Using Sed with regular expression to save results into a variable - bash

What I'm trying to do is take user input as a string and parse a section of the string. The results from my regex I want to save into a new variable. Here is what I have so far.
#!/bin/bash
downloadUrl="$1"
pythonFile=echo $downloadUrl | sed '/Python-[\d+.]+tgz/'
echo "$downloadUrl"
echo "$pythonFile"
And here is my result.
sed: 1: "/Python-[\d+.]+tgz/": command expected

You forgot to run the commands in $() to get command substitution. Use:
pythonFile=$(echo $downloadUrl | sed '/Python-[\d+.]+tgz/')
See the manual for more details.

sed '/Python-[\d+.]+tgz/' is incorrect since you need to have a sed command like p and anyway it is only searching not really extracting part of input text.
You can use grep -oP
pythonFile$(grep -oP '/Python-[\d+.]+tgz/' <<< "$downloadUrl")
Or without -P
pythonFile$(grep -o '/Python-[0-9+.]\+tgz/' <<< "$downloadUrl")

Related

Using a bash variable to pass multiple -e clauses to sed [duplicate]

This question already has answers here:
Why does shell ignore quoting characters in arguments passed to it through variables? [duplicate]
(3 answers)
Closed 6 years ago.
I'm creating a variable from an array which build up multiple -e clauses for a sed command.
The resulting variable is something like:
sedArgs="-e 's/search1/replace1/g' -e 's/search2/replace2/g' -e 's/search3/replace3/g'"
But when I try to call sed with this as the argument I get the error sed: -e expression #1, char 1: unknown command: ''
I've tried to call sed the following ways:
cat $myFile | sed $sedArgs
cat $myFile | sed ${sedArgs}
cat $myFile | sed `echo $sedArgs`
cat $myFile | sed "$sedArgs"
cat $myFile | sed `echo "$sedArgs"`
and all give the same error.
UPDATE - Duplicate question
As has been identified, this is a 'quotes expansion' issue - I thought it was something sed specific, but the duplicate question that has been identified put me on the right track.
I managed to resolve the issue by creating the sedArgs string as:
sedArgs="-e s/search1/replace1/g -e s/search2/replace2/g -e s/search3/replace3/g"
and calling it with:
cat $myFile | sed $sedArgs
which works perfectly.
Then I took the advice of tripleee and kicked the useless cat out!
sed $sedArgs $myFile
also works perfectly.
Use BASH arrays instead of simple string:
# sed arguments in an array
sedArgs=(-e 's/search1/replace1/g' -e 's/search2/replace2/g' -e 's/search3/replace3/g')
# then use it as
sed "${sedArgs[#]}" file
Here is no sane way to do that, but you can pass the script as a single string.
sedArgs='s/search1/replace1/g
s/search2/replace2/g
s/search3/replace3/g'
: then
sed "$sedArgs" "$myFile"
The single-quoted string spans multiple lines; this is scary when you first see it, but perfectly normal shell script. Notice also how the cat is useless as ever, and how the file name needs to be quoted, too.

Use sed substitution from different files

Okay, I am a newbie to Unix scripting. I was given the task to find a temporary work around for this:
cat /directory/filename1.xml |sed -e "s/ABCXYZ/${c}/g" > /directory/filename2.xml
$c is a variable from a sqlplus count query. I totally understand how this sed command is working. But here is where I am stuck. I am storing the count associated with the variable in another file called filename3 as count[$c] where $c is replaced with a number. So my question is how can I update this sed command to substitute ABCXYZ with the count from file3?
>>>>>>>>>>>>>>>>>>>>>>>>>>>>
UPDATE: In case anyone has a similar issue I got mine to work using:
rm /directory/folder/variablefilename.dat
echo $c >> /directory/folder/variablefilename.dat
d=$(grep [0-9] /directory/folder/variablefilename.dat)
sed -3 "s/ABC123/${d}/g" /directory/folder/inputfile.xml >> /directory/folder/outputfile.xml
thank you to Kaz for pointing me in the right direction
Store the count in filename3 using the syntax c=number. Then you can source the file as a shell script:
. /filename3 # get c variable
sed -e "s/ABCXYZ/${c}/g" /directory/filename1.xml > /directory/filename2.xml
If you can't change the format of filename3, you can write a shell function which scrapes the number out of that file and sets the c variable. Or you can scrape the number out with an external program like grep, and then interpolate its output into a variable assignment using command substitution: $(command arg ...) syntax.
Suppose we can rely on file3 to contain exactly one line of the form count[42]. Then we can just extract the digits with grep -o:
c=$(grep -E -o '[0-9]+' filename3)
sed -e "s/ABCXYZ/$c/g" /directory/filename1.xml > /directory/filename2.xml
The c variable can be eliminated, of course; you can stick the $(grep ...) into the sed command line in place of $c.
A file which contains numerous instances of syntax like count[42] for various variables could be transformed into a set of shell variable assignments using sed, and then sourced into the current shell to make those assignments happen:
$ sed -n -e 's/^\([A-Za-z_][A-Za-z0-9_]\+\)\[\(.*\)\]/\1=\2/p' filename3 > vars.sh
$ . ./vars.sh
you can use sed like this
sed -r "s/ABCXYZ/$(sed -nr 's/.*count[[]([0-9])+[]].*/\1/p' path_to_file)/g" path_to_file
the expression is double quoted which allow the shell to execute below and find the number in count[$c] in the file and use it as a substitute
$(sed -nr 's/.*count[[]([0-9])+[]].*/\1/p' path_to_file)

