Replace text between 2 strings in bash with result of ls - bash

I want to create an automation for a deployment, the js/css are generated with a prefix and I want to import them in the php file between the tags
Expected Output
...
/*bashStart*/
drupal_add_css(drupal_get_path("module","myModule")."/styles/c91c6d11.main.css");
drupal_add_js(drupal_get_path("module","myModule")."/scripts/j91c6d11.main.js");
/*bashEnd*/
...
I used awk and got me here so far but I have a problem, it's generating
...
/*bashStart*/
drupal_add_css(drupal_get_path("module","myModule")."/styles/c91c6d11.main.css
");
drupal_add_js(drupal_get_path("module","myModule")."/scripts/j91c6d11.main.js
");
/*bashEnd*/
...
here is the awk script:
awk 'BEGIN {p=1}/Start/{print;printf("drupal_add_css(drupal_get_path(\"module\",\"myModule\").\"/styles/");system("ls styles");printf("\");\n");printf("drupal_add_js(drupal_get_path(\"module\",\"myModule\").\"/scripts/");system("ls scripts");printf("\");\n");p=0}/Finish/{p=1} p' myModule.module > tmp;

Using ls within awk isn't very nice - I think you can do this entirely in the shell:
#!/bin/bash
p=1
while read -r line; do
[[ $line = '/*bashEnd*/' ]] && p=1
(( p )) && echo "$line"
if [[ $line = '/*bashStart*/' ]]; then
p=0
for style in styles/*; do
echo 'drupal_add_css(drupal_get_path("module","myModule")."/styles/'"$style"'");'
done
for script in scripts/*; do
echo 'drupal_add_js(drupal_get_path("module","myModule")."/scripts/'"$script"'");'
done
fi
done < file.php > output.php
Loop through the input file until you reach the "bashStart" line, then add the lines you want. Output goes to a file output.php which you can check before overwriting the original file. If you're feeling confident you can add && mv output.php file.php to the done line, to overwrite the original file.
The flag p controls which lines are printed. It is set to 0 when the "bashStart" line is reached and back to 1 when the bashEnd line is reached, so lines between the two are replaced.

Related

Current Count vs Total Count output in a single line using Bash

I need an output of current count vs total count in single line. I would like to know if this could be done Via Bash using 'for' 'while' loop.
Expecting an output that should only update the count and should not display multiple lines
File Content
$ cat ~/test.rtf
hostname1
hostname2
hostname3
hostname4
#!/bin/sh
j=1
k=$(cat ~/test.rtf | wc -l)
for i in $(cat ~/test.rtf);
do
echo "Working on line ($j/$k)"
echo "$i"
#or any other command for i
j=$((j+1))
done
EX:
Working on line (2/4)
Not like,
Working on line (2/4)
Working on line (3/4)
Assumptions:
OP wants to generate n lines of output that overwrite each other on successive passes through the loop
in OP's sample code there are two echo calls so in this case n=2
General approaches:
issue a clear at the beginning of each pass through the loop so as to clear the current output and reposition the cursor at the 'top' of the console/window
use tput to manage movement of the cursor (and clearing/overwriting of previous output)
Sample input:
$ cat test.rtf
this is line1
then line2
and line3
and last but not least line4
real last line5
clear approach:
j=1
k=$(wc -l < test.rtf)
while read -r line
do
clear
echo "Working on line ($j/$k)"
echo "${line}"
((j++))
done < test.rtf
tput approach:
j=1
k=$(wc -l < test.rtf)
EraseToEOL=$(tput el) # grab terminal specific code for clearing from cursor to EOL
clear # optional: start with a new screen otherwise use current position in console/window for next command ...
tput sc # grab current cursor position
while read -r line
do
tput rc # go (back) to cursor position stored via 'tput sc'
echo "Working on line ($j/$k)"
echo "${line}${EraseToEOL}" # ${EraseToEOL} forces clearing rest of line, effectively erasing a previous line that may have been longer then the current line of output
((j++))
done < test.rtf
Both of these generate the same result:
Something along these lines:
file=~/test.rtf
nl=$(wc -l "$file")
nl=${nl%%[[:blank:]]*}
i=0
while IFS= read -r line; do
i=$((i+1))
echo "Working on line ($i/$nl)"
done < "$file"
Your main question is how to avoid each the counter to be written to new lines. The newlines are \n characters, which is appended by echo. You want \r, like
for ((i=0; i<10; i++)); do
printf "Counter $i\r"
sleep 1
done
echo
When you echo something from the line you are working on, you will use \n again. I will use cut as an example of processing the inputline. Use the output string in the same printf command like
j=1
k=$(cat ~/test.rtf | wc -l)
while IFS= read -r line; do
printf "Working on line (%s): %s\r" "$j/$k" $(cut -c1-10 <<< "${line}")
sleep 1
((j++))
done < ~/test.rft
The problem with the above solution is that you will see output from previous lines when your last output is shorter than the previous one. When you know the maximum length that your processing of the line will show, you can force additional spaces:
j=1
k=$(cat ~/test.rtf | wc -l)
while IFS= read -r line; do
printf "Working on line (%5.5s): %-20s\r" "$j/$k" "$(cut -c1-20 <<< "${line}")";
sleep 1
((j++))
done < ~/test.rft

