Split function in oracle to comma separated values with automatic sequence - oracle

Question

Need Split function which will take two parameters, string to split and delimiter to split the string and return a table with columns Id and Data.And how to call Split function which will return a table with columns Id and Data. Id column will contain sequence and data column will contain data of the string.
Eg.
SELECT*FROM Split('A,B,C,D',',')
Result Should be in below format:
|Id | Data
-- ----
|1 | A |
|2 | B |
|3 | C |
|4 | D |

Answer 1

Here is how you could create such a table:
SELECT LEVEL AS id, REGEXP_SUBSTR('A,B,C,D', '[^,]+', 1, LEVEL) AS data
FROM dual
CONNECT BY REGEXP_SUBSTR('A,B,C,D', '[^,]+', 1, LEVEL) IS NOT NULL;
With a little bit of tweaking (i.e., replacing the , in [^,] with a variable) you could write such a function to return a table.

Answer 2

There are multiple options. See Split single comma delimited string into rows in Oracle
You just need to add LEVEL in the select list as a column, to get the sequence number to each row returned. Or, ROWNUM would also suffice.
Using any of the below SQLs, you could include them into a FUNCTION.
INSTR in CONNECT BY clause:
SQL> WITH DATA AS
2 ( SELECT 'word1, word2, word3, word4, word5, word6' str FROM dual
3 )
4 SELECT trim(regexp_substr(str, '[^,]+', 1, LEVEL)) str
5 FROM DATA
6 CONNECT BY instr(str, ',', 1, LEVEL - 1) > 0
7 /
STR
----------------------------------------
word1
word2
word3
word4
word5
word6
6 rows selected.
SQL>
REGEXP_SUBSTR in CONNECT BY clause:
SQL> WITH DATA AS
2 ( SELECT 'word1, word2, word3, word4, word5, word6' str FROM dual
3 )
4 SELECT trim(regexp_substr(str, '[^,]+', 1, LEVEL)) str
5 FROM DATA
6 CONNECT BY regexp_substr(str , '[^,]+', 1, LEVEL) IS NOT NULL
7 /
STR
----------------------------------------
word1
word2
word3
word4
word5
word6
6 rows selected.
SQL>
REGEXP_COUNT in CONNECT BY clause:
SQL> WITH DATA AS
2 ( SELECT 'word1, word2, word3, word4, word5, word6' str FROM dual
3 )
4 SELECT trim(regexp_substr(str, '[^,]+', 1, LEVEL)) str
5 FROM DATA
6 CONNECT BY LEVEL
Using XMLTABLE
SQL> WITH DATA AS
2 ( SELECT 'word1, word2, word3, word4, word5, word6' str FROM dual
3 )
4 SELECT trim(COLUMN_VALUE) str
5 FROM DATA, xmltable(('"' || REPLACE(str, ',', '","') || '"'))
6 /
STR
------------------------------------------------------------------------
word1
word2
word3
word4
word5
word6
6 rows selected.
SQL>
Using MODEL clause:
SQL> WITH t AS
2 (
3 SELECT 'word1, word2, word3, word4, word5, word6' str
4 FROM dual ) ,
5 model_param AS
6 (
7 SELECT str AS orig_str ,
8 ','
9 || str
10 || ',' AS mod_str ,
11 1 AS start_pos ,
12 Length(str) AS end_pos ,
13 (Length(str) - Length(Replace(str, ','))) + 1 AS element_count ,
14 0 AS element_no ,
15 ROWNUM AS rn
16 FROM t )
17 SELECT trim(Substr(mod_str, start_pos, end_pos-start_pos)) str
18 FROM (
19 SELECT *
20 FROM model_param MODEL PARTITION BY (rn, orig_str, mod_str)
21 DIMENSION BY (element_no)
22 MEASURES (start_pos, end_pos, element_count)
23 RULES ITERATE (2000)
24 UNTIL (ITERATION_NUMBER+1 = element_count[0])
25 ( start_pos[ITERATION_NUMBER+1] = instr(cv(mod_str), ',', 1, cv(element_no)) + 1,
26 end_pos[iteration_number+1] = instr(cv(mod_str), ',', 1, cv(element_no) + 1) ) )
27 WHERE element_no != 0
28 ORDER BY mod_str ,
29 element_no
30 /
STR
------------------------------------------
word1
word2
word3
word4
word5
word6
6 rows selected.
SQL>
You could also use DBMS_UTILITY package provided by Oracle. It provides various utility subprograms. One such useful utility is COMMA_TO_TABLE procedure, which converts a comma-delimited list of names into a PL/SQL table of names.
Read DBMS_UTILITY.COMMA_TO_TABLE

