I am writing a bash command that sums the number of services running on specified ports. In my case 4092, 4903, 4904, 4905. Below is my command:
ps -ef | grep '4905\|4904\|4903\|4902' | wc -l
OUTPUT: 5
Here "\|" serves as OR operator. Now the result of this is 5, since it greps the command itself. How can I subtract 1 from the answer so that the output is 4.
Use:
ps -ef | grep '4905\|4904\|4903\|4902' | wc -l | awk '{print $0-1}'
You can remove the last line that contains the result itself before you print number of matches:
ps -ef | grep '4905\|4904\|4903\|4902' | head -n -1 | wc -l
you can save the wc and use awk to get the expected number
ps -ef|grep ...|awk 'END{print NR-1}'
Related
I am trying to retreive open file handle count for a particular PID in a variable via shell script and displaying the same.It is not showing the correct count. Can someone please advise?
pid=$(ps -ef | grep 'instance="AC"' | grep -v grep | awk '{print $2}') f_count=$(ls /proc/$'{pid}' | wc -l)
Expected output:
=============
When executed in command line , it shows
ps -ef | grep 'service_instance="AC"' | grep -v grep | awk '{print $2}'
25939
ls /proc/25939/fd | wc -l
98
Actual Output:
f_count= 0
Appreciate your help, thanks
Suggesting to replace:
pid=$(ps -ef | grep 'instance="AC"' | grep -v grep | awk '{print $2}')
With:
pid=$(pgrep -f 'instance="AC"')
Notice that pid takes the first matched process.
If there are more than one matched process pgrep returns multiple lines.
Suggesting to replace:
f_count=$(ls /proc/$'{pid}' | wc -l)
with
f_count=$(ls /proc/${pid}/fd | wc -l)
Or all together in one line
f_count=$(ls /proc/$(pgrep -f 'instance="AC"')/fd | wc -l)
I'm looking to create a one liner that, given a port number (2550) uses the returned value from netstat would allow me to then run the resulting output against ps -ef to return the path of the process in question. I have:
ps -ef | grep $(netstat -tonp | grep 2550 | awk '{split($7,a,"/"); print a[1]}')
and whilst I know
netstat -tonp | grep 2550 | awk '{split($7,a,"/"); print a[1]}'
returns the expected resulted, the subsequent grep tells me that there is no such file or directory (but, if I do the ps -ef | grep **) it works just fine... I'm obviously missing something... well, obvious, but I can't see what?
try something like (it takes the first PID/port corresponding, not all):
Port=2550;ps -f --pid $( netstat -tonp | awk -F '[ \t/]+' -v Port=$Port '$0 ~ "([0-9]+[.:]){4}" Port { PID= $7;exit}; END { print PID+0 }' ) | sed 's/^\([^ \t]*[ \t]*\)\{7\}//'
the last sed is assuming a ps reply like this (space are important):
usertest 4408 4397 0 09:43 pts/6 00:00:00 ssh -p 22 -X -l usertest 198.198.131.136
for every PID and with no ending sed:
Port=2550; ps -ef | awk -v PIDs="$( netstat -tonp | awk -F '[ \t/]+' -v Port=${Port} '$0 ~ (":" Port) { print $7}' )" 'BEGIN{ split( PIDs, aTemp, /\n/); for( PID in aTemp) aPID[ aTemp[PID] ] }; $2 in aPID { sub( /^([^ \t]*[ \t]*){7}/, ""); print}'
This will give you the pids:
<sudo> netstat -tulpen | awk '$4 ~ /:2550$/{sub("/.*","",$NF);print $NF}'
You can use xargs to pass the pid to ps:
netstat -tulpen | awk '$4 ~ /:2550$/{sub("/.*","",$NF);print $NF}' | xargs -P 1 ps -o pid,cmd -p
I keep getting unary operator expected. It seems PRC is not being assigned the value.
