I am using MVC knockout, with View Model on single js file, on a button click i am loading a partial view that is already having data-bind="text: type" done. but the view model is not able to bind the elements as it is in partial view and its is loading on a button click...is there any way that we can using bind data after pager render.
Check code below to load partial view and get data for partial view:-
$('#btnCreateTask').click(function () {
var url = getAppPath() + 'Home/CreateTask';
$('#midsection').load(url);
var url = getAppPath() + 'Task/GetTaskFormDetails';
$.ajax({
url: url,
cache: false,
type: 'POST',
contentType: 'application/json; charset=utf-8',
data: {},
success: function (data) {
viewModel.task.TaskType.push.apply(viewModel.task.TaskType, data["objType"]);
When using MVC to load partials via jQuery.load() into your application dynamically, you must understand that the elements you are bringing in are not registered with knockout. When you initialize a page you invoke knockout with ko.applybindings(). Once. Any further DOM manipulation must be a byproduct of knockout's bindings.
One of our projects is a huge Enterprise application and we load all possible partials into our View(s) on load and control their visibility by formatting them as either a knockout template or by just having a knockout visibility binding.
With either option, you are loading the DOM elements on the initial load. The added overhead is minimal and will prevent a call back to the server.
Related
When I load a Partial View with some unobtrusive AJAX I also need the URL to change accordingly.
It would be okay if I had to do the work in the jQuery's done() callback.
But it's not possible right, wihtout loading something new. So the only choise I have is to load a View?
$.ajax({
//some jquery ajax call properties
success: function(){
location.hash = 'your_unique_value';
}
})
or use history api window.history.pushState('page2', 'Title', '/page2.php');
Docs
I have two controllers, A and B. A is responsible for representing some data in a grid view. Assume I have a button called "ShowInfo" which brings additional info about the selected record. And to retrieve the info about the selected record is the job of controller B.
The info is so little that it'd take just a tiny place in the corner if I navigate to another view. So I thought I'd rather bring that info inside a jQuery dialog without navigating to anywhere. But I'm a bit confused as to how to do it.
Here's the action method in controller B that is responsible for providing that info in a partial view.
public class BController:Controller{
public ActionResult GetInfo(int recordID){
RecordInfo info=RecordsRepository.GetRecordInfoById(recordID);
return PartialView(viewName:"RecordInfo",model:info);
}
}
I don't know, maybe the action method needs to different. Maybe I should return JSON instead of Partial view, but anyway, how do I do that?
You can use the jquery .get or .load methods. For example, to replace the contents of <div id="SomeElement"></div> with the partial view returned by GetInfo()
$('#ShowInfo').click(function() {
var url = '#Url.Action("GetInfo", "B")';
var ID = someValue; // the value to pass to the GetInfo method
$.get(url, { recordID: ID }, function(data) {
$('#someElement').html(data);
});
});
You can use Jquery ajax to achieve this.
Wrtire jquery ajax on the view page and call the partial view action from ajax.
receive the result in html format and replace it in the dialog box.
Put following code on main view page(ShowInfo button page)
$(document).ready(function(){
$("#ShowInfo").on("click",function(){ ///give id to showinfo button and attr data-id is record id
var id=$(this).attr("data-id");
$.ajax({
type: "POST",
url: "B/GetInfo",
data: JSON.stringify({ recordID: id }),
dataType: "html",
success: function (html)
{
////put the html response in dialog box
}
});
})
});
I have a partial view which I load dynamically by calling a function similar to this as described here
$("#addItem").click(function() {
$.ajax({
url: this.href,
cache: false,
success: function(html) { $("#editorRows").append(html); }
});
return false;
});
As described, the cache is set to false to maintain the uniqueness of the elements. How does the code above acheive this? That is, what is the new ID that is assigned to the elements? How can I control these Ids?
I have a partial view where each I pass the id of a control to another control. However, I do not know how to do this after a partial view has been rendered dynamically. I need some way to figure out the new Id that is assign to each element.
I need to display a number of "dynamic" grids using jqGrid. By dynamic I mean that both definition and data of the grid are retrieved from a database. There are many grids on the page, so I am trying to minimize the number of server trips, and there is a lot of data, so server-side paging is a must.
My workflow is
On initialization of each grid, retrieve grid definition and first
page of data in one server call.
If a user sorts/pages, then retrieve a page of data from the server
Because I want to retrieve the grid definition and first page of data in one call, I cannot use datatype: 'json', url: '###' approach; instead I do:
grid.jqGrid({
mtype: 'post',
...
datatype: function (postdata) {
if (!init.data) {
var request = {
screenId: settings.screenId,
pageNumber: postdata.page,
pageSize: postdata.rows,
sortColumn: postdata.sidx,
sortDirection: postdata.sortd,
date: settings.date
};
site.callWs("/MyService", request, function (pageResponse) {
//WHAT TO CALL HERE TO SET A PAGE OF DATA?
});
} else {
//WHAT TO CALL HERE TO SET A PAGE OF DATA?
init.data = null;
}
}
});
My data object (pageResponse or init.data) looks like this
I am not sure what method to call on jqGrid once a page of data is returned. I considered addJSONData, but it seems so inefficient to convert JSON back to string, then use EVAL(). Also, considered addRowData or setting the data property, but I am confused how to instruct jqGrid that I am doing server-side paging -- if I set the data property to one page of records, what do I need to do to tell jqGrid that there is a total of 50 records and this is page 1 out of 10.
Thanks for your help.
It was a user error (mine :). I had some show/hide logic in loadComplete of jqGrid, but this event does not fire when addJSONData is called.
addJSONData works just fine when provided with a properly-structured JavaScript object.
I have a page that i want to remain static with two divs that i want to load different html views during user navigation. I want the content to change without refreshing the entire page, only refreshing those two divs.
How can i load a specific view into those divs?
I already have the menu navigation that determines the html views to be loaded into those divs and controller functions to the menu choices that i get using javascript and then use it in the controller of the main page, i just dont know how to load the content.
You can load the views using a bit of Javascript with AJAX.
With jQuery:
$('a.nav-button').click(function(e) {
// prevent the default action when a nav button link is clicked
e.preventDefault();
// ajax query to retrieve the HTML view without refreshing the page.
$.ajax({
type: 'get',
url: '/path/to/your/controller/method',
dataType: 'html',
success: function (html) {
// success callback -- replace the div's innerHTML with
// the response from the server.
$('#yourDiv').html(html);
}
});
});
I think you need to use a jquery and Codeigniter
This will be your jQuery Code
$('nav').click(function(){//element to be click to load the page in the div
$(your_div_element).load('controller/method');
});
This will be your Codeigniter
function method(){
$data['result'] = ''//you can use this if you need to pass some data to the view
print $this->load->view('your_view',$data,true);//This will load your view page to the div element
}
Goodluck!
In order to put content without refreshing you should use ajax, lets say you have divs in a file under a directory (webparts), and you want to add it's content to a div called my_div; first create a method on the controller that renders just the view (div) you want to put something like this
function part($part = false)
{
$data = array(); // you can add data to your div, if you need to.
$this->load->view("webparts/$part", $data);
}
Then with javascript (jQuery in this case) you can call
$('#my_div').load('controller/mypart');
Note: I like to use "load" because it allows me to select certain sections of the view Im requesting, using something like this
$('#my_div').load('controller/mypart #certainsection');
Will load the element with the id="certainsection" from mypart view