Answer 3

Oracle Setup:
CREATE OR REPLACE FUNCTION split_String(
i_str IN VARCHAR2,
i_delim IN VARCHAR2 DEFAULT ','
) RETURN SYS.ODCIVARCHAR2LIST DETERMINISTIC
AS
p_result SYS.ODCIVARCHAR2LIST := SYS.ODCIVARCHAR2LIST();
p_start NUMBER(5) := 1;
p_end NUMBER(5);
c_len CONSTANT NUMBER(5) := LENGTH( i_str );
c_ld CONSTANT NUMBER(5) := LENGTH( i_delim );
BEGIN
IF c_len > 0 THEN
p_end := INSTR( i_str, i_delim, p_start );
WHILE p_end > 0 LOOP
p_result.EXTEND;
p_result( p_result.COUNT ) := SUBSTR( i_str, p_start, p_end - p_start );
p_start := p_end + c_ld;
p_end := INSTR( i_str, i_delim, p_start );
END LOOP;
IF p_start <= c_len + 1 THEN
p_result.EXTEND;
p_result( p_result.COUNT ) := SUBSTR( i_str, p_start, c_len - p_start + 1 );
END IF;
END IF;
RETURN p_result;
END;
/
Query
SELECT ROWNUM AS ID,
COLUMN_VALUE AS Data
FROM TABLE( split_String( 'A,B,C,D' ) );
Output:
ID DATA
-- ----
1 A
2 B
3 C
4 D

Answer 4

If you need a function try this.
First we'll create a type:
CREATE OR REPLACE TYPE T_TABLE IS OBJECT
(
Field1 int
, Field2 VARCHAR(25)
);
CREATE TYPE T_TABLE_COLL IS TABLE OF T_TABLE;
/
Then we'll create the function:
CREATE OR REPLACE FUNCTION TEST_RETURN_TABLE
RETURN T_TABLE_COLL
IS
l_res_coll T_TABLE_COLL;
l_index number;
BEGIN
l_res_coll := T_TABLE_COLL();
FOR i IN (
WITH TAB AS
(SELECT '1001' ID, 'A,B,C,D,E,F' STR FROM DUAL
UNION
SELECT '1002' ID, 'D,E,F' STR FROM DUAL
UNION
SELECT '1003' ID, 'C,E,G' STR FROM DUAL
)
SELECT id,
SUBSTR(STR, instr(STR, ',', 1, lvl) + 1, instr(STR, ',', 1, lvl + 1) - instr(STR, ',', 1, lvl) - 1) name
FROM
( SELECT ',' || STR || ',' AS STR, id FROM TAB
),
( SELECT level AS lvl FROM dual CONNECT BY level <= 100
)
WHERE lvl <= LENGTH(STR) - LENGTH(REPLACE(STR, ',')) - 1
ORDER BY ID, NAME)
LOOP
IF i.ID = 1001 THEN
l_res_coll.extend;
l_index := l_res_coll.count;
l_res_coll(l_index):= T_TABLE(i.ID, i.name);
END IF;
END LOOP;
RETURN l_res_coll;
END;
/
Now we can select from it:
select * from table(TEST_RETURN_TABLE());
Output:
SQL> select * from table(TEST_RETURN_TABLE());
FIELD1 FIELD2
---------- -------------------------
1001 A
1001 B
1001 C
1001 D
1001 E
1001 F
6 rows selected.
Obviously you'd need to replace the WITH TAB AS... bit with where you would be getting your actual data from.
Credit Credit

Answer 5

Use this 'Split' function:
CREATE OR REPLACE FUNCTION Split (p_str varchar2) return sys_refcursor is
v_res sys_refcursor;
begin
open v_res for
WITH TAB AS
(SELECT p_str STR FROM DUAL)
select substr(STR, instr(STR, ',', 1, lvl) + 1, instr(STR, ',', 1, lvl + 1) - instr(STR, ',', 1, lvl) - 1) name
from
( select ',' || STR || ',' as STR from TAB ),
( select level as lvl from dual connect by level <= 100 )
where lvl <= length(STR) - length(replace(STR, ',')) - 1;
return v_res;
end;
You can't use this function in select statement like you described in question, but I hope you will find it still useful.
EDIT: Here are steps you need to do.
1. Create Object: create or replace type empy_type as object(value varchar2(512))
2. Create Type: create or replace type t_empty_type as table of empy_type
3. Create Function:
CREATE OR REPLACE FUNCTION Split (p_str varchar2) return sms.t_empty_type is
v_emptype t_empty_type := t_empty_type();
v_cnt number := 0;
v_res sys_refcursor;
v_value nvarchar2(128);
begin
open v_res for
WITH TAB AS
(SELECT p_str STR FROM DUAL)
select substr(STR, instr(STR, ',', 1, lvl) + 1, instr(STR, ',', 1, lvl + 1) - instr(STR, ',', 1, lvl) - 1) name
from
( select ',' || STR || ',' as STR from TAB ),
( select level as lvl from dual connect by level <= 100 )
where lvl <= length(STR) - length(replace(STR, ',')) - 1;
loop
fetch v_res into v_value;
exit when v_res%NOTFOUND;
v_emptype.extend;
v_cnt := v_cnt + 1;
v_emptype(v_cnt) := empty_type(v_value);
end loop;
close v_res;
return v_emptype;
end;
Then just call like this:
SELECT * FROM (TABLE(split('a,b,c,d,g')))

