I am trying to loop my project folder recursively, grep every PHP file and find any string that matches xdebug_break();.
Then I want to remove that xdebug_break() (I will accept replacing with a space as well).
Here's what I got so far:
#!/bin/bash
FILES=$(find ../../Dev/projects/api -type f -name *.php)
for f in $FILES
do
if grep -nr "xdebug_break();" $f
then
sed -e '/xdebug_break();/d' -i $f
echo "xdebug_break(); has been deleted."
fi
done
Everything works, except the replace part. I keep getting this error:
sed: -i may not be used with stdin
I do not care if its sed or awk or whatever (but I do use a mac).
Thanks,
SOLUTION (FOR FUTURE READERS)
Thanks for the help everyone (ESP #anubhava). This one line trick did it for me:
find ../../Dev/projects/api -type f -name "*.php" -exec sed -i '' '/xdebug_break();/d' {} +
Also you can do it by loop (if you really really want to) like this:
#!/bin/bash
FILES=$(find ../../Dev/projects/api -type f -name *.php)
for f in $FILES
do
if grep -nr "xdebug_break();" $f
then
sed -i '' '/xdebug_break();/d' "$f"
echo "xdebug_break(); has been deleted."
fi
done
On OSX, your sed command should be:
sed -i.bak '/xdebug_break();/d' "$f"
Here .bak is the name of extension to create a backup of input file in inline editing.
You can avoid loop and do it in one find like this:
find ../../Dev/projects/api -type f -name "*.php" \
-exec sed -i.bak '/xdebug_break();/d' {} +
You can combine find and sed:
find Dev/projects/api -type f -name '*.php' -exec sed -i.bak '/xdebug_break();/d' {} \;
Related
I have a large directory of folders, each of which has only one file:
directory/folder1/208hasdfasdf.jpg
directory/folder2/f230fsdf.gif
directory/folder3/23fsdbfasf.jpg
I'd like to rename this to:
directory2/folder1/folder1.jpg
directory2/folder2/folder2.gif
directory3/folder3/folder3.jpg
How can I do that?
For the path and filenames shown, you can use a loop and combination of find and sed to make the substitutions, e.g.
for f in $(find directory -type f -wholename "*folder*"); do
mv "$f" $(sed -E 's|^([^/]+)/([^/]+)/([^.]+)[.](.*)$|\1/\2/\2.\4|' <<< "$f")
done
Where sed -E 's|^([^/]+)/([^/]+)/([^.]+)[.](.*)$|\1/\2/\2.\4| uses the alternative delimiter '|' instead of '/' to ease dealing with pathnames, and then separates and captures the "directory" with ^([^/]+) and then the "folderX" with ([^/]+), followed by the filename without the extension ([^.]+) and lastly the extension (.*)$ making each component available through the numbered backreferences \1, \2, \3, and \4, respectively.
Then to form the new filename, you just duplicate the \2 foldername in place of the \3 filename, for a new filename of \1/\2/\2.\4
Example Use/Output
$ find tmp-david -type f -wholename "*folder*"
tmp-david/folder3/23fsdbfasf.jpg
tmp-david/folder2/f230fsdf.gif
tmp-david/folder1/208hasdfasdf.jpg
And the replacement of the filenames with
$ for f in $(find tmp-david -type f -wholename "*folder*"); do
> mv "$f" $(sed -E 's|^([^/]+)/([^/]+)/([^.]+)[.](.*)$|\1/\2/\2.\4|' <<< "$f")
> done
Resulting in:
$ find tmp-david -type f -wholename "*folder*"
tmp-david/folder3/folder3.jpg
tmp-david/folder2/folder2.gif
tmp-david/folder1/folder1.jpg
You could try something like this, assuming you're using bash:
find directory/ \( -name '*.gif' -o -name '*.jpg' \) -print |
while read old; do
parent=${old%/*}
base=${parent##*/}
ext=${old##*.}
mv $old $parent/$base.$ext
done
If you're dealing with filenames that contain whitespace you're going
to need to massage this a bit.
Before running this script:
$ find directory -type f -print
directory/folder2/f230fsdf.gif
directory/folder1/208hasdfasdf.jpg
directory/folder3/23fsdbfasf.jpg
After running this script:
$ find directory -type f -print
directory/folder2/folder2.gif
directory/folder1/folder1.jpg
directory/folder3/folder3.jpg
Here is my current code, my goal is to find every file in a given directory (recursively) and replace "FIND" with "REPLACEWITH" and overwrite the files.
