Find all dir's called "example", set it and its contents writable - shell

I have a site, with some template directories, there are a few modules, each with their own template dir (So there are N dirs called templates).
Each of those dirs has a dir in it, called translated. I need a script to set all those dirs and it's contents writable.
I prefer this via a loop so I can echo the result. My shell skills are (still) very minimal, I can't seem to combine them, I can find the dirs from the current working directory, but I can't seem to get it recursive:
for f in ./*/translated/
do
echo $f
done
This only finds ./templates/translated/, but not ./some/dirs/deeper/translated/
I can use $f now for a chmod a+rw, but this will only set the contents writable, how do I also get the dir itself? I need new files to be written in it too.
Summery:
1) How do I make it recursive?
2) How do I set the dir itself to +rw?

The tool for finding stuff recursively is called find.
find . -name 'translated' -type d -exec echo chmod -R u+rw {} +
Take out the echo if you are satisfied with the results. If your find does not support -exec ... + then try with -exec ... \; instead.
Some shells have a wildcard ** which will do the same thing, but then your script will be tied to that particular shell.

Related

Mv files contained in directories to directories/new path

I'm working with macOS Sierra.
I have ~ 1000+ directories with lots of files in it. Word, Excel and Zipped documents in it. Only one sub level. Important : there is spaces in the filenames and in the folder names.
We decided to change the arborescence of the files ; all the files in each directory need to be moved to a subdirectory in it called "Word & Excel" before merging with another directory tree.
I managed to create the Word & Excel directory with this command :
for dir in */; do mkdir -- "$dir/Word & Excel"; done
Basically, I just want to do
for dir in */; do mv $dir/* "./Word & Excel"; done
It is not going to work. I even do not understand if the problem is with the $dir — I need the double quote to avoid the space problem, but the asterisk is not going to work if I work with the double quote... — or with the asterisk.
I tried to get a cleaner version by following a previous answer found on the web to a similar problem, clearing the subfolder of the results (and trying basically to avoid my wildcard problem) :
for dir in */; do mv `ls -A "$dir" | grep -v "Word & Excel"` ./"Word & Excel" | cd ../ ; done
I am completely stuck.
Any idea how to handle this?
This should make it, even on Mac OS X. And yes, find sometimes needs the anchor directory.
while read dir; do
mkdir -p "$dir/Word & Excel"
find "$dir" -maxdepth 1 -type f -exec mv {} "$dir/Word & Excel" \;
done < <(find . -mindepth 1 -maxdepth 1 -type d)
This loops over the sub-directories of the current directory (one sub-level only), for each of them (dir), creates the dir/Word & Excel sub-sub-directory if it does not already exist, finds all regular files immediately inside dir and moves them in the dir/Word & Excel. And it should work even with crazy directory and file names.
This being said, if you could convince your boss not to use unusual file or directory names, you life with bash and the Command Line Interface (CLI) would probably be much easier.
Okay, I will use "subfolder" as my subfolder name.
First, creating subfolder within all the dirs
for dir in $(find -type d | grep "/");do mkdir $dir/subfolder; done
I each of one of those, I created a file. I order to move all files within the dirs to the subfolder, I will do something like:
for dir in $(find -type d | grep -vE 'subfolder' | grep '/');do for file in $(find $dir -type f);do mv $file $dir/subfolder;done ;done
You might want to experiment with --exec in find, but just creating a nested loop was the fastest solution for me.
Let me break it down for you. Here, I try to find all the directories in my path, excluding the subfolder directory and the current one. I could've used -maxdepth 0 with find but since I only had these dirs, it wasnt necessary
for dir in $(find -type d | grep -vE 'subfolder' | grep '/')
Now, in each of those dirs, we try to find all the files (in your case, the zip files and what now).
do for file in $(find $dir -type f)
Now, we just move the found files into the directories from the first loop with the name of the subfolder appended.
do mv $file $dir/subfolder;done ;done
Keep in mind that since the first loop is closed at the very end, it will do the move operation for 1 directory at a time, and for all files in only that directory. Nested loops can be a bit trickier to understand, especially when someone else does them their own way, I know :(