How do you name output files using an increment after a bash file loop?

I'm trying to treat a bunch of files (five) with an awk command and name the output files using an incrementation.
The input files have complicated names. I know how to reuse the files' basenames to rename the outputs but I want to simplify the file names.
this is my code:
for f in *.txt; do
for i in {1..5}; do
echo processing file $f
awk '
{ if ($1=="something" && ($5=="60" || $5=="61"|| $5=="62"|| $5=="63"|| $5=="64"|| $5=="65"|| $5=="66"|| $5=="67"|| $5=="68"|| $5=="69"|| $5=="70"))
print }' $b.txt>"file_treated"$i.txt
echo processing file $f over
done
done
I understand that the error is in the second line because what I wrote runs the second loop for each value of the first one. I want each value of the first loop to correspond to one value of the second one.
Hope this was clear enough
How about:
i=0
for f in *.txt; do
let i++;
awk '$1=="something" && ($5 >= 60 && $5 <=70)' "$f" > file_treated"${i}".txt
done
I simplified your awk command and straightened out your various quoting issues. I also removed the $b.txt since you were simply recreating $f. I left the echo $b etc in case you actually wanted that but it could just as easily be replaced with echo "$f".
Use a counter:
i=1
for f in *.txt
do
echo "$f is number $((i++))"
done

Parsing .csv file in bash, not reading final line

I'm trying to parse a csv file I made with Google Spreadsheet. It's very simple for testing purposes, and is basically:
1,2
3,4
5,6
The problem is that the csv doesn't end in a newline character so when I cat the file in BASH, I get
MacBook-Pro:Desktop kkSlider$ cat test.csv
1,2
3,4
5,6MacBook-Pro:Desktop kkSlider$
I just want to read line by line in a BASH script using a while loop that every guide suggests, and my script looks like this:
while IFS=',' read -r last first
do
echo "$last $first"
done < test.csv
The output is:
MacBook-Pro:Desktop kkSlider$ ./test.sh
1 2
3 4
Any ideas on how I could have it read that last line and echo it?
Thanks in advance.
You can force the input to your loop to end with a newline thus:
#!/bin/bash
(cat test.csv ; echo) | while IFS=',' read -r last first
do
echo "$last $first"
done
Unfortunately, this may result in an empty line at the end of your output if the input already has a newline at the end. You can fix that with a little addition:
!/bin/bash
(cat test.csv ; echo) | while IFS=',' read -r last first
do
if [[ $last != "" ]] ; then
echo "$last $first"
fi
done
Another method relies on the fact that the values are being placed into the variables by the read but they're just not being output because of the while statement:
#!/bin/bash
while IFS=',' read -r last first
do
echo "$last $first"
done <test.csv
if [[ $last != "" ]] ; then
echo "$last $first"
fi
That one works without creating another subshell to modify the input to the while statement.
Of course, I'm assuming here that you want to do more inside the loop that just output the values with a space rather than a comma. If that's all you wanted to do, there are other tools better suited than a bash read loop, such as:
tr "," " " <test.csv
cat file |sed -e '${/^$/!s/$/\n/;}'| while IFS=',' read -r last first; do echo "$last $first"; done
If the last (unterminated) line needs to be processed differently from the rest, #paxdiablo's version with the extra if statement is the way to go; but if it's going to be handled like all the others, it's cleaner to process it in the main loop.
You can roll the "if there was an unterminated last line" into the main loop condition like this:
while IFS=',' read -r last first || [ -n "$last" ]
do
echo "$last $first"
done < test.csv

