus, not a real sphere)
the area of one board cell should be approximately equal to any other cell
a cell should have got an associated longitude-latitude coordinates (I wrote "associated" because I want from the representation to only have got some way to obtain these coordinates from the position of a cell, not to be eg. a table with lat-long indexes)
There's no simple geometric solution to this. The crux of the problem is that, say you have n columns at the equator, and you're currently near the north poll, and heading north. Then the combination of the direction and the column number from the top row (and second from top row) must be able to uniquely identify which one of the n positions at the equator that path is going to cross. Therefore, direction could not be an integer unless you have n columns in the top (or second to top) row. Notice that if the polygons have more than three sides, then they must have common edges (and triangles won't work for other reasons). So now you have a grid, but if you have more than three rows (i.e. a cube, or other regular prism), then moving sideways on the second-to-top row will not navigate you to the southern hemisphere.
The best bet might be to create a regular polyhedron, and keep the point and direction as floating point vectors/points, and calculate the actual position when you move, and figure out which polygon you land in (note, you would have the possibility of moving to non-adjacent polygons with this method, and you might have issues if you land exactly on an edge/vertex, etc).

Algorithm to fill arbitrary marked/selected tiles on a square grid with the smallest number of rectangles?

What I am asking here is an algorithm question. I'm not asking for specifics of how to do it in the programming language I'm working in or with the framework and libraries I'm currently using. I want to know how to do this in principle.
As a hobby, I am working on an open source virtual reality remake of the 1992 first-person shooter game Wolfenstein 3D. My program will support classic mods and map packs for WOLF3D made in the original format from the 90s. This means that my program will not know in advance what the maps are going to be. They are loaded in at runtime from user provided files.
A Wolfenstein 3D map is a 2D square grid of normally 64x64 tiles. let's assume I have a 2D array of bools which return true if a particular tile can be traversed by the player and false if the tile will never be traversable no matter what happens in the game.
I want to generate rectangular collision objects for a modern game engine which will prevent collisions into non traversable tiles on the map. Right now, I have a small collision object on each surface of each wall tile with a traversible tile next to it and that is very inefficient because it makes way more collision objects than necessary. What I should have instead is a smaller number of large rectangles which fill all of the squares on the grid where that 2D array I mentioned has a false value to indicate non-traversible.
When I search for any algorithms or research that might have been done for problems similar to this, I find lots of information about rectangle packing for the purposes of making texture atlases for games, which packs rectangles into a square, but I haven't found anything that tries to pack the smallest number of rectangles into an arbitrary set of selected / marked square tiles.
The naive approach which occurs to me is to first make 64 rectangles representing 64 rows and then chop out whatever squares are traversible. but I suspect that there's got to be an algorithm which can do better, meaning that it can fill the same spaces with a smaller number of rectangles. Maybe something that starts with my naive approach and then checks each rectangle for adjacent rectangles which it could merge with? But I'm not sure how far to take that approach or if it will even truly reduce the number of rectangles.
The result doesn't have to be perfect. I am just fishing here to see if anyone has any magic tricks that could take me even a little bit beyond the naive approach.
Has anyone done this before? What is it called? Just knowing what some of the vocabulary words I would need to even talk about this are would help. Thanks!
(later edit)
Here is some sample input as comma-separated values. The 1s represent the area that must be filled with the rectangles while the 0s represent the area that should not be filled with the rectangles.
I expect that the result would be a list of sets of 4 integers where each set represents a rectangle like this:
First integer would be the x coordinate of the left/western edge of the rectangle.
Second integer would be the y coordinate of the top/northern edge of the rectangle.
Third integer would be the width of the rectangle.
Fourth integer would be the depth of the rectangle.
My program is in C# but I'm sure I can translate anything in a normal mainstream general purpose programming language or psuedocode.
Mark all tiles as not visited
For each tile:
skip if the tile is not a top-left corner or was visited before
# now, the tile is a top-left corner
expand right until top-right corner is found
expand down
save the rectangle
mark all tiles in the rectangle as visited
However simplistic it looks, it will likely generate minimal number of rectangles - simply because we need at least one rectangle per pair of top corners.
For faster downward expansion, it makes sense to precompute a table holding sum of all element top and left from the tile (aka integral image).
For non-overlapping rectangles, worst case complexity for an n x n "image" should not exceed O(n^3). If rectangles can overlap (would result in smaller number of them), integral image optimization is not applicable and the worst case will be O(n^4).

