Grab current session's cookie with cURL - bash

Question

I'm working on a script that send a POST request to an URL, actually I'm sending the cookies manually in the header.. but how to take it from the current browser session?
I used tcpdump and grep but it's really the wrong choice :,D
Some suggestions?
I wont take them from a file but from the browser session and without enter in the cookie path of the browser

Answer 1

Curl can handle that for you; there is an option to store the cookies in a cookiejar and use those in subsequent requests.
Here is an example from the main curl site, which uses cookies from a file cookies.txt to set some and at the same time stores new cookies in newcookies.txt.
http://curl.haxx.se/docs/httpscripting.html#Cookie_Basics
curl --cookie cookies.txt --cookie-jar newcookies.txt http://www.example.com
When going through a login process, for example, one would reuse the cookies from cookie jar.

Answer 2

I had found a link now broken with an example from snipplr.com. I'll post it here for future references (credits to the owner):
$ch = curl_init();
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 5);
curl_setopt($ch, CURLOPT_TIMEOUT, 10);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
curl_setopt($ch, CURLOPT_USERAGENT, "Mozilla/4.0");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
if (isset($_COOKIE[session_name()])) {
curl_setopt($ch, CURLOPT_COOKIE, session_name().'='.$_COOKIE[session_name()].'; path=/');
}
session_write_close();
$result = curl_exec($ch);
if (curl_errno($ch)) {
echo 'curl error: '.curl_error($ch);
}
curl_close($ch);
session_start();