In new in laravel.
I trying to create a folder inside a folder using laravel.I want to create a new folder inside the another folder .what is the html code for blade.php page.
you can use File::makeDirectory to create folder inside folder
$path = public_path().'/uploads/test';
File::makeDirectory($path,0777, true, true);
List All Directory for user john
main directory john_1
1.1 john has 3 sub directory abc,xyz and mno
get all directory of user john and pass it view from controller
$list = File::directories('/john_1');
return View::make('upload',array('list' => $list));
finally display it as selectbox
{{ Form::select('folder_name', $list, null, array('class' => 'form-control')) }}
list all image from user john
foreach (File::allFiles(public_path().'/john_1/img/') as $file) {
$filename = $file->getRelativePathName();
echo HTML::image('public/john_1/img/'.$filename, $filename);
}
This will attempt to create /uploads if it doesn't exist. Then
/uploads/test if it doesn't exist.If all created directories are
successfully created then true will be returned.
Related
I want to create search file form, where user search files based on year.I already made folder file in a years (ex. folder 2019, folder 2018, etc), so when user input value the results will show based on user input. I get the result that i want, but i can't download file as zip because the value og path folder is null. I already tried use input-> get and session-> set_flashdata, but the result still null. My question is how do I get the year value, so can direct to the path folder?
Note : tahun is years in english
Controller
public function download_zip() {
// Read files from directory
$tahun = $this->input->get('tahun');
if($this->input-post('but_createzip2') != NULL){
// File name
$filename = $tahun . _laporan.zip;
// Directory path (uploads directory stored in project root)
$path = './uploaded/laporan/'.$tahun.'/';
// Add directory to zip
$this->zip->read_dir($path, FALSE);
// Save the zip file to archivefiles directory
$this->zip->archive('./uploaded/backup_laporan/'. $filename);
// Download
$this->zip->download($filename);
}
// Load view
$this->load->view('v_detail_laporan');
}}
View
<form role="form" action="<?php echo base_url().'laporan'?>">
<input type = "text" id="tahun" name="tahun" class="form-control" placeholder="Masukkan Tahun" required/>
</form>
// Download
<?php echo form_open('laporan/download_zip'); ?>
You are posting dat using GET method then why are you made condition in POST method
public function download_zip() {
// Read files from directory
$tahun = $this->input->get('tahun');
if($this->input->get('tahun') != NULL){ // MODIFIED HERE YOU ARE PASSING VALUES USING GET METHOD
// File name
$filename = $tahun ."_laporan.zip";
// Directory path (uploads directory stored in project root)
$path = './uploaded/laporan/'.$tahun.'/';
// Add directory to zip
$this->zip->read_dir($path, FALSE);
// Save the zip file to archivefiles directory
$this->zip->archive('./uploaded/backup_laporan/'. $filename);
// Download
$this->zip->download($filename);
}
// Load view
$this->load->view('v_detail_laporan');
}
Try this code
You have a wrong form target, try to modify the codes be like below.
View :
<?php echo form_open('laporan/download_zip', ['method' => 'post', 'role' => 'form']); ?>
<?php echo form_hidden('but_createzip2','1');?>
<input type = "text" id="tahun" name="tahun" class="form-control" placeholder="Masukkan Tahun" required/>
<?php echo form_close(); ?>
Controller :
public function download_zip() {
// Read files from directory
$tahun = $this->input->post('tahun');
if($this->input-post('but_createzip2') != NULL){
// File name
$filename = $tahun . _laporan.zip;
// Directory path (uploads directory stored in project root)
$path = './uploaded/laporan/'.$tahun.'/';
// Add directory to zip
$this->zip->read_dir($path, FALSE);
// Save the zip file to archivefiles directory
$this->zip->archive('./uploaded/backup_laporan/'. $filename);
// Download
$this->zip->download($filename);
}
// Load view
$this->load->view('v_detail_laporan');
}
I can't figure out how to get a database file attachment, to be downloaded with is real file name.
My model have many file attachements (many attachOne) and there is no problem to get link to them with
{{ model.myfile.filename }}
What I want to do is to get those files downloaded with their real file name.
I try to define an ajax event handler in my layout like so :
function onDonwload()
{
$path = post('path');
$name = post('name');
// Storage::exists('uploads/public/5ce/28c/3aa/5ce27c3aae590316657518.pdf'); => OK
// Storage::exists($path); =>OK
$path = storage_path().'/app/'. $path;
return Response::download( $path, $name);
}
and
<button data-request="onDonwload"
data-request-data="path: 'uploads/public/5ce/28c/3aa/5ce27c3aae590316657518.pdf', name: 'my real name">
Download
</button>
No missing file error, but get the browser to freeze with an alert that say "A webpage slow down your browser, what do you want to do?".
Did I miss an important point?
You should add separate page for downloading files, Ajax can not help you to download file ( may be it can but process is little complex and long)
create page with /file-download/:id here you can specify any url wit param :id and give it name file-download you can give any name you like for demo i used this name.
In that Page Html section will be Blank and in Page's code section add this code. here you can also check additional security check like user is logged in or not file is of related user or not. for now i am just checking file is related to particular Modal or not.
function onStart() {
$fileId = $this->param('id');
$file = \System\Models\File::find($fileId);
// for security please check attachment_type == your model with namespace
// only then lat use download file other wise user can download all the files by just passing id
if($file && $file->attachment_type == 'Backend\Models\User') { // here add your relation model name space for comparison
$file->output('attachment');
}
else {
echo "Unauthorised.";
}
exit();
}
Generating links, please replace page name with page you created.