Unix shell scripting, need assign the text files values to the sed command

i was trying to add the lines from the text file to the sed command
observered_list.txt
Uncaught SlingException
cannot render resource
IncludeTag Error
Recursive invocation
Reference component error
i need it to be coded like the following
sed '/Uncaught SlingException\|cannot render resource\|IncludeTag Error\|Recursive invocation\|Reference component error/ d'
help me to do this.
I would suggest you create a sed script and delete each pattern consecutively:
while read -r pattern; do
printf "/%s/ d;\n" "$pattern"
done < observered_list.txt >> remove_patterns.sed
# now invoke sed on the file you want to modify
sed -f remove_patterns.sed file_to_clean
Alternatively you could construct the sed command like this:
pattern=
while read -r line; do
pattern=$pattern'\|'$line
done < observered_list.txt
# strip of first and last \|
pattern=${pattern#\\\|}
pattern=${pattern%\\\|}
printf "sed '/%s/ d'\n" "$pattern"
# you still need to invoke the command, it's just printed
You can use grep for that:
grep -vFf /file/with/patterns.txt /file/to/process.txt
Explanation:
-v excludes lines of process.txt which match one of the patterns from output
-F treats patterns in patterns.txt as fixed strings instead of regexes (looks like this is desired here)
-f reads patterns from patterns.txt
Check man grep for further information.

Replace all unquoted characters from a file bash

Using bash, how would one replace all unquoted characters from a file?
I have a system that I can't modify that spits out CSV files such as:
code;prop1;prop2;prop3;prop4;prop5;prop6
0,1000,89,"a1,a2,a3",33,,
1,,,"a55,a10",1,1 L,87
2,25,1001,a4,,"1,5 L",
I need this to become, for a new system being added
code;prop1;prop2;prop3;prop4;prop5;prop6
0;1000;89;a1,a2,a3;33;;
1;;;a55,a10;1;1 L;87
2;25;1001;a4;1,5 L;
If the quotes can be removed after this substitution happens in one command it would be nice :) But I prefer clarity to complicated one-liners for future maintenance.
Thank you
With sed:
sed -e 's/,/;/g' -e ':loop; s/\("\)\([^;]*\);\([^"]*"\)/\1\2,\3/; t loop'
Test:
$ sed -e 's/,/;/g' -e ':loop; s/\("\)\([^;]*\);\([^"]*"\)/\1\2,\3/; t loop' yourfile
code;prop1;prop2;prop3;prop4;prop5;prop6
0;1000;89;"a1,a2,a3";33;;
1;;;"a55,a10";1;1 L;87
2;25;1001;a4;;"1,5 L";
You want to use a csv parser. Parsing csv with shell tools is hard (you will encounter regular expressions soon, and they rarely get all cases).
There is one in almost every language. I recommend python.
You can also do this using excel/openoffice variants by opening the file and then saving with ; as the separator.
You can used sed:
echo '0,1000,89,"a1,a2,a3",33,,' | sed -e "s|\"||g"
This will replace " with the empty string (deletes it), and you can pipe another sed to replace the , with ;:
sed -e "s|,|;|g"
$ echo '0,1000,89,"a1,a2,a3",33,,' | sed -e "s|\"||g" | sed -e "s|,|;|g"
>> 0;1000;89;a1;a2;a3;33;;
Note that you can use any separator you want instead of | inside the sed command. For example, you can rewrite the first sed as:
sed -e "s-\"--g"

How to delete the string which is present in parameter from file in unix

I have redirected some string into one parameter for ex: ab=jyoti,priya, pranit
I have one file : Name.txt which contains -
jyoti
prathmesh
John
Kelvin
pranit
I want to delete the records from the Name.txt file which are contain in ab parameter.
Please suggest if this can be done ?
If ab is a shell variable, you can easily turn it into an extended regular expression, and use it with grep -E:
grep -E -x -v "${ab//,/|}" Name.txt
The string substitution ${ab//,/|} returns the value of $ab with every , substituted with a | which turns it into an extended regular expression, suitable for passing as an argument to grep -E.
The -v option says to remove matching lines.
The -x option specifies that the match needs to cover the whole input line, so that a short substring will not cause an entire longer line to be removed. Without it, ab=prat would cause pratmesh to be removed.
If you really require a sed solution, the transformation should be fairly trivial. grep -E -v -x 'aaa|bbb|ccc' is equivalent to sed '/^\(aaa\|bbb\|ccc)$/d' (with some dialects disliking the backslashes, and others requiring them).
To do an in-place edit (modify Name.txt without a temporary file), try this:
sed -i "/^\(${ab//,/\|}\)\$/d" Name.txt
This is not entirely robust against strings containing whitespace or other shell metacharacters, but if you just need
Try with
sed -e 's/\bjyoti\b//g;s/\bpriya\b//g' < Name.txt
(using \b assuming you need word boundaries)
this will do it:
for param in `echo $ab | sed -e 's/[ ]+//g' -e 's/,/ /g'` ; do res=`sed -e "s/$param//g" < name.txt`; echo $res > name.txt; done
echo $res

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