Go into every subdirectory and mass rename files by stripping leading characters

From the current directory I have multiple sub directories:
subdir1/
001myfile001A.txt
002myfile002A.txt
subdir2/
001myfile001B.txt
002myfile002B.txt
where I want to strip every character from the filenames before myfile so I end up with
subdir1/
myfile001A.txt
myfile002A.txt
subdir2/
myfile001B.txt
myfile002B.txt
I have some code to do this...
#!/bin/bash
for d in `find . -type d -maxdepth 1`; do
cd "$d"
for f in `find . "*.txt"`; do
mv "$f" "$(echo "$f" | sed -r 's/^.*myfile/myfile/')"
done
done
however the newly renamed files end up in the parent directory
i.e.
myfile001A.txt
myfile002A.txt
myfile001B.txt
myfile002B.txt
subdir1/
subdir2/
In which the sub-directories are now empty.
How do I alter my script to rename the files and keep them in their respective sub-directories? As you can see the first loop changes directory to the sub directory so not sure why the files end up getting sent up a directory...
Your script has multiple problems. In the first place, your outer find command doesn't do quite what you expect: it outputs not only each of the subdirectories, but also the search root, ., which is itself a directory. You could have discovered this by running the command manually, among other ways. You don't really need to use find for this, but supposing that you do use it, this would be better:
for d in $(find * -maxdepth 0 -type d); do
Moreover, . is the first result of your original find command, and your problems continue there. Your initial cd is without meaningful effect, because you're just changing to the same directory you're already in. The find command in the inner loop is rooted there, and descends into both subdirectories. The path information for each file you choose to rename is therefore stripped by sed, which is why the results end up in the initial working directory (./subdir1/001myfile001A.txt --> myfile001A.txt). By the time you process the subdirectories, there are no files left in them to rename.
But that's not all: the find command in your inner loop is incorrect. Because you do not specify an option before it, find interprets "*.txt" as designating a second search root, in addition to .. You presumably wanted to use -name "*.txt" to filter the find results; without it, find outputs the name of every file in the tree. Presumably you're suppressing or ignoring the error messages that result.
But supposing that your subdirectories have no subdirectories of their own, as shown, and that you aren't concerned with dotfiles, even this corrected version ...
for f in `find . -name "*.txt"`;
... is an awfully heavyweight way of saying this ...
for f in *.txt;
... or even this ...
for f in *?myfile*.txt;
... the latter of which will avoid attempts to rename any files whose names do not, in fact, change.
Furthermore, launching a sed process for each file name is pretty wasteful and expensive when you could just use bash's built-in substitution feature:
mv "$f" "${f/#*myfile/myfile}"
And you will find also that your working directory gets messed up. The working directory is a characteristic of the overall shell environment, so it does not automatically reset on each loop iteration. You'll need to handle that manually in some way. pushd / popd would do that, as would running the outer loop's body in a subshell.
Overall, this will do the trick:
#!/bin/bash
for d in $(find * -maxdepth 0 -type d); do
pushd "$d"
for f in *.txt; do
mv "$f" "${f/#*myfile/myfile}"
done
popd
done
You can do it without find and sed:
$ for f in */*.txt; do echo mv "$f" "${f/\/*myfile/\/myfile}"; done
mv subdir1/001myfile001A.txt subdir1/myfile001A.txt
mv subdir1/002myfile002A.txt subdir1/myfile002A.txt
mv subdir2/001myfile001B.txt subdir2/myfile001B.txt
mv subdir2/002myfile002B.txt subdir2/myfile002B.txt
If you remove the echo, it'll actually rename the files.
This uses shell parameter expansion to replace a slash and anything up to myfile with just a slash and myfile.
Notice that this breaks if there is more than one level of subdirectories. In that case, you could use extended pattern matching (enabled with shopt -s extglob) and the globstar shell option (shopt -s globstar):
$ for f in **/*.txt; do echo mv "$f" "${f/\/*([!\/])myfile/\/myfile}"; done
mv subdir1/001myfile001A.txt subdir1/myfile001A.txt
mv subdir1/002myfile002A.txt subdir1/myfile002A.txt
mv subdir1/subdir3/001myfile001A.txt subdir1/subdir3/myfile001A.txt
mv subdir1/subdir3/002myfile002A.txt subdir1/subdir3/myfile002A.txt
mv subdir2/001myfile001B.txt subdir2/myfile001B.txt
mv subdir2/002myfile002B.txt subdir2/myfile002B.txt
This uses the *([!\/]) pattern ("zero or more characters that are not a forward slash"). The slash has to be escaped in the bracket expression because we're still inside of the pattern part of the ${parameter/pattern/string} expansion.
Maybe you want to use the following command instead:
rename 's#(.*/).*(myfile.*)#$1$2#' subdir*/*
You can use rename -n ... to check the outcome without actually renaming anything.
Regarding your actual question:
The find command from the outer loop returns 3 (!) directories:
.
./subdir1
./subdir2
The unwanted . is the reason why all files end up in the parent directory (that is .). You can exclude . by using the option -mindepth 1.
Unfortunately, this was onyl the reason for the files landing in the wrong place, but not the only problem. Since you already accepted one of the answers, there is no need to list them all.
a slight modification should fix your problem:
#!/bin/bash
for f in `find . -maxdepth 2 -name "*.txt"`; do
mv "$f" "$(echo "$f" | sed -r 's,[^/]+(myfile),\1,')"
done
note: this sed uses , instead of / as the delimiter.
however, there are much faster ways.
here is with the rename utility, available or easily installed wherever there is bash and perl:
find . -maxdepth 2 -name "*.txt" | rename 's,[^/]+(myfile),/$1,'
here are tests on 1000 files:
for `find`; do mv 9.176s
rename 0.099s
that's 100x as fast.
John Bollinger's accepted answer is twice as fast as the OPs, but 50x as slow as this rename solution:
for|for|mv "$f" "${f//}" 4.316s
also, it won't work if there is a directory with too many items for a shell glob. likewise any answers that use for f in *.txt or for f in */*.txt or find * or rename ... subdir*/*. answers that begin with find ., on the other hand, will also work on directories with any number of items.