Shell Script: how to read a text file that does not end with a newline on Windows

The following program reads a file and it intends to store the all values (each line) into a variable but doesn't store the last line. Why?
file.txt :
1
2
.
.
.
n
Code :
FileName=file.txt
if test -f $FileName # Check if the file exists
then
while read -r line
do
fileNamesListStr="$fileNamesListStr $line"
done < $FileName
fi
echo "$fileNamesListStr" // 1 2 3 ..... n-1 (but it should print up to n.)
Instead of reading line-by-line, why not read the whole file at once?
[ -f $FileName ] && fileNameListStr=$( tr '\n' ' ' < $FileName )
One probable cause is that there misses a newline after the last line n.
Use the following command to check it:
tail -1 file.txt
And the following fixes:
echo >> file.txt
If you really need to keep the last line without newline, I reorganized the while loop here.
#!/bin/bash
FileName=0
if test -f $FileName ; then
while [ 1 ] ; do
read -r line
if [ -z $line ] ; then
break
fi
fileNamesListStr="$fileNamesListStr $line"
done < $FileName
fi
echo "$fileNamesListStr"
The issue is that when the file does not end in a newline, read returns non-zero and the loop does not proceed. The read command will still read the data, but it will not process the loop. This means that you need to do further processing outside of the loop. You also probably want an array instead of a space separated string.
FileName=file.txt
if test -f $FileName # Check if the file exists
then
while read -r line
do
fileNamesListArr+=("$line")
done < $FileName
[[ -n $line ]] && fileNamesListArr+=("$line")
fi
echo "${fileNameListArr[#]}"
See the "My text files are broken! They lack their final newlines!" section of this article:
http://mywiki.wooledge.org/BashFAQ/001
As a workaround, before reading from the text file a newline can be appended to the file.
echo "\n" >> $file_path
This will ensure that all the lines that was previously in the file will be read. Now the file can be read line by line.

bash: append newline when redirecting file

Here is how I read a file row by row:
while read ROW
do
...
done < file
I don't use the other syntax
cat file | while read ROW
do
...
done
because the pipe creates a subshell and makes me lose the environment variables.
The problem arises if the file doesn't end with a newline: last line is not read. It is easy to solve this in the latter syntax, by echoing just a newline:
(cat file; echo) | while read ROW
do
...
done
How do I do the same in the former syntax, without opening a subshell nor creating a temporary file (the list is quite big)?
A way that works in all shells is the following:
#!/bin/sh
willexit=0
while [ $willexit == 0 ] ; do
read ROW || willexit=1
...
done < file
A direct while read will exit as soon as read encounters the EOF, so the last line will not be processed. By checking the return value outside the while, we can process the last line. An additional test for the emptiness of $ROW should be added after the read though, since otherwise a file whose last line ends with a newline will generate a spurious execution with an empty line, so make it
#!/bin/sh
willexit=0
while [ $willexit == 0 ] ; do
read ROW || willexit=1
if [ -n "$ROW"] ; then
...
fi
done < file
#!/bin/bash
while read ROW
...
done < <(cat file ; echo)
The POSIX way to do this is via a named pipe.
#!/bin/sh
[ -p mypipe ] || mkfifo mypipe
(cat num7; echo) > mypipe &
while read line; do
echo "-->$line<--"
export CNT=$((cnt+1))
done < mypipe
rm mypipe
echo "CNT is '$cnt'"
Input
$ cat infile
1
2
3
4
5$
Output
$ (cat infile;echo) > mypipe & while read line; do echo "-->$line<--"; export CNT=$((cnt+1)); done < mypipe; echo "CNT is '$cnt'"
[1] 22260
-->1<--
-->2<--
-->3<--
-->4<--
-->5<--
CNT is '5'
[1]+ Done ( cat num7; echo ) > mypipe
From an answer to a similar question:
while IFS= read -r LINE || [ -n "${LINE}" ]; do
...
done <file
The IFS= part prevents read from stripping leading and trailing whitespace (see this answer).
If you need to react differently depending on whether the file has a trailing newline or not (e.g., warn the user) you'll have to make some changes to the while condition.

Categories

Resources