FetchXML equivalent - Left outer join, Union and Ordering - dynamics-crm

I'd like to create a dynamics CRM 2013 report which basically joins one table to a union of two other tables, with a left outer join. I believe that the outer join is now not a problem with the latest version, however there is still no union equivalent. What would be the best way to achieve this? I need the union as I want to sort data from two tables on a date column that is in both. Please see below for a tsql representation.
select * from
Record as rec
LEFT OUTER JOIN
(select * from Data1 as d1
UNION
select * from Data2 as d2) as data
on
rec.recordId = data.RecordId
order by rec.recordId, data.Date

Related

Oracle: Joining two table with a common column plus a additional column(latest effective date) from second table to select other column

Joining two table with a common column plus an additional column (latest effective date) from the second table to select another column. I joined the tables with all conditions, but the resulting table has duplicate records as there are multiple records in Table2 for the same identifier, out of which I just need the record with the latest effective date. I am using Oracle.
Table1 (Column A, B, C, D);Table2 (C, Efft_date, X),Table3...
The result should be as below after Joining the tables: A, B, C, X and columns from other tables
Value of X depends on latest/max value of efft_date from Table2.
Other Info: There are other tables that are joined and other conditions in where clause.
Please help to join the tables without duplicates
So you need to further restrict your result set based on the max of table2.efft_date. So you need a clause like:
AND table2.efft_date = ( SELECT MAX( table2b.efft_date)
FROM table2 AS table2b
WHERE table2b.c = table2.c )
This assumes that table2 cannot have duplicate efft_date values.
You need to join to a subquery so that you get just 1 "latest date" for each value of column c. For this I recommend using row_number()
select t1.A, t1.B, t1.C, t1.D, t2.x, t2.efft_date
from table1 t1
inner join (
select c, x, efft_date, row_number() over(partition by c order by efft_date DESC) as rn
from table2
) t2 on t1.c = t2.c and t2.rn = 1
...
Note that by ordering the dates in descending values, the most recent date will be assigned the row number of 1. Hence the join condition and rn = 1 will only allow the most recent dates to be included in the result.
Changing the order to ascending date order would do the revers, just allow the earliest dates.

Difference between standard outer left join and join using select

Is there any difference between these two statements:
-- Statement 1:
SELECT *
FROM Table1 t1
LEFT OUTER JOIN TABLE2 t2 on t1.id = t2.id
and
-- Statement 2:
SELECT *
FROM Table1 t1
LEFT OUTER JOIN (SELECT id, a, b, c FROM Table2) t2 on t1.id = t2.id
I'm not an expert but statement 2 just looks like poorly written sql, and like it would take much longer. I'm attempting to optimize a code block and it has many joins like the second one. Are they technically the same and I can just replace with the standard join statement 1?
Thanks!
Ps. This is Oracle, and working with 100's of millions of rows.
PSS. I'm doing my own detective work to figure out if they are the same, and time differences, was hoping an expert could explain if there is a technical difference what it is.
They are not same queries, with the lack of a criteria in the subquery that depends on whether the all columns and all column names of the TABLE2 is involved in the subquery. If the subquery involves all of the column names of the TABLE2 in the select list then they are the same query and the subquery is unnecessary. With subquery I refer to the part with a select statement after the join statement in the parens.
The first one uses the TABLE2 with its all columns, all those columns will be available in the result set where the criteria met.
However in the second one the table you make the JOIN is not the TABLE2 of yours but a table with just columns from TABLE2 specified in the subquery's SELECT list, namely id, a, b, and c. But it will have all the rows after this subquery since no criteria is enforced on it by a WHERE clause in the subquery.
You will have same number of rows with only selected columns participating from the TABLE2.
The second one is not necessarily the poorly written one. You could have a criteria to met before you JOIN to the TABLE2.

How to left join with conditions in Toad Data Point Query Builder?