Dividing the plane into regions of equal mass based on a density function

Given a "density" scalar field in the plane, how can I divide the plane into nice (low moment of inertia) regions so that each region contains a similar amount of "mass"?
That's not the best description of what my actual problem is, but it's the most concise phrasing I could think of.
I have a large map of a fictional world for use in a game. I have a pretty good idea of approximately how far one could walk in a day from any given point on this map, and this varies greatly based on the terrain etc. I would like to represent this information by dividing the map into regions, so that one day of walking could take you from any region to any of its neighboring regions. It doesn't have to be perfect, but it should be significantly better than simply dividing the map into a hexagonal grid (which is what many games do).
I had the idea that I could create a gray-scale image with the same dimensions as the map, where each pixel's color value represents how quickly one can travel through the pixel in the same place on the map. Well-maintained roads would be encoded as white pixels, and insurmountable cliffs would be encoded as black, or something like that.
My question is this: does anyone have an idea of how to use such a gray-scale image (the "density" scalar field) to generate my "grid" from the previous paragraph (regions of similar "mass")?
I've thought about using the gray-scale image as a discrete probability distribution, from which I can generate a bunch of coordinates, and then use some sort of clustering algorithm to create the regions, but a) the clustering algorithms would have to create clusters of a similar size, I think, for that idea to work, which I don't think they usually do, and b) I barely have any idea if any of that even makes sense, as I'm way out of my comfort zone here.
Sorry if this doesn't belong here, my idea has always been to solve it programatically somehow, so this seemed the most sensible place to ask.
UPDATE: Just thought I'd share the results I've gotten so far, trying out the second approach suggested by #samgak - recursively subdividing regions into boxes of similar mass, finding the center of mass of each region, and creating a voronoi diagram from those.
I'll keep tweaking, and maybe try to find a way to make it less grid-like (like in the upper right corner), but this worked way better than I expected!
Building upon #samgak's solution, if you don't want the grid-like structure, you can just add a small random perturbation to your centers. You can see below for example the difference I obtain:
without perturbation
adding some random perturbation
A couple of rough ideas:
You might be able to repurpose a color-quantization algorithm, which partitions color-space into regions with roughly the same number of pixels in them. You would have to do some kind of funny mapping where the darker the pixel in your map, the greater the number of pixels of a color corresponding to that pixel's location you create in a temporary image. Then you quantize that image into x number of colors and use their color values as co-ordinates for the centers of the regions in your map, and you could then create a voronoi diagram from these points to define your region boundaries.
Another approach (which is similar to how some color quantization algorithms work under the hood anyway) could be to recursively subdivide regions of your map into axis-aligned boxes by taking each rectangular region and choosing the optimal splitting line (x or y) and position to create 2 smaller rectangles of similar "mass". You would end up with a power of 2 count of rectangular regions, and you could get rid of the blockiness by taking the centre of mass of each rectangle (not simply the center of the bounding box) and creating a voronoi diagram from all the centre-points. This isn't guaranteed to create regions of exactly equal mass, but they should be roughly equal. The algorithm could be improved by allowing recursive splitting along lines of arbitrary orientation (or maybe a finite number of 8, 16, 32 etc possible orientations) but of course that makes it more complicated.

