I would like to extract a line of strings but am having difficulties using the correct RegEx. Any help would be appreciated.
String to extract: KSEA 122053Z 21008KT 10SM FEW020 SCT250 17/08 A3044 RMK AO2 SLP313 T01720083 50005
For Some reason StackOverflow wont let me cut and paste the XML data here since it includes "<>" characters. Basically I am trying to extract data between "raw_text" ... "/raw_text" from a xml that will always be formatted like the following: http://www.aviationweather.gov/adds/dataserver_current/httpparam?dataSource=metars&requestType=retrieve&format=xml&hoursBeforeNow=3&mostRecent=true&stationString=PHNL%20KSEA
However, the Station name, in this case "KSEA" will not always be the same. It will change based on user input into a search variable.
Thanks In advance
if I can assume that every strings that you want starts with KSEA, then the answer would be:
.*(KSEA.*?)KSEA.*
using ? would let .* match as less as possible.
Related
I'm new here, so please don't scold me for misspellings etc.
What I need to do is to rename a bunch of files with a date in different formats at the beginning of their names, like:
05.07.2020-abc.pdf
2020.07.05-pqr.pdf
Instead of writing a different expression for each formatting, eg.
^(\d{2})\.(\d{2}).(\d{4})(.+) => $3-$2-$1$4
Example
02.11.2022-abc.pdf => 2022-11-02-abc.pdf
I'd like to do it in one fell swoop using the OR operator "|" but I have no idea how to formulate the groupings etc. Can one have nested groupings in regex?
Any ideas? Thank in advance!
#The fourth bird:
No (.+) needed. You're right, I condensed my actual expression and could have taken it out.
The different date 'formats' I mean are dd.mm.yyyy and yyyy.mm.dd respectively, and I need to convert both to yyyy-mn-dd
So,if the format is dd.mm.yyyy I have to flip the string, so to say, else I just need to replace the dots by hyphens.
The OS is Android, and for this operation I use Solid Explorer multi search & replace using regex.
I hope I made myself clear this time around ;-)
I'm honestly a novice on scilab.
I'm using print function to create .txt file with my character matrix in it.
But , when I open txt file, double quote appeared. I just want words without "".
This is how I'm using print
Compterendu(1,1)= "Medecin demandeur: "
fileresname= fullfile(RES_PATH, "compterendu.txt")
print(fileresname,Compterendu)
And, compterendu.txt was printed out like this.
Would be so grateful for any help!!
Thanks
Why do you use "print" ? After looking into the doc, yes, it is used to produce the same text as when you type the expression or the variable name on the command line. Hence it does print double quotes for strings. If you need something more basic use lower level i/o commands, like mputl.
S.
but I have a question about a small piece of code using the awk command. I have not found an answer/solution anywhere.
I am trying to parse an output file and extract all data between the 1st expression (including) ATOMIC and 2nd expression (excluding) Bond. This data is to be sent to a new file $1_geom. So far I have the following:
`awk '/ATOMIC/{flag=1;next}/Bond lengths in Bohr/{flag=0}flag' $1` >> $1_geom
This script will extract the correct data for me, but there are 2 problems:
The line ATOMICis not extracted with the data
The data is extracted and appended to a single line. I want the data to retain the formatting from the parsed file (5 columns, variable amount of lines). Please see attachment to see a visual. Visual Example Attachment. Is there a different way to append data (other than >>) so that I can keep formatting?
Any help is appreciated, thank you.
The next is causing the first match to be skipped; take it out if you don't want that.
The backticks by themselves are a shell syntax error (unless your Awk script happens to produce valid shell commands). I'm guessing you have a useless echo or something like that in your actual script which disarms the error, but instead produces the symptoms you describe.
This was part of a code in a csh script and I did have an "echo" in front of this line. Removing the "echo" makes it work perfectly and addresses the 2 questions that I had.
I have a long string, consisting of multiple sentences, of various length, divided by a "-".
I want to iterate over the string and extract everything between the -'s, preferably to an array.
From another thread I found something that gets me pretty close, but not all the way:
longString.scan( /-([^-]*)-/)
Needless to say, I am new to Ruby, and especially to RegEx.
What's wrong with using String#split?
longString.split('-')
Why not just use string.split()?
longString.split('-');
Trying to grab the two $ values and the X value from this string in Ruby/watir:
16.67%: $xxx.xx down, includes the Policy Fee, and x installments of $xxx.xx
So far I've got:
16.67%:\s+\$(\d+.\d{2})
which grabs the first xxx.xx fine, what do I need to add to it to grab the last two variables and load this all into an array?
You can use the following, but regex may be unnecessary if the surrounding text is always the same:
\$(\d+.\d{2}).*?(\d+) installments.*?\$(\d+.\d{2})
http://www.rubular.com/r/sk5wO3fyZF
if you know that the text in between will always be the same you could just:
16.67%:\s+\$(\d+.\d{2}) down, includes the Policy Fee, and x installments of (\d+.\d{2})
You better use scan.
sub(/.*%/, '').scan(/\$?([\d\.]+)/)
Have you considered just splitting the string on the $ character?, then manipulating what you get with a regex or basic string commands?
/\$(\d+.\d{2}).+\$(\d+.\d{2})/ should do it. it wont matter what text is there, only that there are two "$" in the sentence.