the below script gives me an error. Basically I am trying to delete the records that I got from the first query. I have put them in a text file, formatted them and used them in the delete operation.
After executing the script I am getting the below error:-
: line 5: syntax error at line 27: `<<' unmatched
Can't tell because the code you dumped is unformatted, but my first guess would be you have leading spaces in front of the EOF in your here document.
This should work (note that there are no leading spaces in front of the EOF.:
sqlplus -s $dbcreds << EOF > output.txt
SET SERVEROUTPUT OFF
select empname from emp where dept_no=123;
EOF
if [ -s "output.txt" ]
then
echo " Found the below employees....Deleting them from Database ..............!!!! \n"
cat output.txt
sed "s/(.*)/'\1'/" output.txt| tr '\n' ','|sed 's/.$//' >final_employees.txt
while read line
do
sqlplus -s $dbcreds <<EOF
SET SERVEROUTPUT OFF
Delete from emp where empname in ($line);
EOF
done < final_employees.txt
else
echo " No employees found....!!!"
fi
Related
#cat file.txt
12354
13456
13498
#!/bin/bash
for i in `cat file.txt`
do
sqlplus XXXXX/XXXXX#DB_NAME << EOF
select *from TABLE_NAME where id="$i"
EOF
done
This is not working for me. Help me how I can solve this.
The solution given by #codeforester works. However I was unable to use it because it created as many DB connections as the number of lines in your file which is a potential impact.
To overcome this, I chose the below solution which may not be ideal but does the job with just one DB connection.
Considering the same data in file.txt
12354
13456
13498
I used the below sed command to populate the above to a single variable "12354,13456,13498"
myvariable=$(echo "`cat file.txt | sed '$!s/$/,/g' | tr -d '\n' | tr -d ' '`")
Now below script will pass this variable to the SQL query and spool the data into a text file:
#!/bin/bash
myvariable=$(echo "`cat file.txt | sed '$!s/$/,/g' | tr -d '\n' | tr -d ' '`")
echo #myvariable
sqlplus /nolog << EOF
CONNECT user#dbname/dbpassword
SPOOL dboutput.txt
select column1 from table_name where id in ($myvariable);
SPOOL OFF
EOF
The output is stored in dboutput.txt (along with the SQL query)
cat dboutput.txt
SQL> select column1 from table_name where id in (12354,13456,13498);
NAME
---------------------------------------------------------------------------- ----
data1
data2
data3
SQL> spool off
Here is the right way to use the heredoc <<, along with the choice of while read instead of for to read the file:
#!/bin/bash
while read -r value; do
sqlplus xxxxx/xxxxx#db_name << EOF
select * from table_name where id='$value';
# make sure heredoc marker "EOF" is not indented
EOF
done < file.txt
See also:
How can I write a here doc to a file in Bash script?
BashFAQ001 to understand why for loop is not the best way to read text lines from a file.
This question already has answers here:
here-document gives 'unexpected end of file' error
(10 answers)
Closed 6 years ago.
I have the following function;
function getdetails {
if ! "${PSQL_PATH}" -d "$DB" -U "$DB_USER" -h localhost -p "$DB_PORT" -t -c | while read -a Record ; do
taskid="${Record[0]}"
clientname="${Record[1]}"
backup_pass="${Record[2]}"
backup_dir="${Record[3]}"
done; then
echo "Could not fech next task metadata from database"
exit 1
fi <<EOF
WITH firsttask AS (SELECT taskid from tasks
WHERE status = 'PENDING'
ORDER BY date_started ASC
LIMIT 1)
SELECT taskid, username, storage_password AS backup_password, location AS backup_dir
FROM firsttask
INNER JOIN users USING (userid)
INNER JOIN storage USING (userid)
WHERE (username = '$1');
EOF
}
For some reason, bash does not detect the last EOF and reports:
./processor.sh: line 138: warning: here-document at line 41 delimited by end-of-file (wanted `EOF')
./processor.sh: line 139: syntax error: unexpected end of file
Any ideas why the EOF is not picked up? Thank you!
It fails because the closing EOF word has trailing whitespace. It must be on a line by itself, with no leading or trailing whitespace.
An exception is when using the <<- syntax, in which case the closing word may be preceded by one or more TABs (but never spaces).
