Gulp folder compiling - sass

Question

I am relatively new to gulp. I have one issue when I try to compile one directory with subfolders with their sass files.
Folder structure:
|_sass
|__folder1
| |_file.sass
|__folder2
| |_file.sass
|__folder3
|_file.sass
My simple gulp task to try the compilation
gulp.task('sass', function(){
return sass('sass/')
.pipe(gulp.dest('css');
}
This task above doesn't work with a folder but if I specify the file like in gulp task below, it works correctly.
gulp.task('sass', function(){
return sass('sass/folder1/file1.sass')
.pipe(gulp.dest('css');
}
I have checked the documentation of the repository (gulp-ruby-sass) and other topics in stackoverflow and the one solution that i have found is import all sass code into one file and compile it.
I have tried different paths: ./sass, sass, sass/ even the last syntax with gulp.src(path/**/*.sass) with gulp-sass repository as well.
Can you help me?
Thanks in advance

Answer 1

Edit: Using gulp-sass, not gulp-ruby-sass, since gulp-ruby-sass does only support single files, as mentioned in the docs:
gulp-ruby-sass doesn't support globs yet, only single files or directories. Just like Sass.
You should create a stream with valid glob arguments gulp.src() instead of just calling sass() directly and call it in a pipe():
gulp.task('sass', function (){
return gulp.src([
'sass/folder1/file.sass',
'sass/folder2/file.sass',
'sass/folder3/file.sass'
])
.pipe(sass())
.pipe(gulp.dest('css'));
});
If the files you just want to import are named correctly (starting with an underscore), this should work as well:
gulp.task('sass', function (){
return gulp.src('sass/**/*.sass')
.pipe(sass())
.pipe(gulp.dest('css'));
});
Edit: Fixed some code errors - SO needs a linter (;