Randomly and efficiently filling space with shapes

What is the most efficient way to randomly fill a space with as many non-overlapping shapes? In my specific case, I'm filling a circle with circles. I'm randomly placing circles until either a certain percentage of the outer circle is filled OR a certain number of placements have failed (i.e. were placed in a position that overlapped an existing circle). This is pretty slow, and often leaves empty spaces unless I allow a huge number of failures.
So, is there some other type of filling algorithm I can use to quickly fill as much space as possible, but still look random?
Issue you are running into
You are running into the Coupon collector's problem because you are using a technique of Rejection sampling.
You are also making strong assumptions about what a "random filling" is. Your algorithm will leave large gaps between circles; is this what you mean by "random"? Nevertheless it is a perfectly valid definition, and I approve of it.
Solution
To adapt your current "random filling" to avoid the rejection sampling coupon-collector's issue, merely divide the space you are filling into a grid. For example if your circles are of radius 1, divide the larger circle into a grid of 1/sqrt(2)-width blocks. When it becomes "impossible" to fill a gridbox, ignore that gridbox when you pick new points. Problem solved!
Possible dangers
You have to be careful how you code this however! Possible dangers:
If you do something like if (random point in invalid grid){ generateAnotherPoint() } then you ignore the benefit / core idea of this optimization.
If you do something like pickARandomValidGridbox() then you will slightly reduce the probability of making circles near the edge of the larger circle (though this may be fine if you're doing this for a graphics art project and not for a scientific or mathematical project); however if you make the grid size 1/sqrt(2) times the radius of the circle, you will not run into this problem because it will be impossible to draw blocks at the edge of the large circle, and thus you can ignore all gridboxes at the edge.
Implementation
Thus the generalization of your method to avoid the coupon-collector's problem is as follows:
Inputs: large circle coordinates/radius(R), small circle radius(r)
Output: set of coordinates of all the small circles
Algorithm:
divide your LargeCircle into a grid of r/sqrt(2)
ValidBoxes = {set of all gridboxes that lie entirely within LargeCircle}
SmallCircles = {empty set}
until ValidBoxes is empty:
pick a random gridbox Box from ValidBoxes
pick a random point inside Box to be center of small circle C
check neighboring gridboxes for other circles which may overlap*
if there is no overlap:
add C to SmallCircles
remove the box from ValidBoxes # possible because grid is small
else if there is an overlap:
increase the Box.failcount
if Box.failcount > MAX_PERGRIDBOX_FAIL_COUNT:
remove the box from ValidBoxes
return SmallCircles
(*) This step is also an important optimization, which I can only assume you do not already have. Without it, your doesThisCircleOverlapAnother(...) function is incredibly inefficient at O(N) per query, which will make filling in circles nearly impossible for large ratios R>>r.
This is the exact generalization of your algorithm to avoid the slowness, while still retaining the elegant randomness of it.
Generalization to larger irregular features
edit: Since you've commented that this is for a game and you are interested in irregular shapes, you can generalize this as follows. For any small irregular shape, enclose it in a circle that represent how far you want it to be from things. Your grid can be the size of the smallest terrain feature. Larger features can encompass 1x2 or 2x2 or 3x2 or 3x3 etc. contiguous blocks. Note that many games with features that span large distances (mountains) and small distances (torches) often require grids which are recursively split (i.e. some blocks are split into further 2x2 or 2x2x2 subblocks), generating a tree structure. This structure with extensive bookkeeping will allow you to randomly place the contiguous blocks, however it requires a lot of coding. What you can do however is use the circle-grid algorithm to place the larger features first (when there's lot of space to work with on the map and you can just check adjacent gridboxes for a collection without running into the coupon-collector's problem), then place the smaller features. If you can place your features in this order, this requires almost no extra coding besides checking neighboring gridboxes for collisions when you place a 1x2/3x3/etc. group.
One way to do this that produces interesting looking results is
create an empty NxM grid
create an empty has-open-neighbors set
for i = 1 to NumberOfRegions
pick a random point in the grid
assign that grid point a (terrain) type
add the point to the has-open-neighbors set
while has-open-neighbors is not empty
foreach point in has-open-neighbors
get neighbor-points as the immediate neighbors of point
that don't have an assigned terrain type in the grid
if none
remove point from has-open-neighbors
else
pick a random neighbor-point from neighbor-points
assign its grid location the same (terrain) type as point
add neighbor-point to the has-open-neighbors set
When done, has-open-neighbors will be empty and the grid will have been populated with at most NumberOfRegions regions (some regions with the same terrain type may be adjacent and so will combine to form a single region).
Sample output using this algorithm with 30 points, 14 terrain types, and a 200x200 pixel world:
Edit: tried to clarify the algorithm.
How about using a 2-step process:
Choose a bunch of n points randomly -- these will become the centres of the circles.
Determine the radii of these circles so that they do not overlap.
For step 2, for each circle centre you need to know the distance to its nearest neighbour. (This can be computed for all points in O(n^2) time using brute force, although it may be that faster algorithms exist for points in the plane.) Then simply divide that distance by 2 to get a safe radius. (You can also shrink it further, either by a fixed amount or by an amount proportional to the radius, to ensure that no circles will be touching.)
To see that this works, consider any point p and its nearest neighbour q, which is some distance d from p. If p is also q's nearest neighbour, then both points will get circles with radius d/2, which will therefore be touching; OTOH, if q has a different nearest neighbour, it must be at distance d' < d, so the circle centred at q will be even smaller. So either way, the 2 circles will not overlap.
My idea would be to start out with a compact grid layout. Then take each circle and perturb it in some random direction. The distance in which you perturb it can also be chosen at random (just make sure that the distance doesn't make it overlap another circle).
This is just an idea and I'm sure there are a number of ways you could modify it and improve upon it.

