How to Copy Files Without Overwriting Any Files in Bash Script - bash

I am trying to write a script that finds all my files that are .jpg, and copies them do a new directory. It currently looks like this:
find ~/Pictures -iname \*.jpg -exec cp {} ...newDirectory \;
The problem is that some of my older files have the same name as newer files, when the IMG_#### reset back to 0001 and started counting again.
Is there a way to find the .jpgs and copy without overwriting the files? Ideally giving them a new name in the process.
EDIT
I ended up learning about rsync, which in its own way does exactly what I was looking for. Thanks for the help!

Use -n parameter for cp, that means: do not overwrite an existing file.
To prevent identical names, you could just name all of them unique.
Example:
$ touch screenshot.jpg
$ cp screenshot.jpg screenshot-$(date "+%s").jpg
So basically, mass rename the new files you want to copy to the same name+date.
That will make them different from what's already there, sice the older ones are unnamed or (if you repeat this later) will have different dates.

Related

command rename does not work on my bash script

Yesterday I made a question here: How can I run a bash in every subfolder of a base folder and my main problem was solved but I have another one: I don't know why but the rename command does NOTHING if I try to use it recursively. I've tried all different options they told me and other I found and if I run the rename on a single directory it works fine (so the line its ok) but can't make it work recursively.
The question of optimizing images doen't matter now cause I changed the script to do it first. Now I have all the images like this way: image.png (which is the oriniginal) and image-nq8.png which is the optimized one)
What I want now is to have the optimized one with the name of the original, and the original deleted. But as any of my attempts on it, they all fail and I don't know why.
I made an script: scriptloop
for i in $(find /path/to/start/ -name "*.png");do
rename -nq8.png .png *-nq8*
done
and call it this way: ./scriptloop
and tried too using: find . -name '*-nq8.png' -print0 | xargs -0 -P6 -n1 scriptOneLine
with this inside scriptOneLine: rename -nq8.png .png *-nq8*
Note: as I said if I run rename -nq8.png .png *-nq8* on a directory it works but I can't make it work recursive. Any idea of why or what am I doing wrong? (I'm on fedora)
Thank you so much

Script to find files in subdirectories

I need a script that will find and get me all files in all subdirectories (and leave them in the folder structure as they are now). I know how to find and print that files:
find . -name "something.extension"
The point is, in those directories are lots files that was used before, but I don't want to get those, so the script should only find me files that matches some kind of path pattern which is:
xxx/trunk/xxx/src/main/resources
xxx is different everytime, and after resources there are still some folders that directories are different based on xxx.
Every top xxx folder contains folder named 'tags' (the same level as trunk) that stores previous releases of module (and every release has files that name I am looking for, but I don't want outdated files).
So I want to find all that files in subdirectories of that path pattern that I specified and copy to new location but leave folder structure as it is right now.
I am using Windows and cygwin.
Update
I combined answer commands that 'that other guy' posted below, and it works. Just to be clear I have something like this:
find */trunk/*/src/main/resources -name "something.extension" -exec mkdir -p /absolute/target/path/{} \; -exec cp {} /absolute/target/path/{} \;
Thanks.
Instead of searching under the entire current directory (.), just search under the directories you care about:
find */trunk/*/src/main/resources -name "something.extension"

Copying multiple files with same name in the same folder terminal script

I have a lot of files named the same, with a directory structure (simplified) like this:
../foo1/bar1/dir/file_1.ps
../foo1/bar2/dir/file_1.ps
../foo2/bar1/dir/file_1.ps
.... and many more
As it is extremely inefficient to view all of those ps files by going to the
respective directory, I'd like to copy all of them into another directory, but include
the name of the first two directories (which are those relevant to my purpose) in the
file name.
I have previously tried like this, but I cannot get which file is from where, as they
are all named consecutively:
#!/bin/bash -xv
cp -v --backup=numbered {} */*/dir/file* ../plots/;
Where ../plots is the folder where I copy them. However, they are now of the form file.ps.~x~ (x is a number) so I get rid of the ".ps.~*~" and leave only the ps extension with:
rename 's/\.ps.~*~//g' *;
rename 's/\~/.ps/g' *;
Then, as the ps files have hundreds of points sometimes and take a long time to open, I just transform them into jpg.
for file in * ; do convert -density 150 -quality 70 "$file" "${file/.ps/}".jpg; done;
This is not really a working bash script as I have to change the directory manually.
I guess the best way to do it is to copy the files form the beginning with the names
of the first two directories incorporated in the copied filename.
How can I do this last thing?
If you just have two levels of directories, you can use
for file in */*/*.ps
do
ln "$file" "${file//\//_}"
done
This goes over each ps file, and hard links them to the current directory with the /s replaced by _. Use cp instead of ln if you intend to edit the files but don't want to update the originals.
For arbitrary directory levels, you can use the bash specific
shopt -s globstar
for file in **/*.ps
do
ln "$file" "${file//\//_}"
done
But are you sure you need to copy them all to one directory? You might be able to open them all with yourreader */*/*.ps, which depending on your reader may let browse through them one by one while still seeing the full path.
You should run a find command and print the names first like
find . -name "file_1.ps" -print
Then iterate over each of them and do a string replacement of / to '-' or any other character like
${filename/\//-}
The general syntax is ${string/substring/replacement}. Then you can copy it to the required directory. The complete script can be written as follows. Haven't tested it (not on linux at the moment), so you might need to tweak the code if you get any syntax error ;)
for filename in `find . -name "file_1.ps" -print`
do
newFileName=${filename/\//-}
cp $filename YourNewDirectory/$newFileName
done
You will need to place the script in the same root directory or change the find command to look for the particular directory if you are placing the above script in some other directory.
References
string manipulation in bash
find man page

Bash script to find specific files in a hierarchy of files

I have a folder in which there are many many folder and in each of these I have lots and lots of files. I have no idea which folder each files might be located in. I will periodically receive a list of files I need to copy to a predefined destination.
The script will run on a Unix machine.
So, my little script should:
read received list
find all files in the list
copy each file to a predefined destination via SCP
step 1 and 3, I think I'll manage on my own, but how will I do step 2?
I was thinking about using "find" to locate each file and when found, write the location in a string array. When all files are found I loop through the string array, running the "SCP" command for each file-location.
I think this should work, but I've never written a bash script before so could anyone help me a little to get started? I just need a basic "find" command which finds a filename and returns the file location if the file is found.
find $dir -name $name -exec scp {} $destination \;

Batch script to move files into a zip

Is anybody able to point me in the right direction for writing a batch script for a UNIX shell to move files into a zip one at at time and then delete the original.
I cant use the standard zip function because i don't have enough space to fit the zip being created.
So any suggestions please
Try this:
zip -r -m source.zip *
Not a great solution but simple, i ended up finding a python script that recursively zips a folder and just added a line to delete the file after it is added to the zip
You can achieve this using find as
find . -type f -print0 | xargs -0 -n1 zip -m archive
This will move every file into the zip preserving the directory structure. You are then left with empty directories that you can easily remove. Moreover using find gives you a lot of freedom on what files you want to compress.
I use :
zip --move destination.zip src_file1 src_file2
Here the detail of "--move" option from the man pages
--move
Move the specified files into the zip archive; actually, this
deletes the target directories/files after making the specified zip
archive. If a directory becomes empty after removal of the files, the
directory is also removed. No deletions are done until zip has
created the archive without error. This is useful for conserving disk
space, but is potentially dangerous so it is recommended to use it in
combination with -T to test the archive before removing all input
files.

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