I'm trying to build a query in Toad Data Point. I have a subquery that has a row number to identify the records I'm interested in. This subquery needs to be left joined onto the main table only when the row number is 1. Here's the query I'm trying to visualize:
SELECT distinct E.EMPLID, E.ACAD_CAREER
FROM PS_STDNT_ENRL E
LEFT JOIN (
SELECT ACAD_CAREER, ROW_NUMBER() OVER (PARTITION BY ACAD_CAREER ORDER BY EFFDT DESC) as RN
FROM PS_ACAD_CAR_TBL
) T on T.ACAD_CAREER = E.ACAD_CAREER and RN = 1
When I try to replicate this, the row number condition is placed in the global WHERE clause. This is not the intended functionality because it removes any records that don't have a match in the subquery effectively making it an inner join.
Here is the query it's generating:
SELECT DISTINCT E.EMPLID, E.ACAD_CAREER, T.RN
FROM SYSADM.PS_STDNT_ENRL E
LEFT OUTER JOIN
(SELECT PS_ACAD_CAR_TBL.ACAD_CAREER,
ROW_NUMBER ()
OVER (PARTITION BY ACAD_CAREER ORDER BY EFFDT DESC)
AS RN
FROM SYSADM.PS_ACAD_CAR_TBL PS_ACAD_CAR_TBL) T
ON (E.ACAD_CAREER = T.ACAD_CAREER)
WHERE (T.RN = 1)
Is there a way to get the query builder to place that row number condition on the left join instead of the global WHERE clause?
I found a way to get this to work.
Add a calculated field to the main table with a value of 1.
Join the row number to this new calculated field.
Now the query has the filter in the join condition instead of the WHERE clause so that it joins as intended. Here is the query it made:
SELECT DISTINCT E.EMPLID, E.ACAD_CAREER, T.RN
FROM SYSADM.PS_STDNT_ENRL E
LEFT OUTER JOIN
(SELECT PS_ACAD_CAR_TBL.ACAD_CAREER,
ROW_NUMBER ()
OVER (PARTITION BY ACAD_CAREER ORDER BY EFFDT DESC)
AS RN
FROM SYSADM.PS_ACAD_CAR_TBL PS_ACAD_CAR_TBL) T
ON (E.ACAD_CAREER = T.ACAD_CAREER) AND (1 = T.RN)

Converting rownum from Oracle to Postgres

I need to make a conversion from Oracle SQL to PostgreSQL.
select * from table1 inner join table2 on table1.id = table2.table1Id
where table1.col1 = 'TEST'
and rownum <=5
order by table2.col1
If I delete and rownum <=5 and put at the end limit 5, there are differences between the 2 dialects. In Oracle, first are selected the 5 elements, and after that, they are sorted by table2.col1 . In Postgres, first all the list is sorted, and AFTER there are selected the first 5 elements.
How can I obtain the same result in Postgres as in Oracle?
Thanks!
To get the behavior you desire, you can use a subquery like this:
SELECT * FROM (
SELECT table1.col1 as t1col1, table2.col1 as t2col1
FROM table1 INNER JOIN table2 ON table1.id = table2.table1Id
WHERE table1.col1 = 'TEST'
LIMIT 5
) AS sub
ORDER BY t2col1;
I named the columns there because in your example both tables had a col1.
Note however that without any ordering on the inner query, the selection of 5 rows you get will be purely random and subject to change.
Depending on the version you are using, PostgreSQL 8.4 and above have Window functions. Window function ROW_NUMBER() is capable of implementing the functionality of Oracle pseudo column rownum.
select row_number() over() as rownum,* from table1 inner join table2 on table1.id = table2.table1Id where table1.col1 = 'TEST' and rownum <=5 order by table2.col1;

Oracle join query

I have two tables
Table A has columns id|name|age.
Table B has columns id|name|age.
Sample Records from table A
1|xavi |23
2|christine|24
3|faisal |25
5|jude |27
Sample Records from table B
1|xavi |23
2|christine|22
3|faisal |23
4|ram |25
If id values from table A matches in table B than take records from table A only.
Also take records which are present in table A only
Also take records which are present in table B only
So my result should be
1|xavi |23
2|christine|24
3|faisal |25
4|ram |25
5|jude |27
You can simply use union operator to get unique values from both tables. Operator UNION will remove repeated values.
SELECT * FROM tableA AS t1
UNION
SELECT * FROM tableB AS t2
You have a precedence problem here. Take all the records from table A and then the extra records from table B:
select *
from A
union all
select *
from B
where B.id not in (select A.id from A);
You can also express this with a full outer join (assuming id is not duplicated in either table):
select coalesce(A.id, B.id) as id,
coalesce(A.name, B.name) as name,
coalesce(A.age, B.age) as age
from A full outer join
B
on A.id = B.id;
In this case, the coalesce() gives priority to the values in A.
select distinct * FROM
(
select ID, NAME, AGE from TableA
UNION ALL
select ID, NAME, AGE from TableB
) TableAB
Some things to consider --> Unless you're updating specific tables and the records are the same, it will not matter which table you're viewing the records from (because they're the same...).
If you want to see which table the records are deriving from, let me know and i'll show you how to do that as well... but the query is more complex and i don't really think it's required for the purpose described above. let me know if this helps... thanks, Brian
If the tables has relation you need:
Select DISTINCT *
from tableA a
Inner Join tableB b
On a.id = b.id
If not:
You have to use UNION and after using DISTINCT.
DISTINCT will not permit repeat rows.

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