I'm trying to get 2 files using curl based on some pattern but that doesn't seem to work:
Files:
SystemOut_15.04.01_21.12.36.log
SystemOut_15.04.01_15.54.05.log
curl -f -k -u "login:password" https://myserver/cgi-bin/logviewer/index.cgi?getlogfile=SystemOut_15.04.01_21.12.36.log'&'server=qwerty123.com'&'numlines=100000000'&'appenv=MBL%20-%20PROD'&'directory=/app/WAS/was85/profiles/node/logs/mbl-server1
I know there is -A key but it doesn't work since my file is inside the link.
How can I extract those 2 files using a pattern?
Did that myself. One curl gets the list of logs on the webpage. Another downloads those files.
The code looks like:
for file in $(curl -f -k -u "user:pwd" https://selfservice.pwj.com/cgi-bin/logviewer/index.cgi?listdirectory=/app/smx_client_mob/data/log'&'appenv=MBL%20-%20PROD'&'server=xshembl04pap.she.pwj.com | grep href | sed 's/.*href="//' | sed 's/".*//' | sed 's/javascript:getLog//g' | sed "s/['();]//g" | grep -i 'service' | grep '^[a-zA-Z].*'); do
curl -o $file -f -k -u "user:pwd" https://selfservice.pwj.com/cgi-bin/logviewer/index.cgi?getlogfile="$file"'&'server=xshembl04pap.she.pwj.com'&'numlines=100000000'&'appenv=MBL%20-%20PROD'&'directory=/app/smx_client_mob/data/log; done
Related
I want to check some file on the remote website.
Here is bash command to generate commands that calculate the file md5
[root]# head -n 3 zrcpathAll | awk '{print $3}' | xargs -I {} echo wget -q -O - -i {}e \| md5sum\;
wget -q -O - -i https://example.com/zrc/3d2f0e76e04444f4ec456ef9f11289ec.zrce | md5sum;
wget -q -O - -i https://example.com/zrc/e1bd7171263adb95fb6f732864ceb556.zrce | md5sum;
wget -q -O - -i https://example.com/zrc/5300b80d194f677226c4dc6e17ba3b85.zrce | md5sum;
Then I pipe the outputed commands to bash, but only the first command was executed.
[root]# head -n 3 zrcpathAll | awk '{print $3}' | xargs -I {} echo wget -q -O - -i {}e \| md5sum\; | bash -v
wget -q -O - -i https://example.com/zrc/3d2f0e76e04444f4ec456ef9f11289ec.zrce | md5sum;
3d2f0e76e04444f4ec456ef9f11289ec -
[root]#
Would you please try the following instead:
while read -r _ _ url _; do
wget -q -O - "$url"e | md5sum
done < <(head -n 3 zrcpathAll)
we should not put -i in front of "$url" here.
[Explanation about -i option]
Manpage of wget says:
-i file
--input-file=file
Read URLs from a local or external file. [snip]
If this function is used, no URLs need be present on the command line. [snip]
If the file is an external one, the document will be automatically treated as html if the Content-Type matches text/html.
Furthermore, the file's location will be implicitly used as base
href if none was specified.
where the file will contain line(s) of url such as:
https://example.com/zrc/3d2f0e76e04444f4ec456ef9f11289ec.zrce
https://example.com/zrc/e1bd7171263adb95fb6f732864ceb556.zrce
https://example.com/zrc/5300b80d194f677226c4dc6e17ba3b85.zrce
Whereas if we use the option as -i url, wget first
downloads the url as a file which contains the lines of urls
as above. In our case, the url is the target to download itself,
not the list of urls, wget causes an error: No URLs found in url.
Even if the wget fails, why the command outputs just one line, not
three lines as the result of md5sum?
This seems to be because the head command immediately flushes the remaining
lines when the piped subprocess fails.
I am using grep to extract data from a log file. The log file is dynamically updating new rows. and I need to send the grepped data to a REST endpoint using curl. This can be done easily for a static file but cannot find a solution fo a running log file. How can I realize this situation?
eg: tail -f | grep "<string>" > ~/<fileName>.log
The above can put the data in a file. Need to send it using a POST curl.
