I want to "hardcode" an expiration date into my beta code. Right now I manually calculate a unix date and compare that to the current date time:
if([[NSDate date] timeIntervalSince1970]>1422748800) mustHalt = TRUE;
I'd like a way of replacing the 1422748800 with a macro that generates the equivalent number for a date 90 days in the future at compile time.
Any suggestions?
The predefined macro __DATE__ is what you need. Here is a SO question related to this. But maybe you want to use a code like this:
const int daysToExpire = 14;
NSString *compileDate = [NSString stringWithUTF8String:__DATE__];
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"MMM d yyyy"];
NSLocale *usLocale = [[NSLocale alloc] initWithLocaleIdentifier:#"en_US"];
[df setLocale:usLocale];
NSDate *expireDate = [df dateFromString:compileDate];
bool isExpired = ([[NSDate date] compare:expireDate] == NSOrderedDescending); // decide for it
Related
I tried this :
NSDate *date = [NSDate date];
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"YYYY-MM-dd hh:mm:ss TZD"];
NSString *dateString = [dateFormat stringFromDate:date];
NSLog(#"Current Date : %#",dateString);
and the result I get is Date and Time but not the Timezone.
#Vaibhav you have to use time zone like this
NSTimeZone *timeZone = [NSTimeZone localTimeZone];
refer this link
Get the time and date of selected time zone?
In my App, When i select a day in the datepicker it should automatically calculate and display 4 other days and also it should notify on the corresponding days. For Eg. if i enter 19-08-2014, it should calculate and display the 3rd day, the 7th day, the 14th day and the 21st day from 19-08-2014(the day i entered in datepicker).
How would i achieve this. Any help would be greatly appreciated.
I have added my current code for your reference. This doesnt serve my purpose.
Kindly Help.
(IBAction)save:(UIButton *)sender {
NSDate *pickerDate = [self.picker date];
UILocalNotification *localNotif = [[UILocalNotification alloc]init];
//localNotif.alertBody = _enterText.text;
localNotif.alertBody = #"Please Take Your Rabipur Dosage";
localNotif.fireDate = pickerDate;
localNotif.timeZone = [NSTimeZone defaultTimeZone];
localNotif.soundName = (UILocalNotificationDefaultSoundName);
localNotif.applicationIconBadgeNumber = 1;
//localNotif.repeatInterval = NSDayCalendarUnit;
[[UIApplication sharedApplication]scheduleLocalNotification:localNotif];
[self dismissViewControllerAnimated:YES completion:nil];
}
Create an NSDateComponents object with the date difference you want to add, and add it to pickerDate via NSCalendar -dateByAddingComponents:toDate:options. Then create your notification based on the resulting date.
In this case, something like this:
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *offsetComponents = [[NSDateComponents alloc] init];
[offsetComponents setDay:3];
NSDate *reminderDate = [gregorian dateByAddingComponents:offsetComponents toDate:pickerDate options:0];
Repeat for 7th, 14th, and 21st day.
quick question I used the following code to retrieve a difference between two timestamps.
The minutes are given to me now in 0.5 hrs.
how do I get that into minutes (NSInteger format)?
NSDateFormatter* dateFormatter = [[[NSDateFormatter alloc] init] autorelease];
[dateFormatter setLocale:[[[NSLocale alloc] initWithLocaleIdentifier:#"en_US_POSIX"] autorelease]];
[dateFormatter setDateFormat:#"mm:ss"];
NSDate* firstDate = [dateFormatter dateFromString:#"06:00"];
NSDate* secondDate = [dateFormatter dateFromString:#"17:30"];
NSTimeInterval timeDifference = [secondDate timeIntervalSinceDate:firstDate];
I'm using an NSInteger to get the full hours, but can't figure out the minutes... must be too late at night for me :-/
NSInteger hoursBetweenDates = timeDifference / 60;
NSInteger minutesBetweenDates = ??;
NSLog(#"RAW: %f", timeDifference);
NSLog(#"Hours: %i", hoursBetweenDates);
NSLog(#"Minutes: %i", minutesBetweenDates);
Thanks guys! :-D
The NSTimeInterval is in seconds. So minutes would be diff/60.0 and hours would be diff/3600.0.
you could do:
NSTimeInterval timeDifference = [secondDate timeIntervalSinceDate:firstDate];
int minute = (int)timeDifference % 3600 / 60;
I am trying to calculate an interval between now and a user defined date in days so that the results appear in a label on tapping a button.