shell-script -cd in all subdirecories of a directory, execute command on their files

I am new to bash and i am trying to cd to all subdirectories of a parent directory and execute a command in all files these subdirecories contain.But it s not working.
for subdir in $parentdirectory
do
for file in $subdir
do
ngram - lm somefilename.lm - ppl file
done
done
There's many ways to do this, but one would require you to explicitly change to that directory. Assuming $parentdirectory is correctly initialized, then you could look into something like:
for subdir in ${parentdirectory}
do
cd ${subdir} # go into the subdir
for file in * # glob expansion
do
ngram - lm somefilename.lm - ppl ${file}
done
cd .. # go back up
done
Also have a look at the excellent Advanced Bash-Scripting Guide: http://tldp.org/LDP/abs/html/loops1.html
If you're wanting to do this with a small amount of space, you could do something using find -exec.
Such as:
# add a file called foo into every subdirectory
find . -type d -exec sh -c 'touch "$0/foo"' {} \;
Or, if you wanted to echo a string into each of those files you just created:
# find all files and append 'ABC' into them
find . -type f -exec sh -c 'echo "ABC" >> $0' {} \;
The find -exec combo is an extremely powerful tool that can save you on a bit of directory / file navigation, and allows you to achieve what it sounds like is the desired functionality without having to play descend/ascend through the directory structure.
Also, as you can probably guess, this kind of thing can go horribly wrong if you're not careful, so use with great caution.

Bash: How to control iteration flow/loops?

