I would like to write the equivalent of
convert left.jpg right.jpg +append ouput.jpg
I found something like it in another post:
files = glob('*.jpg')
with Image() as orig: # create empty Image object
for f in files:
page = Image(filename=f)
orig.sequence.append(page)
orig.save(filename='result.pdf')
and changed it to
with Image() as orig: # create empty Image object
page = Image(filename='left.jpg'); orig.sequence.append(page)
page = Image(filename='right.jpg'); orig.sequence.append(page)
orig.save(filename='output.jpg')
but the output file just shows the first file, rather than a file with the images side-by-side.
My first attempt was completely wrong, it probably makes an animated image. Provided the two images are the same size, this will do it:
with Image() as blankimage:
with Image(filename = 'imageA.tif') as imageA:
w = imageA.width; h = imageA.height
with Image(filename = 'imageB.tif') as imageB:
blankimage.blank(w*2, h)
blankimage.composite(imageA, 0, 0)
blankimage.composite(imageB, w, 0)
blankimage.save(filename = 'output.tif')
Related
I'm trying to write a code in Image J that will:
Open all images in separate windows that contains "488" within a folder
Use look up tables to convert images to green and RGB color From ImageJ, the commands are: run("Green"); and run("RGB Color");
Adjust the brightness and contrast with defined values for Min and Max (same values for each image).
I know that the code for that is:
//run("Brightness/Contrast..."); setMinAndMax(value min, value max); run("Apply LUT");
Save each image in the same, original folder , in Tiff and with the same name but finishing with "processed".
I have no experience with Java and am very bad with coding. I tried to piece something together using code I found on stackoverflow and on the ImageJ website, but kept getting error codes. Any help is much appreciated!
I don't know if you still need it, but here is an example.
output_dir = "C:/Users/test/"
input_dir = "C:/Users/test/"
list = getFileList(input_dir);
listlength = list.length;
setBatchMode(true);
for (z = 0; z < listlength; z++){
if(endsWith(list[z], 'tif')==true ){
if(list[z].contains("488")){
title = list[z];
end = lengthOf(title)-4;
out_path = output_dir + substring(title,0,end) + "_processed.tif";
open(input_dir + title);
//add all the functions you want
run("Brightness/Contrast...");
setMinAndMax(1, 15);
run("Apply LUT");
saveAs("tif", "" + out_path + "");
close();
};
run("Close All");
}
}
setBatchMode(false);
I think it contains all the things you need. It opens all the images (in specific folder) that ends with tif and contains 488. I didn't completely understand what you want to do with each photo, so I just added your functions. But you probably won't have problems with adding more/different since you can get them with macro recorder.
And the code is written to open tif files. If you have tiff just be cerful that you change that and also change -4 to -5.
I started to learn Matlab newly. I am trying to learn about classification. I will make classification for my 23 images. In my function file I am using
I = imread('img.jpg');
a = rgb2gray(I);
bw = double(imread('mask_img.jpg'))/255;
b = rgb2gray(bw);
bwi = 1-b;
And working on the original image and ground truth of the image. I can handle one image and I have loop in the my main file.
for i=1:original_images_db.Count
original = original_images_db.ImageLocation(i);
groundtruth = original_file;
[x,y] = calculateFeatures(original, groundtruth, parameters);
dataset.HorizonFeats{i} = features;
end
And i related original_images_db with imageset to files. When i run my main file, naturally everytime it reads img from function file but actually in command file main can detect other images. My question is how can i make a loop in my function file so my data can be in all other images?
Thank you
fname={'1.jpg','2.jpg','3.jpg'};
create cell like that, it contains all file-path of images
for i=1: length(fname)
im= imread(fname{i});
end
and now you can iterate the all images
or
use dir(image_path) function
fnames = dir('image_directory_path');
Hello!
i'm trying to have my images appearing on a label by using this code
this is to save a random image from a particular URL
def photo_1():
urls = "https://www.flickr.com/photos/flickr/galleries/72157644537473411/" # You may change this into other websites!
regex = '<img src="([^"]+)".*>'
pattern = re.compile(regex)
photofile=urllib.urlopen(urls)
raw_data=photofile.read()
download=re.findall(pattern,raw_data)
randomdownload=random.choice(download)
urllib.urlretrieve(randomdownload, "1.gif")
global done_button2
done_button2 = Button(photo_window, text = 'Click here to display your chosen image on the black screen!', width = 53, command = generate_1)
done_button2.grid(row = 5, sticky = N)
done_button.config(state='disabled')
and this is to have the saved image appearing on a label but apparently not working so well ..
def generate_1():
img = ImageTk.PhotoImage(Image.open("1.gif"))
image_area = Label(photo_window, image = img, width = 55, height = 5).grid(row=2)
global done_button3
done_button3 = Button(photo_window, text = 'Click here to save the second random image locally! ', width = 53, command = photo_2)
done_button3.grid(row = 6, sticky = N)
done_button2.config(state='disabled')
this was a part of my code and when i run this application i made,
the only thing i can see is a white rectangular shape and i would like it to be as big as a black label underneath (size of (55,5) )with the actual image appearing...
can anyone help me with this problem?
You might have thought that my English is not that great haha
but please have mercy!
