Say I have a string representing a URL:
http://www.mysite.com/somepage.aspx?id=33
..I'd like to escape the forward slashes and the question mark:
http:\/\/www.mysite.com\/somepage.aspx\?id=33
How can I do this via gsub? I've been playing with some regular expressions in there but haven't hit on the winning formula yet.
I suggest you use
url = url.gsub(/(?=[\/?])/, '\\')
As shown here
url = 'http://www.mysite.com/somepage.aspx?id=33'
url = url.gsub(/(?=[\/?])/, '\\')
puts url
output
http:\/\/www.mysite.com\/somepage.aspx\?id=33
How about this one result = searchText.gsub(/(\/|\?)/, "\\\\$1")
I will suggest using a block to make it more readable:
url.gsub(/[\/?]/) { |c| "\\#{c}" }
I can't figure out how to search for text containing single quotes using XPATHs.
For example, I've added a quote to the title of this question. The following line
$x("//*[text()='XQuery looking for text with 'single' quote']")
Returns an empty array.
However, if I try the following
$x("//*[text()=\"XQuery looking for text with 'single' quote\"]")
It does return the link for the title of the page, but I would like to be able to accept both single and double quotes in there, so I can't just tailor it for the single/double quote.
You can try it in chrome's or firebug's console on this page.
Here's a hackaround (Thanks Dimitre Novatchev) that will allow me to search for any text in xpaths, whether it contains single or double quotes. Implemented in JS, but could be easily translated to other languages
function cleanStringForXpath(str) {
var parts = str.match(/[^'"]+|['"]/g);
parts = parts.map(function(part){
if (part === "'") {
return '"\'"'; // output "'"
}
if (part === '"') {
return "'\"'"; // output '"'
}
return "'" + part + "'";
});
return "concat(" + parts.join(",") + ")";
}
If I'm looking for I'm reading "Harry Potter" I could do the following
var xpathString = cleanStringForXpath( "I'm reading \"Harry Potter\"" );
$x("//*[text()="+ xpathString +"]");
// The xpath created becomes
// //*[text()=concat('I',"'",'m reading ','"','Harry Potter','"')]
Here's a (much shorter) Java version. It's exactly the same as JavaScript, if you remove type information. Thanks to https://stackoverflow.com/users/1850609/acdcjunior
String escapedText = "concat('"+originalText.replace("'", "', \"'\", '") + "', '')";!
In XPath 2.0 and XQuery 1.0, the delimiter of a string literal can be included in the string literal by doubling it:
let $a := "He said ""I won't"""
or
let $a := 'He said "I can''t"'
The convention is borrowed from SQL.
This is an example:
/*/*[contains(., "'") and contains(., '"') ]/text()
When this XPath expression is applied on the following XML document:
<text>
<t>I'm reading "Harry Potter"</t>
<t>I am reading "Harry Potter"</t>
<t>I am reading 'Harry Potter'</t>
</text>
the wanted, correct result (a single text node) is selected:
I'm reading "Harry Potter"
Here is verification using the XPath Visualizer (A free and open source tool I created 12 years ago, that has taught XPath the fun way to thousands of people):
Your problem may be that you are not able to specify this XPath expression as string in the programming language that you are using -- this isn't an XPath problem but a problem in your knowledge of your programming language.
Additionally, if you were using XQuery, instead of XPath, as the title says, you could also use the xml entities:
"" for double and ' for single quotes"
they also work within single quotes
You can do this using a regular expression. For example (as ES6 code):
export function escapeXPathString(str: string): string {
str = str.replace(/'/g, `', "'", '`);
return `concat('${str}', '')`;
}
This replaces all ' in the input string by ', "'", '.
The final , '' is important because concat('string') is an error.
Well I was in the same quest, and after a moment I found that's there is no support in xpath for this, quiet disappointing! But well we can always work around it!
I wanted something simple and straight froward. What I come with is to set your own replacement for the apostrophe, kind of unique code (something you will not encounter in your xml text) , I chose //apos// for example. now you put that in both your xml text and your xpath query . (in case of xml you didn't write always we can replace with replace function of any editor). And now how we do? we search normally with this, retrieve the result, and replace back the //apos// to '.
Bellow some samples from what I was doing: (replace_special_char_xpath() is what you need to make)
function repalce_special_char_xpath($str){
$str = str_replace("//apos//","'",$str);
/*add all replacement here */
return $str;
}
function xml_lang($xml_file,$category,$word,$language){ //path can be relative or absolute
$language = str_replace("-","_",$language);// to replace - with _ to be able to use "en-us", .....
$xml = simplexml_load_file($xml_file);
$xpath_result = $xml->xpath("${category}/def[en_us = '${word}']/${language}");
$result = $xpath_result[0][0];
return repalce_special_char_xpath($result);
}
the text in xml file:
<def>
<en_us>If you don//apos//t know which server, Click here for automatic connection</en_us> <fr_fr>Si vous ne savez pas quelle serveur, Cliquez ici pour une connexion automatique</fr_fr> <ar_sa>إذا لا تعرفوا أي سرفير, إضغطوا هنا من أجل إتصال تلقائي</ar_sa>
</def>
and the call in the php file (generated html):
<span><?php echo xml_lang_body("If you don//apos//t know which server, Click here for automatic connection")?>
I have a string containing a path:
/var/www/project/data/path/to/file.mp3
I need to get the substring starting with '/data' and delete all before it. So, I need to get only /data/path/to/file.mp3.
What would be the fastest solution?
'/var/www/project/data/path/to/file.mp3'.match(/\/data.*/)[0]
=> "/data/path/to/file.mp3"
could be as easy as:
string = '/var/www/project/data/path/to/file.mp3'
path = string[/\/data.*/]
puts path
=> /data/path/to/file.mp3
Using regular expression is a good way. Though I am not familiar with ruby, I think ruby should have some function like "substring()"(maybe another name in ruby).
Here is a demo by using javascript:
var str = "/var/www/project/data/path/to/file.mp3";
var startIndex = str.indexOf("/data");
var result = str.substring(startIndex );
And the link on jsfiddle demo
I think the code in ruby is similar, you can check the documentation. Hope it's helpful.
Please try this:
"/var/www/project/data/path/to/file.mp3".scan(/\/var\/www(\/.+)*/)
It should return you all occurrences.
Let's say I've got some text with a couple tags like this:
[twitter:jpunt]
I want to replace those into something like this:
#Jpunt
How could I do this in Ruby? I've been researching regular expressions for a couple of hours, just with a lot of frustration as a result. Anyone?
This should do the job:
initial = "[twitter:jpunt]"
link = initial.gsub(/\[twitter:(\w+)\]/i, '#\1')
It is one line code (click here to test this code) >>
output = input.gsub(/\[([^:]+):([^\]]+)\]/) {
'#' + $2.capitalize + '' }
The above code works with any tag name. If you want just twitter to be allowed, then go with modification:
output = input.gsub(/\[twitter:([^\]]+)\]/) {
'#' + $1.capitalize + '' }
I have a QString that I need to parse. This QString is a QNetworkReply object obtained from an URL.
<label id='Today_LastSale1'>$ 21.2401</label>
I need the value 21.2401 from the QString.
I am tried this.
QRegExp rx("<label id='Today_LastSale1'>$ (\\d)</label>");
But it returns -1. Need help with this.
Thanks in Advance!
You can just try to remove the non-numeric and "." characters from your string. Try regex replace with this expression: "[^0-9\.]"
Code
QRegExp rx("[^0-9\\.]");
yourString.replace(rx, "");