FIND='ALEX'
REPLACEWITH='<strong>ALEX</strong>'
DIRECTORY='/some/directory/'
find $DIRECTORY -type f -name "*.html" -print0 |
LANG=C xargs -0 sed -i "s|$FIND|$REPLACEWITH|g"
The error I am getting is:
sed: 1: "/some/directory ...": command a expects \ followed by text
As given in BashFAQ #21, you can use perl to perform search-and-replace operations with no potential for data being treated as code:
in="$FIND" out="$REPLACEWITH" find "$DIRECTORY" -type f -name '*.html' \
-exec perl -pi -e 's/\Q$ENV{"in"}/$ENV{"out"}/g' '{}' +
If you want to include only files matching the FIND string, find can be told to only pass files which grep flags on to perl:
in="$FIND" out="$REPLACEWITH" find "$DIRECTORY" -type f -name '*.html' \
-exec grep -F -q -e "$FIND" '{}' ';' \
-exec perl -pi -e 's/\Q$ENV{"in"}/$ENV{"out"}/g' '{}' +
Because grep is being used to evaluate individual files, it's necessary to use one grep call per file so its exit status can be evaluated on a per-file basis; thus, the use of the less efficient -exec ... {} ';' action. For perl, it's possible to put multiple files to process on one command, hence the use of -exec ... {} +.
Note that fgrep is line-oriented; if your FIND string contains multiple lines, then files with any one of those lines will be passed to perl for replacements.
You can have find invoke sed directly although I think all the modification times on your files will be affected (which might matter or not):
find $DIRECTORY -type f -name "*.html" -exec sed -i "s|$FIND|$REPLACEWITH|g" '{}' ';'
I would like to replace the part of each file path, which will be find by find linux command.
My approach is attached below:
find . -type f -name "*.txt" -exec echo {} | sed "s/f/u/g" {} \;
I expect the replacement of each letter "f" with "u" in file path. Unfortunately I got this error:
find: missing argument to `-exec'
sed: can't read {}: No such file or directory
sed: can't read ;: No such file or directory
What I did wrong? Thank you for your help.
I would like to replace the part of each file path
If you want to change just the file names/paths then use:
find . -type f -name "*.txt" -exec bash -c 'echo "$1" | sed "s/f/u/g"' - {} \;
or a bit more efficient with xargs (since it avoids spawning subshell for each found file):
find . -type f -name "*.txt" -print0 |
xargs -0 bash -c 'for f; do sed "s/f/u/g" <<< "$f"; done'
find . -type f -name "*.txt" | while read files
do
newname=$(echo "${files}" | sed s"#f#u#"g)
mv -v "${files}" "${newname}"
done
I don't completely understand what you meant by file path. If you weren't talking about the file name, please clarify further.
How can I convert tabs to spaces in in all .js files in a directory in one command?
find . -type f -iname "*.js" -print0 | xargs -0 -I _FILE_ tab2space _FILE_ _FILE_
This would convert tabs to four spaces:
find /path/to/directory -type f -iname '*.js' -exec sed -ie 's|\t| |g' '{}' \;
Change the space part in sed between the next two | to have a custom number of spaces you like.
Another way is to process all files to one sed call at once with +:
find /path/to/directory -type f -iname '*.js' -exec sed -ie 's|\t| |g' '{}' '+'
Just consider the possible limit of arguments to a command by the system.
Simpler syntax:
for F in *.js; do sed -iE 's|\t| |g' $F; done
(Caution, edits files in place.) Could be made to rename edited copy, or placed into a function if you do this often.
I have a script for changing file names of mht files but it does not traverse through dirs and sub dirs. I asked a question on a local forum and I got an answer that this is a solution:
find . -type f -name "*.mhtml" -o -type f -name "*.mht" | xargs -I item sh -c '{ echo item; echo item | sed "s/[:?|]//g"; }' | xargs -n2 mv
But it generates an error. With some of my experimenting it turns out that sh -c breaks file names with space and that this generates an error. How can I fix this?
#!/bin/bash
# renames.sh
# basic file renamer
for i in . *.mht
do
j=`echo $i | sed 's/|/ /g' | sed 's/:/ /g' | sed 's/?//g' | sed 's/"//g'`
mv "$i" "$j"
done
#! /bin/bash
find . -type f \( -name "*.mhtml" -o -name ".mht" \) -print0 |
while IFS= read -r -d '' source; do
target="${source//[:?|]/}"
[ "X$source" != "X$target" ] &&
mv -nv "$source" "$target"
done
Update: Do the rename according to the original question, and added support for .mht.
Use rename. With rename you can specify a renaming pattern:
find . -type f \( -name "*.mhtml" -o -name "*.mht" \) -print0 | xargs -0 -I'{}' rename 's/[:?|]//g' "{}"
This way you can properly handle names with spaces. xargs will replace {} with every names of file provided by the find command. Also note the use of -print0 and -0. This use a \0 as a separator so its avoid problems dealing with filnames containing \n (newline).
The -o was not working the way it was intended to. you must use parenthesis to group conditions.
You may also consider using -iname instead of -name if you deal with file ending with ".mHtml".