I have a CSV files like this:
2015-12-10,22:45:00,205,5626,85
2015-12-10,23:00:01,79,5625,85
2015-12-13,13:00:01,4410,5629,85
2015-12-13,13:15:00,4244,5627,85
2015-12-13,13:30:00,4082,5627,85
I tried this script to generate an SQL statement:
#!/bin/bash
inputfile=${1}
echo $inputfile
OLDIFS=$IFS
IFS=,
while read date time current full cycle
do
echo -—$date --$time --$current --$full --$cycle
echo insert into table values($date,$time,$current,$full,$cycle)
sleep 1
done < $inputfile
IFS=$OLDIFS
But on execution I get this error and it doesn't run as expected:
/Scripts/CreateSql.sh: line 10: syntax error near unexpected token `('
/Scripts/CreateSql.sh: line 10: `echo insert into table values(\$date,$time,$current,$full,$cycle)'
I need the statement generated like this:
insert into table values($date,$time,$current,$full,$cycle)
Please kindly suggest a fix for this.
Use double quotes as anything under () to shell means spawn a new process.
echo "insert into table values($date,$time,$current,$full,$cycle)"
All,
i fixed this-
echo 'insert into table values ('$date','$time','$current','$full','$cycle')'
I'm building a string in Bash in a loop. The data processed by the loop from the lines in two files which are looking like this:
FIRST part of the string is a line in file 1 looking like:
SOME_PACKAGE
SECOND PART is a line of a file 2 looking like:
someFunction('some',parameters,here)
The final output has a dot between the two strings:
1 SOME_PACKAGE.someFunction('some',parameters,here)
The 1 is important here. Explaination in a second.
The string is formed in a double while loop
while read line1 ; do
while read line2 ; do
stringArray=($line2)
string=$line1.${stringArray[1]}
sqlplus -s /nolog > /dev/null 2>&1 <<EOF
connect user/password#db_instance
variable rc refcursor;
SPOOL ${line1}_${stringArray[0]}.DATA
exec :rc := $string;
print rc;
spool off
exit
EOF
done < file2.txt
done < file1.txt
This string is then passed to SQLPlus, and SQLPlus should exit a command like this:
SQL> variable rc refcursor;
SQL> exec :rc := SOME_PACKAGE.someFunction('some',parameters,here);
SQL> print rc;
Until now, everything was working fine. But I got a more complicated parameters next to the someFunction. Now it looks like this:
SOME_PACKAGE.someFunction('some',parameters,here,'and 2 more',NULL)
It seems that the variable passed to SQL*Plus ends on the first space... So it looks like:
SOME_PACKAGE.someFunction('some',parameters,here,'and
From what I know I shouldnt pass spaces in variables, or if I want to do this, I should wrap them in quote signs: "" but where should I put those quote signs to pass the final vatiable to SQL*Plus WITHOUT those quote signs? Or what other solution do You guys propose?
The answer was simple thanks to #arco444.
The reason all this happened was the Internal field separator, which was set to default.
What I did was the following:
I've changed the look of file2 from
1 SOME_PACKAGE.someFunction('some',parameters,here,'and 2 more',NULL)
to
1§SOME_PACKAGE.someFunction('some',parameters,here,'and 2 more',NULL)
And I added some ILS changes before and after the loop, so the final code looks like this:
oldifs=$IFS
IFS="§"
while read line1 ; do
while read line2 ; do
stringArray=($line2)
string=$line1.${stringArray[1]}
sqlplus -s /nolog > /dev/null 2>&1 <<EOF
connect user/password#db_instance
variable rc refcursor;
SPOOL ${line1}_${stringArray[0]}.DATA
exec :rc := $string;
print rc;
spool off
exit
EOF
done < file2.txt
done < file1.txt
IFS=$oldifs
Everything is working like a charm now.
When I try running the script, I am gettin the error line 45: syntax error: unexpected end of file. I am relatively new to scripting. Please help me resolve it.
#!/bin/ksh
set -xv
export HOME=/home/mine
. $HOME/.env.ksh
BIS_SPOOL=/tmp/bis_table_mine.spl
BIS_REPORT_MINE=/tmp/bis_table_report_mine.txt
touch $BIS_SPOOL
rm $BIS_SPOOL
touch $BIS_SPOOL
exec 5< $BIS_REPORT_MINE
while read -u5 REC_MINE
do
TBLENAME=`echo "$REC_MINE" | awk '{print $3}' | tr '[:upper:]' '[:lower:]'`
sqlplus -s ${USER_ID}/${USER_PASS}#${ORACLE_SID} <<- EOF
set feedback off
set hea ON
set pagesize 9999
set linesize 9999
set trimspool ON
set termout off
spool $BIS_SPOOL append
Column C1 Heading 'Job Name' Format a30
Column C2 Heading 'Table Name' Format a30
SELECT job_name C1,
table_name C2,
FROM table_usage
WHERE table_name like 'TBLENAME%'
/
exit;
EOF
done
exec 5<& -
The <<- EOS is interpreted literally. Make it
sqlplus -s ${USER_ID}/${USER_PASS}#${ORACLE_SID} <<-EOF
without the space char.
Also make sure there is no space char before or after your closing EOS , but leading tab chars are allowed.
IHTH