<a href="{{ 'file-download'|page({'id': model.myfile.id}) }}" >{{ model.myfile.filename }}</a>
Now, when you click on link file should be downloaded with its original name, and for invalid file id it should show message Unauthorised..
if any doubts please comment.
i have upload section that stores files name in user's table, and files in Folder named as File.
i want to access that file from name stored in database.
i.e if it is a zip file it should get downloaded, if doc, pdf etc it should get open online.
my code in controller that fetches files:
$users = DB::table('users')->select('attachments')->where('id',$id)->first();
$attach = explode(",", $users->attachments);
return View::make('admin.RegisterStaff.show')
->with('attach', $attach);
my code in blade file to display files:
<div class="col-md-4">
#foreach($attach as $data)
{{ $data }}<br>
#endforeach
</div>
what is the best way to access files..??
You can try
#if($data->getClientOriginalExtension() == 'docx')
//do anything you want
#endif
I wanna ask a question, anyone know how to transfer data from local / public to ftp, I'm using Storage class
https://laravel.com/docs/5.4/filesystem
Here's my code
$file_local = Storage::disk('local')->get('public/uploads/ftp/file.pdf');
$file_ftp = Storage::disk('ftp')->put('/file.pdf', $file_local');
But my code is not working, when I open the file on ftp, the file is broken, then I open it with notepad, inside file, the content is 'public/uploads/ftp/file.pdf' the content I mean content should on local not what I was wrote,
Anyone know how to transfer file from local to ftp, sorry for my bad English, Thanks for your answer anyway
To get started, you should know the details of your FTP host, FTP username, and FTP password. Once, you are ready with the details open the .env files and add the details as below:
FTP_HOST=YOUR_FTP_HOST_VALUE
FTP_USERNAME=YOUR_FTP_USERNAME_VALUE
FTP_PASSWORD=YOUR_FTP_PASSWORD_VALUE
Make sure to replace the placeholders with the actual values. Next, open the config/filesystems.php file and add the ‘ftp’ configuration to the ‘disks’ array.
<?php
return [
......
'disks' => [
......
'ftp' => [
'driver' => 'ftp',
'host' => env('FTP_HOST'),
'username' => env('FTP_USERNAME'),
'password' => env('FTP_PASSWORD'),
'root' => 'DIR_PATH_TO_WHERE_IMAGE_STORE' // for example: /var/www/html/dev/images
],
],
];
Replace DIR_PATH_TO_WHERE_IMAGE_STORE with the actual path where you need to store images. For example, if we have folder called ‘images’ and path to this folder is /var/www/html/dev/images then this path will go as the value for ‘root’ in the above array.
For uploading files through FTP we need a form where a user can submit the image. Add the below code in your view file.
<form action="{{ url('PASS_ACTION_URL_HERE') }}" method="post" enctype="multipart/form-data">
<div class="form-group">
<label for="exampleInputFile">File input</label>
<input type="file" name="profile_image" id="exampleInputFile" multiple />
</div>
{{ csrf_field() }}
<button type="submit" class="btn btn-default">Submit</button>
</form>
You should replace the PASS_ACTION_URL_HERE with your actual route. As we are using a Laravel Storage to file uploading user need add Facade to the controller file as follows:
public function store(Request $request)
{
if($request->hasFile('profile_image')) {
//get filename with extension
$filenamewithextension = $request->file('profile_image')->getClientOriginalName();
//get filename without extension
$filename = pathinfo($filenamewithextension, PATHINFO_FILENAME);
//get file extension
$extension = $request->file('profile_image')->getClientOriginalExtension();
//filename to store
$filenametostore = $filename.'_'.uniqid().'.'.$extension;
//Upload File to external server
Storage::disk('ftp')->put($filenametostore, fopen($request->file('profile_image'), 'r+'));
//Store $filenametostore in the database
}
return redirect('images')->with('status', "Image uploaded successfully.");
}
‘profile_image’ is the name of our file input. We build the unique name of our file and then uploading it to an external server. Notice we have used Storage::disk(‘ftp’) method. This function would store our file to the path as defined in the configuration. A user should store the value ‘$filenametostore’ in your database.
'local' => [
'driver' => 'local',
'root' => storage_path().'/app',
],
If you use the local disk (config/filesystems.php) you are looking in 'storage/app' not the public folder unless you have changed the default settings. So:
$file_local = Storage::disk('local')->get('file.pdf');
will look for 'Storage/App/file.pdf'
Make sure your pdf is in that folder and give this a try:
$file_local = Storage::disk('local')->get('file.pdf');
$file_ftp = Storage::disk('ftp')->put('file.pdf', $file_local);
EDIT: also, I notice in your original post second line of code you have rogue ' after $file_local ;)
Iam new in laravel. 1st Im create a new folder (gallery) in public/img/uploads/gallery.
code is $f1=Input::get('f1');
$path ='img/uploads/'.$f1;
File::makeDirectory($path, 0777, true, true);
Then Im trying to insert image to this gallery folder.
1st Im create a select box to etch all the folders from public/img/uploads/ using this code { Form::select('f1', $list, null, array('class' => 'form-control')) }}
and enter gallery name(textbox) ,browse image(file).then im submit. the details are goto database .but the image not go to gallery folder ,but create a new folder &image save into that folder. using controller.php is here else
{ $f1=Input::get('f1');
$file=File::directories('/img/uploads/', '=', $f1)->first();
$file=Input::file('galimg');
$filename=$file->getClientOriginalName();
$file->move('img/uploads/'.$f1,$filename);
ForumGallery::create([
'galname'=>Input::get('galname'),
'galimg'=>$f1.'/'.$filename
]);return Redirect::route('addnewgallery')
->with('success',' Gallery Details Entered succesfully');}
i Want image save into gallery(selcted) folder and databse.
How to save image into selected folder??