Converting vector-contoured regions (borders) to a raster map (pixel grid)

I have a map that is cut up into a number of regions by borders (contours) like countries on a world map. Each region has a certain surface-cover class S (e.g. 0 for water, 0.03 for grass...). The borders are defined by:
what value of S is on either side of it (0.03 on one side, 0.0 on the other, in the example below)
how many points the border is made of (n=7 in example below), and
n coordinate pairs (x, y).
This is one example.
0.0300 0.0000 7
2660607.5 6332685.5 2660565.0 6332690.5 2660541.5 6332794.5
2660621.7 6332860.5 2660673.8 6332770.5 2660669.0 6332709.5
2660607.5 6332685.5
I want to make a raster map in which each pixel has the value of S corresponding to the region in which the center of the pixel falls.
Note that the borders represent step changes in S. The various values of S represent discrete classes (e.g. grass or water), and are not values that can be averaged (i.e. no wet grass!).
Also note that not all borders are closed loops like the example above. This is a bit like country borders: e.g. the US-Canada border isn't a closed loop, but rather a line joining up at each end with two other borders: the Canada-ocean and the US-ocean "borders". (Closed-loop borders do exist nevertheless!)
Can anyone point me to an algorithm that can do this? I don't want to reinvent the wheel!
The general case for processing this sort of geometry in vector form can be quite difficult, especially since nothing about the structure you describe requires the geometry to be consistent. However, since you just want to rasterize it, then treating the problem as a Voronoi diagram of line segments can be more robust.
Approximating the Voronoi diagram can be done graphically in OpenGL by drawing each line segment as a pair of quads making a tent shape. The z-buffer is used to make the closest quad take precedence, and thus color the pixel based on whichever line is closest. The difference here is that you will want to color the polygons based on which side of the line they are on, instead of which line they represent. A good paper discussing a similar algorithm is Hoff et al's Fast Computation of Generalized Voronoi Diagrams Using Graphics Hardware
The 3d geometry will look something like this sketch with 3 red/yellow segments and 1 blue/green segment:
This procedure doesn't require you to convert anything into a closed loop, and doesn't require any fancy geometry libraries. Everything is handled by the z-buffer, and should be fast enough to run in real time on any modern graphics card. A refinement would be to use homogeneous coordinates to make the bases project to infinity.
I implemented this algorithm in a Python script at http://www.pasteall.org/9062/python. One interesting caveat is that using cones to cap the ends of the lines didn't work without distorting the shape of the cone, because the cones representing the end points of the segments were z-fighting. For the sample geometry you provided, the output looks like this:
I'd recommend you to use a geometry algorithm library like CGAL. Especially the second example in the "2D Polygons" page of the reference manual should provide you what you need. You can define each "border" as a polygon and check if certain points are inside the polygons. So basically it would be something like
for every y in raster grid
for every x in raster grid
for each defined polygon p
if point(x,y) is inside polygon p
pixel[X][Y] = inside_color[p]
I'm not so sure about what to do with the outside_color because the outside regions will overlap, won't they? Anyway, looking at your example, every outside region could be water, so you just could do a final
if pixel[X][Y] still undefined then pixel[X][Y] = water_value
(or as an alternative, set pixel[X][Y] to water_value before iterating through the polygon list)
first, convert all your borders into closed loops (possibly including the edges of your map), and indentify the inside colour. this has to be possible, otherwise you have an inconsistency in your data
use bresenham's algorithm to draw all the border lines on your map, in a single unused colour
store a list of all the "border pixels" as you do this
then for each border
triangulate it (delaunay)
iterate through the triangles till you find one whose centre is inside your border (point-in-polygon test)
floodfill your map at that point in the border's interior colour
once you have filled in all the interior regions, iterate through the list of border pixels, seeing which colour each one should be
choose two unused colors as markers "empty" and "border"
fill all area with "empty" color
draw all region borders by "border" color
iterate through points to find first one with "empty" color
determine which region it belongs to (google "point inside polygon", probably you will need to make your borders closed as Martin DeMello suggested)
perform flood-fill algorithm from this point with color of the region
go to next "empty" point (no need to restart search - just continue)
and so on till no "empty" points will remain
The way I've solved this is as follows:
March along each segment; stop at regular intervals L.
At each stop, place a tracer point immediately to the left and to the right of the segment (at a certain small distance d from the segment). The tracer points are attributed the left and right S-value, respectively.
Do a nearest-neighbour interpolation. Each point on the raster grid is attributed the S of the nearest tracer point.
This works even when there are non-closed lines, e.g. at the edge of the map.
This is not a "perfect" analytical algorithm. There are two parameters: L and d. The algorithm works beautifully as long as d << L. Otherwise you can get inaccuracies (usually single-pixel) near segment junctions, especially those with acute angles.

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