I have written this code to help me compare different image histograms however when i run it i get a figure window popping up. I can't see anywhere in the code where i have written imshow and am really confused. Can anyone see why? thanks
%ensure we start with an empty workspace
clear
myPath= 'C:\coursework\'; %#'
number_of_desired_results = 5; %top n results to return
images_path = strcat(myPath, 'fruitnveg');
images_file_names = dir(fullfile(images_path, '*.png'));
images = cell(length(images_file_names), 3);
number_of_images = length(images);
%textures contruction
%loop through all textures and store them
disp('Starting construction of search domain...');
for i = 1:length(images)
image = strcat(images_path, '\', images_file_names(i).name); %#'
%store image object of image
images{i, 1} = imread(image);
%store histogram of image
images{i, 2} = imhist(rgb2ind(images{i, 1}, colormap(colorcube(256))));
%store name of image
images{i, 3} = images_file_names(i).name;
disp(strcat({'Loaded image '}, num2str(i)));
end
disp('Construction of search domain done');
%load the three example images
RGB1 = imread('C:\coursework\examples\salmon.jpg');
X1 = rgb2ind(RGB1,colormap(colorcube(256)));
example1 = imhist(X1);
RGB2 = imread('C:\coursework\examples\eggs.jpg');
X2 = rgb2ind(RGB2,colormap(colorcube(256)));
example2 = imhist(X2);
RGB3 = imread('C:\coursework\examples\steak.jpg');
X3 = rgb2ind(RGB3,colormap(colorcube(256)));
example3 = imhist(X3);
disp('three examples loaded');
disp('compare examples to loaded fruit images');
results = cell(length(images), 2);
results2 = cell(length(images), 2);
results3 = cell(length(images), 2);
for i = 1:length(images)
results{i,1} = images{i,3};
results{i,2} = hi(example1,images{i, 2});
end
results = flipdim(sortrows(results,2),1);
for i = 1:length(images)
results2{i,1} = images{i,3};
results2{i,2} = hi(example2,images{i, 2});
end
results2 = flipdim(sortrows(results2,2),1);
for i = 1:length(images)
results3{i,1} = images{i,3};
results3{i,2} = hi(example3,images{i, 2});
end
results3 = flipdim(sortrows(results3,2),1);
The colormap function sets the current figure's colormap, if there is no figure one is created.
The second parameter of imhist should be the number of bins used in the histogram, not the colormap.
Run your code in the Matlab debugger, step through it line by line, and see when the figure window pops up. That'll tell you what's creating it.
Etienne's answer is right for why you're getting a figure, but I'd just like to add that colormap is unnecessary in this code:
images{i, 2} = imhist(rgb2ind(images{i, 1}, colormap(colorcube(256))));
All you need is:
images{i, 2} = imhist(rgb2ind(images{i, 1}, colorcube(256)));
The second input of rgb2ind should be a colormap, yes. But the output of colorcube is a colormap already. Unless you've got an existing figure and you either want to set the colormap of it or retrieve the colormap it is currently using, the actual function colormap is not necessary.
Other than opening an unnecessary figure, the output of your existing code won't be wrong, as I think in this situation colormap will just pass as an output argument the colormap it was given as an input argument. For example, if you want to set the current figure colormap to one of the inbuilts and return the actual colormap:
cmap = colormap('bone');
I've got code along the lines of the following which generates a new image out of some existing images.
from PIL import Image as pyImage
def create_compound_image(back_image_path, fore_image_path, fore_x_position):
back_image_size = get_image_size(back_image_path)
fore_image_size = get_image_size(fore_image_path)
new_image_width = (fore_image_size[0] / 2) + back_image_size[0]
new_image_height = fore_image_size[1] + back_image_size[1]
new_image = create_new_image_canvas(new_image_width, new_image_height)
back_image = pyImage.open(back_image_path)
fore_image = pyImage.open(fore_image_path)
new_image.paste(back_image, (0, 0), mask = None)
new_image.paste(fore_image, (fore_x_position, back_image_size[1]), mask = None)
return new_image
Later in the code, I've got something like this:
from kivy.uix.image import Image
img = Image(source = create_compound_image(...))
If I do the above, I get the message that Image.source only accepts string/unicode.
If I create a StringIO.StringIO() object from the new image, and try to use that as the source, the error message is the same as above. If I use the output of the StringIO object's getvalue() method as the source, the message is that the source must be encoded string without NULL bytes, not str.
What is the proper way to use the output of the create_compound_image() function as the source when creating a kivy Image object?
It seems you want to just combine two images into one, you can actually just create a texture using Texture.create and blit the data to a particular pos using Texture.blit_buffer .
from kivy.core.image import Image
from kivy.graphics import Texture
bkimg = Image(bk_img_path)
frimg = Image(fr_img_path)
new_size = ((frimg.texture.size[0]/2) + bkimg.texture.size[0],
frimg.texture.size[1] + bkimg.texture.size[1])
tex = Texture.create(size=new_size)
tex.blit_buffer(pbuffer=bkimg.texture.pixels, pos=(0, 0), size=bkimg.texture.size)
tex.blit_buffer(pbuffer=frimg.texture.pixels, pos=(fore_x_position, bkimg.texture.size[1]), size=frimg.texture.size)
Now you can use this texture anywhere directly like::
from kivy.uix.image import Image
image = Image()
image.texture = tex
source is a StringProperty and is expecting a path to file. That's why you got errors when you tried to pass PIL.Image object, StringIO object or string representation of image. It's not what framework wants. As for getting image from StringIO, it was discussed before here:
https://groups.google.com/forum/#!topic/kivy-users/l-3FJ2mA3qI
https://github.com/kivy/kivy/issues/684
You can also try much simpler, quick and dirty method - just save your image as a tmp file and read it normal way.