Answer 6

This function returns the nth part of input string MYSTRING.
Second input parameter is separator ie., SEPARATOR_OF_SUBSTR
and the third parameter is Nth Part which is required.
Note: MYSTRING should end with the separator.
create or replace FUNCTION PK_GET_NTH_PART(MYSTRING VARCHAR2,SEPARATOR_OF_SUBSTR VARCHAR2,NTH_PART NUMBER)
RETURN VARCHAR2
IS
NTH_SUBSTR VARCHAR2(500);
POS1 NUMBER(4);
POS2 NUMBER(4);
BEGIN
IF NTH_PART=1 THEN
SELECT REGEXP_INSTR(MYSTRING,SEPARATOR_OF_SUBSTR, 1, 1) INTO POS1 FROM DUAL;
SELECT SUBSTR(MYSTRING,0,POS1-1) INTO NTH_SUBSTR FROM DUAL;
ELSE
SELECT REGEXP_INSTR(MYSTRING,SEPARATOR_OF_SUBSTR, 1, NTH_PART-1) INTO POS1 FROM DUAL;
SELECT REGEXP_INSTR(MYSTRING,SEPARATOR_OF_SUBSTR, 1, NTH_PART) INTO POS2 FROM DUAL;
SELECT SUBSTR(MYSTRING,POS1+1,(POS2-POS1-1)) INTO NTH_SUBSTR FROM DUAL;
END IF;
RETURN NTH_SUBSTR;
END;
Hope this helps some body, you can use this function like this in a loop to get all the values separated:
SELECT REGEXP_COUNT(MYSTRING, '~', 1, 'i') INTO NO_OF_RECORDS FROM DUAL;
WHILE NO_OF_RECORDS>0
LOOP
PK_RECORD :=PK_GET_NTH_PART(MYSTRING,'~',NO_OF_RECORDS);
-- do some thing
NO_OF_RECORDS :=NO_OF_RECORDS-1;
END LOOP;
Here NO_OF_RECORDS,PK_RECORD are temp variables.
Hope this helps.

Answer 7

Best Query For comma separated
in This Query we Convert Rows To Column ...
SELECT listagg(BL_PRODUCT_DESC, ', ') within
group( order by BL_PRODUCT_DESC) PROD
FROM GET_PRODUCT
-- WHERE BL_PRODUCT_DESC LIKE ('%WASH%')
WHERE Get_Product_Type_Id = 6000000000007

Answer 8

Created PL/SQL function that can split string by specified delimiter and return result as VARRAY.
CREATE OR REPLACE FUNCTION split(p_parameters VARCHAR2, p_delimiter VARCHAR2) RETURN string_varray AS
v_delimiter_position NUMBER := 0;
v_read_position NUMBER :=1;
v_list string_varray := string_varray();
v_substring VARCHAR2(4000);
FUNCTION normalize(v_substring VARCHAR2, p_delimiter VARCHAR2) RETURN VARCHAR2 AS
BEGIN
RETURN trim(TRAILING p_delimiter FROM trim(BOTH ' ' FROM v_substring));
END normalize;
BEGIN
LOOP
v_delimiter_position := instr(p_parameters, p_delimiter, v_read_position);
IF v_delimiter_position = 0 THEN
v_delimiter_position := LENGTH(p_parameters);
END IF;
v_substring := substr(p_parameters, v_read_position, v_delimiter_position-v_read_position+1);
v_list.EXTEND;
v_list(v_list.LAST) := normalize(v_substring, p_delimiter);
v_read_position := v_delimiter_position+1;
IF v_delimiter_position = LENGTH(p_parameters) THEN
EXIT;
END IF;
END LOOP;
RETURN v_list;
END split;
string_varray is VARRAY of VARCHAR2(4000) type. Function also removes whitespaces and the start and end of each value. Invocation example:
select * from table(split('zaa, dddd,ccc', ','));
Will produce three rows in output: zaa dddd ccc

Answer 9

begin
for rec in (select * from table(split('shfgjsdfg,242535', ',')))
loop
dbms_output.put_line(rec.COLUMN_VALUE);
end loop;
end;
-- Output
shfgjsdfg
242535

Answer 10

Try like below
select
split.field(column_name,1,',','"') name1,
split.field(column_name,2,',','"') name2
from table_name