The difference is always -4080 I am not sure what is wrong with my equation.
Thank you for your help
- (void)LabelChange2:(id)sender{
NSDateFormatter *df3 = [[NSDateFormatter alloc] init];
df3.dateStyle = NSDateFormatterMediumStyle;
labelDOB.text = [NSString stringWithFormat:#"%#",
[df3 stringFromDate:datepick.date]];
}
NSDate * df3 = [datePick date];
NSCalendar *gregorian = [[NSCalendar alloc]
initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *comps = [gregorian components: NSDayCalendarUnit
fromDate: [NSDate date]
toDate: df3
options: 0];
int days = [comps day];
labelResult.text = [NSString stringWithFormat:#"%i", days];
Your code works fine. However if I run the code with the datePick pointer set to nil I will get an answer of -4080 from this code. You should check your connections to the UIDatePicker.
Is there a better way to do this?
-(NSDate *)getMidnightTommorow {
NSCalendarDate *now = [NSCalendarDate date];
NSCalendarDate *tomorrow = [now dateByAddingYears:0 months:0 days:1 hours:0 minutes:0 seconds:0];
return [NSCalendarDate dateWithYear:[tomorrow yearOfCommonEra]
month:[tomorrow monthOfYear]
day:[tomorrow dayOfMonth]
hour:0
minute:0
second:0
timeZone:[tomorrow timeZone]];
}
Note that I always want the next midnight, even if it happens to be midnight when I make that call, however if it happens to be 23:59:59, I of course want the midnight that is coming in one second.
The natural language functions seem flaky, and I'm not sure what Cocoa would do if I pass 32 in the "day" field. (If that'd work I could drop the [now dateByAddingYears:...] call)
From the documentation:
Use of NSCalendarDate strongly
discouraged. It is not deprecated yet,
however it may be in the next major OS
release after Mac OS X v10.5. For
calendrical calculations, you should
use suitable combinations of
NSCalendar, NSDate, and
NSDateComponents, as described in
Calendars in Dates and Times
Programming Topics for Cocoa.
Following that advice:
NSDate *today = [NSDate date];
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *components = [[NSDateComponents alloc] init];
components.day = 1;
NSDate *tomorrow = [gregorian dateByAddingComponents:components toDate:today options:0];
[components release];
NSUInteger unitFlags = NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit;
components = [gregorian components:unitFlags fromDate:tomorrow];
components.hour = 0;
components.minute = 0;
NSDate *tomorrowMidnight = [gregorian dateFromComponents:components];
[gregorian release];
[components release];
(I'm not sure offhand if this is the most efficient implementation, but it should serve as a pointer in the right direction.)
Note: In theory you can reduce the amount of code here by allowing a date components object with values greater than the range of normal values for the component (e.g. simply adding 1 to the day component, which might result in its having a value of 32). However, although dateFromComponents: may tolerate out-of-bounds values, it's not guaranteed to. You're strongly encouraged not to rely on it.
Nope - it'll be the same way you use to find midnight today.
NSCalendar *gregorian = [[[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar] autorelease];
NSDate *tomorrow = [NSDate dateWithTimeIntervalSinceNow:(24 * 60 * 60)];
NSDateComponents *components = [gregorian components:(NSYearCalendarUnit |
NSMonthCalendarUnit |
NSDayCalendarUnit)
fromDate:tomorrow];
NSDate *midnight = [gregorian dateFromComponents:components];
[NSDate dateWithNaturalLanguageString:#"midnight tomorrow"];
Convert your current date and time to a Unix date (seconds since 1970) or DOS style (since 1980), then add 24 hours and convert it back. Then reset the hours, minutes and seconds to zero to get to midnight.
You could try this way:
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *comps = [[NSDateComponents alloc] init];
[comps setDay:1];
NSDate *tomorrow = [calendar dateByAddingComponents:comps toDate:[NSDate date] options:0]; //it gives us tomorrow with current time
NSDate *midnight = [calendar startOfDayForDate:tomorrow]; //here we get next midnight
It is also easy to retrieve the seconds interval if needed to set up an NSTimer:
double intervalToMidnight = midnight.timeIntervalSinceNow;