For going over some recovered data, I am working on a script that recursively goes through folders & files and finally runs file on them, to check if they are likely fully recovered from a certain backup or not. (recovered files play, and are identified as mp3 or other audio, non-working files as ASCII-Text)
For now I would just be satisfied with having it go over my test folder structure, print all folders & corresponding files. (printing them mainly for testing, but also because I would like to log where the script currently is and how far along it is in the end, to verify what has been processed)
I tried using 2 for loops, one for the folders, then one for the files. (so that ideally it would take 1 folder, then list the files in there (or potentially delve into subfolders) and below each folder only give the files in that subfolders, then moving on to the next.
Such as:
Folder1
- File 1
- File 2
-- Subfolder
-- File3
-- File4
Folder2
- File5
However this doesn't seem to work in the ways (such with for loops) that are normally proposed. I got as far as using "find . -type d" for the directories and "find . -type f" or "find * -type f" (so that it doesn't go in to subdirectories) However, when just printing the paths/files in order to check if it ran as I wanted it to, it became obvious that that didn't work.
It always seemed to first print all the directories (first loop) and then all the files (second loop). For keeping track of what it is doing and for making it easier to know what was checked/recovered I would like to do this in a more orderly fashion as explained above.
So is it that I just did something wrong, or is this maybe a general limitation of the for loop in bash?
Another problem that could be related: Although assigning the output of find to an array seemed to work, it wasn't accessible as an array ...
Example for loop:
for folder in '$(find . -type d)' ; do
echo $folder
let foldercounter++
done
Arrays:
folders=("$(find . -type d)")
#As far as I know this should assign the output as an array
#However, it is not really assigned properly somehow as
echo "$folders[1]"
# does not work (quotes necessary for spaces)
A find ... -exec ... solution #H.-Dirk Schmitt was referring to might look something like:
find . -type f -exec sh -c '
case $(file "$1") in
*Audio file*)
echo "$1 is an audio file"
;;
*ASCII text*)
echo "$1 is an ascii text file"
;;
esac
' _ {} ';'
For going over some recovered data, I am working on a script that recursively goes through folders & files and finally runs file on them, to check if they are likely fully recovered from a certain backup or not. (recovered files play, and are identified as mp3 or other audio, non-working files as ASCII-Text)
If you want to run file on every file and directory in the current directory, including its subdirectories and so on, you don't need to use a Bash for-loop, because you can just tell find to run file:
find -exec file '{}' ';'
(The -exec ... ';' option runs the command ... on every matched file or directory, replacing the argument {} with the path to the file.)
If you only want to run file on regular files (not directories), you can specify -type f:
find -type f -exec file '{}' ';'
If you (say) want to just print the names of directories, but run the above on regular files, you can use the -or operator to connect one directive that uses -type d and one that uses -type f:
find -type d -print -or -type f -exec file '{}' ';'
Edited to add: If desired, the effect of the above commands can be achieved in pure Bash (plus the file command, of course), by writing a recursive shell function. For example:
function foo () {
local file
for file in "$1"/* ; do
if [[ -d "$file" ]] ; then
echo "$file"
foo "$file"
else
file "$file"
fi
done
}
foo .
This differs from the find command in that it will sort the files more consistently, and perhaps in gritty details such as handling of dot-files and symbolic links, but is broadly the same, so may be used as a starting-point for further adjustments.

Bash loop through directory and rename every file

I am horrible at writing bash scripts, but I'm wondering if it's possible to recursively loop through a directory and rename all the files in there by "1.png", "2.png", etc, but I need it to restart at one for every new folder it enters. Here's script that works but only does it for one directory.
cd ./directory
cnt=1
for fname in *
do
mv $fname ${cnt}.png
cnt=$(( $cnt + 1 ))
done
Thanks in advance
EDIT
Can anyone actually write this code out? I have no idea how to write bash, and it's very confusing to me
Using find is a great idea. You can use find with the next syntax to find all directories inside your directory and apply your script to found directories:
find /directory -type d -exec youscript.sh {} \;
-type d parameter means you want to find only directories
-exec youscript.sh {} \; starts your script for every found directory and pass it this directory name as a parameter
Use find(1) to get a list of files, and then do whatever you like with that list.

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