Maybe using a function like
send_data(){
curl -s -k -X POST –header Content-Type: application/json’ \
–header ‘Accept: application/json’ \
“http://${HOST}${PORT}/v1/notify” \
-d $1
}
If tail -f | grep "<string>" > ~/<fileName>.log is working for you then you could do:
tail -f file | stdbuf -i0 -o0 -e0 grep "<string>" | xargs -n 1 -d $'\n' curl ...
or:
while IFS= read -r line; do
curl ... "$line"
done < <(tail -f file | stdbuf -i0 -o0 -e0 grep "<string>")
I trying to add text (predefined) between a sorted output and saved to a new file.
I'm using a curl command to gather my info.
$ curl --user XXX:1234!## "http://......"
Then using grep to find IP addresses and sorting so they only appear once.
$ curl --user XXX:1234!## "http://......" | grep -E -o -m1 '([0-9]{1,3}[\.]){3}[0-9]{1,3}' | sort -u
I need to add <my_text_predefined> ([0-9]{1,3}[\.]){3}[0-9]{1,3} <my_text_predefined> between the regex ip address and then saved to a new file.
The script below only get my the ip address
$ curl --user XXX:1234!## "http://......" | grep -E -o -m1 '([0-9]{1,3}[\.]){3}[0-9]{1,3}' | sort -u
123.12.0.12
123.56.98.76
$ curl --user some_user:password "http://...." | grep -E -o -m1 '([0-9]{1,3}[\.]){3}[0-9]{1,3}' | sort -u | sed 's/.*/<prefix> -s & <suffix>/'
So if we need print some text for each IP ... try xargs
for i in {1..100}; do echo $i; done | xargs -n1 echo "Values are:"
if based on IP you would need to take decision put in a loop
for file $(curl ...) do ...
and check $file or do something with it ...
I have an output of a curl command as below,
comand: curl https://application.com/api/projectcreator
Output:
{"Table":[{"key":"projectA","name":"Jhon"},
{"key":"projectB","name":"Sam"},
{"key":"ProjectC","name":"Jack"}]}
I would like to cut this output to get only names. is there a way to do this in shell?
Eg:
Jhon
Sam
Jack
I tried below but doesnt seem to be promissing for me.
for Table in `curl -s -k http://application.com/api/projectcreator grep "name"`
do
echo "$Table"
done
Thanks for your help and insights!
Using jq you can do this easily:
curl -s -k 'http://application.com/api/projectcreator' |
jq -r '.Table[].name' | paste -s -d ' '
Jhon Sam Jack
If jq cannot be installed then use gnu grep:
curl -s -k 'http://application.com/api/projectcreator' |
grep -oP '"name":"\K[^"]+' | paste -s -d ' '
Here's the command I'm currently running:
curl 'http://test.com/?id=12345' | grep -o -P '(?<=content="2;url=).*?(?=")'
The response from this command is a URL, like this:
$ curl 'http://test.com/?id=12345' | grep -o -P '(?<=content="2;url=).*?(?=")'
http://google.com
I want to use whatever that URL is to essentially do this:
curl 'http://test.com/?id=12345' | grep -o -P '(?<=content="2;url=).*?(?=")' | curl 'http://google.com'
Is there any simple way to do this all in one line?
Use xargs with a place holder for the output from stdin with the -I{} flag as below. The -r flag is to ensure the curl command is not invoked on a empty output from previous grep output.
curl 'http://test.com/?id=12345' | grep -o -P '(?<=content="2;url=).*?(?=")' | xargs -r -I{} curl {}
A small description about the flags, -I and -r from the GNU xargs man page,
-I replace-str
Replace occurrences of replace-str in the initial-arguments with
names read from standard input.
-r, --no-run-if-empty
If the standard input does not contain any nonblanks, do not run
the command. Normally, the command is run once even if there is
no input. This option is a GNU extension
(or) if you are looking for a bash approach without other tools,
curl 'http://test.com/?id=12345' | grep -o -P '(?<=content="2;url=).*?(?=")' | while read line; do [ ! -z "$line" ] && curl "$line"; done