Visual Studio 2010 assembler listing - visual-studio-2010

Question

I use VS2010 to generate an assembler listing. Than I create a new project, add generated *.asm file and try to compile it. During the compillation I receive some erros like:
main.asm(54): error A2008: syntax error : lambda0
at this line of generated asm:
PUBLIC ??R<lambda0>#?A0x1262112e##QBE_NH#Z ; `anonymous namespace'::<lambda0>::operator()
Another one is:
main.asm(72): error A2039: line too long
The length of 72th line is 538 symbols.
Looks like Visual Studio generates an incompatible asm code for examle for lambda expressions.
The next C++ code I used for test:
#include <iostream>
#include <fstream>
#include <string>
#include <algorithm>
#include <cctype>
std::string LTrimString(std::string s)
{
s.erase(s.begin(), std::find_if(s.begin(), s.end(), [](int ch) { return !std::isspace((unsigned char)ch); }));
return s;
}
std::string RTrimString(std::string s)
{
s.erase(std::find_if(s.rbegin(), s.rend(), [](int ch) { return !std::isspace((unsigned char)ch); }).base(), s.end());
return s;
}
std::string TrimString(std::string s)
{
return LTrimString(RTrimString(s));
}
bool StartsWith(std::string full_str, std::string start_str)
{
return full_str.substr(0, start_str.length()) == start_str;
}
int main()
{
std::ifstream ifs("test.txt");
while(ifs)
{
std::string line;
std::getline(ifs, line);
if(StartsWith(TrimString(line), ">>>"))
std::cout << "###";
std::cout << line << '\n';
}
}
The question is: does it possible to generate correct asm file for compilation in visual studio or it can not be used for compilation?