PRC=`ps -ef | grep test | wc -l`
if [ ${PRC} -eq 1 ]
then
echo "Congrats"
Note that ps -ef | grep test will usually include the grep process in the output, which you probably don't want. A "clever trick" to avoid this is to match for the string "test" with a regular expression that is not the simple string "test":
$ ps -ef | grep test
jackman 27787 24572 0 09:53 pts/2 00:00:00 grep --color=auto test
$ ps -ef | grep test | wc -l
1
versus
$ ps -ef | grep '[t]est'
(no output)
$ ps -ef | grep '[t]est' | wc -l
0
I do this often enough that I wrote this bash function psg (for "ps grep"):
psg () {
local -a patterns=()
(( $# == 0 )) && set -- $USER # no arguments? vanity search
for arg do
patterns+=("-e" "[${arg:0:1}]${arg:1}")
done
ps -ef | grep "${patterns[#]}"
}
You could also just use
pgrep -f test
Don't forget your closing "fi":
PRC=`ps -ef | grep test| wc -l`
if [ "${PRC}" -eq 1 ]
then
echo "Congrats"
fi
You didn't mention what shell, but this works in bash.
Save a process by using the -c (count) option to grep:
PRC=`ps -ef | grep -c test`
Be advised your pipeline includes in the count the grep command itself, so as you mentioned in your comment above your count is most likely misleading as it is only counting itself. Instead, use this:
PRC=`ps -ef | grep -c [t]est`
This will match commands with "test" in them but not the grep command itself. This is because this is using a regular expression that matches a word starting with a "t". Your command starts with a square bracket so it won't match itself. Resist doing a "grep test | grep -v grep" which is sloppy and just unnecessarily uses a process.
The script:
#!/bin/bash
SERVICE="$1"
RESULT=`ps -a | sed -n /${SERVICE}/p`
MEM=$(ps aux | sort -rk +4 | grep $1 | grep -v grep | awk '{print $4}' | awk 'NR == 1')
if [ "${RESULT:-null}" = null ]; then
echo "$1 is NOT running"
else
echo "$MEM"
fi
if [ "$MEM" -ge 1 ]; then
mailx -s "Alert: server needs to be checked" me#admins.com
fi
The problem with the ps output piped to sed is even if no process is running it finds itself:
ps aux | sed -n /nfdump/p
root 30724 0.0 0.0 105252 884 pts/1 S+ 14:16 0:00 sed -n /process/p
and them my script bypasses the expected result of "service is not running" and goes straight to echo'ing $MEM, which in this case will be 0.0. Does sed have a grep -v grep eqivalent to get itself out of the way?
Let me add one more example in addition to my comments above. Sed has indeed an equivalent to grep -v: You can negate a match with /RE/! (append a ! to the regex) thus you can try:
ps aux | sed -n '/sed/!{ /nfdump/ p;}'
Here the part inside { ... } is only applied to lines not matching sed.
For the record: there is a command pgrep that can replace your ps sed pipeline, see pgrep in Wikipedia or its manpage.
Try :
ps aux | sed -n '/[n]fdump/p'
or :
ps aux | grep '[n]fdump'
The regex won't be find in the processes list
I want to attach to a running process using 'ddd', what I manually do is:
# ps -ax | grep PROCESS_NAME
Then I get a list and the pid, then I type:
# ddd PROCESS_NAME THE_PID
Is there is a way to type just one command directly?
Remark: When I type ps -ax | grep PROCESS_NAME, grep will match both the process and grep command line itself.
There is an easy way to get rid of the grep process:
ps -ax | grep PROCESS_NAME | grep -v ' grep '
(as long as the process you're trying to find doesn't include the string " grep ").
So something like this should work in a script (again, assuming there's only one copy running):
pid=$(ps -ax | grep $1 | grep -v ' grep ' | awk '{print $1}')
ddd $1 ${pid}
If you call your script dddproc, you can call it with:
dddproc myprogramname
Although I'd add some sanity checks such as detecting if there's zero or more than one process returned from ps and ensuring the user supplies an argument.
As separate commands:
% PID=`ps -ax | grep ${PROCESS_NAME} | grep -v grep | cut -d ' ' -f 1-2`
% ddd ${PROCESS_NAME} ${PID}
In one line:
% PID=`ps -ax | grep ${PROCESS_NAME} | grep -v grep | cut -d ' ' -f 1-2` && ddd ${PROCESS_NAME} ${PID}
ddd <process_name> `pgrep <process_name>`
you can use pggrep to find the process
You can use awk to both filter and get the column you want. The "exit" limits the ps results to the first hit.
function ddd_grep() {
ddd $(ps -ax | awk -v p="$1" '$4 == p { print $1; exit 0; }');
}
ddd_grep PROCESS_NAME
You may have to adjust the columns for your ps output. Also you can change the == to ~ for regex matching.
Do this way -
ddd PROCESS_NAME \`ps -ax | grep PROCESS_NAME | grep -v grep | awk '{print $1}'\`